I have a matlab structure array Modles1 of size (1x180) that has fields a, b, c, ..., z.
I want to understand how many distinct values there are in each of the fields. i.e.
max(grp2idx([foo(:).a]))
The above works if the field a is a double. {foo(:).a} needs to be used in the case where the field a is a string/char.
Here's my current code for doing this. I hate having to use the eval, and what is essentially a switch statement. Is there a better way?
names = fieldnames(Models1);
for ix = 1 : numel(names)
className = eval(['class(Models1(1).',names{ix},')']);
if strcmp('double', className) || strcmp('logical',className)
eval([' values = [Models1(:).',names{ix},'];']);
elseif strcmp('char', className)
eval([' values = {Models1(:).',names{ix},'};']);
else
disp(['Unrecognized class: ', className]);
end
% this line requires the statistics toolbox.
[g, gn, gl] = grp2idx(values);
fprintf('%30s : %4d\n',names{ix},max(g));
end
Indeed, there is a better way. Surprisingly, MATLAB allows you to access the struct fields using a key string without eval, for instance:
Models1(1).(names{ix})
so instead, you can write this:
className = class(Models1(1).(names{ix});
...
values = [Models1(:).(names{ix})];
...
values = {Models1(:).(names{ix})};
Also, instead of using class and strcmp, you can just test the same conditions with isa:
v1 = Models1(1).(names{ix});
if (isa(v1, 'double') || isa(v1, 'logical'))
values = [Models1(:).(names{ix})];
% # ...
elseif (isa(v1, 'char'))
values = {Models1(:).(names{ix})};
% # ...
else
disp(['Unrecognized class: ', class(v1)]);
end
It should be much faster.
Related
I'm trying to exctract some data from a nested structure in a recursive manner. First, I know that this has a field (values) which repeats itself inside the nested structure. Secondly I know that the structure which has those values has only structures as fields. In the below code I've tried to acces the structure.values by searching if my current structure has a field named values. If it has, I put .values at the end of my structure name. If it doesn't have this field, I verify if all the fields are structures. If they are, it means that I will have to consider them further and to extract the values from each one. If the fields are not structures, it means that they are values and I save them into a new simplified structure. Example of fields that I want: S.values.model1.values.mission.values.(alt/list). Currently, with the below code I'm only able to get the values from one field and then I get an error and don't know how to approach further.
Code example:
clear all
clc
S=struct()
S.case='1';
S.type='A';
S.values.model1.case='2'
S.values.model1.type='C'
S.values.model1.values.mission.case='3'
S.values.model1.values.mission.type='D'
S.values.model1.values.mission.values.alt='none'
S.values.model1.values.mission.values.list=2
S.values.model1.values.mission.values.parameter=4
S.values.model1.values.phase.case='4'
S.values.model1.values.phase.type='A'
S.values.model1.values.phase.values.num='all'
S.values.model1.values.phase.values.eq=2
S.values.model1.values.phase.values.unit=4
S.values.model1.values.analysis.case='1'
S.values.model1.values.phase.type='A'
S.values.model1.values.phase.values.nump1.list='all'
S.values.model1.values.phase.values.nump1.table='four'
S.values.model1.values.phase.values.nump1.mean=0
S.values.model1.values.phase.values.nump2.list='none'
S.values.model1.values.phase.values.nump2.table='three';
S.values.model1.values.phase.values.nump2.mean=1
s=S.values.model1;
names=fieldnames(s);
nnames=numel(names);
newStruct={};
[valsi,newstructi]=extractValues(names,s,nnames,newStruct)
function [vals,newStruct]=extractValues(names,vals,nnames,newStruct)
if any(strcmp(names,'values'))
vals=vals.('values');
names=fieldnames(vals)
nnames=numel(names)
[vals,newStruct]=extractValues(names,vals,nnames,newStruct);
end
for j=1:nnames
value(j)=isstruct((vals.(names{j})));
end
if all(value)
for k=1:nnames
vals=(vals.(names{k}));
names=fieldnames(vals);
nnames=numel(names);
[vals,newStruct]=extractValues(names,vals,nnames,newStruct);
end
else
for j=1:nnames
value=(vals.(names{j}));
newStruct.(names{j})=value;
end
end
end
As it is known beforehand what fields are requested you can arrange the subsequent filed names in a cell array and use a loop to extract the value:
names = {'values', 'model1', 'values', 'mission', 'values', 'alt'};
out = S;
for name : names
out = out.(name{1});
end
So that is a loop version of using:
out = S.values.model1.values.mission.values.alt;
EDIT:
If you want to list all field names and all field values you can used these functions:
function out = names(s, p)
if isstruct(s)
out = {};
f = fieldnames(s);
for i = 1:numel(f)
s1 = s.(f{i});
p1 = [p '.' f{i}];
out = [out; names(s1, p1)];
end
else
out = {p};
end
end
function out = values(s)
if isstruct(s)
out = {};
f = fieldnames(s);
for i = 1:numel(f)
out = [out; values(s.(f{i}))];
end
else
out = {s};
end
end
Use them as:
n = names(S, 'S');
v = values(S);
I have a set of structs that all have the same field names. For example structs A, B, and C all have field names name and section. Is there a way to rearrange this organization of data so that the data goes from:
A.name = 'bb';
A.section = 199;
B.name = 'joe';
B.section = 101;
C.name = 'rob';
C.section = 33;
to this:
name =
A: 'bb'
B: 'joe'
C: 'rob'
section =
A: 199
B: 101
C: 33
The current code I have, for example, operates like this:
% ORIGINAL STRUCTS
A.name = 'bb';
A.section = 199;
B.name = 'joe';
B.section = 101;
C.name = 'rob';
C.section = 33;
% CREATE VARIABLE NAMES FOR NEW STRUCTS
oldFNames = fieldnames(A); % old field names
oldVNames{1} = varname(A); % old variable names
oldVNames{2} = varname(B);
oldVNames{3} = varname(C);
% RESTRUCTURE STRUCTS (SWITCH FIELDNAMES AND VARIABLE NAMES)
for j = 1:length(oldFNames)
for k = 1:length(oldVNames)
eval([oldFNames{j} '.' oldVNames{k} ' = ' oldVNames{k} '.' oldFNames{j}]);
end
end
function out = varname(var) % Function to get variable name
out = inputname(1);
end
I find the hack to use the varname function to be not great, and I don't know whether there is a way to make it easily adaptable to the number of variables I have. Any input on how to simplify this procedure would be great. Thanks.
It would be easier to do it all in a function, instead of just using a function to get the input variable name. Here's one solution:
function invert_struct(varargin)
varNames = arrayfun(#inputname, 1:nargin, 'UniformOutput', false); % Get input names
s = [varargin{:}]; % Combine inputs into a structure array
for f = fieldnames(s).' % Loop over fields
assignin('caller', f{:}, cell2struct({s.(f{:})}, varNames, 2));
end
end
And you would call it like so, with however many inputs you like:
invert_struct(A, B, C, ...);
The function uses assignin to create your new variables in the calling function and cell2struct to create a new structure from your field data and old variable names. Note that it also makes use of dynamic field names.
I'd like to achieve the following using dynamic fieldnames instead of setfield:
Say a struct 'myStruct' has a set of nested structures, i.e.
myStruct.a.b.c = 0
myStruct.a.d = 0
myStruct.a.e.f.g = 0
I want to be able to flexibly set the leaf structure values as follows:
fields = {'a', 'b', 'c'}
paramVal = 1
setfield(myStruct, fields{:}, paramVal)
This works using setfield. Is there a syntax that will do this using dynamic fieldnames? The following obviously doesn't work because the fieldname needs to be a string not an array, but demonstrates what I want:
myStruct.(fields{:}) = 0
Which would be equivalent to:
myStruct.('a').('b').('c') = 0
Recursive solution without eval, ripped from one of my old utility functions:
function s = setsubfield(s, fields, val)
if ischar(fields)
fields = regexp(fields, '\.', 'split'); % split into cell array of sub-fields
end
if length(fields) == 1
s.(fields{1}) = val;
else
try
subfield = s.(fields{1}); % see if subfield already exists
catch
subfield = struct(); % if not, create it
end
s.(fields{1}) = setsubfield(subfield, fields(2:end), val);
end
I guess the try/catch can be replaced with if isfield(s, fields{1}) ..., I don't remember why I coded it like that.
Usage:
>> s = struct();
>> s = setsubfield(s, {'a','b','c'}, 55);
>> s = setsubfield(s, 'a.b.d.e', 12)
>> s.a.b.c
ans =
55
>> s.a.b.d.e
ans =
12
Below is a simple, if crude, solution that works for scalar structs. Applying it to your example,
S=setfld(myStruct,'a.b.c',1)
>> S.a.b.c
ans =
1
In general, though, deeply nested structs are unrecommended.
function S=setfld(S,fieldpath,V)
%A somewhat enhanced version of setfield() allowing one to set
%fields in substructures of structure/object S by specifying the FIELDPATH.
%
%Usage: setfld(S,'s.f',V) will set S.s.f=V
%
%
%%Note that for structure S, setfield(S.s,'f') would crash with an error if
%S.s did not already exist. Moreover, it would return a modified copy
%of S.s rather than a modified copy of S, behavior which would often be
%undesirable.
%
%
%Works for any object capable of a.b.c.d ... subscripting
%
%Currently, only single structure input is supported, not structure arrays.
try
eval(['S.' fieldpath '=V;']);
catch
error 'Something''s wrong.';
end
I have data as a struct with several layers, for example:
data.A.B
The data I want to access is in layer B. But the problem is that field names in B can be different depending on where the data comes from. Therefore I can't just type:
data.A.B.myData
myData is itself a struct
I can use:
fieldnames(data.A)
to find the names, but this doesn't help my much. I would have to write code sections for every possible field name that can occur at this level. And that's just what i trying to avoid.
Is there a way to get down to the data I have (myData) without knowing the field names of B?
Traditionally, you can loop over the fieldnames and perform the search of myData at a specific sub-structure of the struct. However, if you don't know which sub-structure you need to search, then you can perform a recursive algorithm. Below is an example. It will return the first match of myData in the struct or an empty matrix if no match found. The code can be improved to find all matches of myData.
function S2=getmyfield(S1,queriedField)
if isstruct(S1)
% Get all fieldnames of S1
fieldArray=fieldnames(S1);
% Find any match with the queried field. You can also use isfield().
% If there is a match return the value of S1.(queriedField),
% else perform a loop and recurse this function.
matchTF=strcmp(queriedField,fieldArray);
if any(matchTF)
S2=S1.(fieldArray{matchTF});
return;
else
S2=[];
i=0; % an iterator count
while isempty(S2)
i=i+1;
S2=getmyfield(S1.(fieldArray{i}),queriedField);
end
end
else
S2=[];
end
end
Cheers.
You just need a recursive function that checks fieldnames at each level for the structure.
This is roughly what you need (it could be improved to supply the path to the found field).
function [ value, found ] = FindField( rootStruct, fieldName )
%FindField - Find a field with a structure
value = [];
found = 0;
if isstruct( rootStruct )
fields = fieldnames(rootStruct);
for fi=1:length(fields)
if strcmp(fields{fi}, fieldName )
value = rootStruct.(fieldName);
found = true;
return;
end
[value, found ] = FindField( rootStruct.(fields{fi}), fieldName );
if found
return;
end
end
end
end
Usage example:
a.b = 1;
a.b.c = 2;
a.b.d = struct('Index',1,'Special',2);
FindField(a,'d')
ans =
Index: 1
Special: 2
Is there a way that I get all the structure subsubfield values of a subfield in one line ? Something like this :
struct.field(1:end).field
If I understand your question aright, you want to collect all the fields of the second-level structure, with the name 'field', into a single output array. It doesn't quite meet your request for a one-liner, but you can do it like this:
a.field1.a = 1;
a.field1.b = 2;
a.field2.a = 3;
a.field2.b = 4;
result = [];
for x = fieldnames(a)'
result = horzcat(result, a.(x{:}).a);
end
The ending value of result is [1 3]
Simple Structure Example
aStruct.subField = struct('subSubField', {1;2;3;4})
So that
aStruct.subField(1).subSubField == 1
aStruct.subField(1).subSubField == 2
Etc. Then the values of the leaf nodes can be obtained via a one-liner as
valueLeafs = [aStruct.subField.subSubField];
Which can be checked via assert(all(valueLeafs == [1,2,3,4])).
Non-Scalar Structure Example
The above one-liner also works when the leaf node values are non-scalar such that they can be horizontally concatenated. For example
bStruct.subField = struct('subSubField', {[1,2];[3,4]})
valueLeafs_b = [bStruct.subField.subSubField]; % works okay
cStruct.subField = struct('subSubField', {[1,2];[3;4]})
valueLeafs_c = [cStruct.subField.subSubField]; % error: bad arg dims
Distinct Class Structure Example
The one-line solution given previously does not work whenever the leaf node values are different class since they cannot - in general, be concatenated. However, use of arrayfun and a tricky anonymous function typically provide the required indexing technique:
dStruct.subField = struct('subSubField', {[1;2];'myString'});
valueLeafs_d = arrayfun(#(x) x.subSubField, dStruct.subField, 'UniformOutput', false)