Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 8 years ago.
Improve this question
I am trying to learn about VPN using OSX and have a question I cannot find the answer to. Any help will be appreciated.
I have an office machine running OSX server 10.7. I set up VPN on it today and set up my laptop (running OSX 10.8) to access it. I am able to connect, but have a problem accessing a machine by its IP address on the office network. I suspect I have and issue because both my networks use the block 10.0.1.xx. Before I change one of my networks IP range I wanted to ask if this is the actual problem or if there is an easier way to resolve this. How would my laptop know that 10.0.1.127 is on the office network and it needs to look over the VPN connection?
Thanks for any help. Trying to wrap my brain around this whole VPN thing.
Thom
You are correct, having both address blocks set to the same address space is very confusing for your workstation. The actual problem is more gateway related, as your machine now has two gateways with (likely) the same IP address.
There is no good way to get that to work using the same IP range on both the local and remote networks.
Note that I said "Good way" I'm certain it's possible, just more trouble than it's worth.
Related
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 2 years ago.
Improve this question
i was trying to scan ports with Nmap trough proxychains4 in order to be anonymous while scanning , but after i used wireshark to capture to traffics , i saw that my private IP didn't change and still the same
You capture traffic on your local machine so it should have your IP address as a source. Traffic should go from your IP to the proxy server, then from the proxy server to the target (it's where the IP address is changed). The problem exists only if the traffic goes directly to the target.
A part of the Nmap functionality is unavailable with proxychains. Here's a good link about it: https://www.1337pwn.com/using-nmap-with-proxychains-in-kali-linux/.
Also, some of the Nmap scan types are "aggressive" so it means you should have permission from the target. To better understand how Nmap works and have legal hands-on experience, use hacking platforms like TryHackMe, HackTheBox, or similar.
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 2 years ago.
Improve this question
For an ethernet connection between 2 points which will be used as point to point communication (for embedded devices). Is internet connection, hubs or switches are really necessary? Or can we still send and receive data from one MCU to another one by using ethernet without using any internet connection, hubs or switches?
There's certainly no need for an Internet connection.
If you want to connect two computers together directly, then you will need to use a crossover cable rather than a patch cable unless the devices you are using support auto MDI-X.
Putting a cheap hub between them will probably be simpler.
No, they are not necessary. We ofen do this between either two of "product board", "FPGA board", and "PC" when debugging ethernet Tx/Rx issues.
Closed. This question is not about programming or software development. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 5 months ago.
Improve this question
When i launching my minecraft server everything is going well at the start but when world is generating... well it is not generating completely. It says around 80-90% and thats it, server is launched but because world is not generated completely i cant join (my friends cant too). I've tried downgrading java, creating the new world, switching port or even the IP. error while joining to server ; console look
Do you have legitimate Mojang Account? If not, the server will not let you join. I have a cracked version of Minecraft (Tlauncher) and it will not let me join most servers. If you have a cracked account, go in the server properties. There should be an option for "cracked" or "online mode." Once you get there, turn on "cracked" or turn off "online mode." Note: Online mode is just a way to authenticate accounts. It does not affect whether or not your server can run online. If you have a legitimate PAID Mojang account, then try checking the IP address on your computer and make sure you type in the IPv4 address (on Windows, you can find this by typing ipconfig into CMD).
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 6 years ago.
Improve this question
When I do socket programming, I found at least one computer has to have a public IP to make the connection (or reverse connection). I'm wondering if it is possible for 2 computers that are behind different routers to connect to each other (and they don't have port forwarding and don't use proxy)? If that's not possible, how bit torrent works for computers that are behind routers? Does it mean the computers that are behind different routers cannot share among each other?
Bittorent clients are using a protocol named uPNP, that tells router to redirect specified port in bittorrent client to computer that runs client.
Here is more information about protocol.
https://en.wikipedia.org/wiki/Universal_Plug_and_Play
Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers.
This question does not appear to be about a specific programming problem, a software algorithm, or software tools primarily used by programmers. If you believe the question would be on-topic on another Stack Exchange site, you can leave a comment to explain where the question may be able to be answered.
Closed 8 years ago.
Improve this question
Hi this will be an easy question.
Ftp, as an example, works on ports 20, 21. How many different people can connect to the same ftp server on the same port (21) at the same time?
As many as the server and the server OS can handle. There is no specific limit.
All the comments citing specific clients are incorrect, as is the one stating '1-8 as far as I know.' The comment about 'FTP Site Default settings' only applies to Microsoft IIS.
Port is the virtual interfacing used to differentiate services. In your case FTP server listen on particular port 21 which differentiate all other services/servers running on the same system listening to the same IP address (eg: DHCP server on 67 etc.,).
So the port are used only at Transport and Application layer (to bind to the particular port). The number of connections is limited with the help of "listen" system call (in case of linux), which will used in server binding.
Note: Observe any PCAP traces and socket programming to understand the usage of port.