I have some files to process , but i have missing files in middle
i am using
for i=1:file;
fid = fopen(['Raw',num2str(i),'.txt']);
D = textscan(fid1,'%*f %f%*f%*f%*f%f%f%[^\n]','delimiter',';', 'headerlines',50,'CollectOutput', 1);
fclose(fid);
Now the rest of program works well when i have files in order
i.e, 100,200 any number of files in my folder in order as Raw1.txt, Raw2.txt, Raw3.txt, ....
I get into trouble as soon as there are missing files like Raw1.txt, Raw4.txt, Raw5.txt
How do i iterate my text scan so it can ignore the file numbering?
Thanks
Edit :
By missing files i mostly mean numbers after 'Raw'
My files get generated as Raw1, Raw2, Raw3............ Raw400.txt
When all the files are in order and present i have no problem.
when i have some missing or jumps like for example
Raw1 . Raw2.......... Raw10, Raw15, Raw16
I have trouble as there is jump from Raw10.txt to Raw15.txt
I have same problem if my files start at anything other than Raw1.txt
look for exist in matlab documentation. Something like this should work:
for i=1:file;
if exist(['Raw',num2str(i),'.txt'], 'file')
% File exists!
fid = fopen(['Raw',num2str(i),'.txt']);
D = textscan(fid1,'%*f %f%*f%*f%*f%f%f%[^\n]','delimiter',';', 'headerlines',50,'CollectOutput', 1);
fclose(fid);
end
end
Note that exist(Name, 'file') checks for the file's directory too, so either give the full file name (i.e. with path), or try something like if exist(Name, 'file') == 2
Related
I have many .txt files that contain n rows and 7 columns each delimited with whitespace. I want to convert each file to .mat file and save that in the same folder.
I tried this but it's not working:
files = dir('*.txt');
for file = files'
data=importdata(file.name);
save(file.name, 'data');
end
While this works for a single file, i want to do it programmably since the number of .txt files i have is very large:
data=importdata('myfile.txt');
save('myfile', 'data');
Thank you for your help
This should work
files = dir('*.txt');
for idx = 1:length(files)
file_name = files(idx).name;
fprintf("Processing File %s\n",file_name);
data=importdata(file_name);
[filepath,name,ext] = fileparts(fullfile(pwd,file_name));
save([name '.mat'],'data');
end
dir creates a stucture which you need to index through so we create the for loop to start at 1 and keep going until all the elements of dir have been processed.
Note in the code, I've also added a section to split the file name (e.g file1.txt) in to the file name and extension. This is so we only use the name part and not the extension when creating the mat file.
#scotty3785's answers worked well and also this worked for me in case somebody needs it:
files = dir('*.txt');
for i=1:length(files)
data=importdata(files(i).name);
save(erase(files(i).name,".txt"), 'data');
end
I have a lot of .fig files that are named like this: 20160922_01_id_32509055.fig, 20160921_02_id_53109418.fig and so on.
So I thought that I create a script that loop through all the .fig files in the folder and group(copy) them into another folder(s) based on the last number in the file name. The folder is created based on the id number. Is this possible?
I have been looking on other solutions involving looping through folders but I am totally fresh. This would make it easier for me to check the .fig files while I am learning to do other stuff in Matlab.
All is possible with MATLAB! We can use dir to get all .fig files, then use regexp to get the numeric part of each filename and then use copyfile to copy the file to it's new home. If you want to move it instead, you can use movefile instead .
% Define where the files are now and where you want them.
srcdir = '/my/input/directory';
outdir = '/my/output/directory';
% Find all .fig files in the source directory
figfiles = dir(fullfile(srcdir, '*.fig'));
figfiles = {figfiles.name};
for k = 1:numel(figfiles)
% Extract the last numeric part from the filename
numpart = regexp(figfiles{k}, '(?<=id_)\d+', 'match', 'once');
% Determine the folder we are going to put it in
destination = fullfile(outdir, numpart);
% Make sure the folder exists
if ~exist(destination, 'dir')
mkdir(destination)
end
% Copy the file there!
copyfile(fullfile(srcdir, figfiles{k}), destination)
end
Here's an example how to identify and copy the files. I'll let you do the for loop :)
>> Figs = dir('*.fig'); % I had two .fig files on my desktop
>> Basename = strsplit(Figs(1).name, '.');
>> Id = strsplit(Basename{1}, '_');
>> Id = Id{3};
>> mkdir(fullfile('./',Id));
>> copyfile(Figs(1).name, fullfile('./',Id));
Play with the commands to see what they do. It should be straightforward :)
I'm trying to access images in a matlab interface
my code is as follows:
global im2 im
axes(handles.axes4);
[path1, user_cance]= imgetfile();
if user_cance
msgbox(sprintf('Error'), 'Error', 'Error');
return
end
srcFiles = dir('C:\Users\User\Desktop\images test\yale faces\yalefaces\..');
% yale faces is the database folder
for i = 1 : length(srcFiles)
file_name=dir(strcat('C:\Users\User\Desktop\images test\yale faces\yalefaces'));
im2=imread(strcat('C:\Users\User\Desktop\images test\yale faces\yalefaces',file_name(i).name));
%processing of read image
end
the issue is that when I run the code, it gives the following error:
Can't open file "C:\Users\User\Desktop\images test\yale faces\yalefaces" for
reading;
you may not have read permission.
Does anyone know how to solve this issue?
When you do a directory listing (without any wildcards) you are going to get the current directory '.' and parent directory as well '..'. You can't read these like files because they are directories. You will need to filter out the directories prior to trying to read them with imread.
files = dir('C:\Users\User\Desktop\images test\yale faces\yalefaces');
% Remove directories
files = files(~[files.isdir]);
As a side note, it is very hard to tell what your code is doing, but I'm pretty sure it doesn't do what you hope.
It seems like you want to get all images within the database. If that's so, you'll want to do something like.
folder = 'C:\Users\User\Desktop\images test\yale faces\yalefaces';
% Get a list of all files in this folder
files = dir(folder);
files = files(~[files.isdir]);
for k = 1:numel(files)
% Append the folder with the filename to get the path and load
im2 = imread(fullfile(folder, files(k).name));
end
I highly discourage using strcat to construct file paths particularly because it removes trailing/leading whitespace from each input which can corrupt a filename. fullfile was designed for exactly this so please use that.
I am using MATLAB
I Have 51 files in their own directory all of .out extention created by a seperate program, all numbered 0 to 50.
ie
0.out
1.out
2.out
and so on til 50.out.
I need to load each file 1 by one to do calculations upon them within a for loop. How would I do this using the count variable to load the file, if the directory is set beforehand?
i.e.
%set directiory
cd(......)
%for loop
For count = 0:50,
data = count.out *<-----this line*
.....
Many thanks!
First generate the file name with
fileName = [int2str(count) '.out'];
then open the file with
fid = fopen(fileName, 'r');
The loading phase depends on the kind of file you want to read. Assuming it is a text file you can, for example, read it line after line with
while ~feof(fid)
line = fgetl(fid);
end
or use more specialized functions (see http://www.mathworks.it/it/help/matlab/text-files.html). Before the end of the for loop you'll have to close the file by calling
fclose(fid);
Another quite nice way to do it is to use the dir function
http://www.mathworks.co.uk/help/matlab/ref/dir.html
a = dir('c:\docs*.out')
Will give you a structure containing all the info about the *.out files in the directory you point it to, (or the path). You can then loop through it bit by bit. using fopen or csvread or whatever file reading function you want to use.
I wish to read files from a directory and iteratively perform an operation on each file. This operation does not require altering the file.
I understand that I should use a for loop for this. Thus far I have tried:
FILES = ls('path\to\folder');
for i = 1:size(FILES, 1);
STRU = pdbread(FILES{i});
end
The error returned here suggests to me, a novice, that listing a directory with ls() does not assign the contents to a data structure.
Secondly I tried creating a file containing on each line a path to a file, e.g.,
C:\Documents and Settings\My Documents\MATLAB\asd.pdb
C:\Documents and Settings\My Documents\MATLAB\asd.pdb
I then read this file using the following code:
fid = fopen('paths_to_files.txt');
FILES = textscan(fid, '%s');
FILES = FILES{1};
fclose(fid);
This code reads the file but creates a newline where a space exists in the pathway, i.e.
'C:\Documents'
'and'
'Setting\My'
'Documents\MATLAB\asd.pdb'
Ultimately, I then intended to use the for loop
for i = 1:size(FILES, 1)
PDB = pdbread(char(FILES{i}));
to read each file but pdbread() throws an error proclaiming that the file is of incorrect format or does not exist.
Is this due to the newline separation of paths when the pathway file is read in?
Any help or suggestions greatly apppreciated.
Thanks,
S :-)
First Get a list of all files matching your criteria:
( in this case pdb files in C:\My Documents\MATLAB )
matfiles = dir(fullfile('C:', 'My Documents', 'MATLAB', '*.pdb'))
Then read in a file as follows:
( Here i can vary from 1 to the number of files )
data = load(matfiles(i).name)
Repeat this until you have read all your files.
A simpler alternative if you can rename your files is as follows:-
First save the reqd. files as 1.pdb, 2.pdb, 3.pdb,... etc.
Then the code to read them iteratively in Matlab is as follows:
for i = 1:n
str = strcat('C:\My Documents\MATLAB', int2str(i),'.pdb');
data = load(matfiles(i).name);
% use our logic here
% before proceeding to the next file
end
I copy this from yahoo answers! It worked for me
% copy-paste the following into your command window or your function
% first, you have to find the folder
folder = uigetdir; % check the help for uigetdir to see how to specify a starting path, which makes your life easier
% get the names of all files. dirListing is a struct array.
dirListing = dir(folder);
% loop through the files and open. Note that dir also lists the directories, so you have to check for them.
for d = 1:length(dirListing)
if ~dirListing(1).isdir
fileName = fullfile(folder,dirListing(d).name); % use full path because the folder may not be the active path
% open your file here
fopen(fileName)
% do something
end % if-clause
end % for-loop