I have done Authentication using Google authentication API.How can I access Google task values into table view and proceed
NSString *googleapi = [NSString stringWithString: #"https://maps.googleapis.com/maps/api/place/search/xml?location=34.0522222,-118.2427778&radius=500&types=bank&sensor=false&key=Your_API_Key"];
NSURL *googlePlacesURL = [NSURL URLWithString:googleapi];
NSData *xmlData = [NSData dataWithContentsOfURL:googlePlacesURL];
For more >> Working with Google Places API in iPhone
Edited Addition...
NSString *usergoogleapi = [NSString stringWithString:#"User_API_Key"];// change this api according to user.
NSString *googleapi = [NSString stringWithFormat: #"https://maps.googleapis.com/maps/api/place/search/xml?location=34.0522222,-118.2427778&radius=500&types=bank&sensor=false&key=%#",usergoogleapi];
Hope, this will help you...
I put some text into the textField like: "Peter.at", and the UIwebview shows all correct (Mag. pharm. Peter MÜLLER)!
The Problem is when I type in the UItextField: "Püter.at", the UIwebView does nothing!
What is wrong? I think it is the "ü" but I don't know how to fix it!
Yep. I see what the problem is.
Your code should look like this:
NSString *preURL = #"";
NSString *middleURL = #".at";
NSString *fullURLString =
[[NSString stringWithFormat:#"%#%#%#",preURL,1.text,middleURL] stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSURL * preparedURL = [[NSURL URLWithString:fullURLString];
[uiwebnamesearch loadRequest: [NSURLRequest requestWithURL: preparedURL]];
[uiwebnamesearch reloadInputViews];
The important change here is that you are "percent escaping" the string, to make it possible to use in a URL.
Here is the documentation for that [NSString stringByAddingPercentEscapesUsingEncoding:] method.
I have problem with NSURL. I am trying to create NSURL with string
code
NSString *prefix = (#"tel://1234567890 ext. 101");
NSString *dialThis = [NSString stringWithFormat:#"%#", prefix];
NSURL *url = [[NSURL alloc] initWithString:dialThis];
NSLog(#"%#",url);
also tried
NSURL *url = [NSURL URLWithString:dialThis];
but it gives null . what is wrong ?
Thanks..
Your problem is the unescaped spaces in the URL. This, for instance, works:
NSURL *url = [NSURL URLWithString:#"tel://1234567890x101"];
Edit: As does this..
NSURL *url2 = [NSURL URLWithString:[#"tel://1234567890 ext. 101"
stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]];
Before passing any string as URL you don't control, you have to encode the whitespace:
NSString *dialThis = [prefix stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
// tel://1234567890%20ext.%20101
As a side note, iOS is not going to dial any extension. The user will have to do that manually.
From Apple URL Scheme Reference: Phone Links:
To prevent users from maliciously redirecting phone calls or changing the behavior of a phone or account, the Phone application supports most, but not all, of the special characters in the tel scheme. Specifically, if a URL contains the * or # characters, the Phone application does not attempt to dial the corresponding phone number.
Im not sure the "ext." in phone number can be replce by what value? but you can try like this,
NSString *prefix = [NSString stringWithString: #"tel://1234567890 ext. 101"];
NSString *dialThis = [NSString stringWithFormat:#"%#", prefix];
NSURL *url = [NSURL URLWithString:[dialThis stringByReplacingOccurrencesOfString:#" ext. " withString:#"#"]];
// it might also represent by the pause symbol ','.
you can go to find the ext. is equivalent to what symbol in the phone, then replace it.
but dunno it can be work in actual situation or not....
As with iOS 9.0,
stringByAddingPercentEscapesUsingEncoding:
has been deprecated.
Use the following method for converting String to NSURL.
let URL = "URL GOES HERE"
let urlString = URL.stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLFragmentAllowedCharacterSet())
If you've got something you think should be a URL string but know nothing about how URL strings are supposed to be constructed, you can use NSURL's URLWithDataRepresentation:relativeToURL: method. It parses the URL string (as bytes in an NSData) and percent-encodes characters as needed. Use the NSUTF8StringEncoding for best results when converting your NSString to NSData.
NSURL *url = [NSURL URLWithDataRepresentation:[#"tel:1234567890 ext. 101" dataUsingEncoding:NSUTF8StringEncoding] relativeToURL:nil];
NSLog(#"%#",url);
creates a URL with the string 1234567890%20ext.%20101
It attempts to do the right thing. However, for best results you should find the specification for the URL scheme you using and follow it's syntax to create your URL string. For the tel scheme, that is https://www.rfc-editor.org/rfc/rfc3966.
P.S. You had "tel://" instead of "tel:" which is incorrect for a tel URL.
Try this one, It works for me....
NSString *prefix = (#"tel://1234567890 ext. 101");
NSString *dialThis = [NSString stringWithFormat:#"%#", prefix];
NSURL *url = [NSURL URLWithString:[queryString stringByReplacingOccurrencesOfString:#" " withString:#"%20"]];
NSLog(#"%#",url);
Make an extension for use in any part of the project as well:
extension String {
var asNSURL: NSURL! {
return NSURL(string: self)
}
}
From now you can use
let myString = "http://www.example.com".asNSURL
or
myString.asNSURL
im kind of a noob on objective c and still are having trouble with some basics, in this case
I'm developing a pdf viewer on xcode, but im having a problem adding a integer to my NSUrl variable.
I have several pdf's on my site:
"http://mysite.com/1.pdf" "2.pdf" etc.
but the number of pdf files allways change so in order to avoid using a NSMutableArray with all the url sites what im trying to make is a NSURL variable like this:
int numpag = 1;
NSString *urlAddress = #"http://mysite.com/%d.pdf", numpag;
[pdfView loadRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:urlAdress]]];
is there a correct way to do this?
Thanks in advance
Try;
NSString *urlAddress = [NSString stringWithFormat:#"http://mysite.com/%d.pdf",numpag];
int numpag = 1;
NSString *baseURLStr = #"http://mysite.com/";
NSURL *url = [NSURL URLWithString:[baseURLStr stringByAppendingFormat:#"%d.pdf", numpag]];
I Have tried
NSString *alertTxt =textfieldName.text;
NSLog(#"Name: %#",alertTxt);
NSURL *urlAddress = [[NSURL alloc ] initWithString: #"%#/login/index.php",alertTxt];
error : too many argument to function initstring ..
the user will giv the url address to the alertText field and i hav to embed in to the webkit may i know the process how to make it !!!
Where im making mistake kindly help me out in this
Thanks
-initWithString: can only take a complete string, not a format string. To use -initWithString: you need to complete the string first.
NSString* urlString = [NSString stringWithFormat:#"%#/login/index.php", alertTxt];
NSURL* urlAddress = [[NSURL alloc] initWithString:urlString];
BTW, it may be more efficient to use -stringByAppendingString:.
NSString* urlString = [alertTxt stringByAppendingString:#"/login/index.php"];