I am working on a extension in which Customer subscribe for Promotion, when Customer subscribe I will save user id, product id.
In subscriber module, I have to show Customer Name and Product Name.
So My Question is how can we Show Another Model Data in Grid?
If your extension uses a grid that extends Mage_Adminhtml_Block_Widget_Grid, you can modify the _prepareCollection() function to include data from other source (via joins). Also you will have to add new columns to the grid, which can be done in function __prepareColumns().
For an example look at the grid block of the Mage_Newsletter module Mage_Adminhtml_Block_Newsletter_Subscriber_Grid
Related
We have a custom field on our Customer form "client_type" and would like to be able to reference the same field's values on the Customer's Contacts as well on the Contact form. The data is populated for all Customers currently, though when creating the custom field on the Contact form and selecting
SOURCE LIST -> Parent & SOURCE FROM -> client_type the Contact records do not have any data populated. Tried waiting to see if this was a caching issue as we saw with another modification in NS we did recently and there was no solution.
I am working on Azure C# project. There is webrole with web form collecting customer’s information.
Depending on the information, they submit I need to create new custom web form for each one of them.
How can I generate new web form with custom web controls inside same site with code? I would prefer not create different site for each customer.
Any ideas appreciated!
You don't have to create a custom web form for each customer, you can have it all in on dynamic form and draw the input controls according to the customer.
You will have to have a form a form or a database table to configure the input needed for each customer which will be used in drawing the form.
ex:
You can have a table named: CustomerAttibute with the following columns
Customer ID
Attribute Name
Attribute Type (Number, text, boolean, ...)
Is Required
Validation Reg Expression
In the web form, you will read the customer ID and retrieve the attributes related to that customer, and use these attributes to draw the form, ex: an attribute of type text will be rendered as a textbox but an attribute of type boolean will be rendered as a checkbox
Capture the values from the user and insert it into another table, ex: CustomerAttributeValue which will have the attribute ID and attribute value, the value will be string to accommodate for any type
I am a beginner in java play framework. I an building an app which will take form data spread in multiple pages say 4 to 5 pages. But all the data is mapped to same model. How can I get the data uploaded by user per page, validate against my model's constraints, and at the end save whole data in my model.
For ex:- If page 1 has name field which is required, and page 2 has hobbies field which is required. Then how can i specifically validate data filled in that particular page, navigate till last page, and save all the data in model, in last page.
Model would have 60-70 fields.
I am using Hibernate ORM.
Thanks !
You could prefill the next form with the values of the last form, save them in the database, go to the next form, load the entered values from the values and pre-fill the next form and so on. For this, use a method in your controller:
public static Result fillOutForm1(){
Hobby form1 = new Hobby("sitting still", "diabetes");
Form<Hobby > preFilledForm = newHobbyForm.fill(form1);
return ok(views.html.YOURVIEWCLASS.render(preFilledForm);
}
With this you "send" some values to the first view class with a form. In there, the user answers some more fields and hits Submit.
So you need a route back to your controller, to handle the new input in routes.conf:
GET /Form1 controllers.Application.fillOutForm1()
POST /Form1 controllers.Application.sendForm1()
This is in your controller class:
public static Result sendForm1(){
Form<Hobby> boundHobby = newHobbyForm.bindFromRequest();
Hobby newHobby = boundHobby.get();
//In your hobby class you need a finder implementation, so that you can interact with the database. With save() you put it into the database. This may be different for the database you use!
newHobby.save();
return redirect(routes.Application.index());
}
You can then not redirect to the index, but to the next view class with the next form and there get your last answers from the db, prefill them again and put them into the form. Do this as often as you need.
I have two entities: product and category (Symfony 2.3).
I want to create a form in which an user can choose a product by first selecting the category. A user selects the category by clicking on image, then I want to set the image's value into a hidden input, but I don't see how can I change a foreign entity choice list to a hidden input (http://symfony.com/doc/current/reference/forms/types/entity.html).
How can I accomplish this? (how to change form input to hidden)
If I set cascade validation to true, will it for example check if a category really exist. (To prevent putting products with non-existing category from malicious users) ?
Part 1
To do this you need to use a data transformer to do two things:
transform an entity into an identifier that is either a string or integer so a form can render it as a hidden field.
transform the string or integer identifier into the entity when the form is submitted so that the parent entity can be saved with the correct relationship
The symfony docs I linked to above (here too) actually walk though an entire example of using a data transformer with a form.
As a shameless plug (because I believe it is helpful) I have written a little tutorial on using a data transformer for a hidden field with an entity id: http://lrotherfield.com/blog/symfony2-forms-entity-as-hidden-field/
Part 2
If you are using the data transformer then you don't need to worry about malicious users. The data transformer will fail because it will not be able to reverse transform the category from the fake id. In my tutorial the transformer will throw a Symfony\Component\Form\Exception\TransformationFailedException exception.
You can also write a validator (potentially using a call back) if you wanted that checks that the submitted category is real if you want an error to show in the form. Doctrine wont allow you to persist a fake category relationship as the foreign key constraint will fail.
Background
I was given the task of writing a Small Business online database. This database is to include a lot of info as well as info on their directors and branches. Since any business can have an unlimited amount of directors and branches, I need to create a database that is not limited to just one director and/or branch.
What do I have
Currently I have 3 tables.
smmes [id, company_name, trading_name, business_address, registration_number, tax_reference, vat_number, bbbee_status, employees, awards, created, modified]
ownerships [id, smme_id, name, surname, gender, age, race, disability, qualification, created, modified]
branches [id, smme_id, location, contact_number, contact_person, created, modified]
Note: smme_id is the id of the company in smmes that the branch or director belongs to.
And I have a view for the SMME's.
What is my question
I'm VERY new to cakePHP (in fact, this is my first app I'm creating with cakePHP). I want to know how I can make one form where a user can enter all this detail and then add the details for all directors and branches from one view. I would prefer that they do not have various views to go through to create all the details. Add to that, this one view should then save all the data to the correct tables with the correct smme_id.
Is this possible or should I rather leave cakePHP and write it manually.
You can load model on demand in your controller and then pass model specific data(received from posted form) to loaded model's save method.
public function detail(){
if($this->request->is('post')): // update only when form is posted
$this->loadModel('ownerships');
$owner_name= $this->request->data['Ownername'];
$ownerships_data = array('Ownership' = > array(
'name' = > $owner_name
//add other keys from posted form
)
);
$this->Ownership->saveAll($ownerships_data);
// load other models for saving posted data in related tables
endif;
}
Similarly load other models and pass fields from posted form as array to it's save method.
Suppose URL format is http://example.com/director/detail.So you would like to put above method(termed as action in MVC terminology) in app/controllers/directors_controller.php
Generally if URL format is http://somesite.com/abc/xyz it will look for xyz action in
app/controllers/abcs_controller.php
You can read more about cake conventions here