In my app to show text in CATextLayer(change colors for characters),using NSMutableAttributedString to change colors,i want remove special characters in NSMutableAttributedString to show PopUp view, but didn't know how to remove special characters, to help to solve problem
i want like this type of o/p
"code" to code //in NSMutableAttributedString, not in NSString
to remove such characters you simply write something like this:
NSMutableString* mutableString = ...;
[mutableString replaceOccurrencesOfString:#"\"" withString:#"" options:0 range:NSMakeRange(0, mutableString.length)];
Note that symbol " is written as \" - this one is called an escape sequence.
Here is a list of such special characters in C - http://msdn.microsoft.com/en-us/library/h21280bw(v=vs.80).aspx
Try this...This may help you.
NSMutableString *unfilteredString = #"!##$%^&*()_+|abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890";
NSCharacterSet *notAllowedChars = [[NSCharacterSet characterSetWithCharactersInString:#"abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890"] invertedSet];
NSMutableString *resultString = [[unfilteredString componentsSeparatedByCharactersInSet:notAllowedChars] componentsJoinedByString:#""];
NSLog (#"Result: %#", resultString);
You can give try to this may it fits in your code:
NSMutableString *mutableStrng = [NSMutableString stringWithCapacity:1000];
[mutableStrng setString:#"my name is i#pho#ne"];
[mutableStrng replaceOccurrencesOfString:#"#" withString:#"" options:0 range:NSMakeRange(0,
mutableStrng.length)];
NSMutableAttributedString *mutableAtrString = [[NSMutableAttributedString
alloc]initWithString:mutableStrng];
Related
So I am trying to parse a string that has the following format:
baz#marroon#red#blue #big#cat#dog
or, it can also be separated by spaces:
baz #marroon #red #blue #big #cat #dog
and here's how I am doing it now:
- (void) parseTagsInComment:(NSString *) comment
{
if ([comment length] > 0){
NSArray * stringArray = [comment componentsSeparatedByString:#" "];
for (NSString * word in stringArray){
}
}
}
I've got the components separated by space working, but what if it has no space.. how do I iterate through these words? I was thinking of using regex.. but I have no idea on how to write such regex in objective-C. Any idea, for a regex that would cover both of these cases?
Here's my first attempt:
NSError * error;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"(#|#)\\S+" options:NSRegularExpressionCaseInsensitive error:&error];
NSArray* wordArray = [regex matchesInString:comment
options:0 range:NSMakeRange(0, [comment length])];
for (NSString * word in wordArray){
}
Which doesn't work.. I think my regex is wrong.
Here is a way to do it using NSScanner that puts the separated strings and a string representation of their ranges into an array (this assumes that your original string started with a # -- if it doesn't and you need it to, then just prepend the hash to the string at the start).
NSMutableArray *array = [NSMutableArray array];
NSString *str = #"#baz#marroon#red#blue #big#cat#dog";
NSScanner *scanner = [NSScanner scannerWithString:str];
NSCharacterSet *searchSet = [NSCharacterSet characterSetWithCharactersInString:#"##"];
NSString *outputString;
while (![scanner isAtEnd]) {
[scanner scanUpToCharactersFromSet:searchSet intoString:nil];
[scanner scanCharactersFromSet:searchSet intoString:&outputString];
NSString *symbol = [outputString copy];
[scanner scanUpToCharactersFromSet:searchSet intoString:&outputString];
NSString *wholePiece = [[symbol stringByAppendingString:outputString]stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
NSString *rangeString = NSStringFromRange([str rangeOfString:wholePiece]);
[array addObject:wholePiece];
[array addObject:rangeString];
}
NSLog(#"%#",array);
I think the regular expression you really want is [##]?\\w+. It will find groups of letters optionally preceded by an # or #. Your expression wouldn't work because it looks for any non-space character, which includes # and #. (Depending on what can be in the "words," you might want something more or less specific than \w, but it isn't clear from the question.)
If you need the ranges, then NSRegularExpression probably works well:
NSString *comment = #"#baz#marroon#red#blue #big#cat#dog";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:#"[##]\\w+" options:0 error:nil];
NSArray* wordArray = [regex matchesInString:comment
options:0
range:NSMakeRange(0, [comment length])];
for (NSTextCheckingResult *result in wordArray)
NSLog(#"%#", [comment substringWithRange:result.range]);
Or, [##][a-zA-z]+ works if you're ok with ASCII alpha words only.
I have a string that contains words with consonants and vowels. How can I extract only consonants from the string?
NSString *str = #"consonants.";
Result must be:
cnsnnts
You could make a character set with all the vowels (#"aeiouy")
+ (id)characterSetWithCharactersInString:(NSString *)aString
then use the
- (NSString *)stringByTrimmingCharactersInSet:(NSCharacterSet *)set
method.
EDIT: This will only remove vowels at the beginning and end of the string as pointed out in the other post, what you could do instead is use
- (NSArray *)componentsSeparatedByCharactersInSet:(NSCharacterSet *)separator
then stick the components back together. You may also need to include capitalized versions of the vowels in the set, and if you want to also deal with accents (à á è è ê ì etc...) you'll probably have to include that also.
Unfortunately stringByTrimmingCharactersInSet wont work as it only trim leading and ending characters, but you could try using a regular expression and substitution like this:
[[NSRegularExpression
regularExpressionWithPattern:#"[^bcdefghjklmnpqrstvwx]"
options:NSRegularExpressionCaseInsensitive
error:NULL]
stringByReplacingMatchesInString:str
options:0
range:NSMakeRange(0, [str length])
withTemplate:#""]
You probably want to tune the regex and options for your needs.
Possible, for sure not-optimal, solution. I'm printing intermediate results for your learning. Take care of memory allocation (I didn't care). Hopefully someone will send you a better solution, but you can copy and paste this for the moment.
NSString *test = #"Try to get all consonants";
NSMutableString *found = [[NSMutableString alloc] init];
NSInteger loc = 0;
NSCharacterSet *consonants = [NSCharacterSet characterSetWithCharactersInString:#"bcdfghjklmnpqrstvwxyz"];
while(loc!=NSNotFound && loc<[test length]) {
NSRange r = [[test lowercaseString] rangeOfCharacterFromSet:consonants options:0 range:NSMakeRange(loc, [test length]-loc)];
if(r.location!=NSNotFound) {
NSString *temp = [test substringWithRange:r];
NSLog(#"Range: %# Temp: %#",NSStringFromRange(r), temp);
[found appendString:temp];
loc=r.location+r.length;
} else {
loc=NSNotFound;
}
}
NSLog(#"Found: %#",found);
Here is a NSString category that does the job:
- (NSString *)consonants
{
NSString *result = [NSString stringWithString:self];
NSCharacterSet *characterSet = [NSCharacterSet characterSetWithCharactersInString:#"aeiou"];
while(1)
{
NSRange range = [result rangeOfCharacterFromSet:characterSet options:NSCaseInsensitiveSearch];
if(range.location == NSNotFound)
break;
result = [result stringByReplacingCharactersInRange:range withString:#""];
}
return result;
}
I have a string say "Allentown, pa"
How to remove the white space in between , and pa using objective c?
This will remove all space from myString.
NSString *newString = [myString stringByReplacingOccurrencesOfString:#" " withString:#""];
Here is a proper and documented way of removing white spaces from your string.
whitespaceCharacterSet Apple Documentation for iOS says:
Returns a character set containing only the in-line whitespace characters space (U+0020) and tab (U+0009).
+ (id)whitespaceCharacterSet
Return Value
A character set containing only the in-line whitespace characters space (U+0020) and tab (U+0009).
Discussion
This set doesn’t contain the newline or carriage return characters.
Availability
Available in iOS 2.0 and later.
You can use this documented way:
[yourString stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
Hope this helps you.
If you need any more help then please let me know on this.
Probably the solution in one of the answers in Collapse sequences of white space into a single character and trim string:
NSString *whitespaceString = #" String with whitespaces ";
NSString *trimmedString = [whitespaceString stringByReplacingOccurrencesOfString:#" " withString:#""];
If you want to white-space and new-line character as well then use "whitespaceAndNewlineCharacterSet" instead of "whitespaceCharacterSet"
NSCharacterSet *whitespace = [NSCharacterSet whitespaceCharacterSet];
NSString *trimmedString = [temp.text stringByTrimmingCharactersInSet:whitespace];
NSLog(#"Value of the text field is %#",trimmedString);
myStr = [myStr stringByReplacingOccurrencesOfString:#" " withString:#""];
NSString *sample = #" string with whitespaces";
NSString *escapeWhiteSpaces = [sample stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
- (NSString *)removeWhitespaces {
return [[self componentsSeparatedByCharactersInSet:
[NSCharacterSet whitespaceCharacterSet]]
componentsJoinedByString:#""];
}
In my case NSString was added Zero Width Space(i i used some library). so solution worked for me.
NSMutableString *newString=[[newString stringByReplacingOccurrencesOfString:#"\u200B" withString:#""] mutableCopy];
#"\u200B" is Zero width space character value.
Here is the proper way to remove extra whitespaces from string which is coming in between.
NSString *yourString = #"Allentown, pa";
NSCharacterSet *whitespaces = [NSCharacterSet whitespaceCharacterSet];
NSPredicate *noEmptyStrings = [NSPredicate predicateWithFormat:#"SELF != ''"];
NSArray *parts = [yourString componentsSeparatedByCharactersInSet:whitespaces];
NSArray *filteredArray = [parts filteredArrayUsingPredicate:noEmptyStrings];
yourString = [filteredArray componentsJoinedByString:#" "];
you can use remove function to remove any substring from the string
- (NSString*)remove:(NSString*)textToRemove fromString:(NSString*)input {
return [input stringByReplacingOccurrencesOfString:textToRemove withString:#""];
}
I have tried all the solutions here, none of them could remove the whitespace generated by the Chinese PinYin Input method.
After some debugging, I found this working:
NSString *newString = [myString stringByReplacingOccurrencesOfString:#"\342\200\206" withString:#""];
I have googled what the '\342\200\206' is, but failed.
Whatever, it works for me.
Hi there is the swift version of the solution with extension :
extension String{
func deleteSpaces() -> String{
return self.stringByReplacingOccurrencesOfString(" ", withString: "")
}
}
And Just call
(yourString as! String).deleteSpaces()
Swift 3:
var word: String = "Hello world"
let removeWhiteSpace = word.stringByRemovingWhitespaces
word = "Helloworld"
I want simply replace all occourrencies of "+" with a blank " " char...
I tried some sample listed here, also used NSSMutableString, but the program crash...
what's the best way to replace a char from another??
thanks
If you want to replace with a mutable string (NSMutableString) in-place:
[theMutableString replaceOccurrencesOfString:#"+"
withString:#" "
options:0
range:NSMakeRange(0, [theMutableString length])]
If you want to create a new immutable string (NSString):
NSString* newString = [theString stringByReplacingOccurrencesOfString:#"+"
withString:#" "];
NSString *firstString = #"I'm a noob at Objective-C", *finalString;
finalString = [[firstString stringByReplacingOccurrencesOfString:#"O" withString:#"0"] stringByReplacingOccurrencesOfString:#"o" withString:#"0"];
Got the code from here!
How can I remove the first \n character from an NSString?
Edit: Just to clarify, what I would like to do is:
If the first line of the string contains a \n character, delete it else do nothing.
ie: If the string is like this:
#"\nhello, this is the first line\nthis is the second line"
and opposed to a string that does not contain a newline in the first line:
#"hello, this is the first line\nthis is the second line."
I hope that makes it more clear.
[string stringByTrimmingCharactersInSet:[NSCharacterSet newlineCharacterSet]]
will trim your string from any kind of newlines, if that's what you want.
[string stringByReplacingOccurrencesOfString:#"\n" withString:#"" options:0 range:NSMakeRange(0, 1)]
will do exactly what you ask and remove newline if it's the first character in the string
This should do the trick:
NSString * ReplaceFirstNewLine(NSString * original)
{
NSMutableString * newString = [NSMutableString stringWithString:original];
NSRange foundRange = [original rangeOfString:#"\n"];
if (foundRange.location != NSNotFound)
{
[newString replaceCharactersInRange:foundRange
withString:#""];
}
return [[newString retain] autorelease];
}
Rather than creating an NSMutableString and using a few retain/release calls, you can use only the original string and simplify the code by using the following instead: (requires 10.5+)
NSRange foundRange = [original rangeOfString:#"\n"];
if (foundRange.location != NSNotFound)
[original stringByReplacingOccurrencesOfString:#"\n"
withString:#""
options:0
range:foundRange];
(See -stringByReplacingOccurrencesOfString:withString:options:range: for details.)
The result of the last call method call can even be safely assigned back to original IF you autorelease what's there first so you don't leak the memory.