how to copy instance and override value field declared in trait - scala

Suppose I have some abstract value field defined in a trait:
trait Base {
val toBeOverride: String
}
case class Impl(other:Int) extends Base {
override val toBeOverride = "some value"
}
How can I write a function that I can easily get a cloned instance only overriding the toBeOverride value, like this:
// copy only available to case class instance
// v does not have method 'copy'
def overrideBaseValue[T <: Base](v: Base) =
v.copy(toBeOverride = "prefix" + v.toBeOverride)
?
Edit
#som-snytt, I don't think this is a duplicate, just like a Trait is not the same as an Abstract Class. And the answers of that question do not satisfy me, see below.
#Blaisorblade, yes, it is a problem. For instances of each sub case class, the toBeOverride field are the same, so it should not appear in the constructor.
For now all the suggestions are to define an customized copy method in each(!) sub case class and that in my opinion is ugly and shows the incapability of the language.

The simplest solution is to just add the method you want to Base:
trait Base {
val toBeOverride: String
def copyBase(newToBeOverridden: String): Base
}
case class Impl(other:Int, override val toBeOverride: String = "some value") extends Base {
def copyBase(newToBeOverridden: String) = copy(toBeOverride = newToBeOverridden)
}
This also allows to directly create an instance of Impl while specifying the value of toBeOverride (which wasn't possible). The only disadvantage is that now pattern matches using Impl have to change syntax - please update your question and add a comment if that's a problem.
BTW, if you just want to add a prefix (as in your example), that's no problem:
case class Impl(other:Int, override val toBeOverride: String = "some value") extends Base {
def copyBase(newToBeOverridden: String) = copy(toBeOverride = toBeOverride + newToBeOverridden)
}

Here are two mechanisms.
Apparently, in the near future you'll be able to write a macro that can emit the anonymous subclass, but until then, I think this typeclass is not arduous.
Just kicking the tires on Dynamic here.
import scala.language.dynamics
import scala.reflect._
import scala.reflect.runtime.{ currentMirror => cm }
import scala.reflect.runtime.universe._
trait Base {
def m: String
}
case class Impl(p: Int) extends Base {
override val m = "some value"
}
trait Basic extends Dynamic {
protected def m: String
def selectDynamic(f: String): Any =
if ("m" == f) m else reflecting(this, f)
protected def reflecting(b: Basic, f: String) = {
val im = cm.reflect(b)
val member = im.symbol.typeSignature member newTermName(f)
require(member != NoSymbol, s"No such member $f")
(im reflectMethod member.asMethod)()
}
}
case class Implic(p: Int) extends Basic {
override protected val m = "some value"
}
object Test extends App {
implicit class Copy[A <: Base](val b: A) {
def overriding(overm: String): A = (b match {
case impl: Impl => new Impl(impl.p) { override val m = overm }
case b: Base => new Base { override val m = overm }
}).asInstanceOf[A]
}
implicit class Proxy[A <: Basic : ClassTag](val b: A) {
def proximately(overm: String): Basic = new Basic {
override val m = overm
override def selectDynamic(f: String): Any =
if ("m" == f) overm else reflecting(b, f)
override def toString = b.toString
}
}
// asked for this
//def overriding[T <: Base](v: Base) = v.copy(m = "prefix" + v.m)
/* want something like this
def overriding[T <: Base](v: Base) = new Impl(v.p) {
override val m = "some value"
} */
val a = Impl(5)
val b = a overriding "bee good"
Console println s"$a with ${a.m} ~> $b with ${b.m}"
// or
val c = Implic(7)
val d = c proximately "dynomite"
Console println s"$c with ${c.m} ~> $d with ${d.m}"
}

Since traits don't get copy methods automatically, you can try using a Base case class instead:
case class Base(toBeOverride: String)
case class Impl(other: Int, someVal: String = "some value") extends Base(someVal)
def overrideBaseValue[T <: Base](v: Base) =
v.copy(toBeOverride = "prefix" + v.toBeOverride)
The problem that you're going to run into though, is that copy returns an instance of Base and I don't think that you can convert it back to your original Impl class. For instance, this won't compile:
def overrideBaseValue[T <: Base](v: T): T =
v.copy(toBeOverride = "prefix" + v.toBeOverride)

Related

Syntax extension using type class methods in Scala

I want to bind a check method to the Test in such a way that the implementation does not contain an argument (look at the last line). It is necessary to use type classes here, but I'm new in Scala, so I have problems.
Object Checker is my attempts to solve the problem. Perhaps it is enough to make changes to it...
trait Test[+T] extends Iterable[T]
class TestIterable[+T](iterable: Iterable[T]) extends Test[T] {
override def iterator: Iterator[T] = iterable.iterator
}
object Test {
def apply[T](iterable: Iterable[T]): Test[T] = new TestIterable[T](iterable)
}
trait Check[M] {
def check(m: M): M
}
object Checker {
def apply[M](implicit instance: Check[M]): Check[M] = instance
implicit def checkSyntax[M: Check](m: M): CheckOps[M] = new CheckOps[M](m)
private implicit def test[T](m: Test[T]) : Check[Test[T]] = {
new Check[Test[T]] {
override def check(m: Test[T]) = m
}
}
final class CheckOps[M: Check](m: M) {
def x2: M = Checker[M].check(m)
}
}
import Checker._
val test123 = Test(Seq(1, 2, 3))
Test(test123).check

List of inner classes/objects during compilation

This is the simplified code of a class(object) I'm working on:
object T {
val default = A
val options = List(A,B,C)
sealed trait T
object A extends T {
override def toString = "A"
}
object B extends T {
override def toString = "B"
}
object C extends T {
override def toString = "C"
}
}
This hierarchy maps directly to GUI element which requires a options = List(A,B,C) to build.
Problem with current approach:
Every time I add an extra object I have to change the option manually. This isn't too much work however the code isn't too elegant this way.
My question is:
Can I generate a list of inner objects during compile time? I wouldn't like to do this during runtime, it would be an overkill.
To add to #Samar's comment, to make it clear. The following is what you need:
import scala.reflect.runtime.universe._
case object K {
val default = A
val options = getObjects[this.type]
sealed trait T
object A extends T {
override def toString = "A"
}
object B extends T {
override def toString = "B"
}
object C extends T {
override def toString = "C"
}
def getObjects[T: TypeTag] = typeOf[T].members.collect {
case m: ModuleSymbol if m.isModule => m
}.toList
}

Scala - handling "multiple overloaded alternatives of method ... define default arguments"

Let's say I have a setting such as this:
sealed trait Annotation {
def notes : Seq[String]
}
trait Something extends Annotation{
//do something funny
}
case class A(val i:Int)(val notes:Seq[String] = Nil) extends Something
object A{
def apply(a:A)(notes:Seq[String] = Nil):A = A(a.i)(notes)
}
case class B(val b:Boolean)(val notes:Seq[String] = Nil) extends Something
object B{
def apply(b:B)(notes:Seq[String] = Nil):B = B(b.b)(notes)
}
case class C(val s:String)(val notes:Seq[String] = Nil) extends Something
object C{
def apply(c:C)(notes:Seq[String] = Nil) :C = C(c.s)(notes)
}
Trying to compile this will result in
Main.scala:10: error: in object A, multiple overloaded alternatives of method apply define
default arguments.
object A{
^
Main.scala:15: error: in object B, multiple overloaded alternatives of method apply define
default arguments.
object B{
^
Main.scala:20: error: in object C, multiple overloaded alternatives of method apply define
default arguments.
object C{
^
three errors found
I have read this, so I do at least have an idea as to why this is happening, what I don't know, however, is how I am supposed to resolve the issue.
One possibility would - of course - be to simply omit the default values and force the client to provide Nil when no notes are to be stored, but is there a better solution?
My first guess was to simply make the default arguments explicit:
case class A(i: Int)(val notes: Seq[String]) extends Something
object A {
def apply(i: Int): A = new A(i)(Nil)
def apply(a: A)(notes: Seq[String]): A = new A(a.i)(notes)
def apply(a: A): A = new A(a.i)(Nil)
}
However, now, because of currying, you just have a function Int => A and Int => Seq[String] => A (and analogous for A => A) with the same name in scope.
If you refrain from currying you can manually define the overloaded methods:
case class B(b: Boolean, notes: Seq[String]) extends Something
object B {
def apply(b: Boolean): B = B(b, Nil)
def apply(b: B, notes: Seq[String] = Nil): B = B(b.b, notes)
}
But, since notes is now part of the same parameter list as b, the behavior of the case-class methods such as toString is changed.
println(B(true)) // B(true,List())
println(B(true, List("hello"))) // B(true,List(hello))
println(B(B(false))) // B(false,List())
Finally, to mimic the original behavior more closely, you can implement your own equals, hashCode, toString, and unapply methods:
class C(val s:String, val notes:Seq[String] = Nil) extends Something {
override def toString = s"C($s)"
override def equals(o: Any) = o match {
case C(`s`) => true
case _ => false
}
override def hashCode = s.hashCode
}
object C{
def apply(s: String, notes: Seq[String]) = new C(s, notes)
def apply(s: String): C = C(s, Nil)
def apply(c:C, notes:Seq[String] = Nil): C = C(c.s, notes)
def unapply(c: C): Option[String] = Some(c.s)
}
Example:
val c1 = C("hello")
val c2 = C("hello", List("world"))
println(c1) // C(hello)
println(c2) // C(hello)
println(c1 == c2) // true
c1 match { // hello
case C(n) => println(n)
case _ =>
}

creating a new instance of a type in scala

If I have a class C defined as
class C[A]
is there any way to create a new instance of A within C? Something like
class C[A] {
def f(): A = new A()
}
I understand that, if this were possible, you'd probably have to specify the constructor arguments somewhere, and that's fine.
If it's not possible, are there any design patterns for dealing with the sort of situation where you'd like to create a new instance of a type?
You could use a type class to abstract instantiation:
trait Makeable[T] {
def make: T
}
class C[T: Makeable] {
def f(): T = implicitly[Makeable[T]].make
}
For example,
implicit object StringIsMakeable extends Makeable[String] {
def make: String = "a string"
}
val c = new C[String]
c.f // == "a string"
When you instantiate C, you'll need to provide, explicitly or implicitly, a Makeable that will act as a factory of the appropriate type. That factory, of course, would be responsible for supplying any constructor arguments when it invokes the constructor.
Alternatively, you could use a Manifest, but be warned that this approach relies on reflection and is not type safe:
class C[T: Manifest] {
def f(): T = manifest[T].erasure.newInstance.asInstanceOf[T]
}
For completeness, you can also easily extend this approach to pass some or all of the constructor parameters in to the make method:
trait Makeable[Args, T] { def make(a: Args): T }
class C[Args, T](implicit e: Makeable[Args, T]) {
def f(a: Args): T = e.make(a)
}
// some examples
case class Person(firstName: String, lastName: String)
implicit val personFactory1 = new Makeable[(String, String), Person] {
def make(a: (String, String)): Person = Person(a._1, a._2)
}
implicit val personFactory2 = new Makeable[String, Person] {
def make(a: String): Person = Person(a, "Smith")
}
val c1 = new C[String, Person]
c1.f("Joe") // returns Person("Joe", "Smith")
val c2 = new C[(String, String), Person]
c2.f("John", "Smith") // returns Person("John", "Smith")
You can demand an implicit parameter, like so:
class A[T](implicit newT : T) {
val t = newT
}
All you need then is to have an implicit factory of the desired type in scope when you instanciate A, e.g. the following works:
implicit def newSeq[T] = Seq[T]()
val a = new A[Seq[String]]
As shown by:
scala> a.t
res22: Seq[String] = List()
The same as #Raphael's answer with a case class's apply method:
class Container[A](contained: A)
case class Person(name: String)
case class PersonContainer(person: Person) extends Container[Person](person)
implicit def _ = PersonContainer.apply _
class Creator {
def deserializeAndPackage[A, B <: Container[A]](data: Array[Byte])
(implicit containerCreator: (A => B)): B = {
val p = /* deserialize data as type of A */
containerCreator(p)
}
}

Method polymorphism

I am trying to write a generic method f[T](id:String) that is something like this:
case class A(x:String)
case class B(y:String)
case class C(z:String)
def f[T](id:String): T = { /* equivalent to T(id) */ }
val result1:A = f[A]("123") // returns A("123")
val result2:B = f{B]("345") // returns B("345")
val result3:C = f[C]("567") // returns C("567")
Unfortunately I cannot figure out how to work with the type T inside the method, besides using reflection. By "working with the type T" i mean for example being able to do something like the following, which I know doesn't work (for illustration purposes only):
T match {
case A => A(id)
case B => B(id)
}
or simply invoke T(ID) to create a new object of whatever type T is.
I can of course break up this into three methods:
def f1(id:String): A = { A(id) }
def f2(id:String): B = { B(id) }
def f3(id:String): C = { C(id) }
val result1:A = f1("123") // returns A("123")
val result2:B = f2("345") // returns B("345")
val result3:C = f3("567") // returns C("567")
but I'm hoping there is a way to keep it as one generic method to avoid some ugly boilerplate code duplication, and still be nearl as fast as the tree method version.
If you do not want to use reflection (ClassTag or TypeTag), you could use a Factory type class to achieve the desired functionality (unless it defeats the purpose of your generic function by generating a lot of duplicated simple code ;)).
case class A(s: String)
case class B(s: String)
case class C(s: String)
trait Factory[T] extends ((String) => T) {
def apply(arg: String): T
}
object Factory {
implicit object AFactory extends Factory[A] {
override def apply(arg: String): A = A(arg)
}
implicit object BFactory extends Factory[B] {
override def apply(arg: String): B = B(arg)
}
implicit object CFactory extends Factory[C] {
override def apply(arg: String): C = C(arg)
}
}
def create[T : Factory](arg: String): T = implicitly[Factory[T]].apply(arg)
create[A]("foo") | -> res0: A = A(foo)