NSString *string = [myString stringByReplacingOccurrencesOfString:#"<wow>" withString:someString];
I have this code. Now suppose my app's user enters two different strings I want to replace with two different other strings, how do I achieve that? I don't care if it uses private APIs, i'm developing for the jailbroken platform. My user is going to either enter or or . I want to replace any occurrences of those strings with their respective to-be-replaced-with strings :)
Thanks in advance :P
Both dasblinkenlight’s and Matthias’s answers will work, but they both result in the creation of a couple of intermediate NSStrings; that’s not really a problem if you’re not doing this operation often, but a better approach would look like this.
NSMutableString *myStringMut = [[myString mutableCopy] autorelease];
[myStringMut replaceOccurrencesOfString:#"a" withString:somethingElse];
[myStringMut replaceOccurrencesOfString:#"b" withString:somethingElseElse];
// etc.
You can then use myStringMut as you would’ve used myString, since NSMutableString is an NSString subclass.
The simplest solution is running stringByReplacingOccurrencesOfString twice:
NSString *string = [[myString
stringByReplacingOccurrencesOfString:#"<wow>" withString:someString1]
stringByReplacingOccurrencesOfString:#"<boo>" withString:someString2];
I would just run the string replacing method again
NSString *string = [myString stringByReplacingOccurrencesOfString:#"foo" withString:#"String 1"];
string = [string stringByReplacingOccurrencesOfString:#"bar" withString:#"String 2"];
This works well for me in Swift 3.1
let str = "hi hello hey"
var replacedStr = (str as NSString).replacingOccurrences(of: "hi", with: "Hi")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hello", with: "Hello")
replacedStr = (replacedStr as NSString).replacingOccurrences(of: "hey", with: "Hey")
print(replacedStr) // Hi Hello Hey
Related
I code only been a short time and started with Swift .
Can me somebody convert the String in Swift?
Or can me give Tipps?
The main problem lies the selectedSegmentIndex?
NSString *response = [NSString stringWithFormat:#"P%ld%#", tag , button.selectedSegmentIndex?#"L" : #"H"];
greetings
The above code is not C, but Objective-C. If you are not interested in learning about Objective-C at this time and do not need explanation of the above code, this should work:
var response = String(format: "P%ld%#", tag, button.selectedSegmentIndex == 0 ? "L" : "H")
I have an output string in this format .
I need to format the string such that i can display the URL separately and my Content, the description separately. Is there any functions , so i can format them easily ?
The code :
NSLog(#"Description %#", string);
The OUTPUT String:
2013-07-28 11:13:59.083 RSSreader[4915:c07] Description
http://www.apple.com/pr/library/2013/07/23Apple-Reports-Third-Quarter-Results.html?sr=hotnews.rss
Apple today announced financial results for its fiscal 2013 third quarter ended
June 29, 2013. The Company posted quarterly revenue of $35.3 billion and quarterly
net profit of $6.9 billion, or $7.47 per diluted share.
Apple sold 31.2 million iPhones, which set a June quarter record.
You should extract URL from string, then display it in formatted way.
A simple way to extracting URL is regular expressions (RegEX).
After extracting URL you can replace it with nothing:
str = [str stringByReplacingOccurrencesOfString:extractedURL
withString:#""];
You can use this :
https://stackoverflow.com/a/9587987/305135
If description string separated by line break (\n), you can do this:
NSArray *items = [yourString componentsSeparatedByString:#"\n"];
Regex is a good idea.
But there is a default way of detecting URLs within a String in Objective C, NSDataDetector.
NSDataDetector internally uses Regex.
NSString *aString = #"YOUR STRING WITH URLs GOES HERE"
NSDataDetector *aDetector = [NSDataDetector dataDetectorWithTypes:NSTextCheckingTypeLink error:nil];
NSArray *theMatches = [aDetector matchesInString:aString options:0 range:NSMakeRange(0, [aString length])];
for (int anIndex = 0; anIndex < [theMatches count]; anIndex++) {
// If needed, Save this URL for Future Use.
NSString *anURLString = [[[theMatches objectAtIndex:anIndex] URL] absoluteString];
// Replace the Url with Empty String
aTitle = [aTitle stringByReplacingOccurrencesOfString:anURLString withString:#""];
}
How can I construct a regular expression which matches an literal " but only if it is not preceded by the escape slash namely \
I have a NSMutableString str which prints the following on NSLog. The String is received from a server online.
"Hi, check out \"this book \". Its cool"
I want to change it such that it prints the following on NSLog.
Hi, check out "this book ". Its cool
I was originally using replaceOccurencesOfString ""\" with "". But then it will do the following:
Hi, check out \this book \. Its cool
So, I concluded I need the above regular expression to match only " but not \" and then replace only those double quotes.
thanks
mbh
[^\\]\"
[^m] means does not match m
Not sure how this might translate to whatever is supported in the iOS apis, but, if they support anchoring (which I think all regex engines should), you're describing something like
(^|[^\])"
That is, match :
either the beginning of the string ^ or any character that's not
\ followed by:
the " character
If you want to do any sort of replacement, you'll have to grab the first (and only) group in the regex (that is the parenthetically grouped part of the expression) and use it in the replacement. Often this value labeled as $1 or \1 or something like that in your replacement string.
If the regex engine is PCRE based, of course you could put the grouped expression in a lookbehind so you wouldn't need to capture and save the capture in the replacement.
Not sure about regex, a simpler solution is,
NSString *str = #"\"Hi, check out \\\"this book \\\". Its cool\"";
NSLog(#"string before modification = %#", str);
str = [str stringByReplacingOccurrencesOfString:#"\\\"" withString:#"#$%$#"];
str = [str stringByReplacingOccurrencesOfString:#"\"" withString:#""];
str = [str stringByReplacingOccurrencesOfString:#"#$%$#" withString:#"\\\""];//assuming that the chances of having '#$%$#' in your string is zero, or else use more complicated word
NSLog(#"string after modification = %#", str);
Output:
string before modification = "Hi, check out \"this book \". Its cool"
string after modification = Hi, check out \"this book \". Its cool
Regex: [^\"].*[^\"]. which gives, Hi, check out \"this book \". Its cool
It looks like it's a JSON string? Perhaps created using json_encode() in PHP on the server? You should use the proper JSON parser in iOS. Don't use regex as you will run into bugs.
// fetch the data, eg this might return "Hi, check out \"this book \". Its cool"
NSData *data = [NSData dataWithContentsOfURL:#"http://example.com/foobar/"];
// decode the JSON string
NSError *error;
NSString *responseString = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:&error];
// check if it worked or not
if (!responseString || ![responseString isKindOfClass:[NSString class]]) {
NSLog(#"failed to decode server response. error: %#", error);
return;
}
// print it out
NSLog(#"decoded response: %#", responseString);
The output will be:
Hi, check out "this book ". Its cool
Note: the JSON decoding API accepts an NSData object, not an NSString object. I'm assuming you also have a data object and are converting it to a string at some point... but if you're not, you can convert NSString to NSData using:
NSString *responseString = [NSJSONSerialization JSONObjectWithData:[myString dataUsingEncoding:NSUTF8StringEncoding] options:NSJSONReadingAllowFragments error:&error];
More details about JSON can be found at:
http://www.json.org
http://developer.apple.com/library/ios/#documentation/Foundation/Reference/NSJSONSerialization_Class/Reference/Reference.html
How do I use NSLocalizedString in this case when I have a header where I define a few parameters, say:
#define appKey #"appKey1 is: %#"
I think I know that my Localizable.strings should look like that:
"blabla" = "appKey1 is: %#"
but how do I use NSLocalizedString? I read that I need to use stringWithFormat, but not sure how...
thanks!
You would define your constant as:
#define appKey NSLocalizedString(#"appKey1 is: %#", #"appkey constant")
Then it should get picked up by the genstrings tool in the usual way.
In the strings file it would then come out like this:
/* appkey constant */
"appKey1 is: %#" = "appKey1 is: %#";
And you would translate just the right hand side.
String literals are acceptable in NSLocalizedStrings. What you need to do is something like
#define appKey NSLocalizedString(BlahBlah , comments);
"BlahBlah" = "appKey1 is: %#";
(Be sure to end your lines with a semi-colon in Localizable.strings, or it will end up being corrupted).
This is how you would do it normally,
NSString * myString = [NSString stringWithFormat:#"appKey1 is: %#",yourAppKeyString];
Since you have it defined you can use it like so
NSString * myString = [NSString stringWithFormat:appKey,yourAppKeyString];
Either case both would fill your myString like so
yourAppKeyString = #"keyString";
myString = #"appKey1 is: keyString";
NSString * myString = [NSString stringWithFormat: NSLocalizedString(#"appKey", #""),yourAppKeyString];
I got the problem that the if-statement doesn't work. After the first code line the variable contains the value "(null)", because the user who picked the contact from his iphone address book doesn't set the country key for this contact, so far so good.
but if I check the variable, it won't be true, but the value is certainly "(null)"... does someone have an idea?
NSString *country = [NSString [the dict objectForKey:(NSString *)kABPersonAddressCountryKey]];
if(country == #"(null)")
{
country = #"";
}
thanks in advance
sean
The correct expression would be:
if (country == nil)
which can be further shortened to:
if (!country)
And if you really want to test equality with the #"(null)" string, you should use the isEqual: method or isEqualToString:
if ([country isEqualToString:#"(null)"])
When you compare using the == operator, you are comparing object addresses, not their contents:
NSString *foo1 = [NSString stringWithString:#"foo"];
NSString *foo2 = [NSString stringWithString:#"foo"];
NSAssert(foo1 != foo2, #"The addresses are different.");
NSAssert([foo1 isEqual:foo2], #"But the contents are same.");
NSAssert([foo1 isEqualToString:foo2], #"True again, faster than isEqual:.");
That was a great answer I didn't know there was all those different ways of checking for nil or null string.