Perl running a batch file #echo command not found - perl

I am using mr on Windows and it allows running arbitrary commands before/after any repository action. As far as I can see this is done simply by invoking perl's system function. However something seems very wrong with my setup: when making mr run the following batch file, located in d:
#echo off
copy /Y foo.bat bar.bat
I get errors on the most basic windows commands:
d:/foo.bat: line 1: #echo: command not found
d:/foo.bat: line 2: copy: command not found
To make sure mr isn't the problem, I ran perl -e 'system( "d:/foo.bat" )' but the output is the same.
Using xcopy instead of copy, it seems the xcopy command is found since the output is now
d:/foo.bat: line 1: #echo: command not found
Invalid number of parameters
However I have no idea what could be wrong with the parameters. I figured maybe the problem is the batch file hasn't full access to the standard command environment so I tried running it explicitly via perl -e 'system( "cmd /c d:\foo.bat" )' but that just starts cmd and does not run the command (I have to exit the command line to get back to the one where I was).
What is wrong here? A detailed explanation would be great. Also, how do I solve this? I prefer a solution that leaves the batch file as is.

The echo directive is executed directly by the running command-prompt instance.
But perl is launching a new process with your command. You need to run your script within a cmd instance, for those commands to work.
Your cmd /c must work. Check if you have spaces in the path you are supplying to it.
You can use a parametrized way of passing arguments,
#array = qw("/c", "path/to/xyz.bat");
system("cmd.exe", #array);
The echo directive is not an executable and hence, it errors out.
The same is true of the copy command also. It is not an executable, while xcopy.exe is.

Related

how to run a cmd file from matlab

I am trying to run a cmd file from MATLAB but unable to execute it. Can anybody see nay problem in the below code?
this is what I have inside my cmd file:
echo on
>test.log 2>&1 (
C:/testProj/Make/makeit.cmd param1
)
And this is the MATLAB code:
Out = 'C:/testProj/test.cmd';
system(Out);
But this actually does not run the cmd file.
Well for somereason it would not run if i would give the complete path of the cmd in bat file. so I had a cd command to change the directory and then run. now it runs fine, Thanks all appreciate your help!
What about using eval, like this:
eval(['!test.cmd']);
I have succesfully used this to run .bat files (and this output of the .bat script showed in my matlab command line). I also found this dos command, but I am not sure if it works allright:
You can just type the following strings to get things down:
!(c:/testProj/test.cmd)
This is actually no different from
system('c:/testProj/test.cmd')
I think you should check if the path is wrong. As to your code in the cmd file, that's beyond my ability to help.

Running Executable from Shell Script

I am having trouble launching an executable that I have created from a shell script. I would like to automate testing by running the program many times with different command line options to verify it is working.
When I type echo $SHELL, /bin/sh is displayed.
The following is my shell script:
#!/bin/sh
clear
echo "Running first test."
./myProgram
exit 0
When I run the script (sh myScript.sh), with myProgram in the same directory, I see the following output:
Running first test.
: not foundsh: line 4:
When executing the program ./myProgram, it runs as expected with no command line options.
I have also tried:
myProgram
./myProgram &
myProgram &
based on answers to somewhat similar questions, but they all result in the above error message.
Your newlines are goofed. Use dos2unix to fix.
why don't you try using the full path?
e.g., if myProgram is in /home/user1/bin, you can try /home/user1/bin/myProgram instead of ./myProgram. This should work.
You can also add the path to path variable, $PATH and directly call myProgram from anywhere.
Run "export PATH=$PATH:/home/user1/bin" on your terminal without the quotes. Note that this affects only your current termial session. If you want to permanently add the path, update your .bashrc file in your home directory with the following line:

try run to `eof script batch file` (.bat)

I have scrip contain command line:
set dir=%1
cd %dir%
test.bat
echo successful
When run this script, file test.bat (this file run phpunit) run complete then this script don't run command line echo successful.
So, how to try run to eof script.
Use call test.bat.
When you try running a batch file from another batch like in your question control does not pass back to your calling batch.
Side note: I'd usually use pushd/popd for going into directories from batch files. At least I prefer when a batch file doesn't have a side-effect on the shell I'm working on (similar rationale for setlocal). Also this solves the problem when you pass a directory on another drive (although you could do cd /d in that case.

How is this zip command being used in perl?

I found this piece of code in perl
system("zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude");
However I don't understand how it is working. I mean system() is used to fire 'system' commands right ? So is this 'zip' command used here a 'system' command ?
But I tried firing just the following on the command prompt;
zip $ZIP_DEBUG -r -9 itvlib.zip arg1 arg2
It didn't work !
it gave the following error:
'zip' is not recognized as an internal or external command,
operable program or batch file.
Well this shouldn't have happened, since the command seems to use 'zip' as a system command. So this makes the command 'zip' mysterious
Can you please help me to understand this command with all its parameters?
It's probably not working since you're not replacing things like $ZIP_DEBUG with their equivalent real values. Within Perl, they will be replaced with the values of the variables before being passed to the system call.
If you print out those Perl variables (or even the entire command) before you execute that system call, you'll find out those real values that you need to use. You can use the following transcript to guide you:
$ perl -e '
> $ZIP_DEBUG = "xyzzy";
> $include = "inc_files";
> $exclude = "exc_files";
> print "zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude";
> '
zip xyzzy -r -9 itvlib.zip inc_files exc_files
For details on how system works, see here. For details on what zip needs to function, you should just be able to run:
man zip
from a command line shell (assuming you're on Linux or its brethren). If, instead, you're on a different operating system (like Windows), you'll have to figure out how to get the zip options out. This may well be as simple as zip -? of zip -h but there's no guarantee that will work.
If it's the same as the Info-ZIP zip under Linux (and it may be if you have the -9 and -r options and your exclude variable starts with -x), then zip -h will get you basic help and zip -h2 will give you a lot more.
system("zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude");
is running a program named zip (probably zip.exe) somewhere on the path. $ZIP_DEBUG, $include, and $exclude are Perl variables that are interpolated into the command line before the command is run.
If the system call works in the Perl script, but zip -? gives the 'zip' is not recognized as an internal or external command, operable program or batch file error, then the PATH of the Perl script must be different than the PATH in your command prompt. Or, there might be a zip command in the current directory when Perl executes the system command. (In Windows, the current directory is an implicit member of your PATH.)
To see what the PATH is for the Perl script, you can add a print "$ENV{PATH}\n"; before the system command. To see what the PATH is in your command prompt, type PATH.
Yes, zip is a system command. The variables $ZIP_DEBUG and such are perl variables that are interpolated to the command before launching zip.
To debug what the actual call is, try adding:
print("zip $ZIP_DEBUG -r -9 itvlib.zip $include $exclude\n");
See perldoc for details on system.

Disable powershell expansion of command's extension?

We have a lot of existing batch files that help with the running of different perl and ruby scripts.
A batch file (e.g. test.bat) would normally be invoked like:
$ test
and within the batch file, it will set some settings and finally try to run the corresponding script file (e.g. test.pl) like this:
perl -S "%0.pl" %*
All works with cmd.exe, but today, I decided to switch to PowerShell and found out that it expands the commands. So trying to run "test" will actually run "Full\path\test.bat" and my script would complain that there is no file test.bat.pl.
Is there a way to prevent this command expansion? Rewriting all batch files is not an option.
One way is to call cmd explicitly:
cmd /c test