How do I remove exactly 1 word after the search string?
I am able to delete the search word but not the word after that i.e. "utf8"
# echo "varchar(255) CHARACTER SET utf8,"
varchar(255) CHARACTER SET utf8,
# echo "varchar(255) CHARACTER SET utf8," | sed 's/ CHARACTER SET[^ ]* / /g'
varchar(255) utf8,
expected output:
varchar(255) ,
echo "varchar(255) CHARACTER SET utf8," | sed 's/ CHARACTER SET [[:alnum:]]\+/ /g'
This might work for you (GNU sed):
echo "varchar(255) CHARACTER SET utf8," | sed 's/ CHARACTER SET \w*/ /g'
Did you mean this?
echo "varchar(255) CHARACTER SET utf8," | sed 's/ CHARACTER SET[ a-z0-9,]*/ /g'
Output
varchar(255)
echo "varchar(255) CHARACTER SET utf8, aa" | sed 's/ CHARACTER SET.*,/ /g'
Related
I expected sed 's/\s+$//g' to strip trailing spaces
echo "'$(echo 'Magnetic ' | sed 's/\s+$//g')'"
outputs 'Magnetic ', as does
echo "'$(echo 'Magnetic ' | sed 's/[\n\s]+$//g')'"
How do I remove the trailing space with sed?
You have to escape the plus sign + because sed uses BRE, so:
echo "'$(echo 'Magnetic ' | sed 's/\s\+$//g')'"
if there's -r or -E flag, sed uses ERE instead so you don't have to escape it:
echo "'$(echo 'Magnetic ' | sed -r 's/\s+$//g')'"
I have the following script to extract text inside "reportBody" text, but I need also to decode this text from a new file to base64. How can I do this?
Here's a script:
cat $1 | tr "\n" "|" | grep -o '<reportBody>.*</reportBody>' | sed 's/\(<reportBody>\|<\/reportBody>\)//g' | sed 's/|/\n/g' | sed '/^\s*$/d' > $2
tried :
cat $1 | tr "\n" "|" | grep -o '<reportBody>.*</reportBody>' | sed 's/\(<reportBody>\|<\/reportBody>\)//g' | sed 's/|/\n/g' | sed '/^\s*$/d' | base64 -d $2 > $2
but it doesn't decode it,
Can I overwrite the same file or at least save decoded text in a new one? without calling addition modules from python etc.
Note: File contains 20k+ symbols to decode.
I am trying to replace all escaped characters \" in a string with "" but not if \" is preceded by a \
So that input such as:
\"\"\"\" would return """"""""
\"\\"\"\" would return ""\\"""""
\" would return ""
\"\" would return """"
\\"\" would return \\"""
\"\\" would return ""\\"
\\\\\\\" would return \\\\\\\"
So far I have
$ echo sed -e 's/\([^\]\)\\"/\1""/;s/^\\"/""/'
but in the case of
$ echo '\"\"\"\"\"' | sed -e 's/\([^\]\)\\"/\1""/;s/^\\"/""/'`
I am getting incorrect results.
Any help would be appreciated.
This might work for you (GNU sed):
sed 's/\\\\"/\n/g;s/\\"/""/g;s/\n/\\\\"/g' file
Replace all occurances of the string you want untouched by something else (\n is a good choice), replace the string you want changed globally, reinstate the first set of strings.
How about this:
#!/bin/bash
function myreplace {
echo "$1" | sed -e "s/[\\]\"/MYDUMMY/g" \
-e 's/\\MYDUMMY/\\\\"/g' \
-e 's/MYDUMMY/""/g'
}
myreplace '\"\"\"\"'
myreplace '\"\\"\"\"'
myreplace '\"'
myreplace '\"\"'
myreplace '\\"\"'
myreplace '\"\\"'
myreplace '\\\\\\\"'
Executing the script above results in:
""""""""
""\\"""""
""
""""
\\"""
""\\"
\\\\\\\"
Using a sed loop will allow not having to pick a unique replacement string for an unknown dataset.
sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
$ echo '\"\"\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g;t inner'
""""""""
$ echo '\"\\"\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""\\"""""
$ echo '\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""
$ echo '\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""""
$ echo '\\"\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
\\"""
$ echo '\"\\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
""\\"
$ echo '\\\\\\\"' | sed -e 's/^\\"/""/;:inner; s/\([^\]\)[\]"/\1""/g; t inner'
\\\\\\\"
I'm using this code to get all titles from urls with http://something.txt:
#!/usr/bin/perl -w
$output = `cat source.html | grep -o '<a .*href=.*>' | grep -E 'txt' | sed -e 's/<a /\n<a /g' | sed -e 's/<a .*title="//' | cut -f1 -d '"'`;
print("$output");
When i run this on perl i get the error:
sed: -e expression #1, char 6: unterminated `s' command
The error is related with this portion of code:
sed -e 's/<a /\n<a /g'
In backquotes, Perl uses the same rules as in double quotes. Therefore, \n corresponds to a newline; you have to backslash the backslash to pass literal \ to the shell:
`sed -e 's/<a /\\n<a /g'`
I have a example cut down from a log file.
112 172.172.172.1#50912 (ssl.bing.com):
I would like some how to remove the # and numbers after and (): from the url.
Would like the result.
112 172.172.172.1 ssl.bing.com
Here is the sed oneliner I have been working on.
cat newdns.log | sed -e 's/.*query: //' | cut -f 1 -d' ' | sort | uniq -c | sort -k2 > old.log
Thanks
Using sed, you could say:
sed 's/#[0-9]*//;s/(\(.*\)):$/\1/' filename
or, in a single substitution:
sed 's/#[0-9]* *(\(.*\)):$/ \1/' filename
Another sed:
sed -r 's/#[^ ]+|[():]//g'
$ echo '112 172.172.172.1#50912 (ssl.bing.com):' | sed -r 's/#[^ ]+|[():]//g'
112 172.172.172.1 ssl.bing.com