Merry Christmas to everybody. I'm having a dilemma with a perl script. In my script, I call another program with a system call, but I got this error:
Can't exec "./Classificador/svm_classify": No such file or directory at Analise_de_Sentimentos_mudanca.pl line 463.
I don't know if there is a problem in having my program in a different directory than the called program.
Another curious thing is that this script used to run normally in Ubuntu 10.10. But now I've changed to Mint 14. Is it missing some library?
Best wishes,
Thiago
The relative pathname ./Classificador/svm_classify is interpreted relative to the user's current directory, not the directory containing the perl script. You need to do one of the following:
The user must cd to the directory containing the perl script before running it.
The perl script should call chdir() to set the current directory to the directory where it's stored.
Put the absolute pathname in the script, instead of ./.
Does this "./Classificador/svm_classify" exists ?
Check the following :
1) to go the directory where this file lays - Analise_de_Sentimentos_mudanca.pl
2) run :
ll Classificador/svm_classify
3) show us the results
Related
I have the following code in a perl module,
package Foo;
our $pathToScript = "/home/Lucas/project841/python_script.py";
It is frequently called by other modules in the same file directory through
$output = `$Foo::pathToScript`;
# etc
I would like to remove the hard coding of the actual path and use relative path, Eg. ./python_script.py to call the script from other modules.
What would be the ideal way?
You said your Perl script is "frequently" called from the same directory where the Python script resides, not "always". If you remove the absolute path, you'll need to change that "frequently" to "always", and just change $pathToScript to the Python script name (no path).
You could also consider setting the environment PATH (in the Perl script) so that the Python script (without the full path in $pathToScript) is always found, regardless of where the user is running from or where the Perl script is located.
I have a 3D modal for cup.obj. I need to convert to .h file so I downloaded this http://heikobehrens.net/2009/08/27/obj2opengl/ And put cup.obj file to this folder. Then I run from terminal obj2opengl.pl cup.obj I didn't get .h file.
Ranganatha-GVs-Mac-mini:~ ranganathagv$ ./obj2opengl.pl cup.obj
-bash: ./obj2opengl.pl: No such file or directory
Ranganatha-GVs-Mac-mini:~ ranganathagv$
The obj2opengl.pl script probably hasn't the right permission set in order to be executable using the ./ syntax.
Two choices here, you can either:
Change the permission on the script using chmod +x obj2opengl.pl, and using ./obj2opengl.pl cup.obj should work from there on, or
Run the script using perl obj2opengl.pl cup.obj.
Hope this helps!
I have a script in one of my application folders.Usually I just cd into that locatin in Unix box and run the script e.g.
UNIX> cd My\Folder\
My\Folder> MyScript
This prints the required result.
I am not sure how do I do this in Bash script.I have done the following
#!/bin/bash
mydir=My\Folder\
cd $mydir
echo $(pwd)
This basically puts me in the right folder to run the required script . But I am not sure how to run the script in the code?
If you can call MyScript (as opposed to ./MyScript), obviously the current directory (".") is part of your PATH. (Which, by the way, isn't a good idea.)
That means you can call MyScript in your script just like that:
#!/bin/bash
mydir=My/Folder/
cd $mydir
echo $(pwd)
MyScript
As I said, ./MyScript would be better (not as ambiguous). See Michael Wild's comment about directory separators.
Generally speaking, Bash considers everything that does not resolve to a builtin keyword (like if, while, do etc.) as a call to an executable or script (*) located somewhere in your PATH. It will check each directory in the PATH, in turn, for a so-named executable / script, and execute the first one it finds (which might or might not be the MyScript you are intending to run). That's why specifying that you mean the very MyScript in this directory (./) is the better choice.
(*): Unless, of course, there is a function of that name defined.
#!/bin/bash
mydir=My/Folder/
cd $mydir
echo $(pwd)
MyScript
I would rather put the name in quotes. This makes it easier to read and save against mistakes.
#!/bin/bash
mydir="My Folder"
cd "$mydir"
echo $(pwd)
./MyScript
Your nickname says it all ;-)
When a command is entered at the prompt that doesn't contain a /, Bash first checks whether it is a alias or a function. Then it checks whether it is a built-in command, and only then it starts searching on the PATH. This is a shell variable that contains a list of directories to search for commands. It appears that in your case . (i.e. the current directory) is in the PATH, which is generally considered to be a pretty bad idea.
If the command contains a /, no look-up in the PATH is performed. Instead an exact match is required. If starting with a / it is an absolute path, and the file must exist. Otherwise it is a relative path, and the file must exist relative to the current working directory.
So, you have two acceptable options:
Put your script in some directory that is on your PATH. Alternatively, add the directory containing the script to the PATH variable.
Use an absolute or relative path to invoke your script.
I am doing a batch scripting assignment where I have to call one script from inside another. I need the script to run the second script no matter where my lecturer saves these scripts. How would I do this. Is there some way to find the path of script inside the script and use that to execute the file. Any help would be great. I think I need to use %'s but i'm not sure.
The name of the script is Hello World.bat.
How would I copy Hello World.bat to the C:\ if I don't know which directory the lecturer has placed it in. what command/s would I use so that the copy would work regardless of the scripts location.
I don't see the "DOS" tag, but I'll assume that it is for now. If you want the entire path, you can get it by doing this:
echo %cd%
If you want just the last folder, this works (inside a .bat file):
for %%* in (.) do #echo %%~n*
Note that from the command line, the above command will work with single %'s:
for %* in (.) do #echo %~n*
If the script you are executing is calling other scripts in the SAME folder location, you can prefix the path statement with "%~dp0" or "%~dps0" but do not put a backslash between that and the name of the script you are calling. In other words, if script1.bat is calling script2.bat in the same folder, the statement in script1.bat would refer to "%~dp0script2.bat"
sorry about batch files, am not familiar, but in nix shell, there is the locate command which can return the path of the file , if you know the filename exactly and the name is unique.
like
name=$(locate filname)
I am using the system command in MATLAB as follows (with the current directory being 'scripts'):
[status, result] = system('cd ..\\TxtInOut')
However, invoking the system command does not seem to work. It returns status = 0 and result = ''.
Any suggestions?
If you want to change directories, you should use the CD command. The argument can be either a full path or relative path:
cd('c:\matlab\toolbox'); %# Full path to a directory
cd('scripts'); %# Move to a subdirectory "scripts"
cd('..\TxtInOut'); %# Move up one level, then to directory "TxtInOut"
If you want information about a directory, you should use the DIR command. DIR will return an m-by-1 structure of information for a directory, where m is the number of files and folders in the directory. Again, the argument can be either a full path or relative path:
data = dir('c:\matlab\toolbox'); %# Data for a full path to a directory
data = dir('scripts'); %# Data for a subdirectory "scripts"
NOTE: When working on different platforms (i.e. Windows or UNIX), you will have to pay attention to whether you use the file separator \ or /. You can get the file separator for your platform using the function FILESEP. You can also build your file paths using the function FULLFILE.
Any command executed by "system" is external to MATLAB. A command shell is generated, executes your request, and then returns the result. The 0 result indicates successful completion: the command shell changed its current directory as requested and then returned. (Command shells use non-zero to indicate an error, because there are usually many more ways that a program can fail than succeed.) Unfortunately that only affects the command shell's current directory - see gnovice's answer for how to actually change the directory.
you can use cd, dir, ls, etc directly in matlab without call system functions.
You can also use the underlying operating system commands by preceding them by an exclamation sign.
For instance:
!dir will show you the current directory contents in Windows
!pwd will show you the current directory in Linux/Mac
But calling cd does not change the current directory!