I have a string with some font size & added that text on UIView using drawInRect method. I am able to calculate the approx Y position of the string by calculating its height, but I want to know the X position as well.
Can I calculate the x location of string where my string gets end.
string length & font size can vary.
Thanks
Perhaps calling CGContextGetTextPosition after drawing the string will give you the coordinate you need.
For more information, read the “Text” chapter of Quartz 2D Programming Guide.
Related
Following the idea from SouthernYankee65 (many thanks again) (see: Drawing Text to a CGContext for Quartz PDF not working) I'd like to know, if there's a way to get the range of text, that fits into the calculated frame
let frameSize = CTFramesetterSuggestFrameSizeWithConstraints(frameSetter, CFRangeMake(0, attributedString.string.count), nil, rect.size, nil)
might be the answer, because the docs say for the last option:
fitRange: On return, contains the range of the string that actually fit in the constrained size.
How do I use this? When I know the range of text, that fits into my frame, I can calc the number of frames needed to display the whole string and therefor I can create a paginated pdf.
When I call setFixedHeight() on a PdfPCell, and add more text than fits in the given height, iText seems to print the prefix of the string which fits.
Can I control this clipping algorithm? For example:
Print a suffix of the string rather than a prefix.
Mark a substring of the string as not to be removed. This is with footnote references. If I add text saying "Hello World [1]", the [1] is a reference to a footnote and should not be removed. It's okay to remove the other characters of the string, like "World".
When there are multiple words in the string, iText seems to eliminate a word that doesn't fit, while I would like it partially printed. That is, if the string is "Hello World", and the cell has room only for "Hello Wo...", I would like that to be printed, rather than just "Hello", as iText prints.
Rather than printing characters in their entirety, print only part of them. Imagine printing the text to a PNG and chopping off the top and/or bottom part of the PNG to fit it in the space available. For example, notice that the top line and the bottom line are partially clipped here:
Are any of these possible? Does iText give me any control over how text is clipped? Thanks.
This is with reference to iText 2.1.6.
I have written a proof of concept, ClipCenterCellContent, where we try to fit the text "D2 is a cell with more content than we can fit into the cell." in a cell that is too small.
Just like in your other question ( iText -- How do I get the rendered dimensions of text? ), we add the content using a cell event, but we now add it twice: once in simulation mode (to find out how much space is needed vertically) and once for real (using an offset).
This adds the content in simulation mode (we use the width of the cell and an arbitrary height):
PdfContentByte canvas = canvases[PdfPTable.TEXTCANVAS];
ColumnText ct = new ColumnText(canvas);
ct.setSimpleColumn(new Rectangle(0, 0, position.getWidth(), -1000));
ct.addElement(content);
ct.go(true);
float spaceneeded = 0 - ct.getYLine();
System.out.println(String.format("The content requires %s pt whereas the height is %s pt.", spaceneeded, position.getHeight()));
We now know the needed height and we can add the content for real using an offset:
float offset = (position.getHeight() - spaceneeded) / 2;
System.out.println(String.format("The difference is %s pt; we'll need an offset of %s pt.", -2f * offset, offset));
PdfTemplate tmp = canvas.createTemplate(position.getWidth(), position.getHeight());
ct = new ColumnText(tmp);
ct.setSimpleColumn(0, offset, position.getWidth(), offset + spaceneeded);
ct.addElement(content);
ct.go();
canvas.addTemplate(tmp, position.getLeft(), position.getBottom());
In this case, I used a PdfTemplate to clip the content.
I also have answers to your other questions, but I don't have the time to answer them right now.
For straight Text box clipping, I adapted the C# code given here
http://itextsharp.10939.n7.nabble.com/Limiting-Text-Width-using-PdfContentByte-td2481.html
to the Java code below. The clipping area ends up outside this rectangle, so you can still draw a rectangle on the same exact coordinates.
cb.saveState();
cb.rectangle(left,top,width,height);
cb.clip();
cb.newPath();
// perform clipped output here
cb.restoreState();
I used a try/finally to ensure restoreState() was called.
When i extract text using itextsharp, i will get x and y coordinate of text. By using these 2 coordinates if i convert text from pdf to html based on x y position the text position chnages . to get x ,y coordinates i used
Vector curBaseline = renderInfo.GetBaseline().GetStartPoint();
float x=curBaseline[Vector.I1];
float y= curBaseline[Vector.I2];
for example : when i extract text using above method say x=42 and y=659;
" < span style=left:{0}px;bottom:{1}px;position:relative;\">",curBaseline[Vector.I1],curBaseline[Vector.I2]); the position changes . can you help me how to set position of text default as pdf.?????
Posted as answer...
If i recall correctly, PDF uses a coordinate system which starts in the left corner at the BOTTOM of the page, not at the Top. So every coordiante is wrong, when you use it directly in html. You will have to convert the values.
Your pdf document should have something like document.actualheight, simply subtract your value from that....
How does one use the CGRectIntegral function? I understand it's purpose.
The documentation isn't clear on it's exact use.
CGRectIntegral to convert any decimal values to their integer equivalents
see image may be you can understand
How do I fix it?
frame = CGRectIntegral(frame);
-OR-
myTextView.frame = CGRectIntegral(myTextView.frame);
see this for more information of CGRectIntegral
CGRectIntegral Method is used to create integer rect . I mean to say suppose if you calculate frame in app you may get frames value in float.
Setting float value as frame to some UIElement like UILabel would make the text looks blur. To avoid that, we use CGRectIntegral.Please look at the example below,
NSLog(#"%#",NSStringFromCGRect( CGRectIntegral(CGRectMake(0, 15.6, 16.1, 20.2))));
This will print, {0,15},{17,21}.
This explanation is found in the header file.
/* Expand `rect' to the smallest rect containing it with integral origin and
size. */
One particular usage is to fix frames that do not align perfectly with on-screen pixels.
See this question: UITextField blurred text
If a label or textfield has a frame that isn't pixel-aligned when rendered to the screen, the text will appear blurred. This can happen if you calculate the frame using division (for example to center it in a parent view).
CGRectIntegral will remove the fractional part of the frame, fixing this problem. Note however that with retina displays a .5 frame value is pixel aligned, but CGRectIntgral will still remove the fractional part.
I am creating a Microsoft Word document using the OpenXml library. Most of what I need is already working correctly. However, I can't for the life of me find the following bit of information.
I'm displaying an image in an anchor, which causes text to wrap around the image. I used WrapSquare but this seems to affect the last line of the previous paragraph as shown in the image below. The image is anchored to the second paragraph but causes the last line of the first paragraph to also indent around the image.
Word Screenshot http://www.softcircuits.com/Client/Word.jpg
Experimenting within Word, I can make the text wrap how I want by changing the wrapping to WrapTight. However, this requires a WrapPolygon with several coordinates. And I can't find any way to determine the polygon coordinates so that they match the size of the image, which is in pixels.
The documentation doesn't even seem to indicate what units are used for these coordinates, let alone how to calculate them from pixels. I can only assume the calculation would involve a DPI value, but I have no idea how to determine what DPI will be used when the user eventually loads the document into Word.
I would also be satisfied if someone can explain why the issues described above is happening in the first place. I can shift the image down and the previous paragraph is no longer affected. But why is this necessary? (The Distance from text setting for both Left and Top is 0".)
The WrapPolygon element has two possible child elements of LineTo and StartPoint that each take a x and y coordinate. According to 2.1.1331 Part 1 Section 20.4.2.9, lineTo (Wrapping Polygon Line End Position) and 2.1.1334 Part 1 Section 20.4.2.14, start (Wrapping Polygon Start) found in the [MS-OI29500: Microsoft Office Implementation Information for ISO/IEC-29500 Standard Compliance]:
The standard states that the x and y attributes are represented in
EMUs. Office interprets the x and y attributes in a fixed coordinate
space of 21600x21600.
As far as converting pixels to EMUs (English Metric Units), take a look at this blog post for an example.
I finally resolved this. Despite what the standard says, the WrapPolygon coordinates are not EMUs (English Metric Units). The coordinates are relative to the fixed coordinate space (21600 x 21600, as mentioned in the quote provided by amurra).
More specifically, this means 0,0 is at the top, left corner of the image, and 21600,21600 is at the bottom, right corner of the image. This is the case no matter what the size of the image is. Coordinates greater than 21600 extend outside the image.
According to this article, "The 21600 value is a legacy artifact from the drawing layer of early versions of the Microsoft Office."