Combine two fields from different documents in Mongodb - mongodb

I have these documents in a collection :
{topic : "a",
messages : [ObjectId("21312321321323"),ObjectId("34535345353"),...]
},
{topic : "b,
messages : [ObjectId("1233232323232"),ObjectId("6556565656565"),...]
}
Is there a posibility to get a result with the combination of messages fields ? I like to get this for example :
{[
ObjectId(""),ObjectId(""),ObjectId(""),ObjectId("")
]}
I thought that this was possible with MapReduce but in my case the documents doesn't have anything in common. Right now I'm doing this in the backend using javascript and loops, but i think that this isn't the best option. Thanks.

You could use the $group operator in the Aggregation Framework. To use the Aggregation Framework you will want to be sure you're running on MongoDB 2.2 or newer, of course.
If used with $push you will get all the lists of messages concatenated together.
db.myCollection.aggregate({ $group: { messages: { $push: '$messages' } } });
If used with $addToSet you will get only the distinct values.
db.myCollection.aggregate({ $group: { messages: { $addToSet: '$messages' } } });
And if you want to filter down the candidate documents first, you can use $match.
db.myCollection.aggregate([
{ $match: { topic: { $in: [ 'a', 'b' ] } } },
{ $group: { matches: { $sum: 1 }, messages: { $push: '$messages' } } }
]);

One option is to use the aggregation framework.
However, if you're planning on having a large number of results (beyond just a "lightweight" result), a result document exceeding 16MB in size, or using excessive system memory, you'll need to just loop through the objects in the collection and concatenate the results manually (as you suggest you might be doing now) or risk mongodb throwing an exception.
Aggregation limits may be found at the bottom of this page:
http://docs.mongodb.org/manual/applications/aggregation/
Given the limitations, you may want to just use find with a projection to return just messages.
(And with anything like this, I'd strongly recommend you do some performance benchmarks to compare options with your data on your servers as the "Internet" would suggest right now that some people have found the Aggregation support to be slower than other techniques).

Related

MongoDB querying aggregation in one single document

I have a short but important question. I am new to MongoDB and querying.
My database looks like the following: I only have one document stored in my database (sorry for blurring).
The document consists of different fields:
two are blurred and not important
datum -> date
instance -> Array with an Embedded Document Object; Our instance has an id, two not important fields and a code.
Now I want to query how many times an object in my instance array has the group "a" and a text "sample"?
Is this even possible?
I only found methods to count how many documents have something...
I am using Mongo Compass, but i can also use Pymongo, Mongoengine or every other different tool for querying the mongodb.
Thank you in advance and if you have more questions please leave a comment!
You can try this
db.collection.aggregate([
{
$unwind: "$instance"
},
{
$unwind: "$instance.label"
},
{
$match: {
"instance.label.group": "a",
"instance.label.text": "sample",
}
},
{
$group: {
_id: {
group: "$instance.label.group",
text: "$instance.label.text"
},
count: {
$sum: 1
}
}
}
])

MongoDb aggregate with limit and without limit

There is a collection in mongo
In the collection of 40 million records
db.getCollection('feedposts').aggregate([
{
"$match": {
"$or": [
{
"isOfficial": true
},
{
"creator": ObjectId("537f267c984539401ff448d2"),
type: { $nin: ['challenge_answer', 'challenge_win']}
}
],
}
},
{
$sort: {timeline: -1}
}
])
This request never ends
But if you add a limit before sorting, and the limit is higher than the total number of records in advance, for example, 1,000,000,000,000,000 - the request will be processed instantly
db.getCollection('feedposts').aggregate([
{
"$match": {
"$or": [
{
"isOfficial": true
},
{
"creator": ObjectId("537f267c984539401ff448d2"),
type: { $nin: ['challenge_answer', 'challenge_win']}
}
],
}
},
{
$limit: 10000000000000000
},
{
$sort: {timeline: -1}
}
])
Please tell me why this is happening?
What problems can I expect in the future if I leave it this way?
TLDR: Mongo is using the wrong index for the query
Why is this happening?
Well basically every query you do Mongo simulates a quick "competition" between the relevant indexes in order to choose which one to use, the first index to retrieve 1001 documents "wins".
Now usually this situation of picking the wrong index occurs with ascending or descending fields and a matching index making this index with the fetching competition under certain conditions, Meaning this is very risky as you can have stable code that can suddenly become a huge bottleneck.
What can we do?
You have a few options:
Use the hint option and make Mongo use the compound index you have ready for this pipeline.
Drop the rogue index to ensure this will never happen again elsewhere (which is my recommended option).
Keep doing what you're doing. basically by adding this random $limit stage you're throwing Mongo's competition off and ensuring the right index will be picked.

Why sort document by id is slower with $match than not in mongodb?

So, I tried to query
db.collection('collection_name').aggregate([
{
$match: { owner_id: '5be9b2f03ef77262c2bd49e6' }
},
{
$sort: { _id: -1 }
}])
the query above takes up 20s
but If I tried to query
db.collection('collection_name').aggregate([{$sort : {_id : -1}}])
it's only take 0.7s
Why does it the one without $match is actually faster than without match ?
update :
when I try this query
db.getCollection('callbackvirtualaccounts').aggregate([
{
$match: { owner_id: '5860457640b4fe652bd9c3eb' }
},
{
$sort: { created: -1 }
}
])
it's only takes 0.781s
Why sort by _id is slower than by created field ?
note : I'm using mongodb v3.0.0
db.collection('collection_name').aggregate([
{
$match: { owner_id: '5be9b2f03ef77262c2bd49e6' }
},
{
$sort: { _id: -1 }
}])
This collection probably won't be having and index on owner_id; Try using below mentioned index creation query and rerun your previous code.
db.collection('collection_name').createIndexes({ owner_id:1}) //Simple Index
or
db.collection('collection_name').createIndexes({ owner_id:1,_id:-1}) //Compound Index
**Note:: If you don't know how to compound index yet, you can create simple indexes individually on all keys which are used either in match or sort and that should be making query efficient as well.
The query speed depends upon a lot of factors. The size of collection, size of the document, indexes defined on the collection (and used in the queries and properly), the hardware components (like CPU, RAM, network) and other processes running at the time the query is running.
You have to tell what indexes are defined on the collection being discussed for further analysis. The command will retrieve them: db.collection.getIndexes()
Note the unique index on the _id field is created by default, and cannot be modified or deleted.
(i)
But If I tried to query: db.collection.aggregate( [ { $sort : { _id : -1 } } ] ) it's
only take 0.7s.
The query is faster because there is an index on the _id field and it is used in sort process. Aggregation queries use indexes with sort stage and when this sort happens early in the pipeline. You can verify if the index is used or not by generating a query plan (use explain with executionStats mode). There will be an index scan (IXSCAN) in the generated query plan.
(ii)
db.collection.aggregate([
{
$match: { owner_id: '5be9b2f03ef77262c2bd49e6' }
},
{
$sort: { _id: -1 }
}
])
The query above takes up 20s.
When I try this query it's only takes 0.781s.
db.collection.aggregate([
{
$match: { owner_id: '5860457640b4fe652bd9c3eb' }
},
{
$sort: { created: -1 }
}
])
Why sort by _id is slower than by created field ?
Cannot come to any conclusions with the available information. In general, the $match and $sort stages present early in the aggregation query can use any indexes created on the fields used in the operations.
Generating a query plan will reveal what the issues are.
Please run the explain with executionStats mode and post the query plan details for all queries in question. There is documentation for Mongodb v3.0.0 version on generation query plans using explain: db.collection.explain()

How to find max sum after $group sorting

I have the following query:
db.pmusers.aggregate([
{
$unwind: '$preferableUsersIds'
},
{
$group:{_id: '$preferableUsersIds', number:{$sum: 1}}
},
{
$sort:{number:-1}
},
{
$limit:1
}
])
I understand that it is not the optimal solution because I sort all rntries instead of find only one.
Does mongoDb support to rewrite it in more efficient way?
P.S.
I know aboout $max but don't see how it can help me.
this one works at least not faster:
db.pmusers.aggregate([
{
$unwind: '$preferableUsersIds'
},
{
$sortByCount: "$preferableUsersIds"
},
{
$limit:1
}
])
See the answer here
MongoDB coalesces the sort and limit in an aggregation to optimise the query. You can also add an index if you're doing this a lot to make sure it's a covered query.
Text from linked answer:
According to the MongoDB documentation:
When a $sort immediately precedes a $limit, the optimizer can coalesce
the $limit into the $sort. This allows the sort operation to only
maintain the top n results as it progresses, where n is the specified
limit, and MongoDB only needs to store n items in memory.

Matching for latest documents for a unique set of fields before aggregating

Assuming I have the following document structures:
> db.logs.find()
{
'id': ObjectId("50ad8d451d41c8fc58000003")
'name': 'Sample Log 1',
'uploaded_at: ISODate("2013-03-14T01:00:00+01:00"),
'case_id: '50ad8d451d41c8fc58000099',
'tag_doc': {
'group_x: ['TAG-1','TAG-2'],
'group_y': ['XYZ']
}
},
{
'id': ObjectId("50ad8d451d41c8fc58000004")
'name': 'Sample Log 2',
'uploaded_at: ISODate("2013-03-15T01:00:00+01:00"),
'case_id: '50ad8d451d41c8fc58000099'
'tag_doc': {
'group_x: ['TAG-1'],
'group_y': ['XYZ']
}
}
> db.cases.findOne()
{
'id': ObjectId("50ad8d451d41c8fc58000099")
'name': 'Sample Case 1'
}
Is there a way to perform a $match in aggregation framework that will retrieve only all the latest Log for each unique combination of case_id and group_x? I am sure this can be done with multiple $group pipeline but as much as possible, I want to immediately limit the number of documents that will pass through the pipeline via the $match operator. I am thinking of something like the $max operator except it is used in $match.
Any help is very much appreciated.
Edit:
So far, I can come up with the following:
db.logs.aggregate(
{$match: {...}}, // some match filters here
{$project: {tag:'$tag_doc.group_x', case:'$case_id', latest:{uploaded_at:1}}},
{$unwind: '$tag'},
{$group: {_id:{tag:'$tag', case:'$case'}, latest: {$max:'$latest'}}},
{$group: {_id:'$_id.tag', total:{$sum:1}}}
)
As I mentioned, what I want can be done with multiple $group pipeline but this proves to be costly when handling large number of documents. That is why, I wanted to limit the documents as early as possible.
Edit:
I still haven't come up with a good solution so I am thinking if the document structure itself is not optimized for my use-case. Do I have to update the fields to support what I want to achieve? Suggestions very much appreciated.
Edit:
I am actually looking for an implementation in mongodb similar to the one expected in How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL? except it involves two distinct field values. Also, the $match operation is crucial because it makes the resulting set dynamic, with filters ranging to matching tags or within a range of dates.
Edit:
Due to the complexity of my use-case I tried to use a simple analogy but this proves to be confusing. Above is now the simplified form of the actual use case. Sorry for the confusion I created.
I have done something similar. But it's not possible with match, but only with one group pipeline. The trick is do use multi key with correct sorting:
{ user_id: 1, address: "xyz", date_sent: ISODate("2013-03-14T01:00:00+01:00"), message: "test" }, { user_id: 1, address: "xyz2", date_sent: ISODate("2013-03-14T01:00:00+01:00"), message: "test" }
if i wan't to group on user_id & address and i wan't the message with the latest date we need to create a key like this:
{ user_id:1, address:1, date_sent:-1 }
then you are able to perform aggregate without sort, which is much faster and will work on shards with replicas. if you don't have a key with correct sort order you can add a sort pipeline, but then you can't use it with shards, because all that is transferred to mongos and grouping is done their (also will get memory limit problems)
db.user_messages.aggregate(
{ $match: { user_id:1 } },
{ $group: {
_id: "$address",
count: { $sum : 1 },
date_sent: { $max : "$date_sent" },
message: { $first : "$message" },
} }
);
It's not documented that it should work like this - but it does. We use it on production system.
I'd use another collection to 'create' the search results on the fly - as new posts are posted - by upserting a document in this new collection every time a new blog post is posted.
Every new combination of author/tags is added as a new document in this collection, whereas a new post with an existing combination just updates an existing document with the content (or object ID reference) of the new blog post.
Example:
db.searchResult.update(
... {'author_id':'50ad8d451d41c8fc58000099', 'tag_doc.tags': ["TAG-1", "TAG-2" ]},
... { $set: { 'Referenceid':ObjectId("5152bc79e8bf3bc79a5a1dd8")}}, // or embed your blog post here
... {upsert:true}
)
Hmmm, there is no good way of doing this optimally in such a manner that you only need to pick out the latest of each author, instead you will need to pick out all documents, sorted, and then group on author:
db.posts.aggregate([
{$sort: {created_at:-1}},
{$group: {_id: '$author_id', tags: {$first: '$tag_doc.tags'}}},
{$unwind: '$tags'},
{$group: {_id: {author: '$_id', tag: '$tags'}}}
]);
As you said this is not optimal however, it is all I have come up with.
If I am honest, if you need to perform this query often it might actually be better to pre-aggregate another collection that already contains the information you need in the form of:
{
_id: {},
author: {},
tag: 'something',
created_at: ISODate(),
post_id: {}
}
And each time you create a new post you seek out all documents in this unqiue collection which fullfill a $in query of what you need and then update/upsert created_at and post_id to that collection. This would be more optimal.
Here you go:
db.logs.aggregate(
{"$sort" : { "uploaded_at" : -1 } },
{"$match" : { ... } },
{"$unwind" : "$tag_doc.group_x" },
{"$group" : { "_id" : { "case" :'$case_id', tag:'$tag_doc.group_x'},
"latest" : { "$first" : "$uploaded_at"},
"Name" : { "$first" : "$Name" },
"tag_doc" : { "$first" : "$tag_doc"}
}
}
);
You want to avoid $max when you can $sort and take $first especially if you have an index on uploaded_at which would allow you to avoid any in memory sorts and reduce the pipeline processing costs significantly. Obviously if you have other "data" fields you would add them along with (or instead of) "Name" and "tag_doc".