What are anonymous hashes in perl? - perl

$hash = { 'Man' => 'Bill',
'Woman' => 'Mary,
'Dog' => 'Ben'
};
What exactly do Perl's “anonymous hashes” do?

It is a reference to a hash that can be stored in a scalar variable. It is exactly like a regular hash, except that the curly brackets {...} creates a reference to a hash.
Note the usage of different parentheses in these examples:
%hash = ( foo => "bar" ); # regular hash
$hash = { foo => "bar" }; # reference to anonymous (unnamed) hash
$href = \%hash; # reference to named hash %hash
This is useful to be able to do, if you for example want to pass a hash as an argument to a subroutine:
foo(\%hash, $arg1, $arg2);
sub foo {
my ($hash, #args) = #_;
...
}
And it is a way to create a multilevel hash:
my %hash = ( foo => { bar => "baz" } ); # $hash{foo}{bar} is now "baz"

You use an anonymous hash when you need reference to a hash and a named hash is inconvenient or unnecessary. For instance, if you wanted to pass a hash to a subroutine, you could write
my %hash = (a => 1, b => 2);
mysub(\%hash);
but if there is no need to access the hash through its name %hash you could equivalently write
mysub( {a => 1, b => 2} );
This comes in handy wherever you need a reference to a hash, and particularly when you are building nested data structures. Instead of
my %person1 = ( age => 34, position => 'captain' );
my %person2 = ( age => 28, position => 'boatswain' );
my %person3 = ( age => 18, position => 'cabin boy' );
my %crew = (
bill => \%person1,
ben => \%person2,
weed => \%person3,
);
you can write just
my %crew = (
bill => { age => 34, position => 'captain' },
ben => { age => 28, position => 'boatswain' },
weed => { age => 18, position => 'cabin boy' },
);
and to add a member,
$crew{jess} = { age => 4, position => "ship's cat" };
is a lot neater than
my %newperson = ( age => 4, position => "ship's cat" );
$crew{jess} = \%newperson;
and of course, even if a hash is created with a name, if its reference is passed elsewhere then there may be no way of using that original name, so it must be treated as anonymous. For instance in
my $crew_member = $crew{bill}
$crew_member is now effectively a reference to an anonymous hash, regardless of how the data was originally constructed. Even if the data is (in some scope) still accessible as %person1 there is no general way of knowing that, and the data can be accessed only by its reference.

It's quite simple. They allow you to write
push #hashes, { ... };
f(config => { ... });
instead of
my %hash = ( ... );
push #hashes, \%hash;
my %config = ( ... );
f(config => \%config);
(If you want to know the purpose of references, that's another story entirely.)

Anything "anonymous" is a data structure that used in a way where it does not get a name.
Your question has confused everyone else on this page, because your example shows you giving a name to the hash you created, thus it is no longer anonymous.
For example - if you have a subroutine and you want to return a hash, you could write this code:-
return {'hello'=>123};
since it has no name there - it is anonymous. Read on to unwind the extra confusion other people have added on this page by introducing references, which are not the same thing.
This is another anonymous hash (an empty one):
{}
This is an anonymous hash with something in it:
{'foo'=>123}
This is an anonymous (empty) array:
[]
This is an anonymous array with something in it:
['foo',123]
Most of the time when people use these things, they are really trying to magically put them inside of other data structures, without the bother of giving them a waste-of-time temporary name when they do this.
For example - you might want to have a hash in the middle of an array!
#array=(1,2,{foo=>3});
that array has 3 elements - the last element is a hash! ($array[2]->{foo} is 3)
perl -e '#array=(1,2,{foo=>1});use Data::Dumper;print Data::Dumper->Dump([\#array],["\#array"]);'
$#array = [
1,
2,
{
'foo' => 1
}
];
Sometimes you want to don't want to pass around an entire data structure, instead, you just want to use a pointer or reference to the data structure. In perl, you can do this by adding a "\" in front of a variable;
%hashcopy=%myhash; # this duplicates the hash
$myhash{test}=2; # does not affect %hashcopy
$hashpointer=\%myhash; # this gives us a different way to access the same hash
$hashpointer->{test}=2;# changes %myhash
$$hashpointer{test}=2; # identical to above (notice double $$)
If you're crazy, you can even have references to anonymous hashes:
perl -e 'print [],\[],{},\{}'
ARRAY(0x10eed48)REF(0x110b7a8)HASH(0x10eee38)REF(0x110b808)
and sometimes perl is clever enough to know you really meant reference, even when you didn't specifically say so, like my first "return" example:
perl -e 'sub tst{ return {foo=>bar}; }; $var=&tst();use Data::Dumper;print Data::Dumper->Dump([\$var],["\$var"]);'
$var = \{
'foo' => 'bar'
};
or:-
perl -e 'sub tst{ return {foo=>bar}; }; $var=&tst(); print "$$var{foo}\n$var->{foo}\n"'
bar
bar

Related

How do I decipher an array of hashes?

I totally got this question wrong. Am using the method from TMDB:
my #results = $search->find(id => 'tt0114694', source => 'imdb_id');
I thought the output was in JSON format, so that's what confused me, which kept me running in circles because I was looking at it all wrong.
Didn't realize the data below, from Dumper, was the actual hashes the I had to go through.
This is where I am running into a wall, So the data below is a hash with five keys. The fifth key, the I want, contains another array. It is that array I cannot read into. I try dereferencing that into a hash, and that is where I fail.
The code I am trying is:
foreach my $narray (#results){
print $narray->{"movie_results"};
my #newarray = $narray->{"movie_results"};
foreach my $otherarray (#newarray){
my %innerhash = $otherarray;
print %innerhash;
print "\n";
}
}
It will print out an array, but I am unable to read the hash in that array.
p.s. I had to format this output as code, or else it came out with no line breaks.
$VAR1 = {
'tv_season_results' => [],
'tv_results' => [],
'person_results' => [],
'tv_episode_results' => [],
'movie_results' => [
{
'adult' => bless( do{\(my $o = 0)}, 'JSON::PP::Boolean' ),
'vote_average' => '6.8',
'original_title' => 'Tommy Boy',
'vote_count' => 635,
'id' => 11381,
'release_date' => '1995-03-31',
'overview' => 'Party animal Tommy Callahan is a few cans short of a six-pack. But when the family business starts tanking, it\'s up to Tommy and number-cruncher Richard Hayden to save the day.',
'genre_ids' => [
35
],
'title' => 'Tommy Boy',
'video' => $VAR1->{'movie_results'}[0]{'adult'},
'poster_path' => '/g32WbO9nbY5ydpux5hIoiJkLEQi.jpg',
'original_language' => 'en',
'backdrop_path' => '/bZ4diYf7oyDVaRYeWG42Oify2mB.jpg',
'popularity' => '13.945'
}
]
};
You mention that you thought you'd get JSON output, but got something else. The module made a web request for you, received the JSON response, and translated that to a Perl data structure. That Perl version of the JSON is what you see in the dump.
A JSON object turns into a Perl hash, so that's what you see in the top level of the data structure. That's the single thing find returns (more on that in a moment):
Here's what you have, removing the outer foreach loop:
my #newarray = $narray->{"movie_results"};
foreach my $otherarray (#newarray){
my %innerhash = $otherarray;
print %innerhash;
print "\n";
}
The value in $narray->{"movie_results"} is an array reference. All references are scalars, and those scalars point to some data structure. When you assign that scalar to an array, you just end up with a one element array that's the same reference. Instead, you can
my $movie_results = $narray->{"movie_results"};
You then dereference that reference to treat it as an array:
foreach my $result ( #$movie_results ){ ... }
Or, the v5.24 postfix dereferencing way that I find slightly more pleasing since it reads better, especially when you skip the intermediate variable:
foreach my $result ( $movie_results->#* ){ ... }
foreach my $result ( $narray->{"movie_results"}->#* ){ ... }
That thing in $result is another hash reference.
References and data structures are about half of the content of Intermediate Perl, but there is also the Perl data structures cookbook (perldsc).
Improving your question a bit
You can help us a lot by showing us a complete, working demonstration of your problem. Here's what I cobbled together:
use v5.10;
use TMDB;
use Data::Dumper;
my $tmdb = TMDB->new( apikey => $ENV{TMDB_API_KEY} );
my #results = $tmdb->search->find(
id => 'tt0114694',
source => 'imdb_id'
);
say Dumper( \#results );
There was a question about the results of find. The documentation example shows it returning a list (well, the result being assigned to a named array, which implies that), but there's not actual documentation for find. It returns the decoded JSON from the response. Assigning it to a scalar (which will be a reference) works just fine too:
my $result = $tmdb->search->find(
id => 'tt0114694',
source => 'imdb_id'
);
say Dumper( $results );
The return value comes from TMDB::Sesssion::talk(), which is just this (or the empty list):
return $self->json->decode(
Encode::decode( 'utf-8-strict', $response->{content} ) );
That's not a big deal. That just means you don't need the outer foreach. That's not on you because the example in the docs tells you to do exactly what you did.
Now a better program
Putting all that together, here's a simple program pared down to just what you need:
use v5.10;
use TMDB;
my $tmdb = TMDB->new( apikey => $ENV{TMDB_API_KEY} );
my $result = $tmdb->search->find(
id => 'tt0114694',
source => 'imdb_id'
);
foreach my $item ( $result->{movie_results}->#* ) {
say "Title: $item->{title}";
}
Ref aliasing
There's an experimental feature called ref aliasing that lets you assign a reference to a reference of a named variable. It's an alias, so you can access and change the same data, just with a named variable. Something this is handy when you don't like
use v5.10;
use TMDB;
use experimental qw(refaliasing);
my $tmdb = TMDB->new( apikey => $ENV{TMDB_API_KEY} );
# response is a hash ref, so ref alias to a named hash
\my %result = $tmdb->search->find(
id => 'tt0114694',
source => 'imdb_id'
);
# the part you want is an array ref, so alias that
\my #movie_results = $result{movie_results};
# each item in the array is a hash ref, so alias those too
foreach \my %item ( #movie_results ) {
say "Title: $item{title}";
}
When dealing with reference, use the same syntax as if you weren't, but replace the name of the variable with a block that returns the reference.
%NAME -> %{ $ref } Or just %$ref
$NAME{...} -> ${ $ref }{...} Although $ref->{...} easier to read.
#NAME -> #{ $ref } Or just #$ref
$NAME[...] -> ${ $ref }[...] Although $ref->[...] easier to read.
Let's give $VAR a better name,
my $response = $VAR1;
This means you want
my $results = $response->{movie_results};
for my $result (#$results) {
for my $key (keys(%$result)) {
say "$key: $result->{$key}";
}
}
See
perlreftut
Perl Dereferencing Syntax
%newhash{$newkey} should be $newhash{$newkey}.

How to merge two hashes returned from sub, in Perl

I am trying to merge two hashes. But they are return values from functions. How can I dereference the return values inline? I don't want to use extra variables such as my $pos = makePos();
use v5.8.8;
use strict;
use warnings;
sub _makePos
{
my $desc= {
pos50 => {unit => 'm', desc => 'position error' },
pos95 => {unit => 'm', desc => '95% position error' }
};
return $desc;
}
sub _makeVel
{
my $desc= {
vel50 => {unit => 'm/s', desc => 'velocity error' },
vel95 => {unit => 'm/s', desc => '95% velocity error' }
};
return $desc;
}
my $descs = {_makePos(), _makeVel()};
use Data::Dumper;
print Dumper($descs);
this prints only the hash returned from _makeVel. how does it work?
$VAR1 = {
'HASH(0x21ea4a0)' => {
'vel50' => {
'desc' => 'velocity error',
'unit' => 'm/s'
},
'vel95' => {
'unit' => 'm/s',
'desc' => '95% velocity error'
}
}
};
changing this line as
my $descs = {%{_makePos()}, %{_makeVel()}};
worked!
Actually, your original solution did print both of the hashes, but the first one was "stringified" as it was being used as the key of your hash. It's there as HASH(0x21ea4a0).
I see you have a solution, but it might be worth explaining what was going wrong and why your solution fixed it.
Your two subroutines don't return hashes but, rather, hash references. A hash reference is a scalar value that is, effectively, a pointer to a hash.
A hash is created from a list of values. Your code that creates your news hash (actually, once again, a hash reference) is this:
my $descs = {_makePos(), _makeVel()};
This is two scalar values. The first is used as a key in the new hash and the second is used as the associated value - hence the results you get from Data::Dumper.
What you actually want to do is to "dereference" your hashes and get back to the actual hashes. You can dereference a hash using the syntax %{ ... }, where the ... is any expression returning a hash reference. And that's what you've done in your solution. You dereference the hash references, which gives you a list of key/value pairs. The pairs from the two dereferenced hashes are then joined together in a single list which is used to create your new, combined, hash.
I should point out that there's a danger in this approach. If your two subroutines can ever return references to hashes that contain the same key, then only one version of that repeated key will appear in the combined hash.

How to add a scalar value (string) to an existing hash in Perl

I just want to know what the process is behind merging a value into a hash.
I have a hash which has 5 to 6 keys depending on if the error outputs runtime values. The method that takes in the arguments also take an error message string in first, also. I want it to be able to add this error message string into the hash, to make one big hash basically.
This is how the method would be called:
ASC::Builder::Error->new("Simple error message here", code => "UNABLE_TO_PING_SWITCH_ERROR", switch_ip => $ip3, timeout => $t1);
The last two values assign runtime parameters/values to keys inside the context key in the error hash.
Here is a look at the error hash:
use constant ERROR_CODE => {
UNABLE_TO_PING_SWITCH_ERROR => {
category => 'Connection Error',
template => 'Could not ping switch %s in %s seconds.',
context => [qw(switch_ip timeout)],
tt => {template => 'disabled'},
fatal => 1,
wiki_page => 'www.error-solution.com/ERROR_CODE_A',
}
};
Here is my method to manipulate the error hash and construct the message
sub _create_error_hash {
my $error_string = shift; if(defined($params{code}) {
my $first_param = delete $params{code};
foreach my $key (#{$first_param->{context}}) {
$first_param->{$key} = $key;
}
my #template_args = map { $first_param->{$_}} #{$first_param->{context} };
$first_param->{message} = sprintf($first_param->{template}, #template_args); }
return bless $first_param;
}
sub _merge_hashes {
my ($message = {message => $messsage}, $first_param = {first_param => $first_param}) = # _;
#merge these two hashes and bless into $class (don't know how to merge hashes)
my %merged_hash = ($message, $first_param);
return bless $merged_hash, $class;
}
The output of _create_hash should be the input for _merge_hashes
Not sure if I have handled that properly. These methods will be use inside the new method (which is a mess right now) hence why it's not included.
That's just an attempt , of an example I seen on perlmonks, Here is the link:
http://www.perlmonks.org/?node_id=14263
I'm going to start with the simple explanation of how to merge a hash in perl, it's pretty simple.
use strict;
use warnings;
use Data::Printer;
my (%a, %b, %c);
%a = (a => 1, b => 2);
%b = (a => 0, c => 3, d => 4);
%c = (%a, %b);
p(%c); # { a => 0, b => 2, c => 3, d => 4 }
You'll note with the a keys that if there are duplicates whatever value appears in the second set will be the one that 'wins'.
I honestly have no idea what that second function is doing because it references variables that don't exist on practically every line. (The create one also does this but only on a couple lines).
From your description I think you only want a single key added so you don't really need to do that though, you should be able to just add the key to the original object: $error->{messsage} = $message
But assuming you did want to pass two hash references in and merge them, it would look something like this:
sub merge {
my ($first, $second) = #_;
my %merged = (%$first, %$second);
return bless \%merged, $class;
}

Perl hash referencing itself at declaration

When declaring a Perl hash, I'm wondering if it's possible to use a value that was assigned earlier in the declaration.
I'd like to do the equivalent of this, all in one shot:
my %H = (something => generateString());
$H{foo} = $H{something} . "/FOO",
$H{bar} = $H{something} . "/BAR",
I can imagine something like this:
my %H = (
something => generateString(),
foo => $_{something} . "/FOO",
bar => $_{something} . "/BAR",
);
EDIT: To be clear, I don't care about an actual reference to $H{something} (i.e. changing $H{something} later shouldn't affect $H{foo}). I'd just like to get its value into the string concatenations.
You seem to think there are two assignment operators in
%H = ( a=>1, b=>$H{a} );
There isn't. Keep in mind the above is identical to
%H = ( 'a', 1, 'b', $H{a} );
There's one assignment operator, and before you can perform the assignment, you need to know what is going to be assignment.
What I'm saying is that the real problem with %H = ( a=>1, b=>$H{a} ); isn't one of scope; the real problem is that nothing been assigned to %H when you do $H{a}[1]. As such, $_{a} makes more sense than $H{a}.
The solution is simple:
my $something = generateString();
my %H = (
something => $something,
foo => "$something/FOO",
bar => "$something/BAR",
);
%H hasn't even been created yet!
my %H = (something => generateString());
%H = (%H,
foo => $H{something} ."/FOO",
bar => $H{something} ."/BAR",
);
seems reasonable, but if you want it in one shot at ANY cost,
use strict;
use warnings;
%{ $_->{hash} } = (
something => $_->{thing},
foo => "$_->{thing}/FOO",
bar => "$_->{thing}/BAR",
)
for {hash => \my %H, thing => generateString()};
which can be translated to more verbose version,
my %H;
local $_ = {hash => \%H, thing => generateString()};
%{ $_->{hash} } = (
something => $_->{thing},
foo => "$_->{thing}/FOO",
bar => "$_->{thing}/BAR",
);
As ikegami says, there is only one assignment operation; it is executed after the entire right hand side is evaluated.
A couple alternatives:
my %H = map {;
'something' => $_,
'foo' => "$_/FOO",
'bar' => "$_/BAR",
} generateString();
and
use Memoize;
memoize('generateString');
my %H = (
'something' => scalar(generateString()),
'foo' => generateString() . '/FOO',
'bar' => generateString() . '/BAR',
);
(scalar needed because otherwise, memoize will make separate calls for list and scalar context.)
An alternative is to do the definition as part of the assignments:
my %H = (
something => ( local our $str=generateString() ),
foo => qq{$str/FOO},
bar => qq{$str/BAR}
);
There are two things to consider:
Notice the use of local our instead of my
I advise against this. For many reasons; if not for best coding practices, but for bugs that may be introduced.
I feel that defining a variable outside the hash definition (as shown in Ikegami's answer) is the best way to go for many reasons, but I realize that's also not the question being asked. The answer to the question is that a hash cannot be referenced before it is created and during creation it is not exposed within the constructor.

in perl ,how to use variable value as hash element

I am new to Perl, and can't find the answer to the question in the Learning Perl book.
For example I have a array like:
my #loop=("op1_sel","op2_sel");
and two hash table as:
my %op1_sel=(
"bibuf","000",
"self","101"
);
my %op2_sel=(
"zero","1",
"temp","0"
);
Now I want to use variables in the loop to loop for the hash table for a particular key
for example:
foreach(#loop)
{
print ${$_}{"bibuf"} ;
}
But it seems not working, I know the ${$_} part is wrong, can anyone can tell me how
to fix this ?
Use nested hashes. Like this:
my %op;
# put a hash reference into hash, twice
$op{op1_sel} = \%op1_sel;
$op{op2_sel} = \%op2_sel;
# later ...
foreach (keys %op) {
print "bibuf of $_: $op{$_}->{bibuf}\n";
};
Or, long story short, just
my %op = (
op1_sel => {
foo => 1,
bar => 2,
# ...
},
op2_sel => {
# ...
},
};
The {} construct creates a reference to anonymous hash and is the standard way of handling nested data structures.
See also perldoc perldsc.
You can't refer to lexical (my) variables using the ${$foo} syntax. You could probably make it work if they were package variables, but this would not be the right way to go about it.
The right way to do it is using a nested data structure.
I can see two obvious ways of doing it. You could either make an array of op_sel containing the inner hashes directly, or create a hash of hashes, and then index into that.
So "array of hashes":
my #op_sels = (
{
bibuf => '000',
self => '101',
},
{
zero => '1',
temp => '0',
},
);
for my $op (#op_sels) {
print $$op{bibuf};
}
and "hash of hashes":
my %op_sels = (
1 => {
bibuf => '000',
self => '101',
},
2 => {
zero => '1',
temp => '0',
},
);
for my $op_key (sort keys %op_sels) {
print $op_sels{$op_key}{bibuf};
}
You can use eval for this.
foreach(#loop)
{
eval "\%var = \%$_";
print $var{"bibuf"} ;
}