Objective-C how to disable user interaction selectively - iphone

I have a Main View Controller that has many subviews. What I want is to disable all other views except one subview and its subviews programmatically from the subview file. But all I get is all frozen views. What did I do wrong?
I tried this code:
#define kDontDisableUserInteraction 321
- (id)initWithFrame:(CGRect)frame
{
NSLog(#"initWithFrame");
self = [super initWithFrame:frame];
if (self) {
// Initialization code
self.tag = kDontDisableUserInteraction;
}
return self;
}
-(void)something{
MVC *myController = [self getMVC];
for (UIView* subview in myController.view.subviews) {
NSLog(#"subview.tag %i", subview.tag);
if (subview.tag != kDontDisableUserInteraction){
subview.userInteractionEnabled = NO;
}
}
for (UIView *view in self.subviews){
NSLog(#"enabled!");
view.userInteractionEnabled = YES;
}
}
- (MVC *)getMVC {
Class vcc = [MVC class]; // Called here to avoid calling it iteratively unnecessarily.
UIResponder *responder = self;
while ((responder = [responder nextResponder])) if ([responder isKindOfClass: vcc]) return (MVC *)responder;
return nil;
}

Following links may be helpful:
How to disable touch input to all views except the top-most view?
UIView -- "user interaction enabled" false on parent but true on child?

I solved it by applying a full screen of a button on all other views and get the one view that I want to have user interaction upon the button. This way I disallow the user to click on any function except the one view I want the user to click on certain functions.

Related

random UIView switcher

I have three different views in my iPhone app, and when the user presses a button, I need the view to change to either of the three views randomly. I've found this code, but i don't know how to load images..sorry but i'm newbie....!!
- (IBAction) yourBtnPressed : (id) sender
{
int i = arc4random() % 3;
if(i == 1)
{
//load first view
}
else if(i == 2)
{
//load second view
}
else
{
//load third view
}
}
if view are all in the same viewcontroller you can simply write
self.view = firstView;
or for more cool transition you can use these method
+ transitionWithView:duration:options:animations:completion:
+ transitionFromView:toView:duration:options:completion:
see apple documentation:
http://developer.apple.com/library/IOs/#documentation/UIKit/Reference/UIView_Class/UIView/UIView.html
If your views are in a .xib file you can use this code:
[self.view addSubview:aView];
If you think to create your views programmatically, then:
UIView *aView = [[UIView alloc] initWithFrame:aFrame];
// add contents to your aView here
[self.view addSubview:aView];
[aView release]; // if you don't need it anymore

adding a UIScrollView as a superview of 2 UITextview made no view can be scrolled

i have 2 textview in a viewcontroller. the 1st textview is not editable, but the 2nd is editable. i want to make both of them scroll in the same position and size when the keyboard is appear. I think i have to use UIScrollView as base of both of textview. And then i add the UIScrollView in xib (bot of textview are made in xib too). and this is the picture if this hierarchy :
in the viewDidLoad method, i add this code :
- (void)viewDidLoad {
[super viewDidLoad];
[scrollTextView addSubview:lineNumberTextView];
[scrollTextView addSubview:_codeTextView];
[lineNumberTextView bringSubviewToFront:scrollTextView];
[_codeTextView bringSubviewToFront:scrollTextView];
}
but after that i can't scroll anything. What i have to do?
thx for the advices
UPDATE
this my code after do some advises like mac gave to me :
- (void)viewDidLoad {
[super viewDidLoad];
scrollTextView.showsVerticalScrollIndicator = YES;
scrollTextView.showsHorizontalScrollIndicator = YES;
scrollTextView.scrollEnabled = YES;
_codeTextView.showsHorizontalScrollIndicator = NO;
_codeTextView.showsVerticalScrollIndicator = NO;
_codeTextView.scrollEnabled = YES;
_codeTextView.tag = 0;
_codeTextView.delegate = self;
lineNumberTextView.showsVerticalScrollIndicator = NO;
lineNumberTextView.showsHorizontalScrollIndicator = NO;
lineNumberTextView.scrollEnabled = YES;
lineNumberTextView.tag = 1;
lineNumberTextView.delegate = self;
}
but just the _codeTextView scroll, the lineTextVew stil didn't scroll...somebody know why??
Verify that user interaction enabled is checked in interface builder for the 2nd textview.
you give some tag values for both the textfields, and in the delegate methods, do userinteraction enabled(false,true)whatever you required.

scrollView delegates not working (scrollViewDidEndDecelerating)

I am building a sort of slide show where the user slides through the images himself via a scrollView with paging enabled. i have a view controller for portrait and a view controller for landscape. The portrait view controller works fine with the "scrollViewDidEndDecelerating" function but i did the same exact thing on the landscape view controller and it does not respond.
- (void)viewDidLoad {
[super viewDidLoad];
imageNamesArray = [[NSMutableArray alloc] initWithCapacity:LNumImages];
int x = 0;
for(x=0; x<LNumImages;x++) {
[imageNamesArray insertObject: [NSString stringWithFormat:#"kr_Page_%d.png",x+1] atIndex:x];
}
LScrollView.delegate = self;
LScrollView.pagingEnabled = YES;
LScrollView.showsHorizontalScrollIndicator = YES;
LScrollView.contentSize = CGSizeMake(LScrollWidth * LNumImages, LScrollHeight);
[self initImages:0];
}
- (void)LScrollViewDidEndDecelerating:(UIScrollView *)LScrollView {
NSLog(#"stopped");
//does not get called
//[self arangeImages];
}
Because you're not implementing a UIScrollViewDelegate method. Note you're implementing LScrollViewDidEndDecelerating: and not scrollViewDidEndDecelerating:
See the UIScrollViewDelegate documentation for more information.

dismissing the NumberPad keyboard from a UIScrollView

I have an application with UIScrollView added as a subview of UIView. This Scroll view has a textfield with keyboard type set to numberPad.
Now the problem is , i want to dismiss the keyboard when i tap anywhere else in the scroll view. how can i do this ... ?
Just call the textField's resignFirstResponder in the touch handler.
(void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event {
[myTextField resignFirstResponder];
}
When I added the gesture to a subclass of UIScrollView, I was having problems with the various gestures in my view tree interfering with each other, such as being able to click on subviews, scroll the view, and have the keyboard dismiss in all cases. I came up with this solution, which can be setup from a superclass of UIScrollView or from a UIViewController.
The DismissKeyboardTapGesture class uses ARC, works with any text fields under the view, and doesn't take over any clicks from subviews like buttons. Also takes advantage of iOS7 scrolling effect to dismiss keyboard.
Setting up from UISScrollView superclass:
_dismissKeyboard = [[DismissKeyboardTapGesture alloc] initWithView:self];
or from UIViewController:
_dismissKeyboard = [[DismissKeyboardTapGesture alloc] initWithView:self.view];
Here is the class:
#interface DismissKeyboardTapGesture : NSObject <UIGestureRecognizerDelegate>
#end
#implementation DismissKeyboardTapGesture
- (id)initWithView:(UIView *)view
{
self = [super init];
if (self) {
UITapGestureRecognizer *singleTap = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(singleTap:)];
singleTap.cancelsTouchesInView = NO;
singleTap.delegate = self;
[view addGestureRecognizer:singleTap];
if ([view respondsToSelector:#selector(setKeyboardDismissMode:)]) {
// Bonus effect to dismiss keyboard by scrolling
((UIScrollView *)view).keyboardDismissMode = UIScrollViewKeyboardDismissModeInteractive;
}
}
return self;
}
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer
{
// Don't stop any existing gestures in our view from working
if (otherGestureRecognizer.view == gestureRecognizer.view) {
return YES;
}
return NO;
}
- (void)singleTap:(UIGestureRecognizer*)gestureRecognizer
{
// Close keyboard for any text edit views that are children of the main view
[gestureRecognizer.view endEditing:YES];
}
#end

Iphone SDK dismissing Modal ViewControllers on ipad by clicking outside of it

I want to dismiss a FormSheetPresentation modal view controller when the user taps outside the modal view...I have seen a bunch of apps doing this (ebay on ipad for example) but i cant figure out how since the underneath views are disabled from touches when modal views are displayed like this (are they presenting it as a popover perhaps?)...anyone have any suggestions?
I'm a year late, but this is pretty straightforward to do.
Have your modal view controller attach a gesture recognizer to the view's window:
UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(handleTapBehind:)];
[recognizer setNumberOfTapsRequired:1];
recognizer.cancelsTouchesInView = NO; //So the user can still interact with controls in the modal view
[self.view.window addGestureRecognizer:recognizer];
[recognizer release];
The handling code:
- (void)handleTapBehind:(UITapGestureRecognizer *)sender
{
if (sender.state == UIGestureRecognizerStateEnded)
{
CGPoint location = [sender locationInView:nil]; //Passing nil gives us coordinates in the window
//Then we convert the tap's location into the local view's coordinate system, and test to see if it's in or outside. If outside, dismiss the view.
if (![self.view pointInside:[self.view convertPoint:location fromView:self.view.window] withEvent:nil])
{
// Remove the recognizer first so it's view.window is valid.
[self.view.window removeGestureRecognizer:sender];
[self dismissModalViewControllerAnimated:YES];
}
}
}
That's about it. HIG be damned, this is a useful and often intuitive behavior.
For iOS 8, you must both implement the UIGestureRecognizer, and swap the (x,y) coordinates of the tapped location when in landscape orientation. Not sure if this is due to an iOS 8 bug.
- (void) viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
// add gesture recognizer to window
UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(handleTapBehind:)];
[recognizer setNumberOfTapsRequired:1];
recognizer.cancelsTouchesInView = NO; //So the user can still interact with controls in the modal view
[self.view.window addGestureRecognizer:recognizer];
recognizer.delegate = self;
}
- (void)handleTapBehind:(UITapGestureRecognizer *)sender
{
if (sender.state == UIGestureRecognizerStateEnded) {
// passing nil gives us coordinates in the window
CGPoint location = [sender locationInView:nil];
// swap (x,y) on iOS 8 in landscape
if (SYSTEM_VERSION_GREATER_THAN_OR_EQUAL_TO(#"8.0")) {
if (UIInterfaceOrientationIsLandscape([UIApplication sharedApplication].statusBarOrientation)) {
location = CGPointMake(location.y, location.x);
}
}
// convert the tap's location into the local view's coordinate system, and test to see if it's in or outside. If outside, dismiss the view.
if (![self.view pointInside:[self.view convertPoint:location fromView:self.view.window] withEvent:nil]) {
// remove the recognizer first so it's view.window is valid
[self.view.window removeGestureRecognizer:sender];
[self dismissViewControllerAnimated:YES completion:nil];
}
}
}
#pragma mark - UIGestureRecognizer Delegate
- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
return YES;
}
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer
{
return YES;
}
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldReceiveTouch:(UITouch *)touch
{
return YES;
}
The other apps are not using Modal Views if they allow the view to be dismissed by clicking outside of it. UIModalPresentationFormSheets cannot be dismissed this way. (nor, indeed can any UIModal in SDK3.2). Only the UIPopoverController can be dismissed by clicking outside of the area. It is very possible (though against Apple's iPad HIG) for the app developer to have shaded out the background screen and then displayed the UIPopoverController so that it looks like a UIModalPresentationFormSheets (or other UIModal View).
[...] UIModalPresentationCurrentContext style lets a view controller adopt the presentation style of its parent. In each modal view, the dimmed areas show the underlying content but do not allow taps in that content. Therefore, unlike a popover, your modal views must still have controls that allow the user to dismiss the modal view.
See the iPadProgrammingGuide on the developer site for more information (Page 46 -- "Configuring the Presentation Style for Modal Views")
The code above works great, but I would change the if statement to,
if (!([self.view pointInside:[self.view convertPoint:location fromView:self.view.window] withEvent:nil] || [self.navigationController.view pointInside:[self.navigationController.view convertPoint:location fromView:self.navigationController.view.window] withEvent:nil]))
{
// Remove the recognizer first so it's view.window is valid.
[self.view.window removeGestureRecognizer:sender];
[self dismissModalViewControllerAnimated:YES];
}
This makes sure you can still interact with the navigation bar, otherwise tapping in it dismisses the modal view.
Answer updated for iOS 8
Apparently, in iOS 8, the UIDimmingView has a tap gesture recognizer, which interferes with the initial implementation, so we ignore it and don't require it to fail.
This is the age of speed, so most are probably just copying the code above.. But, I suffer from OCD when it comes to code, unfortunately.
Here is a modular solution that uses Danilo Campos's answer with categories. It also solves an important bug that may occur if you are dismissing your modal through other means, as mentioned.
NOTE: The if statements are there because I use the view controller for both iPhone and iPad, and only the iPad needs to register/unregister.
UPDATE: The gist has been updated, since it didn't work properly with the awesome FCOverlay code, and it didn't allow gestures to be recognized in the presented view. Those issues are fixed.
Using the category is as easy as:
- (void)viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
if (self.presentingViewController) {
[self registerForDismissOnTapOutside];
}
}
- (void)viewWillDisappear:(BOOL)animated
{
if (self.presentingViewController) {
[self unregisterForDismissOnTapOutside];
}
[super viewWillDisappear:animated];
}
Copy paste this code in your ModalViewController :
- (void) viewDidAppear:(BOOL)animated
{
[super viewDidAppear:animated];
//Code for dissmissing this viewController by clicking outside it
UITapGestureRecognizer *recognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:#selector(handleTapBehind:)];
[recognizer setNumberOfTapsRequired:1];
recognizer.cancelsTouchesInView = NO; //So the user can still interact with controls in the modal view
[self.view.window addGestureRecognizer:recognizer];
}
- (void)handleTapBehind:(UITapGestureRecognizer *)sender
{
if (sender.state == UIGestureRecognizerStateEnded)
{
CGPoint location = [sender locationInView:nil]; //Passing nil gives us coordinates in the window
//Then we convert the tap's location into the local view's coordinate system, and test to see if it's in or outside. If outside, dismiss the view.
if (![self.view pointInside:[self.view convertPoint:location fromView:self.view.window] withEvent:nil])
{
// Remove the recognizer first so it's view.window is valid.
[self.view.window removeGestureRecognizer:sender];
[self dismissModalViewControllerAnimated:YES];
}
}
}
Very important: If you have any other way to close your modal popup window, don't forget to remove the tap gesture recognizer!
I forgot this, and got crazy crashes later on, since the tap recognizer was still firing events.
Accoring to Apple's iOS HIG, 1. the modal view doesn't have that ability to be dismissed without any input on itself; 2. use modal view in the situation that a user input is required.
Use UIPresentationController instead:
- (void)presentationTransitionWillBegin
{
[super presentationTransitionWillBegin];
UITapGestureRecognizer *dismissGesture=[[UITapGestureRecognizer alloc]initWithTarget:self action:#selector(dismissGestureTapped:)];
[self.containerView addGestureRecognizer:dismissGesture];
[[[self presentedViewController] transitionCoordinator] animateAlongsideTransition:^(id<UIViewControllerTransitionCoordinatorContext> context) {
} completion:nil];
}
- (void) dismissGestureTapped:(UITapGestureRecognizer *)sender{
if (sender.state==UIGestureRecognizerStateEnded&&!CGRectContainsPoint([self frameOfPresentedViewInContainerView], [sender locationInView:sender.view])) {
[self.presentingViewController dismissViewControllerAnimated:YES completion:nil];
}
}
Modified from LookInside example
This works for me for ios7 an 8 and navigation bar.
If you don't need the nav bar just remove location2 and second condition in the if statement after the pipes.
#MiQUEL this should work for you too
- (void)handleTapBehind:(UITapGestureRecognizer *)sender
{
if (sender.state == UIGestureRecognizerStateEnded)
{
CGPoint location1 = [sender locationInView:self.view];
CGPoint location2 = [sender locationInView:self.navigationController.view];
if (!([self.view pointInside:location1 withEvent:nil] || [self.navigationController.view pointInside:location2 withEvent:nil])) {
[self.view.window removeGestureRecognizer:self.recognizer];
[self dismissViewControllerAnimated:YES completion:nil];
}
}
}
Edit: You may also need to be a gesture recognizer delegate for this and other above solutions to work. Do it like so:
#interface CommentTableViewController () <UIGestureRecognizerDelegate>
set yourself as the delegate for the recognizer:
self.recognizer.delegate = self;
and implement this delegate method:
- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer{
return YES;
}
It is pretty doable.
Take a look here
https://stackoverflow.com/a/26016458/4074557
It is a NavigationController (modal) that auto dismiss for ipad (when you tap outside)
Use your viewcontroller inside of it.
Hope it helps.
I know it's late but consider using CleanModal (tested with iOS 7 and 8).
https://github.com/orafaelreis/CleanModal
You can use MZFormSheetController like this:
MZFormSheetController *formSheet = [[MZFormSheetController alloc] initWithSize:customSize viewController:presentedViewController];
formSheet.shouldDismissOnBackgroundViewTap = YES;
[presentingViewController mz_presentFormSheetController:formSheet animated:YES completionHandler:nil];
In Swift 2/Xcode Version 7.2 (7C68) the following code worked for me.
Attention: this code should be put in the ViewController.swift file of the presented FormSheet or Page Sheet, here: "PageSheetViewController.swift"
class PageSheetViewController: UIViewController, UIGestureRecognizerDelegate {
override func viewDidAppear(animated: Bool) {
let recognizer = UITapGestureRecognizer(target: self, action:Selector("handleTapBehind:"))
recognizer.delegate = self
recognizer.numberOfTapsRequired = 1
recognizer.cancelsTouchesInView = false
self.view.window?.addGestureRecognizer(recognizer)
}
func gestureRecognizer(sender: UIGestureRecognizer,
shouldRecognizeSimultaneouslyWithGestureRecognizer:UIGestureRecognizer) -> Bool {
return true
}
func handleTapBehind(sender:UIGestureRecognizer) {
if(sender.state == UIGestureRecognizerState.Ended){
var location:CGPoint = sender.locationInView(nil)
// detect iOS Version 8.0 or greater
let Device = UIDevice.currentDevice()
let iosVersion = Double(Device.systemVersion) ?? 0
let iOS8 = iosVersion >= 8
if (iOS8) {
// in landscape view you will have to swap the location coordinates
if(UIInterfaceOrientationIsLandscape(UIApplication.sharedApplication().statusBarOrientation)){
location = CGPointMake(location.y, location.x);
}
}
if(!self.view.pointInside(self.view.convertPoint(location, fromView: self.view.window), withEvent: nil)){
self.view.window?.removeGestureRecognizer(sender)
self.dismissViewControllerAnimated(true, completion: nil)
}
}
}
}