I'm trying to replace current time with Test::MockTime module. It works fine:
use Test::MockTime qw(:all);
use Time::Local;
my $sec = 0;
my $min = 0;
my $hour = 14;
my $mday = 1; #1-31
my $mon = 1; #1-12
my $year = 2013; #1970-...
set_fixed_time(timelocal($sec,$min,$hour,$mday,$mon-1,$year-1900));
print join "\n", localtime;
But, when I use Time::localtime, nothing happens:
use Time::localtime;
use Time::Local;
use Test::MockTime qw(:all);
my ($sec,$min,$hour,$mday,$mon,$year)=(0,0,14,1,1,2013);
set_fixed_time(timelocal($sec,$min,$hour,$mday,$mon-1,$year-1900));
my $t=localtime();
my $xmon=$t->mon;
my $xyear=$t->year;
my $xday=$t->mday;
my $xmon_now=$xmon+1;
my $xyear_now=$xyear+1900;
print "$xmon_now $xyear_now\n";
The output will be "12 2012"
How can I change time in my tests when Time::localtime is used?
Thanks and sorry for my English
UPD:
use Time::localtime;
use Test::MockTime qw(:all);
didnt work
use Test::MockTime qw(:all);
use Time::localtime;
works fine) perl magic
Test::MockTime overrides localtime, but Time::localtime uses CORE::localtime (the unoverrided version of localtime). You'd have to rewrite Time::localtime's localtime.
Related
I have a script which will print Start & End time of previous hour of UTC/GMT.
#!/usr/local/bin/perl
use strict;
use warnings;
use POSIX qw(strftime);
my ($tmp_date, $tmp_hour, $Start, $End);
my $date = strftime '%Y-%m-%d', gmtime();
print "Date:$date\n";
my $hour = strftime '%H', gmtime();
print "Hour:$hour\n";
if ($hour == "00"){
$tmp_date = $date-1;
$tmp_hour = "23";
} else {
$tmp_hour = $hour-1;
$tmp_date = $date;
}
$a = length($tmp_hour);
if ($a == 1 ){
$tmp_hour="0".$tmp_hour;
}
$Start = $tmp_date.".".$tmp_hour."00";
$End = $tmp_date.".".$hour."05";
if ($End =~ /0005/){
$tmp_date = `TZ=GMT-12 date +%Y%m%d`;
$End =$tmp_date.".".$hour."05";
}
print "Start:$Start, End:$End\n";
For example, lets say now UTC time is: Wed Jun 10 10:18:57 UTC 2020
This should print Start & End time as 2020-06-10.0900 2020-06-10.1005 respectively.
This script is working as expected. But when Daylight savings happens will there be any impact on fetching Start & End time?
I want experts suggestions how can I avoid unnecessary if statements and achieve it by the use of Perl module itself.
PS: Perl version: v5.10.1. Please suggest Perl modules which comes with standard Perl installation (Ex: POSIX, Time::Local etc.) for solution of above problem.
As you're using gmtime(), any DST changes will have no effect at all.
I'm not sure why your end time ends with '05', I would have thought that the end of the hour comes at '00'.
Here's how I'd write it with Time::Piece and Time::Seconds.
#!/usr/bin/perl
use strict;
use warnings;
use feature 'say';
use Time::Piece;
use Time::Seconds;
my $end = gmtime->truncate(to => 'hour');
my $start = $end - ONE_HOUR;
my $format = '%Y-%m-%d %H:%M:%S';
say 'Start: ', $start->strftime($format);
say 'End: ', $end->strftime($format);
If you really want the end time to be five past the hour, then add this line after the ONE_HOUR line:
$end += (5 * ONE_MINUTE);
You can, of course, use any of the standard strftime() sequences to change the format of the output.
In php you could just do
strtotime("+1 days");
And get the machine time for the next day.
I want to try the same with Perl, I'm going to be doing a sort of cron job to execute certain methods.
I know you could it use str2time from the module http://search.cpan.org/~gaas/HTTP-Date-6.02/lib/HTTP/Date.pm I just can't seem to figure it out.
I tried the following, but I'm unsure if I did it right
use HTTP::Date qw(str2time);
use Time::Piece;
use Time::Seconds;
my $lol = localtime();
my $time = $lol - ONE_HOUR*($lol->hour + 24);
print "Time: " . str2time($time);
use Time::Piece;
use Time::Seconds;
my $t1 = localtime() + ONE_DAY;
print $t1->epoch;
Tool for the job here is Time::Piece.
#!/usr/bin/perl
use strict;
use warnings;
use Time::Piece;
my $this_time = localtime();
print $this_time + 60*60*24,"\n";
The code below only expresses the difference in months and days like so:
0:2:0:5:0:0:0
So it works, but I want to know the total number of days given that $ADDate can vary quite a bit. Hopefully this is simple, and I just completely missed how to do it.
#!/usr/bin/perl
use Date::Manip 6.42;
my $ADDate = "20131211000820.0Z";
my $var;
my #val;
my $diff;
calc_period($ADDate = "20131211000820.0Z");
sub calc_period
{
$ADDate =~ s/^([\d][\d][\d][\d])([\d][\d])([\d][\d])/$1-$2-$3/gs;
$ADDate =~ s/.........$//gs;
$today = ParseDate("today");
$beginning = ParseDate($ADDate);
$end = ParseDate($today);
$delta = DateCalc($beginning,$end,\$err,1);
#$delta =~ s/([\d+][:][\d+]):.*$/$1/gs;
print "$delta\n";
print "$ADDate\n";
}
I'm not familiar with Date::Manip, but I think another way to do this is to use Time::Piece to parse your string and do whatever you like with that since taking the difference of two Time::Piece object returns a Time::Seconds object.
The following example will show the difference of the current time and the hardcoded time and show it in days.
#!/usr/bin/perl
use strict;
use warnings;
use Time::Piece;
use Time::Seconds;
my $d = "20131211000820.0Z";
my $t = Time::Piece->strptime($d, "%Y%m%d%H%M%S.0Z");
my $now = Time::Piece->localtime();
my $diff = Time::Seconds->new($now - $t);
print $diff->days, "\n";
NigoroJr has already given you an answer. However, just as an FYI, the following is how I would clean up the code you originally provided:
#!/usr/bin/perl
use Date::Manip 6.42;
use strict;
use warnings;
calc_period("20131211000820.0Z");
sub calc_period {
my $date = shift;
$date =~ s/^(\d{4})(\d{2})(\d{2}).*/$1-$2-$3/;
my $beginning = ParseDate($date);
my $end = ParseDate("today");
my $delta = DateCalc($beginning, $end, \my $err, 1);
#$delta =~ s/([\d+][:][\d+]):.*$/$1/gs;
print "$delta\n";
print "$date\n";
}
Biggest differences being the proper use of a function and scoped variables, and a simplification of your regex.
I was unable to find a clean way to get Date::Manip to output a strict delta in days though, so the other module is the way to go.
I want to fetch current date and exactly last year date using perl in the format of 140220 and 130220.
Perhaps the following will help:
use strict;
use warnings;
use Time::Piece;
my $time = Time::Piece->new;
my $currDate = $time->strftime('%y%m%d');
print $currDate, "\n";
my $lastYear = $time->add_years(-1)->strftime('%y%m%d');
print $lastYear;
Output:
140219
130219
Here is a sample using DateTime.
#!/usr/bin/env perl
use strict;
use warnings;
use feature qw/say/;
use DateTime;
my $dt = DateTime->now();
my $year_ago = DateTime->now()->subtract(years => 1);
say $dt->strftime("%y%m%d");
say $year_ago->strftime("%y%m%d");
I'm working on a Perl program at work and stuck on (what I think is) a trivial problem. I simply need to build a string in the format '06/13/2012' (always 10 characters, so 0's for numbers less than 10).
Here's what I have so far:
use Time::localtime;
$tm=localtime;
my ($day,$month,$year)=($tm->mday,$tm->month,$tm->year);
You can do it fast, only using one POSIX function. If you have bunch of tasks with dates, see the module DateTime.
use POSIX qw(strftime);
my $date = strftime "%m/%d/%Y", localtime;
print $date;
You can use Time::Piece, which shouldn't need installing as it is a core module and has been distributed with Perl 5 since version 10.
use Time::Piece;
my $date = localtime->strftime('%m/%d/%Y');
print $date;
output
06/13/2012
Update
You may prefer to use the dmy method, which takes a single parameter which is the separator to be used between the fields of the result, and avoids having to specify a full date/time format
my $date = localtime->dmy('/');
This produces an identical result to that of my original solution
use DateTime qw();
DateTime->now->strftime('%m/%d/%Y')
expression returns 06/13/2012
If you like doing things the hard way:
my (undef,undef,undef,$mday,$mon,$year) = localtime;
$year = $year+1900;
$mon += 1;
if (length($mon) == 1) {$mon = "0$mon";}
if (length($mday) == 1) {$mday = "0$mday";}
my $today = "$mon/$mday/$year";
use Time::Piece;
...
my $t = localtime;
print $t->mdy("/");# 02/29/2000
Perl Code for Unix systems:
# Capture date from shell
my $current_date = `date +"%m/%d/%Y"`;
# Remove newline character
$current_date = substr($current_date,0,-1);
print $current_date, "\n";
Formating numbers with leading zero is done easily with "sprintf", a built-in function in perl (documentation with: perldoc perlfunc)
use strict;
use warnings;
use Date::Calc qw();
my ($y, $m, $d) = Date::Calc::Today();
my $ddmmyyyy = sprintf '%02d.%02d.%d', $d, $m, $y;
print $ddmmyyyy . "\n";
This gives you:
14.05.2014