Is there a way of sorting in MongoDB based on an $elemMatch? For example, I have documents which look like this:
{
'user': ObjectId('fsdfsdf'),
...
'array_of_things': [
{
'attribute_1': ObjectId('sdfsdfsd'),
'attribute_2': ObjectId('sdfsfsdf'),
'value': 30000
},
{
'attribute_1': ObjectId('dfdfgfdg'),
'attribute_2': ObjectId('gdfgdfgd'),
'value': 100
},
{
'attribute_1': ObjectId('mbnmbbmb'),
'attribute_2': ObjectId('mbnmbnmb'),
'value': 2000
},
...
]
}
I need to be able to query this data based on a matching element inside the array_of_things field (which is simple enough with an $elemMatch). The problem arises because I also need to be able to sort by value (ascending or descending) that match a certain attribute. For example, a query might be:
{
'user': ObjectId('fsdfsdf'),
'array_of_things': {
$elemMatch: {
'attribute_1': ObjectId('dfdfgfdg'),
'value': {
$gt: 1
}
}
}
}
Sorting solely on value (e.g. sort({ 'array_of_things.value': -1 }) predictably only sorts on all values in any array element, not matching attribute_1 first.
Is there a way to do this?
Apologies if this is an already-asked question, but I can't seem to find any solution to it after looking.
This is currently not possible with the standard query language. You can achieve it with the aggregation framework at (potentially) some performance penalty.
Related
Currently I use the following find query to get the latest document of a certain ID
Conditions.find({
caveId: caveId
},
{
sort: {diveDate:-1},
limit: 1,
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
How can I use the same using multiple ids with $in for example
I tried it with the following query. The problem is that it will limit the documents to 1 for all the found caveIds. But it should set the limit for each different caveId.
Conditions.find({
caveId: {$in: caveIds}
},
{
sort: {diveDate:-1},
limit: 1,
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
One solution I came up with is using the aggregate functionality.
var conditionIds = Conditions.aggregate(
[
{"$match": { caveId: {"$in": caveIds}}},
{
$group:
{
_id: "$caveId",
conditionId: {$last: "$_id"},
diveDate: { $last: "$diveDate" }
}
}
]
).map(function(child) { return child.conditionId});
var conditions = Conditions.find({
_id: {$in: conditionIds}
},
{
fields: {caveId: 1, "visibility.visibility":1, diveDate: 1}
});
You don't want to use $in here as noted. You could solve this problem by looping through the caveIds and running the query on each caveId individually.
you're basically looking at a join query here: you need all caveIds and then lookup last for each.
This is a problem of database schema/denormalization in my opinion: (but this is only an opinion!):
You could as mentioned here, lookup all caveIds and then run the single query for each, every single time you need to look up last dives.
However I think you are much better off recording/updating the last dive inside your cave document, and then lookup all caveIds of interest pulling only the lastDive field.
That will give you immediately what you need, rather than going through expensive search/sort queries. This is at the expense of maintaining that field in the document, but it sounds like it should be fairly trivial as you only need to update the one field when a new event occurs.
I have a mongo collection in which the documents have a field that is an array. I want to be able to publish everything in the documents except for the elements in the array that were created more than a day ago. I suspect the answer will be somewhat similar to this question.
Meteor publication: Hiding certain fields in an array document field?
Instead of limiting fields in the array, I just want to limit the elements in the array being published.
Thanks in advance for any responses!
EDIT
Here is an example document:
{
_id: 123456,
name: "Unit 1",
createdAt: (datetime object),
settings: *some stuff*,
packets: [
{
_id: 32412312,
temperature: 70,
createdAt: *datetime object from today*
},
{
_id: 32412312,
temperature: 70,
createdAt: *datetime from yesterday*
}
]
}
I want to get everything in this document except for the part of the array that was created more than 24 hours ago. I know I can accomplish this by moving the packets into their own collection and tying them together with keys as in a relational database but if what I am asking were possible, this would be simpler with less code.
You could do something like this in your publish method:
Meteor.publish("pubName", function() {
var collection = Collection.find().fetch(); //change this to return your data
_.each(collection, function(collectionItem) {
_.each(collectionItem.packets, function(packet, index) {
var deadline = Date.now() - 86400000 //should equal 24 hrs ago
if (packet.createdAt < deadline) {
collectionItem.packets.splice(index, 1);
}
}
}
return collection;
}
Though you might be better off storing the last 24 hours worth of packets as a separate array in your document. Would probably be less taxing on the server, not sure.
Also, code above is untested. Good luck.
you can use the $elemMatch projection
http://docs.mongodb.org/manual/reference/operator/projection/elemMatch/
So in your case, it would be
var today = new Date();
var yesterday = new Date(today);
yesterday.setDate(today.getDate() - 1);
collection.find({}, //find anything or specifc
{
fields: {
'packets': {
$elemMatch: {$gt : {'createdAt' : yesterday /* or some new Date() */}}
}
}
});
However, $elemMatch only returns the FIRST element matching your condition. To return more than 1 element, you need to use the aggregation framework, which will be more efficient than _.each or forEach, particularly if you have a large array to loop through.
collection.rawCollection().aggregate([
{
$match: {}
},
{
$redact: {
$cond: {
if : {$or: [{$gt: ["$createdAt",yesterday]},"$packets"]},
then: "$$DESCEND",
else: "$$PRUNE"
}
}
}], function (error, result ){
});
You specify the $match in a way similar to find({}). Then all the documents that match your conditions get pipped into the $redact which is specified by the $cond.
$redact scans the document from top level to bottom. At the top level, you have _id, name, createdAt, settings, packets; hence {$or: [***,"$packets"]}
The presence of $packets in the $or allows the $redact to scan the second level which contain the _id, temperature and createdAt; hence {$gt: ["$createdAt",yesterday]}
This is async, you can use Meteor.wrapAsync to wrap around the function.
Hope this help
Let's say I have four documents in my collection:
{u'a': {u'time': 3}}
{u'a': {u'time': 5}}
{u'b': {u'time': 4}}
{u'b': {u'time': 2}}
Is it possible to sort them by the field 'time' which is common in both 'a' and 'b' documents?
Thank you
No, you should put your data into a common format so you can sort it on a common field. It can still be nested if you want but it would need to have the same path.
You can use use aggregation and the following code has been tested.
db.test.aggregate({
$project: {
time: {
"$cond": [{
"$gt": ["$a.time", null]
}, "$a.time", "$b.time"]
}
}
}, {
$sort: {
time: -1
}
});
Or if you also want the original fields returned back: gist
Alternatively you can sort once you get the result back, using a customized compare function ( not tested,for illustration purpose only)
db.eval(function() {
return db.mycollection.find().toArray().sort( function(doc1, doc2) {
var time1 = doc1.a? doc1.a.time:doc1.b.time,
time2 = doc2.a?doc2.a.time:doc2.b.time;
return time1 -time2;
})
});
You can, using the aggregation framework.
The trick here is to $project a common field to all the documents so that the $sort stage can use the value in that field to sort the documents.
The $ifNull operator can be used to check if a.time exists, it
does, then the record will be sorted by that value else, by b.time.
code:
db.t.aggregate([
{$project:{"a":1,"b":1,
"sortBy":{$ifNull:["$a.time","$b.time"]}}},
{$sort:{"sortBy":-1}},
{$project:{"a":1,"b":1}}
])
consequences of this approach:
The aggregation pipeline won't be covered by any of the index you
create.
The performance will be very poor for very large data sets.
What you could ideally do is to ask the source system that is sending you the data to standardize its format, something like:
{"a":1,"time":5}
{"b":1,"time":4}
That way your query can make use of the index if you create one on the time field.
db.t.ensureIndex({"time":-1});
code:
db.t.find({}).sort({"time":-1});
In the MongoDB aggregation framework, I was hoping to use the $unwind operator on an object (ie. a JSON collection). Doesn't look like this is possible, is there a workaround? Are there plans to implement this?
For example, take the article collection from the aggregation documentation . Suppose there is an additional field "ratings" that is a map from user -> rating. Could you calculate the average rating for each user?
Other than this, I'm quite pleased with the aggregation framework.
Update: here's a simplified version of my JSON collection per request. I'm storing genomic data. I can't really make genotypes an array, because the most common lookup is to get the genotype for a random person.
variants: [
{
name: 'variant1',
genotypes: {
person1: 2,
person2: 5,
person3: 7,
}
},
{
name: 'variant2',
genotypes: {
person1: 3,
person2: 3,
person3: 2,
}
}
]
It is not possible to do the type of computation you are describing with the aggregation framework - and it's not because there is no $unwind method for non-arrays. Even if the person:value objects were documents in an array, $unwind would not help.
The "group by" functionality (whether in MongoDB or in any relational database) is done on the value of a field or column. We group by value of field and sum/average/etc based on the value of another field.
Simple example is a variant of what you suggest, ratings field added to the example article collection, but not as a map from user to rating but as an array like this:
{ title : title of article", ...
ratings: [
{ voter: "user1", score: 5 },
{ voter: "user2", score: 8 },
{ voter: "user3", score: 7 }
]
}
Now you can aggregate this with:
[ {$unwind: "$ratings"},
{$group : {_id : "$ratings.voter", averageScore: {$avg:"$ratings.score"} } }
]
But this example structured as you describe it would look like this:
{ title : title of article", ...
ratings: {
user1: 5,
user2: 8,
user3: 7
}
}
or even this:
{ title : title of article", ...
ratings: [
{ user1: 5 },
{ user2: 8 },
{ user3: 7 }
]
}
Even if you could $unwind this, there is nothing to aggregate on here. Unless you know the complete list of all possible keys (users) you cannot do much with this. [*]
An analogous relational DB schema to what you have would be:
CREATE TABLE T (
user1: integer,
user2: integer,
user3: integer
...
);
That's not what would be done, instead we would do this:
CREATE TABLE T (
username: varchar(32),
score: integer
);
and now we aggregate using SQL:
select username, avg(score) from T group by username;
There is an enhancement request for MongoDB that may allow you to do this in the aggregation framework in the future - the ability to project values to keys to vice versa. Meanwhile, there is always map/reduce.
[*] There is a complicated way to do this if you know all unique keys (you can find all unique keys with a method similar to this) but if you know all the keys you may as well just run a sequence of queries of the form db.articles.find({"ratings.user1":{$exists:true}},{_id:0,"ratings.user1":1}) for each userX which will return all their ratings and you can sum and average them simply enough rather than do a very complex projection the aggregation framework would require.
Since 3.4.4, you can transform object to array using $objectToArray
See:
https://docs.mongodb.com/manual/reference/operator/aggregation/objectToArray/
This is an old question, but I've run across a tidbit of information through trial and error that people may find useful.
It's actually possible to unwind on a dummy value by fooling the parser this way:
db.Opportunity.aggregate(
{ $project: {
Field1: 1, Field2: 1, Field3: 1,
DummyUnwindField: { $ifNull: [null, [1.0]] }
}
},
{ $unwind: "$DummyUnwindField" }
);
This will produce 1 row per document, regardless of whether or not the value exists. You may be able tinker with this to generate the results you want. I had hoped to combine this with multiple $unwinds to (sort of like emit() in map/reduce), but alas, the last $unwind wins or they combine as an intersection rather than union which makes it impossible to achieve the results I was looking for. I am sadly disappointed with the aggregate framework functionality as it doesn't fit the one use case I was hoping to use it for (and seems strangely like a lot of the questions on StackOverflow in this area are asking) - ordering results based on match rate. Improving the poor map reduce performance would have made this entire feature unnecessary.
This is what I found & extended.
Lets create experimental database in mongo
db.copyDatabase('livedb' , 'experimentdb')
Now Use experimentdb & convert Array to object in your experimentcollection
db.getCollection('experimentcollection').find({}).forEach(function(e){
if(e.store){
e.ratings = [e.ratings]; //Objects name to be converted to array eg:ratings
db.experimentcollection.save(e);
}
})
Some nerdy js code to convert json to flat object
var flatArray = [];
var data = db.experimentcollection.find().toArray();
for (var index = 0; index < data.length; index++) {
var flatObject = {};
for (var prop in data[index]) {
var value = data[index][prop];
if (Array.isArray(value) && prop === 'ratings') {
for (var i = 0; i < value.length; i++) {
for (var inProp in value[i]) {
flatObject[inProp] = value[i][inProp];
}
}
}else{
flatObject[prop] = value;
}
}
flatArray.push(flatObject);
}
printjson(flatArray);
i have a mongoDB collection named col that has documents that look like this
{
{
intField:123,
strField:'hi',
arrField:[1,2,3]
},
{
intField:12,
strField:'hello',
arrField:[1,2,3,4]
},
{
intField:125,
strField:'hell',
arrField:[1]
}
}
Now i want to remove documents from collection col in which size of the array field is less than 2.
So i wrote a query that looks like this
db.col.remove({'arrField':{"$size":{"$lt":2}}})
Now this query doesnt do anything. i checked with db.col.find() and it returns all the documents. Whats wrong with this query?
With MongoDB 2.2+ you can use numeric indexes in condition object keys to do this:
db.col.remove({'arrField.2': {$exists: 0}})
This will remove any document that doesn't have at least 3 elements in arrField.
From the documentation for $size:
You cannot use $size to find a range of sizes (for example: arrays with more than 1 element).
The docs recommend maintaining a separate size field (so in this case, arrFieldSize) with the count of the items in the array if you want to try this sort of thing.
Note that for some queries, it may be feasible to just list all the counts you want in or excluded using (n)or conditions.
In your example, the following query will give all documents with less than 2 array entries:
db.col.find({
"$or": [
{ "arrField": {"$exists" => false} },
{ "arrField": {"$size" => 1} },
{ "arrField": {"$size" => 0} }
]
})
The following should work
db.col.remove({$where: "this.arrField.length < 2"})