What is this variable-length integer encoding? - encoding

I am documenting an old file format and have stumped myself with the following issue.
It seems to be that integers are variable-length encoded, with numbers <= 0x7F encoded in a single byte, but >= 0x80 are encoded in two bytes. An example set of integers and their encoded counterparts:
0x390 is encoded as 0x9007
0x150 is encoded as 0xD002
0x82 is encoded as 0x8201
0x89 is encoded as 0x8901
I have yet to come across any numbers that are larger than 0xFFFF, so I can't be sure if/how they are encoded. For the life of me, I can't work out the pattern here. Any ideas?

At a glance it looks like the numbers are split into 7-bit chunks, each of which is encoded as the 7 least significant bits of an output byte, while the most significant bit signifies whether there are more bytes following this one (i.e. the last byte of an encoded integer has 0 as its MSB).
The least significant bits of the input come first, so I guess you could call this "little endian".
Edit: see https://en.wikipedia.org/wiki/Variable-length_quantity (this is used in MIDI and Google protocol buffers)

Related

16-bit encoding that has all bits mapped to some value

UTF-32 has its last bits zeroed.
As I understand it UTF-16 doesn't use all its bits either.
Is there a 16-bit encoding that has all bit combinations mapped to some value, preferably a subset of UTF, like ASCII for 7-bit?
UTF-32 has its last bits zeroed
This might be not correct, depending on how you count. Typically we count from left, so the high (i.e. first) bits of UTF-32 will be zero
As I understand it UTF-16 doesn't use all its bits either
It's not correct either. UTF-16 uses all of its bits. It's just that the range [0xD800—0xDFFF] is reserved for UTF-16 surrogate pairs so those values will never be assigned any character and will never appear in UTF-32. If you need to encode characters outside the BMP with UTF-16 then those values will be used
In fact Unicode was limited to U+10FFFF just because of UTF-16, even though UTF-8 and UTF-32 themselves are able to represent up to U+7FFFFFFF and U+FFFFFFFF respectively. The use of surrogate pair makes it impossible to encode values larger than 0x10FFFF in UTF-16
See Why Unicode is restricted to 0x10FFFF?
Is there a 16 bit encoding that has all bit combinations mapped to some value, preferably a subset of UTF, like ASCII for 7 bit?
First there's no such thing as "a subset of UTF", since UTF isn't a character set but a way to encode Unicode code points
Prior to the existence of UTF-16 Unicode was a fixed 16-bit character set encoded with UCS-2. So UCS-2 might be the closest you'll get, which encodes only the characters in the BMP. Other fixed 16-bit non-Unicode charsets also has an encoding that maps all of the bit combinations to some characters
However why would you want that? UCS-2 has been deprecated long ago. Some old tools and less experienced programmers still imply that Unicode is always 16-bit long like that which is correct and will break modern text processing
Also note that not all the values below 0xFFFF are assigned, so no encoding can map every 16-bit value to a Unicode code point
Further reading
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
What is a "surrogate pair" in Java?

UTF8, codepoints, and their representation in Erlang and Elixir

going through Elixir's handling of unicode:
iex> String.codepoints("abc§")
["a", "b", "c", "§"]
very good, and byte_size/2 of this is not 4 but 5, because the last char is taking 2 bytes, I get that.
The ? operator (or is it a macro? can't find the answer) tells me that
iex(69)> ?§
167
Great; so then I look into the UTF-8 encoding table, and see value c2 a7 as hex encoding for the char. That means the two bytes (as witnessed by byte_size/1) are c2 (94 in decimal) and a7 (167 in decimal). That 167 is the result I got when evaluating ?§ earlier. What I don't understand, exactly, is.. why that number is a "code point", as per the description of the ? operator. When I try to work backwards, and evaluate the binary, I get what I want:
iex(72)> <<0xc2, 0xa7>>
"§"
And to make me go completely bananas, this is what I get in Erlang shell:
24> <<167>>.
<<"§">>
25> <<"\x{a7}">>.
<<"§">>
26> <<"\x{c2}\x{a7}">>.
<<"§"/utf8>>
27> <<"\x{c2a7}">>.
<<"§">>
!! while Elixir is only happy with the code above... what is it that I don't understand? Why is Erlang perfectly happy with a single byte, given that Elixir insists that char takes 2 bytes - and Unicode table seems to agree?
The codepoint is what identifies the Unicode character. The codepoint for § is 167 (0xA7). A codepoint can be represented in bytes in different ways, depending of your encoding of choice.
The confusion here comes from the fact that the codepoint 167 (0xA7) is identified by the bytes 0xC2 0xA7 when encoded to UTF-8.
When you add Erlang to the conversation, you have to remember Erlang default encoding was/is latin1 (there is an effort to migrate to UTF-8 but I am not sure if it made to the shell - someone please correct me).
In latin1, the codepoint § (0xA7) is also represented by the byte 0xA7. So explaining your results directly:
24> <<167>>.
<<"§">> %% this is encoded in latin1
25> <<"\x{a7}">>.
<<"§">> %% still latin1
26> <<"\x{c2}\x{a7}">>.
<<"§"/utf8>> %% this is encoded in utf8, as the /utf8 modifier says
27> <<"\x{c2a7}">>.
<<"§">> %% this is latin1
The last one is quite interesting and potentially confusing. In Erlang binaries, if you pass an integer with value more than 255, it is truncated. So the last example is effectively doing <<49831>> which when truncated becomes <<167>>, which is again equivalent to <<"§">> in latin1.
The code point is a number assigned to the character. It's an abstract value, not dependent on any particular representation in actual memory somewhere.
In order to store the character, you have to convert the code point to some sequence of bytes. There are several different ways to do this; each is called a Unicode Transformation Format, and named UTF-n, where the n is the number of bits in the basic unit of encoding. There used to be a UTF-7, used where 7-bit ASCII was assumed and even the 8th bit of a byte couldn't be reliably transmitted; in modern systems, there are UTF-8, UTF-16, and UTF-32.
Since the largest code point value fits comfortably in 21 bits, UTF-32 is the simplest; you just store the code point as a 32-bit integer. (There could theoretically be a UTF-24 or even a UTF-21, but common modern computing platforms deal naturally with values that take up either exactly 8 or a multiple of 16 bits, and have to work harder to deal with anything else.)
So UTF-32 is simple, but inefficient. Not only does it have 11 extra bits that will never be needed, it has 5 bits that are almost never needed. Far and away most Unicode characters found in the wild are in the Basic Multilingual Plane, U+0000 through U+FFFF. UTF-16 lets you represent all of those code points as a plain integer, taking up half the space of UTF-32. But it can't represent anything from U+10000 on up that way, so part of the 0000-FFFF range is reserved as "surrogate pairs" that can be put together to represent a high-plane Unicode character with two 16-bit units, for a total of 32 bits again but only when needed.
Java uses UTF-16 internally, but Erlang (and therefore Elixir), along with most other programming systems, uses UTF-8. UTF-8 has the advantage of completely transparent compatibility with ASCII - all characters in the ASCII range (U+0000 through U+007F, or 0-127 decimal) are represented by single bytes with the corresponding value. But any characters with code points outside the ASCII range require more than one byte each - even those in the range U+0080 through U+00FF, decimal 128 through 255, which only take up one byte in the Latin-1 encoding that used to be the default before Unicode.
So with Elixir/Erlang "binaries", unless you go out of your way to encode things differently, you are using UTF-8. If you look at the high bit of the first byte of a UTF-8 character, it's either 0, meaning you have a one-byte ASCII character, or it's 1. If it's 1, then the second-highest bit is also 1, because the number of consecutive 1-bits counting down from the high bit before you get to a 0 bit tells you how many bytes total the character takes up. So the pattern 110xxxxx means the character is two bytes, 1110xxxx means three bytes, and 11110xxx means four bytes. (There is no legal UTF-8 character that requires more than four bytes, although the encoding could theoretically support up to seven.)
The rest of the bytes all have the two high bits set to 10, so they can't be mistaken for the start of a character. And the rest of the bits are the code point itself.
To use your case as an example, the code point for "§" is U+00A7 - that is, hexadecimal A7, which is decimal 167 or binary 10100111. Since that's greater than decimal 127, it will require two bytes in UTF-8. Those two bytes will have the binary form 110abcde 10fghijk, where the bits abcdefghijk will hold the code point. So the binary representation of the code point, 10100111, is padded out to 00010100111 and split unto the sequences 00010, which replaces abcde in the UTF-8 template, and 100111, which replaces fghijk. That yields two bytes with binary values 11000010 and 10100111, which are C2 and A7 in hexadecimal, or 194 and 167 in decimal.
You'll notice that the second byte coincidentally has the same value as the code point you're encoding, but t's important to realize that this correspondence is just a coincidence. There are a total of 64 code points, from 128 (U+0080) through 191 (U+00BF), that work out that way: their UTF-8 encoding consists of a byte with decimal value 194 followed by a byte whose value is equal to the code point itself. But for the other 1,114,048 code points possible in Unicode, that is not the case.

Regarding unicode characters and their utf8 binary representation

Out of curiosity, i wonder why for example a character "ł" with code point 322 has a UTF8 binary representation of 11000101:10000010 in decimal 197:130 and not its actual binary representation 00000001:01000010 in decimal 1:66 ?
UTF-8 encodes Unicode code points in the range U+0000..U+007F in a single byte. Code points in the range U+0080..U+07FF use 2 bytes, code points in the range U+0800..U+FFFF use 3 bytes, and code points in the range U+10000..U+10FFFF use 4 bytes.
When the code point needs two bytes, then the first byte starts with the bit pattern 110; the remaining 5 bits are the high order 5 bits of the Unicode code point. The continuation byte starts with the bit pattern 10; the remaining 6 bits are the low order 6 bits of the Unicode code point.
You are looking at ł U+0142 LATIN SMALL LETTER L WITH STROKE (decimal 322). The bit pattern representing hexadecimal 142 is:
00000001 01000010
With the UTF-8 sub-field grouping marked by colons, that is:
00000:001 01:000010
So the UTF-8 code is:
110:00101 10:000010
11000101 10000010
0xC5 0x82
197 130
The same basic ideas apply to 3-byte and 4-byte encodings — you chop off 6-bits per continuation byte, and combine the leading bits with the appropriate marker bits (1110 for 3 bytes; 11110 for 4 bytes — there are as many leading 1 bits as there are bytes in the complete character). There are a bunch of other rules that don't matter much to you right now. For example, you never encode a UTF-16 high surrogate (U+D800..U+DBFF) or a low surrogate (U+DC00..UDFFF) in UTF-8 (or UTF-32, come to that). You never encode a non-minimal sequence (so although bytes 0xC0 0x80 could be used to encode U+0000, this is invalid). One consequence of these rules is that the bytes 0xC0 and 0xC1 are never valid in UTF-8 (and neither are 0xF5..0xFF).
UTF8 is designed for compatibility with with 7-bit ASCII.
To achieve this the most significant bit of bytes in a UTF8 encoded byte sequence is used to signal whether a byte is part of a multi-byte encoded code point. If the MSB is set, then the byte is part of a sequence of 2 or more bytes that encode a single code point. If the MSB is not set then the byte encodes a code point in the range 0..127.
Therefore in UTF8 the byte sequence [1][66] represents the two code points 1 and 66 respectively since the MSB is not set (=0) in either byte.
Furthermore, the code point #322 must be encoded using a sequence of bytes where the MSB is set (=1) in each byte.
The precise details of UTF8 encoding are quite a bit more complex but there are numerous resources that go into those details.

Unicode code point limit

As explained here, All unicode encodings end at largest code point 10FFFF But I've heard differently that
they can go upto 6 bytes, is it true?
UTF-8 underwent some changes during its life, and there are many specifications (most of which are outdated now) which standardized UTF-8. Most of the changes were introduced to help compatibility with UTF-16 and to allow for the ever-growing amount of codepoints.
To make the long story short, UTF-8 was originally specified to allow codepoints with up to 31 bits (or 6 bytes). But with RFC3629, this was reduced to 4 bytes max. to be more compatible to UTF-16.
Wikipedia has some more information. The specification of the Universal Character Set is closely linked to the history of Unicode and its transformation format (UTF).
See the answers to Do UTF-8,UTF-16, and UTF-32 Unicode encodings differ in the number of characters they can store?
UTF-8 and UTF-32 are theoretically capable of representing characters above U+10FFFF, but were artificially restricted to match UTF-16's capacity.
The largest unicode codepoint and the encodings for unicode characters used, are two things. According to the standard, the highest codepoint really is 0x10ffff but herefore you'll need just 21 bits which fit easily into 4 bytes, even with 11 bits wasted!
I guess with your question about 6 bytes you mean a 6-byte utf-8 sequence, right? As others have answered already, using the utf-8 mechanism you could really deal with 6-byte sequences, you can even deal with 7-byte sequences and even with an 8-byte sequence. The 7-byte sequence gives you a range of just what the following bytes have to offer, 6 x 6 bits = 36 bits and a 8-byte sequence gives you 7 x 6 bits = 42 bits. You could deal with it but it is not allowed because unneeded, the highest codepoint is 0x10ffff.
It is also forbidden to use longer sequences than needed as Hibou57 has mentioned. With utf-8 one must always use the shortest sequence possible or the sequence will be treated as invalid! An ASCII character must be in a 7-bit singlebyte of course. The second thing is that the utf-8 4-byte sequence gives you 3 bits of payload in the startbyte and 18 bits of payload in the following bytes which are 21 bits and that matches to the calculation of surrogates when using the utf-16 encoding. The bias 0x10000 is subtracted from the codepoint and the remaining 20 bits go to the high- as well lo-surrogate payload area, each of 10 bits. The third and last thing is, that within utf-8 it is not allowed to encode hi- or -lo-surrogate values. Surrogates are not characters but containers for them, surrogates can only appear in utf-16, not in utf-8 or utf-32 encoded files.
Indeed, for some view of the UTF‑8 encoding, UTF‑8 may technically permit to encode code‑points beyond the forever‑fixed valid range upper‑limit; so one may encode a code‑point beyond that range, but it will not be a valid code‑point anywhere. On the other hand, you may encode a character with unneeded zeroed high‑order bits, ex. encoding an ASCII code‑point with multiple bits, like in 2#1100_0001#, 2#1000_0001# (using Ada's notation), which would for the ASCII letter A UTF‑8 encoded with two bytes. But then, it may be rejected by some safety/security filters, at this use to be used for hacking and piracy. RFC 3629 has some explanation about it. One should just stick to encode valid code‑points (as defined by Unicode), the safe way (no extraneous bytes).

UTF-8, UTF-16, and UTF-32

What are the differences between UTF-8, UTF-16, and UTF-32?
I understand that they will all store Unicode, and that each uses a different number of bytes to represent a character. Is there an advantage to choosing one over the other?
UTF-8 has an advantage in the case where ASCII characters represent the majority of characters in a block of text, because UTF-8 encodes these into 8 bits (like ASCII). It is also advantageous in that a UTF-8 file containing only ASCII characters has the same encoding as an ASCII file.
UTF-16 is better where ASCII is not predominant, since it uses 2 bytes per character, primarily. UTF-8 will start to use 3 or more bytes for the higher order characters where UTF-16 remains at just 2 bytes for most characters.
UTF-32 will cover all possible characters in 4 bytes. This makes it pretty bloated. I can't think of any advantage to using it.
In short:
UTF-8: Variable-width encoding, backwards compatible with ASCII. ASCII characters (U+0000 to U+007F) take 1 byte, code points U+0080 to U+07FF take 2 bytes, code points U+0800 to U+FFFF take 3 bytes, code points U+10000 to U+10FFFF take 4 bytes. Good for English text, not so good for Asian text.
UTF-16: Variable-width encoding. Code points U+0000 to U+FFFF take 2 bytes, code points U+10000 to U+10FFFF take 4 bytes. Bad for English text, good for Asian text.
UTF-32: Fixed-width encoding. All code points take four bytes. An enormous memory hog, but fast to operate on. Rarely used.
In long: see Wikipedia: UTF-8, UTF-16, and UTF-32.
UTF-8 is variable 1 to 4 bytes.
UTF-16 is variable 2 or 4 bytes.
UTF-32 is fixed 4 bytes.
Unicode defines a single huge character set, assigning one unique integer value to every graphical symbol (that is a major simplification, and isn't actually true, but it's close enough for the purposes of this question). UTF-8/16/32 are simply different ways to encode this.
In brief, UTF-32 uses 32-bit values for each character. That allows them to use a fixed-width code for every character.
UTF-16 uses 16-bit by default, but that only gives you 65k possible characters, which is nowhere near enough for the full Unicode set. So some characters use pairs of 16-bit values.
And UTF-8 uses 8-bit values by default, which means that the 127 first values are fixed-width single-byte characters (the most significant bit is used to signify that this is the start of a multi-byte sequence, leaving 7 bits for the actual character value). All other characters are encoded as sequences of up to 4 bytes (if memory serves).
And that leads us to the advantages. Any ASCII-character is directly compatible with UTF-8, so for upgrading legacy apps, UTF-8 is a common and obvious choice. In almost all cases, it will also use the least memory. On the other hand, you can't make any guarantees about the width of a character. It may be 1, 2, 3 or 4 characters wide, which makes string manipulation difficult.
UTF-32 is opposite, it uses the most memory (each character is a fixed 4 bytes wide), but on the other hand, you know that every character has this precise length, so string manipulation becomes far simpler. You can compute the number of characters in a string simply from the length in bytes of the string. You can't do that with UTF-8.
UTF-16 is a compromise. It lets most characters fit into a fixed-width 16-bit value. So as long as you don't have Chinese symbols, musical notes or some others, you can assume that each character is 16 bits wide. It uses less memory than UTF-32. But it is in some ways "the worst of both worlds". It almost always uses more memory than UTF-8, and it still doesn't avoid the problem that plagues UTF-8 (variable-length characters).
Finally, it's often helpful to just go with what the platform supports. Windows uses UTF-16 internally, so on Windows, that is the obvious choice.
Linux varies a bit, but they generally use UTF-8 for everything that is Unicode-compliant.
So short answer: All three encodings can encode the same character set, but they represent each character as different byte sequences.
Unicode is a standard and about UTF-x you can think as a technical implementation for some practical purposes:
UTF-8 - "size optimized": best suited for Latin character based data (or ASCII), it takes only 1 byte per character but the size grows accordingly symbol variety (and in worst case could grow up to 6 bytes per character)
UTF-16 - "balance": it takes minimum 2 bytes per character which is enough for existing set of the mainstream languages with having fixed size on it to ease character handling (but size is still variable and can grow up to 4 bytes per character)
UTF-32 - "performance": allows using of simple algorithms as result of fixed size characters (4 bytes) but with memory disadvantage
I tried to give a simple explanation in my blogpost.
UTF-32
requires 32 bits (4 bytes) to encode any character. For example, in order to represent the "A" character code-point using this scheme, you'll need to write 65 in 32-bit binary number:
00000000 00000000 00000000 01000001 (Big Endian)
If you take a closer look, you'll note that the most-right seven bits are actually the same bits when using the ASCII scheme. But since UTF-32 is fixed width scheme, we must attach three additional bytes. Meaning that if we have two files that only contain the "A" character, one is ASCII-encoded and the other is UTF-32 encoded, their size will be 1 byte and 4 bytes correspondingly.
UTF-16
Many people think that as UTF-32 uses fixed width 32 bit to represent a code-point, UTF-16 is fixed width 16 bits. WRONG!
In UTF-16 the code point maybe represented either in 16 bits, OR 32 bits. So this scheme is variable length encoding system. What is the advantage over the UTF-32? At least for ASCII, the size of files won't be 4 times the original (but still twice), so we're still not ASCII backward compatible.
Since 7-bits are enough to represent the "A" character, we can now use 2 bytes instead of 4 like the UTF-32. It'll look like:
00000000 01000001
UTF-8
You guessed right.. In UTF-8 the code point maybe represented using either 32, 16, 24 or 8 bits, and as the UTF-16 system, this one is also variable length encoding system.
Finally we can represent "A" in the same way we represent it using ASCII encoding system:
01001101
A small example where UTF-16 is actually better than UTF-8:
Consider the Chinese letter "語" - its UTF-8 encoding is:
11101000 10101010 10011110
While its UTF-16 encoding is shorter:
10001010 10011110
In order to understand the representation and how it's interpreted, visit the original post.
UTF-8
has no concept of byte-order
uses between 1 and 4 bytes per character
ASCII is a compatible subset of encoding
completely self-synchronizing e.g. a dropped byte from anywhere in a stream will corrupt at most a single character
pretty much all European languages are encoded in two bytes or less per character
UTF-16
must be parsed with known byte-order or reading a byte-order-mark (BOM)
uses either 2 or 4 bytes per character
UTF-32
every character is 4 bytes
must be parsed with known byte-order or reading a byte-order-mark (BOM)
UTF-8 is going to be the most space efficient unless a majority of the characters are from the CJK (Chinese, Japanese, and Korean) character space.
UTF-32 is best for random access by character offset into a byte-array.
I made some tests to compare database performance between UTF-8 and UTF-16 in MySQL.
Update Speeds
UTF-8
UTF-16
Insert Speeds
Delete Speeds
In UTF-32 all of characters are coded with 32 bits. The advantage is that you can easily calculate the length of the string. The disadvantage is that for each ASCII characters you waste an extra three bytes.
In UTF-8 characters have variable length, ASCII characters are coded in one byte (eight bits), most western special characters are coded either in two bytes or three bytes (for example € is three bytes), and more exotic characters can take up to four bytes. Clear disadvantage is, that a priori you cannot calculate string's length. But it's takes lot less bytes to code Latin (English) alphabet text, compared to UTF-32.
UTF-16 is also variable length. Characters are coded either in two bytes or four bytes. I really don't see the point. It has disadvantage of being variable length, but hasn't got the advantage of saving as much space as UTF-8.
Of those three, clearly UTF-8 is the most widely spread.
I'm surprised this question is 11yrs old and not one of the answers mentioned the #1 advantage of utf-8.
utf-8 generally works even with programs that are not utf-8 aware. That's partly what it was designed for. Other answers mention that the first 128 code points are the same as ASCII. All other code points are generated by 8bit values with the high bit set (values from 128 to 255) so that from the POV of a non-unicode aware program it just sees strings as ASCII with some extra characters.
As an example let's say you wrote a program to add line numbers that effectively does this (and to keep it simple let's assume end of line is just ASCII 13)
// pseudo code
function readLine
if end of file
return null
read bytes (8bit values) into string until you hit 13 or end or file
return string
function main
lineNo = 1
do {
s = readLine
if (s == null) break;
print lineNo++, s
}
Passing a utf-8 file to this program will continue to work. Similarly, splitting on tabs, commas, parsing for ASCII quotes, or other parsing for which only ASCII values are significant all just work with utf-8 because no ASCII value appear in utf-8 except when they are actually meant to be those ASCII values
Some other answers or comments mentions that utf-32 has the advantage that you can treat each codepoint separately. This would suggest for example you could take a string like "ABCDEFGHI" and split it at every 3rd code point to make
ABC
DEF
GHI
This is false. Many code points affect other code points. For example the color selector code points that lets you choose between 👨🏻‍🦳👨🏼‍🦳👨🏽‍🦳👨🏾‍🦳👨🏿‍🦳. If you split at any arbitrary code point you'll break those.
Another example is the bidirectional code points. The following paragraph was not entered backward. It is just preceded by the 0x202E codepoint
‮This line is not typed backward it is only displayed backward
So no, utf-32 will not let you just randomly manipulate unicode strings without a thought to their meanings. It will let you look at each codepoint with no extra code.
FYI though, utf-8 was designed so that looking at any individual byte you can find out the start of the current code point or the next code point.
If you take a arbitrary byte in utf-8 data. If it is < 128 it's the correct code point by itself. If it's >= 128 and < 192 (the top 2 bits are 10) then to find the start of the code point you need to look the preceding byte until you find a byte with a value >= 192 (the top 2 bits are 11). At that byte you've found the start of a codepoint. That byte encodes how many subsequent bytes make the code point.
If you want to find the next code point just scan until the byte < 128 or >= 192 and that's the start of the next code point.
Num Bytes
1st code point
last code point
Byte 1
Byte 2
Byte 3
Byte 4
1
U+0000
U+007F
0xxxxxxx
2
U+0080
U+07FF
110xxxxx
10xxxxxx
3
U+0800
U+FFFF
1110xxxx
10xxxxxx
10xxxxxx
4
U+10000
U+10FFFF
11110xxx
10xxxxxx
10xxxxxx
10xxxxxx
Where xxxxxx are the bits of the code point. Concatenate the xxxx bits from the bytes to get the code point
Depending on your development environment you may not even have the choice what encoding your string data type will use internally.
But for storing and exchanging data I would always use UTF-8, if you have the choice. If you have mostly ASCII data this will give you the smallest amount of data to transfer, while still being able to encode everything. Optimizing for the least I/O is the way to go on modern machines.
As mentioned, the difference is primarily the size of the underlying variables, which in each case get larger to allow more characters to be represented.
However, fonts, encoding and things are wickedly complicated (unnecessarily?), so a big link is needed to fill in more detail:
http://www.cs.tut.fi/~jkorpela/chars.html#ascii
Don't expect to understand it all, but if you don't want to have problems later it's worth learning as much as you can, as early as you can (or just getting someone else to sort it out for you).
Paul.
After reading through the answers, UTF-32 needs some loving.
C#:
Data1 = RandomNumberGenerator.GetBytes(500_000_000);
sw = Stopwatch.StartNew();
int l = Encoding.UTF8.GetString(Data1).Length;
sw.Stop();
Console.WriteLine($"UTF-8: Elapsed - {sw.ElapsedMilliseconds * .001:0.000s} Size - {l:###,###,###}");
sw = Stopwatch.StartNew();
l = Encoding.Unicode.GetString(Data1).Length;
sw.Stop();
Console.WriteLine($"Unicode: Elapsed - {sw.ElapsedMilliseconds * .001:0.000s} Size - {l:###,###,###}");
sw = Stopwatch.StartNew();
l = Encoding.UTF32.GetString(Data1).Length;
sw.Stop();
Console.WriteLine($"UTF-32: Elapsed - {sw.ElapsedMilliseconds * .001:0.000s} Size - {l:###,###,###}");
sw = Stopwatch.StartNew();
l = Encoding.ASCII.GetString(Data1).Length;
sw.Stop();
Console.WriteLine($"ASCII: Elapsed - {sw.ElapsedMilliseconds * .001:0.000s} Size - {l:###,###,###}");
UTF-8 -- Elapsed 9.939s - Size 473,752,800
Unicode -- Elapsed 0.853s - Size 250,000,000
UTF-32 -- Elapsed 3.143s - Size 125,030,570
ASCII -- Elapsed 2.362s - Size 500,000,000
UTF-32 -- MIC DROP
In short, the only reason to use UTF-16 or UTF-32 is to support non-English and ancient scripts respectively.
I was wondering why anyone would chose to have non-UTF-8 encoding when it is obviously more efficient for web/programming purposes.
A common misconception - the suffixed number is NOT an indication of its capability. They all support the complete Unicode, just that UTF-8 can handle ASCII with a single byte, so is MORE efficient/less corruptible to the CPU and over the internet.
Some good reading: http://www.personal.psu.edu/ejp10/blogs/gotunicode/2007/10/which_utf_do_i_use.html
and http://utf8everywhere.org