I want to show all the rows of the table where col1 has duplicates.
+------+------+------+
| col1 | col2 | col3 |
+------+------+------+
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| 2 | 0 | 0 |
| 3 | 0 | 0 |
| 3 | 1 | 1 |
| 4 | 0 | 0 |
+------+------+------+
The results should be:
+------+------+------+
| col1 | col2 | col3 |
+------+------+------+
| 1 | 0 | 0 |
| 1 | 1 | 1 |
| 3 | 0 | 0 |
| 3 | 1 | 1 |
+------+------+------+
I've tried some queries with no luck, so here I am asking for your help.
Depending on your version of sql server you can use:
select col1, col2, col3
from
(
select col1, col2, col3,
count(col1) over(partition by col1) cnt
from yourtable
) src
where cnt > 1
See SQL Fiddle with Demo
select t.col1, t.col2, t.col3
from mytable t join (select col1
from mytable
group by col1
having count(*) > 1) t2
on t.col1 = t2.col1
Let me add one more variant solution. If you have a pk column that has a UNIQUE or PRIMARY KEY constraint, you can use:
select col1, col2, col3
from <yourTable> t1
where exists
(select *
from <yourTable> t2
where t2.col1 = t1.col1
and t2.pk <> t1.pk
) ;
If the name of the table is T5 then use this:
SELECT COL1, COL2, COL3
FROM T5
WHERE COL1 IN
(
SELECT COL1
FROM T5
GROUP BY COL1
HAVING COUNT(COL1)>=2
)
I checked and the above should not use any nonstandard SQL. I am assuming that is the case for the others.
select col1, col2, col3
from <yourTable> t1
where exists
(select null
from <yourTable> t2
where t2.col1 = t1.col1
group by t2.col1
having count(*) > 1)
sqlFiddle
Guess I am too late.. but how about a left join...
SQLFIDDLE DEMO
Query:
SELECT DISTINCT x.col1, x.col2, x.col3
FROM ab y
LEFT JOIN
ab x
ON y.col1=x.col1 and ( y.col2<> x.col2
OR x.col3<>y.col3 )
where not (x.col3 is null)
and not (x.col2 is null)
;
Results:
COL1 COL2 COL3
1 0 0
1 1 1
3 0 0
3 1 1
Related
I have 4 tables
Table1
id | name
1 | A
2 | B
Table2
id | name1
1 | C
2 | D
Table3
id | name2
1 | E
2 | F
Table4
id | name1_id | name2_id | name3_id
1 | 1 | 2 | 1
2 | 2 | 2 | 2
3 | 1 | 2 | 1
4 | 2 | 1 | 1
5 | 1 | 1 | 2
6 | 2 | 2 | 1
7 | 1 | 1 | 2
8 | 2 | 1 | 1
9 | 1 | 2 | 1
10 | 2 | 2 | 1
Now I want to join all tables with 4 and get this type of output
name | count
{A,B} | {5, 5}
{C,D} | {5, 6}
{E,F} | {7, 3}
I tried this
select array_agg(distinct(t1.name)), array_agg(distinct(temp.test))
from
(select t4.name1_id, (count(t4.name1_id)) "test"
from table4 t4 group by t4.name1_id
) temp
join table1 t1
on temp.name1_id = t1.id
I am trying to achieve this. Anybody can help me.
Calculate the counts for every table separately and union the results:
select
array_agg(name order by name) as name,
array_agg(count order by name) as count
from (
select 1 as t, name, count(*)
from table4
join table1 t1 on t1.id = name1_id
group by name
union all
select 2 as t, name, count(*)
from table4
join table2 t2 on t2.id = name2_id
group by name
union all
select 3 as t, name, count(*)
from table4
join table3 t3 on t3.id = name3_id
group by name
) s
group by t;
name | count
-------+-------
{A,B} | {5,5}
{C,D} | {4,6}
{E,F} | {7,3}
(3 rows)
I need Postgres DISTINCT ON equivalent in HQL. For example consider the following.
SELECT DISTINCT ON (Col2) Col1, Col4 FROM tablename;
on table
Col1 | Col2 | Col3 | Col4
---------------------------------
AA1 | A | 2 | 1
AA2 | A | 4 | 2
BB1 | B | 2 | 3
BB2 | B | 5 | 4
Col2 will not be shown in the result as below
Col1 | Col4
------------
AA1 | 1
BB1 | 3
Can anyone give a solution in HQL. I need to use DISTINCT as it is part of a bigger query.
Sorry but I misread your question:
No, Hibernate does not support a DISTINCT ON query.
Here is possible duplicate of your question: Postgresql 'select distinct on' in hibernate
I have table1:
col1 (integer) | col2 (varchar[]) | col3 (integer)
----------------------------------------------------
1 | {A,B,C} | 2
1 | {A} | 5
1 | {A,B} | 1
2 | {A,B} | 2
2 | {A} | 3
2 | {B} | 1
I want summarize 'col3 ' with a GROUP BY 'col1 ' by keeping only DISTINCT values from 'col3 '
Expected result below :
col1 (integer) | col2 (varchar[]) | col3 (integer)
----------------------------------------------------
1 | {A,B,C} | 8
2 | {A,B} | 6
I tried this :
SELECT col1, array_to_string(array_accum(col2), ','::text),sum(col3) FROM table1 GROUP BY col1
but the result is not the one expected :
col1 (integer) | col2 (varchar[]) | col3 (integer)
---------------------------------------------------------------
1 | {A,B,C,A,A,B} | 8
2 | {A,B,A,B} | 6
do you have any suggestion?
If the logic of which col2 you want is by the largest (like in your expected output is {A,B,C} & {A,B}.
SELECT col1, (SELECT sub.col2
FROM table1 sub
INNER JOIN table1 sub ON MAX(char_length(sub.col2)) = col2
WHERE sub.col1 = col1)
SUM(col3)
FROM table1
GROUP BY col1
SELECT
col1,
array_to_string(array_accum(col2), ','::text),
sum(col3)
FROM table1
GROUP BY col1;
but array_to_string concatenates array elements using supplied delimiter and optional null string.
You have to devise a different strategy like using array_dims(anyarray) to select the array with max elements or create a new aggregation function.
For this you could be interested in this answer:
eliminate duplicate array values in postgres
Actually, I got a good answer about the similar issue on below thread, but I need one more solution for different data set.
How to get the latest 2 rows ( PostgreSQL )
The Data set has historical data, and I just want to get sum(value) for the group on the latest gather_time.
The final result should be as following:
name | col1 | gather_time | sum
-------+------+---------------------+-----
first | 100 | 2016-01-01 23:12:49 | 6
first | 200 | 2016-01-01 23:11:13 | 4
However, I just can see the data for the one group(first-100) with a query below meaning that there is no data for the second group(first-200).
Thing is that I need to get the one row per the group.
The number of the group can be vary.
select name,col1,gather_time,sum(value)
from testtable
group by name,col1,gather_time
order by gather_time desc
limit 2;
name | col1 | gather_time | sum
-------+------+---------------------+-----
first | 100 | 2016-01-01 23:12:49 | 6
first | 100 | 2016-01-01 23:11:19 | 6
(2 rows)
Can you advice me to accomplish this requirement?
Data set
create table testtable
(
name varchar(30),
col1 varchar(30),
col2 varchar(30),
gather_time timestamp,
value integer
);
insert into testtable values('first','100','q1','2016-01-01 23:11:19',2);
insert into testtable values('first','100','q2','2016-01-01 23:11:19',2);
insert into testtable values('first','100','q3','2016-01-01 23:11:19',2);
insert into testtable values('first','200','t1','2016-01-01 23:11:13',2);
insert into testtable values('first','200','t2','2016-01-01 23:11:13',2);
insert into testtable values('first','100','q1','2016-01-01 23:11:11',2);
insert into testtable values('first','100','q1','2016-01-01 23:12:49',2);
insert into testtable values('first','100','q2','2016-01-01 23:12:49',2);
insert into testtable values('first','100','q3','2016-01-01 23:12:49',2);
select *
from testtable
order by name,col1,gather_time;
name | col1 | col2 | gather_time | value
-------+------+------+---------------------+-------
first | 100 | q1 | 2016-01-01 23:11:11 | 2
first | 100 | q2 | 2016-01-01 23:11:19 | 2
first | 100 | q3 | 2016-01-01 23:11:19 | 2
first | 100 | q1 | 2016-01-01 23:11:19 | 2
first | 100 | q3 | 2016-01-01 23:12:49 | 2
first | 100 | q1 | 2016-01-01 23:12:49 | 2
first | 100 | q2 | 2016-01-01 23:12:49 | 2
first | 200 | t2 | 2016-01-01 23:11:13 | 2
first | 200 | t1 | 2016-01-01 23:11:13 | 2
One option is to join your original table to a table containing only the records with the latest gather_time for each name, col1 group. Then you can take the sum of the value column for each group to get the result set you want.
SELECT t1.name, t1.col1, MAX(t1.gather_time) AS gather_time, SUM(t1.value) AS sum
FROM testtable t1 INNER JOIN
(
SELECT name, col1, col2, MAX(gather_time) AS maxTime
FROM testtable
GROUP BY name, col1, col2
) t2
ON t1.name = t2.name AND t1.col1 = t2.col1 AND t1.col2 = t2.col2 AND
t1.gather_time = t2.maxTime
GROUP BY t1.name, t1.col1
If you wanted to use a subquery in the WHERE clause, as you attempted in your OP, to restrict to only records with the latest gather_time then you could try the following:
SELECT name, col1, gather_time, SUM(value) AS sum
FROM testtable t1
WHERE gather_time =
(
SELECT MAX(gather_time)
FROM testtable t2
WHERE t1.name = t2.name AND t1.col1 = t2.col1
)
GROUP BY name, col1
I have query:
Select * from mytable order by 'date'
And result:
date | item_id | user_id | some_data
------------------------------------------
2015-01-01 | 1 | 1 | null
2015-01-01 | 1 | 1 | null
2015-01-02 | 1 | 1 | null
2015-01-03 | 1 | 1 | null
2015-01-03 | 1 | 2 | null
2015-01-04 | 1 | 1 | null
2015-01-05 | 1 | 2 | null
And I want to get position of first row where user_id = 2. In this example it be 5. How to do it?
select pos_overall
from (
select user_id,
row_number() over (order by "date") as pos_overall,
row_number() over (partition by user_id order by "date") as user_pos
from mytable
) t
where user_id = 2
and user_pos = 1
You can use the row_number() function to number the rows in order of date, user_id and then select the minimum value:
select min(rn)
from (
select
user_id, row_number() over (order by date, user_id) as rn
from mytable
) x
where user_id = 2;
If the item_id can change you might want to include that in the order by clause for the row_number function in the derived table.