I have a table in postgresql that contains an array which is updated constantly.
In my application i need to get the number of rows for which a specific parameter is not present in that array column. My query looks like this:
select count(id)
from table
where not (ARRAY['parameter value'] <# table.array_column)
But when increasing the amount of rows and the amount of executions of that query (several times per second, possibly hundreds or thousands) the performance decreses a lot, it seems to me that the counting in postgresql might have a linear order of execution (I’m not completely sure of this).
Basically my question is:
Is there an existing pattern I’m not aware of that applies to this situation? what would be the best approach for this?
Any suggestion you could give me would be really appreciated.
PostgreSQL actually supports GIN indexes on array columns. Unfortunately, it doesn't seem to be usable for NOT ARRAY[...] <# indexed_col, and GIN indexes are unsuitable for frequently-updated tables anyway.
Demo:
CREATE TABLE arrtable (id integer primary key, array_column integer[]);
INSERT INTO arrtable(1, ARRAY[1,2,3,4]);
CREATE INDEX arrtable_arraycolumn_gin_arr_idx
ON arrtable USING GIN(array_column);
-- Use the following *only* for testing whether Pg can use an index
-- Do not use it in production.
SET enable_seqscan = off;
explain (buffers, analyze) select count(id)
from arrtable
where not (ARRAY[1] <# arrtable.array_column);
Unfortunately, this shows that as written we can't use the index. If you don't negate the condition it can be used, so you can search for and count rows that do contain the search element (by removing NOT).
You could use the index to count entries that do contain the target value, then subtract that result from a count of all entries. Since counting all rows in a table is quite slow in PostgreSQL (9.1 and older) and requires a sequential scan this will actually be slower than your current query. It's possible that on 9.2 an index-only scan can be used to count the rows if you have a b-tree index on id, in which case this might actually be OK:
SELECT (
SELECT count(id) FROM arrtable
) - (
SELECT count(id) FROM arrtable
WHERE (ARRAY[1] <# arrtable.array_column)
);
It's guaranteed to perform worse than your original version for Pg 9.1 and below, because in addition to the seqscan your original requires it also needs an GIN index scan. I've now tested this on 9.2 and it does appear to use an index for the count, so it's worth exploring for 9.2. With some less trivial dummy data:
drop index arrtable_arraycolumn_gin_arr_idx ;
truncate table arrtable;
insert into arrtable (id, array_column)
select s, ARRAY[1,2,s,s*2,s*3,s/2,s/4] FROM generate_series(1,1000000) s;
CREATE INDEX arrtable_arraycolumn_gin_arr_idx
ON arrtable USING GIN(array_column);
Note that a GIN index like this will slow updates down a LOT, and is quite slow to create in the first place. It is not suitable for tables that get updated much at all - like your table.
Worse, the query using this index takes up to twice times as long as your original query and at best half as long on the same data set. It's worst for cases where the index is not very selective like ARRAY[1] - 4s vs 2s for the original query. Where the index is highly selective (ie: not many matches, like ARRAY[199]) it runs in about 1.2 seconds vs the original's 3s. This index simply isn't worth having for this query.
The lesson here? Sometimes, the right answer is just to do a sequential scan.
Since that won't do for your hit rates, either maintain a materialized view with a trigger as #debenhur suggests, or try to invert the array to be a list of parameters that the entry does not have so you can use a GiST index as #maniek suggests.
Is there an existing pattern I’m not aware of that applies to this
situation? what would be the best approach for this?
Your best bet in this situation might be to normalize your schema. Split the array out into a table. Add a b-tree index on the table of properties, or order the primary key so it's efficiently searchable by property_id.
CREATE TABLE demo( id integer primary key );
INSERT INTO demo (id) SELECT id FROM arrtable;
CREATE TABLE properties (
demo_id integer not null references demo(id),
property integer not null,
primary key (demo_id, property)
);
CREATE INDEX properties_property_idx ON properties(property);
You can then query the properties:
SELECT count(id)
FROM demo
WHERE NOT EXISTS (
SELECT 1 FROM properties WHERE demo.id = properties.demo_id AND property = 1
)
I expected this to be a lot faster than the original query, but it's actually much the same with the same sample data; it runs in the same 2s to 3s range as your original query. It's the same issue where searching for what is not there is much slower than searching for what is there; if we're looking for rows containing a property we can avoid the seqscan of demo and just scan properties for matching IDs directly.
Again, a seq scan on the array-containing table does the job just as well.
I think with Your current data model You are out of luck. Try to think of an algorithm that the database has to execute for Your query. There is no way it could work without sequential scanning of data.
Can You arrange the column so that it stores the inverse of data (so that the the query would be select count(id) from table where ARRAY[‘parameter value’] <# table.array_column) ? This query would use a gin/gist index.
Related
I have a table with the following columns:
ID (VARCHAR)
CUSTOMER_ID (VARCHAR)
STATUS (VARCHAR) (4 different status possible)
other not relevant columns
I try to find all the lines with customer_id = and status = two different status.
The query looks like:
SELECT *
FROM my_table
WHERE customer_id = '12345678' AND status IN ('STATUS1', 'STATUS2');
The table contains about 1 mio lines. I added two indexes on customer_id and status. The query still needs about 1 second to run.
The explain plan is:
1. Gather
2. Seq Scan on my_table
Filter: (((status)::text = ANY ('{SUBMITTED,CANCELLED}'::text[])) AND ((customer_id)::text = '12345678'::text))
I ran the 'analyze my_table' after creating the indexes. What could I do to improve the performance of this quite simple query?
You need a compound (multi-column) index to help satisfy your query.
Guessing, it seems like the most selective column (the one with the most distinct values) is customer_id. status probably has only a few distinct values. So customer_id should go first in the index. Try this.
ALTER TABLE my_table ADD INDEX customer_id_status (customer_id, status);
This creates a BTREE index. A useful mental model for such an index is an old-fashioned telephone book. It's sorted in order. You look up the first matching entry in the index, then scan it sequentially for the items you want.
You may also want to try running ANALYZE my_table; to update the statistics (about selectivity) used by the query planner to choose an appropriate index.
Pro tip Avoid SELECT * if you can. Instead name the columns you want. This can help performance a lot.
Pro tip Your question said some of your columns aren't relevant to query optimization. That's probably not true; index design is a weird art. SELECT * makes it less true.
I have a table with geometry column.
I have 2 indexes on this column:
create index idg1 on tbl using gist(geom)
create index idg2 on tbl using gist(st_geomfromewkb((geom)::bytea))
I have a lot of queries using the geom (geometry) field.
Which index is used ? (when and why)
If there are two indexes on same column (as I show here), can the select queries run slower than define just one index on column ?
The use of an index depends on how the index was defined, and how the query is invoked. If you SELECT <cols> FROM tbl WHERE geom = <some_value>, then you will use the idg1 index. If you SELECT <cols> FROM tabl WHERE st_geomfromewkb(geom) = <some_value>, then you will use the idg2 index.
A good way to know which index will be used for a particular query is to call the query with EXPLAIN (i.e., EXPLAIN SELECT <cols> FROM tbl WHERE geom = <some_value>) -- this will print out the query plan, which access methods, which indexes, which joins, etc. will be used.
For your question regarding performance, the SELECT queries could run slower because there are more indexes to consider in the query planning phase. In terms of executing a given query plan, a SELECT query will not run slower because by then the query plan has been established and the decision of which index to use has been made.
You will certainly experience performance impact upon INSERT/UPDATE/DELETE of the table, as all indexes will need to be updated with respect to the changes in the table. As such, there will be extra I/O activity on disk to propagate the changes, slowing down the database, especially at scale.
Which index is used depends on the query.
Any query that has
WHERE geom && '...'::geometry
or
WHERE st_intersects(geom, '...'::geometry)
or similar will use the first index.
The second index will only be used for queries that have the expression st_geomfromewkb((geom)::bytea) in them.
This is completely useless: it converts the geometry to EWKB format and back. You should find and rewrite all queries that have this weird construct, then you should drop that index.
Having two indexes on a single column does not slow down your queries significantly (planning will take a bit longer, but I doubt if you can measure that). You will have a performance penalty for every data modification though, which will take almost twice as long as with a single index.
We have a table with 10 million rows. We need to find first few rows with like 'user%' .
This query is fast if it matches at least 2 rows (It returns results in 0.5 sec). If it doesn't find any 2 rows matching with that criteria, it is taking at least 10 sec. 10 secs is huge for us (since we are using this auto suggestions, users will not wait for so long to see the suggestions.)
Query: select distinct(name) from user_sessions where name like 'user%' limit 2;
In the above query, the name column is of type citext and it is indexed.
Whenever you're working on performance, start by explaining your query. That'll show the the query optimizer's plan, and you can get a sense of how long it's spending doing various pieces. In particular, check for any full table scans, which mean the database is examining every row in the table.
Since the query is fast when it finds something and slow when it doesn't, it sounds like you are indeed hitting a full table scan. I believe you that it's indexed, but since you're doing a like, the standard string index can't be used efficiently. You'll want to check out varchar_pattern_ops (or text_pattern_ops, depending on the column type of name). You create that this way:
CREATE INDEX ON pattern_index_on_users_name ON users (name varchar_pattern_ops)
After creating an index, check EXPLAIN query to make sure it's being used. text_pattern_ops doesn't work with the citext extension, so in this case you'll have to index and search for lower(name) to get good case-insensitive performance:
CREATE INDEX ON pattern_index_on_users_name ON users (lower(name) text_pattern_ops)
SELECT * FROM users WHERE lower(name) like 'user%' LIMIT 2
I have a Postgres 9.4 database with a table like this:
| id | other_id | current | dn_ids | rank |
|----|----------|---------|---------------------------------------|------|
| 1 | 5 | F | {123,234,345,456,111,222,333,444,555} | 1 |
| 2 | 7 | F | {123,100,200,900,800,700,600,400,323} | 2 |
(update) I already have a couple indexes defined. Here is the CREATE TABLE syntax:
CREATE TABLE mytable (
id integer NOT NULL,
other_id integer,
rank integer,
current boolean DEFAULT false,
dn_ids integer[] DEFAULT '{}'::integer[]
);
CREATE SEQUENCE mytable_id_seq START WITH 1 INCREMENT BY 1 NO MINVALUE NO MAXVALUE CACHE 1;
ALTER TABLE ONLY mytable ALTER COLUMN id SET DEFAULT nextval('mytable_id_seq'::regclass);
ALTER TABLE ONLY mytable ADD CONSTRAINT mytable_pkey PRIMARY KEY (id);
CREATE INDEX ind_dn_ids ON mytable USING gin (dn_ids);
CREATE INDEX index_mytable_on_current ON mytable USING btree (current);
CREATE INDEX index_mytable_on_other_id ON mytable USING btree (other_id);
CREATE INDEX index_mytable_on_other_id_and_current ON mytable USING btree (other_id, current);
I need to optimize queries like this:
SELECT id, dn_ids
FROM mytable
WHERE other_id = 5 AND current = F AND NOT (ARRAY[100,200] && dn_ids)
ORDER BY rank ASC
LIMIT 500 OFFSET 1000
This query works fine, but I'm sure it could be much faster with smart indexing. There are about 250,000 rows in the table and I always have current = F as a predicate. The input array I'm comparing to the stored array will have 1-9 integers, as well. The other_id can vary. But generally, before limiting, the scan will match between 0-25,000 rows.
Here's an example EXPLAIN:
Limit (cost=36944.53..36945.78 rows=500 width=65)
-> Sort (cost=36942.03..37007.42 rows=26156 width=65)
Sort Key: rank
-> Seq Scan on mytable (cost=0.00..35431.42 rows=26156 width=65)
Filter: ((NOT current) AND (NOT ('{-1,35257,35314}'::integer[] && dn_ids)) AND (other_id = 193))
Other answers on this site and the Postgres docs suggest it's possible to add a compound index to improve performance. I already have one on [other_id, current]. I've also read in various places that indexing can improve the performance of the ORDER BY in addition to the WHERE clause.
What's the right type of compound index to use for this query? I don't care about space at all.
Does it matter much how I order the terms in the WHERE clause?
What's the right type of compound index to use for this query? I don't care about space at all.
This depends on the complete situation. Either way, the GIN index you already have is most probably superior to a GiST index in your case:
Difference between GiST and GIN index
You can combine either with integer columns once you install the additional module btree_gin (or btree_gist, respectively).
Multicolumn index on 3 fields with heterogenous data types
However, that does not cover the boolean data type, which typically doesn't make sense as index column to begin with. With just two (three incl. NULL) possible values it's not selective enough.
And a plain btree index is more efficient for integer. While a multicolumn btree index on two integer columns would certainly help, you'll have to test carefully if combining (other_id, dn_ids) in a multicolumn GIN index is worth more than it costs. Probably not. Postgres can combine multiple indexes in a bitmap index scan rather efficiently.
Finally, while indexes can be used for sorted output, this will probably not pay to apply for a query like you display (unless you select large parts of the table).
Not applicable to updated question.
Partial indexes might be an option. Other than that, you already have all the indexes you need.
I would drop the pointless index on the boolean column current completely, and the index on just rank is probably never used for this query.
Does it matter much how I order the terms in the WHERE clause?
The order of WHERE conditions is completely irrelevant.
Addendum after question update
The utility of indexes is bound to selective criteria. If more than roughly 5 % (depends on various factors) of the table are selected, a sequential scan of the whole table is typically faster than dealing with the overhead on any indexes - except for pre-sorting output, that's the one thing an index is still good for in such cases.
For a query that fetches 25,000 of 250,000 rows, indexes are mostly just for that - which gets all the more interesting if you attach a LIMIT clause. Postgres can stop fetching rows from an index once the LIMIT is satisfied.
Be aware that Postgres always needs to read OFFSET + LIMIT rows, so performance deteriorate with the sum of both.
Even with your added information, much of what's relevant is still in the dark. I am going to assume that:
Your predicate NOT (ARRAY[100,200] && dn_ids) is not very selective. Ruling out 1 to 10 ID values should typically retain the majority of rows unless you have very few distinct elements in dn_ids.
The most selective predicate is other_id = 5.
A substantial part of the rows is eliminated with NOT current.
Aside: current = F isn't valid syntax in standard Postgres. Must be NOT current or current = FALSE;
While a GIN index would be great to identify few rows with matching arrays faster than any other index type, this seems hardly relevant for your query. My best guess is this partial, multicolumn btree index:
CREATE INDEX foo ON mytable (other_id, rank, dn_ids)
WHERE NOT current;
The array column dn_ids in a btree index cannot support the && operator, I just include it to allow index-only scans and filter rows before accessing the heap (the table). May even be faster without dn_ids in the index:
CREATE INDEX foo ON mytable (other_id, rank) WHERE NOT current;
GiST indexes may become more interesting in Postgres 9.5 due to this new feature:
Allow GiST indexes to perform index-only scans (Anastasia Lubennikova,
Heikki Linnakangas, Andreas Karlsson)
Aside: current is a reserved word in standard SQL, even if it's allowed as identifier in Postgres.
Aside 2: I assume id is an actual serial column with the column default set. Just creating a sequence like you demonstrate, would do nothing.
Auto increment SQL function
Unfortunately I don't think you can combine a BTree and a GIN/GIST index into a single compound index, so the planner is going to have to choose between using the other_id index or the dn_ids index. One advantage of using other_id, as you pointed out, is that you could use a multicolumn index to improve the sort performance. The way you would do this would be
CREATE INDEX index_mytable_on_other_id_and_current
ON mytable (other_id, rank) WHERE current = F;
This is using a partial index, and will allow you to skip the sort step when you are sorting by rank and querying on other_id.
Depending on the cardinality of other_id, the only benefit of this might be the sorting. Because your plan has a LIMIT clause, it's difficult to tell. SEQ scans can be the fastest option if you're using > 1/5 of the table, especially if you're using a standard HDD instead of solid state. If you're planner insists on SEQ scanning when you know an IDX scan is faster (you've tested with enable_seqscan false, you may want to try fine tuning your random_page_cost or effective_cache_size.
Finally, I'd recomment not keeping all of these indexes. Find the ones you need, and cull the rest. Indexes cause huge performance degradation in inserts (especially mutli-column and GIN/GIST indexes).
The simplest index for your query is mytable(other_id, current). This handles the first two conditions. This would be a normal b-tree type index.
You can satisfy the array condition using a GIST index on mytable(dn_ids).
However, I don't think you can mix the different data types in one index, at least not without extensions.
I have a table briefly structured like this:
tn( id integer NOT NULL primary key DEFAULT nextval('tn_sequence'),
create_dt TIMESTAMP NOT NULL DEFAULT NOW(),
...............
deleted boolean );
create_dt is the timestamp when the row is inserted into the database.
deleted indicates that the row is or no longer useful.
And I have the following queries:
select * from tn where create_dt > ( NOW() - interval '150 seconds ) and deleted = FALSE;
select * from tn where create_dt < ( NOW() - interval '150 seconds ) and deleted = FALSE;
My question is how these query will slow down when the number of rows increase? For instance, when the number of rows exceeds 10K, 20K, or 100K, will it make a big impact on the speed? Is there any way I can optimize these queries? Note that every 5 seconds I will turn the column 'deleted' of rows which are older than 150 seconds into 'TRUE'.
The effect of table growth on performance will depend on the query plan chosen, available indexes, the selectivity of the query, and lots of other factors. EXPLAIN ANALYZE on the query might help. In short, if your query only selects a few rows and can use a simple b-tree index then it won't usually slow down tons, only a little as the index grows. On the other hand queries using complex non-indexed conditions or returning lots of rows could perform very badly indeed.
Your issue appears to mirror that in the question How should we handle rows which won't be queried once they are old in PostgreSQL?
The advice given there should apply:
Use a partial index with the condition WHERE (not deleted); or
partition on 'deleted' with constraint exclusion enabled.
For example, you might:
CREATE INDEX create_dt_when_not_deleted_idx
ON tn (create_dt)
WHERE (NOT deleted);
This includes only rows where deleted = 'f' (assuming deleted is `not null) in the index. This isn't the same as having them gone from the table completely.
Nothing changes with full table sequential scans, the deleted='t' rows must still be scanned; and
There's more I/O than if the deleted = 't' rows weren't there because any given heap page is likely to contain a mix of deleted = 't' and deleted = 'f' rows.
You can reduce the impact of the latter by CLUSTERing on an index that includes deleted. Again, this will have no effect on sequential scans. To help with sequential scans you would have to partition the table on deleted.
Pg 9.2's index only scans should (I think, haven't tested) use the partial index. When an index only scan is possible the partial index should be as fast as an index on a table containing only the deleted = 'f' rows.
Note that you'll need to keep table and index bloat under control. Ensure autovaccum runs very frequently and use a current version of PostgreSQL that doesn't need things like manually-managed free space map and has the latest, best-behaved autovacuum. I'd recommend 9.0 or above, preferably 9.1 or 9.2. Tune autovacuum to run aggressively.
When tuning and testing performance - test your queries with EXPLAIN ANALYZE, don't just guess.