overhead of reserving address space using mmap - mmap

I have a program that routinely uses massive arrays, where the memory is allocated using mmap
Does anyone know the typical overheads of allocating address space in large amounts before the memory is committed, either if allocating with MAP_NORESERVE or backing the space with a sparse file? It5 strikes me mmap can't be free since it must make page table entries for the allocated space. I want to have some idea of this overhead before implementing an algorithm I'm considering.
Obviously the answer is going to be platform dependent, im most interested in x64 linux, sparc solaris and sparc linux. I'm thinking that the availability of 1mb pages makes the overhead rather less on a sparc than x64.

The overhead of mmap depends on the way you use it. And it is typically negligible when you use it in an appropriate way.
In linux kernel, mmap operation can be divided into two parts:
look for a free address range that can hold the mapping
Create/enlarge vma struct in address space (mm_struct)
So allocate large amount of memory use mmap do not introduce more
overhead than small ones.
So you should allocate memory as larger as possible in each time. (avoid mutiple times of small mmap)
And you may provide the start address explicitly (if possible). This could save some time in kernel in looking for an large enough free space.
If your application is an multi-threaded program. You should avoid concurrent calls to mmap. That is because the address space is protected by a reader-writer lock and the mmap always takes the writer lock. mmap latency will be orders of magnitude greater in this case.
Moreover, mmap only create the mapping but not the page table. Pages are allocated in the page fault handler when being touched. Page fault handler would take the reader lock that protects address space and can also affects mmap performance.
In this case, you should always try to reuse your large array instead of munmap it and mmap again. (Avoid pagefaults)

Related

Why is there no memory translation on the heap?

I'm trying to understand why there is no compaction on the heap. Why is no memory translation possible, if the data is allocated by the program?
Typically the only translation is translating virtual addresses that the program uses into physical addresses that the hardware uses.
Compacting the heap in virtual memory would involve changing the virtual addresses that a program uses, which is expensive or impossible unless all the overhead already exists for other reasons (some approaches to garbage collection).
Fortunately the way the translation (of virtual addresses into physical addresses) works means that you can have unused gaps in virtual memory (or in the heap) that don't cost anything; so for larger gaps (above the system's page size) there isn't much to gain from compacting the heap. Smaller gaps are more likely to be too small to care about (you really don't want to move 1234 MiB of data just to get rid of a little 123 byte gap).

Memory Address Translation in OS

Is Memory address translation only useful when the total size of virtual memory
(summed over all processes) needs to be larger than physical memory?
Basically, the size of virtual memory depends on what you call "virtual memory". If you call virtual memory the virtual memory of one process then virtual memory has the same size than physical memory. If you call virtual memory the whole virtual memory of all processes than virtual memory can (technically) have an infinite size. This is because every process can have a whole address space. The virtual address space of one process cannot be bigger than physical memory because the processor has limited bits to address this memory. In modern long mode the processor has only 48 bits to address RAM at the byte level. This gives a very big amount of RAM but most systems will have 8GB to 32GB.
Technically on a 8GB RAM computer, every process could have 8GB allocated. I say technically because eventually, the computer will constantly be removing page frames from RAM and that will put too much overhead on the OS and on the computer which will make your system freeze. In the end, the size of the sum of the virtual memory of every process is limited by the capacity of your system (and OS) to have an efficient page swapping algorithm (and on your willingness to have a slow system).
Now to answer your question, paging (virtual memory) is used also to avoid fragmentation and for securing the system. With the old segmentation model, fragmentation was an issue because you had to run a complex algorithm to determine which part of memory a process gets. With paging, the smallest granularity of memory is 4KB. This makes everything much easier because a small process just gets a 4KB page and the process can work in that page the way it wants. While a bigger process will get several pages and can allocate more pages by doing a system call. There is still the issue of external fragmentation but it is mostly due to latency of accessing high memory vs low memory. Basically, paging solves the issue of external fragmentation because a process can get a page anywhere (where it's available) and it will not make a difference (except for high vs low memory). There is still the issue of internal fragmentation with paging.
Paging also secures the system. With segmentation you had several levels of ring protection. With paging you have only user or supervisor. With segmentation, the memory is not well protected because one process can access the memory of another process in the same segment. With paging, there are 2 different protections. The first protection is the ring itself (user vs supervisor) the second are the page tables. The page tables isolate one process from another because the memory accesses are translated to other positions in RAM. It is the job of the OS to fill the page tables properly so that one process doesn't have access to the physical memory allocated to another process. The user vs supervisor bit in the page tables, prevent one process from accessing the kernel except via a system call interface (the instruction syscall in assembly for x86).

Where are multiple stacks and heaps put in virtual memory?

I'm writing a kernel and need (and want) to put multiple stacks and heaps into virtual memory, but I can't figure out how to place them efficiently. How do normal programs do it?
How (or where) are stacks and heaps placed into the limited virtual memory provided by a 32-bit system, such that they have as much growing space as possible?
For example, when a trivial program is loaded into memory, the layout of its address space might look like this:
[ Code Data BSS Heap-> ... <-Stack ]
In this case the heap can grow as big as virtual memory allows (e.g. up to the stack), and I believe this is how the heap works for most programs. There is no predefined upper bound.
Many programs have shared libraries that are put somewhere in the virtual address space.
Then there are multi-threaded programs that have multiple stacks, one for each thread. And .NET programs have multiple heaps, all of which have to be able to grow one way or another.
I just don't see how this is done reasonably efficient without putting a predefined limit on the size of all heaps and stacks.
I'll assume you have the basics in your kernel done, a trap handler for page faults that can map a virtual memory page to RAM. Next level up, you need a virtual memory address space manager from which usermode code can request address space. Pick a segment granularity that prevents excessive fragmentation, 64KB (16 pages) is a good number. Allow usermode code to both reserve space and commit space. A simple bitmap of 4GB/64KB = 64K x 2 bits to keep track of segment state gets the job done. The page fault trap handler also needs to consult this bitmap to know whether the page request is valid or not.
A stack is a fixed size VM allocation, typically 1 megabyte. A thread usually only needs a handful of pages of it, depending on function nesting level, so reserve the 1MB and commit only the top few pages. When the thread nests deeper, it will trip a page fault and the kernel can simply map the extra page to RAM to allow the thread to continue. You'll want to mark the bottom few pages as special, when the thread page faults on those, you declare this website's name.
The most important job of the heap manager is to prevent fragmentation. The best way to do that is to create a lookaside list that partitions heap requests by size. Everything less than 8 bytes comes from the first list of segments. 8 to 16 from the second, 16 to 32 from the third, etcetera. Increasing the size bucket as you go up. You'll have to play with the bucket sizes to get the best balance. Very large allocations come directly from the VM address manager.
The first time an entry in the lookaside list is hit, you allocate a new VM segment. You subdivide the segment into smaller blocks with a linked list. When such an allocation is released, you add the block to the list of free blocks. All blocks have the same size regardless of the program request so there won't be any fragmentation. When the segment is fully used and no free blocks are available you allocate a new segment. When a segment contains nothing but free blocks you can return it to the VM manager.
This scheme allows you to create any number of stacks and heaps.
Simply put, as your system resources are always finite, you can't go limitless.
Memory management always consists of several layers each having its well defined responsibility. From the perspective of the program, the application-level manager is visible that is usually concerned only with its own single allocated heap. A level above could deal with creating the multiple heaps if needed out of (its) one global heap and assigning them to subprograms (each with its own memory manager). Above that could be the standard malloc()/free() that it uses and above those the operating system dealing with pages and actual memory allocation per process (it is basically not concerned not only about multiple heaps, but even user-level heaps in general).
Memory management is costly and so is trapping into the kernel. Combining the two could impose severe performance hit, so what seems to be the actual heap management from the application's point of view is actually implemented in user space (the C runtime library) for the sake of performance (and other reason out of scope for now).
When loading a shared (DLL) library, if it is loaded at program startup, it will of course be most probably loaded to CODE/DATA/etc so no heap fragmentation occurs. On the other hand, if it is loaded at runtime, there's pretty much no other chance than using up heap space.
Static libraries are, of course, simply linked into the CODE/DATA/BSS/etc sections.
At the end of the day, you'll need to impose limits to heaps and stacks so that they're not likely to overflow, but you can allocate others.
If one needs to grow beyond that limit, you can either
Terminate the application with error
Have the memory manager allocate/resize/move the memory block for that stack/heap and most probably defragment the heap (its own level) afterwards; that's why free() usually performs poorly.
Considering a pretty large, 1KB stack frame on every call as an average (might happen if the application developer is unexperienced) a 10MB stack would be sufficient for 10240 nested call -s. BTW, besides that, there's pretty much no need for more than one stack and heap per thread.

How does external fragmentation happen?

As processes are loaded and removed from memory , the free memory space is broken into little pieces ,causing fragmentation ... but how does this happen ?
And what is the best solution to external fragmentation ?
External fragmentation exists when there is enough total memory to satisfy a request (from a process usually), but the total required memory is not available at a contiguous location i.e, its fragmented.
Solution to external fragmentation :
1) Compaction : shuffling the fragmented memory into one contiguous location.
2) Virtual memory addressing by using paging and segmentation.
External Fragmentation
External fragmentation happens when a dynamic memory allocation algorithm allocates some memory and a small piece is left over that cannot be effectively used. If too much external fragmentation occurs, the amount of usable memory is drastically reduced. Total memory space exists to satisfy a request, but it is not contiguous.
see following example
0x0000 0x1000 0x2000
A B C //Allocated three blocks A, B, and C, of size 0x1000.
A C //Freed block B
Now Notice that the memory that B used cannot be included for an allocation larger than B's size
External fragmentation can be reduced by compaction or shuffle memory contents to place all free memory together in one large block. To make compaction feasible, relocation should be dynamic.External fragmentation is also avoided by using paging technique.
The best solution to avoid external fragmentation is Paging.
Paging is a memory management technique usually used by virtual memory operating systems to help ensure that the data you need is available as quickly as possible.
for more see this : What's the difference between operating system "swap" and "page"?
In case of Paging there is no external fragmentation but it doesn't avoid internal fragmentation.

What's the difference between "virtual memory" and "swap space"?

Can any one please make me clear what is the difference between virtual memory and swap space?
And why do we say that for a 32-bit machine the maximum virtual memory accessible is 4 GB only?
There's an excellent explantation of virtual memory over on superuser.
Simply put, virtual memory is a combination of RAM and disk space that running processes can use.
Swap space is the portion of virtual memory that is on the hard disk, used when RAM is full.
As for why 32bit CPU is limited to 4gb virtual memory, it's addressed well here:
By definition, a 32-bit processor uses
32 bits to refer to the location of
each byte of memory. 2^32 = 4.2
billion, which means a memory address
that's 32 bits long can only refer to
4.2 billion unique locations (i.e. 4 GB).
There is some confusion regarding the term Virtual Memory, and it actually refers to the following two very different concepts
Using disk pages to extend the conceptual amount of physical memory a computer has - The correct term for this is actually Paging
An abstraction used by various OS/CPUs to create the illusion of each process running in a separate contiguous address space.
Swap space, OTOH, is the name of the portion of disk used to store additional RAM pages when not in use.
An important realization to make is that the former is transparently possible due to the hardware and OS support of the latter.
In order to make better sense of all this, you should consider how the "Virtual Memory" (as in definition 2) is supported by the CPU and OS.
Suppose you have a 32 bit pointer (64 bit points are similar, but use slightly different mechanisms). Once "Virtual Memory" has been enabled, the processor considers this pointer to be made as three parts.
The highest 10 bits are a Page Directory Entry
The following 10 bits are a Page Table Entry
The last 12 bits make up the Page Offset
Now, when the CPU tries to access the contents of a pointer, it first consults the Page Directory table - a table consisting of 1024 entries (in the X86 architecture the location of which is pointed to by the CR3 register). The 10 bits Page Directory Entry is an index in this table, which points to the physical location of the Page Table. This, in turn, is another table of 1024 entries each of which is a pointer in physical memory, and several important control bits. (We'll get back to these later). Once a page has been found, the last 12 bits are used to find an address within that page.
There are many more details (TLBs, Large Pages, PAE, Selectors, Page Protection) but the short explanation above captures the gist of things.
Using this translation mechanism, an OS can use a different set of physical pages for each process, thus giving each process the illusion of having all the memory for itself (as each process gets its own Page Directory)
On top of this Virtual Memory the OS may also add the concept of Paging. One of the control bits discussed earlier allows to specify whether an entry is "Present". If it isn't present, an attempt to access that entry would result in a Page Fault exception. The OS can capture this exception and act accordingly. OSs supporting swapping/paging can thus decide to load a page from the Swap Space, fix the translation tables, and then issue the memory access again.
This is where the two terms combine, an OS supporting Virtual Memory and Paging can give processes the illusion of having more memory than actually present by paging (swapping) pages in and out of the swap area.
As to your last question (Why is it said 32 bit CPU is limited to 4GB Virtual Memory). This refers to the "Virtual Memory" of definition 2, and is an immediate result of the pointer size. If the CPU can only use 32 bit pointers, you have only 32 bit to express different addresses, this gives you 2^32 = 4GB of addressable memory.
Hope this makes things a bit clearer.
IMHO it is terribly misleading to use the concept of swap space as equivalent to virtual memory. VM is a concept much more general than swap space. Among other things, VM allows processes to reference virtual addresses during execution, which are translated into physical addresses with the support of hardware and page tables. Thus processes do not concern about how much physical memory the system has, or where the instruction or data is actually resident in the physical memory hierarchy. VM allows this mapping. The referenced item (instruction or data) may be resident in L1, or L2, or RAM, or finally on disk, in which case it is loaded into main memory.
Swap space it is just a place on secondary memory where pages are stored when they are inactive. If there is no sufficient RAM, the OS may decide to swap-out pages of a process, to make room for other process pages. The processor never ever executes instruction or read/write data directly from swap space.
Notice that it would be possible to have swap space in a system with no VM. That is, processes that directly access physical addresses, still could have portions of it on
disk.
Though the thread is quite old and has already been answered. Still would like to share this link as this is the simplest explanation I have found so far. Below link has got diagrams for better visualization.
Key Difference: Virtual memory is an abstraction of the main memory. It extends the available memory of the computer by storing the inactive parts of the content RAM on a disk. Whenever the content is required, it fetches it back to the RAM. Swap memory or swap space is a part of the hard disk drive that is used for virtual memory. Thus, both are also used interchangeably.
Virtual memory is quiet different from the physical memory. Programmers get direct access to the virtual memory rather than physical memory. Virtual memory is an abstraction of the main memory. It is used to hide the information of the real physical memory of the system. It extends the available memory of the computer by storing the inactive parts of the RAM's content on a disk. When the content is required, it fetches it back to the RAM. Virtual memory creates an illusion of a whole address space with addresses beginning with zero. It is mainly preferred for its optimization feature by which it reduces the space requirements. It is composed of the available RAM and disk space.
Swap memory is generally called as swap space. Swap space refers to the portion of the virtual memory which is reserved as a temporary storage location. Swap space is utilized when available RAM is not able to meet the requirement of the system’s memory. For example, in Linux memory system, the kernel locates each page in the physical memory or in the swap space. The kernel also maintains a table in which the information regarding the swapped out pages and pages in physical memory is kept.
The pages that have not been accessed since a long time are sent to the swap space area. The process is referred to as swapping out. In case the same page is required, it is swapped in physical memory by swapping out a different page. Thus, one can conclude that swap memory and virtual memory are interconnected as swap memory is used for the technique of virtual memory.
difference-between-virtual-memory-and-swap-memory
"Virtual memory" is a generic term. In Windows, it is called as Paging or pagination. In Linux, it is called as Swap.