how can I get formatted address - iphone

How can I get formatted address like Covington, AL, USA of google web service in my iphone
from the below url
http://maps.google.com/maps/api/geocode/xml?latlng=31.319016,-86.399871&sensor=false

- (void) getAddress
{
NSData *data = [NSData dataWithContentsOfURL:[NSURL URLWithString:#"http://maps.google.com/maps/api/geocode/json?latlng=31.319016,-86.399871&sensor=false"]];
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingAllowFragments error:nil];
NSString *str = [[[dict objectForKey:#"results"] objectAtIndex:0] valueForKey:#"formatted_address"];
NSLog(#"Address = %#", str);
}
Use this json this is much faster that xml.

Related

How to format a ReturnString Array from a webService

I get a returnString from a WebService in iOS:
[
{"datum":"2013-07-24
09:38:43","nummer":"1017348010239480212208","anmerkung":"Elektronische
Auftragsdaten wurden vom Versender
\u00fcbermittelt"},{"datum":"2013-07-24
09:38:44","nummer":"1017348010239480212208","anmerkung":"Sendung in
Verteilung"},{"datum":"2013-07-24
09:38:44","nummer":"1017348010239480212208","anmerkung":"Sendung in
Verteilung"},{"datum":"2013-07-24
09:38:44","nummer":"1017348010239480212208","anmerkung":"Sendung in
Zustellung"},{"datum":"2013-07-24
09:26:06","nummer":"1017348010239480212208","anmerkung":"Empf\u00e4nger
nicht angetroffen - benachrichtigt"},{"datum":"2013-07-19
06:24:42","nummer":"1017348010239480212208","anmerkung":"Sendung in
Post-Empfangsbox eingelangt"}
]
the Objective C Code works fine:
#import "SBJson.h"
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
self.textfeld.text = [NSString stringWithFormat: #"%#", returnString];
I try to format the Response with NSMutableArray or NSArray and JSONValue but without success :
NSMutableArray *meinErgebnis = [responseString JSONValue];
NSLog(#"%#",[[meinErgebnis objectAtIndex:0] objectAtIndex:1]);
How to format the returnCode like that?
Nummer: 1017348010239480212208
Anmerkung: Sendung in Verteilung
Nummer: 1017348010239480212208
Anmerkung: Sendung in Post-Empfangsbox
You can obtain Data with following method,
id Data = [NSJSONSerialization JSONObjectWithData:fetchedData options:kNilOptions error:&error];
Then you can loop the data accordingly. For your example,
for(id object in Data)
{
NSLog(#"%#",[object valueForKey:#"nummer"]);
NSLog(#"%#",[object valueForKey:#"anmerkung"]);
}
The loop used above is of fast Enumeration type. Hope this helps.
Use following code for get all the values of nummer and anmerkung from your mutable array.
NSMutableArray *meinErgebnis = [responseString JSONValue];
for(int i = 0; i < meinErgebnis.count; i++)
{
NSLog(#"%#",[[meinErgebnis objectAtIndex:i] objectForKey:#"nummer"]);
NSLog(#"%#",[[meinErgebnis objectAtIndex:i] objectForKey:#"anmerkung"]);
}

How do I extract a value from the following code?

How do I extract just the "token" value from the following code? I'm looking to save this value into a string.
Is meta an array? If so how would I extract the data from the "token" value?
thanks for any help
NSString *responseData = [[NSString alloc]initWithData:urlData encoding:NSUTF8StringEncoding];
Response ==> {"meta":[],"data":{"token":"IVZ2ciRkbVtDLUl3YmhwOTkyXzpRR1M3LUUsRiElfWF6T3I6dCxsRWg6di1XcyR6OTUzZHhVazdLTEJ7blU5O258d2xRTXg0VUxwQXBlNHRSOXd2VXZ1aG1RfFhQQjJsSkkoc2IuOTFyYkYodyhAe2RldXR1aDF3RClXWyhoMiU="}}
2013-07-19 15:10:23.139 appName [11190:907] {
data = {
token = "IVZ2ciRkbVtDLUl3YmhwOTkyXzpRR1M3LUUsRiElfWF6T3I6dCxsRWg6di1XcyR6OTUzZHhVazdLTEJ7blU5O258d2xRTXg0VUxwQXBlNHRSOXd2VXZ1aG1RfFhQQjJsSkkoc2IuOTFyYkYodyhAe2RldXR1aDF3RClXWyhoMiU=";
};
meta = (
);
}
I believe the data is in JSON format. In that case, this should work.
NSError *error = nil;
NSDictionary *responseDict = [NSJSONSerialization JSONObjectWithData:urlData options:0 error:&error];
NSString *token = [[responseDict objectForKey:#"data"] objectForKey:#"token"];
I'd just do this:
NSData *responseData = [NSData dataWithContentsOfURL:yourURL];
NSString *token = [NSJSONSerialization JSONObjectWithData:responseData
options:kNilOptions error:NULL][#"data"][#"token"];
It will be nil if there's any error.
In your Case, meta is an Array and data is a Dictionary. If your Response is properly formatted in JSON then you can use the below sample code to get the TokenString and metaArray.
Sample Code :
NSData *data = [NSData dataWithContentsOfURL:yourURL];
NSError* error = nil;
NSDictionary* responseDict = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
NSString *token = [[responseDict objectForKey:#"data"] objectForKey:#"token"];
NSArray *meta = [responseDict objectForKey:#"meta"];
NSLog(#"\ntoken :: %#\nmeta :: %#",token,meta);
PS : To know more about JSON response , take a look at this Answer.

Break String that came from Json

I have a String that I got from a webserver which came in json format, but the string is huge with everything in it. I tried using the NSDICTIONARY but to no success. I was wondering what would be the best approach to break this string and add to different strings and eventually put it all in a class of strings. Thanks for the help! Here is my code:
NSMutableURLRequest *request = [[NSMutableURLRequest alloc]init];
[request setURL:[NSURL URLWithString:#"http://mym2webdesign.com/meiplay/paulsuckedabuffalo/artists.php"]];
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; //Or async request
returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSError *error=nil;
NSLog(#"HHHHHHHHHHHHHH"); //use this to know how far Im getting
NSLog(returnString); // Look at the console and you can see what the restults are
/*NSDictionary *results = [returnString JSONValue];
NSString *ID = [results objectForKey:#"ID"]; // for example
NSLog(#"ID Number: %#", ID);*/
Here is some of the log i get:
[{"ID":"1","name":"kevin","bio":"kevins bio"},{"ID":"1","name":"kevin","age":"20"},{"ID":"2","name":"Cesar","bio":"Cesar bio"},{"ID":"2","name":"Cesar","age":"19"},{"ID":"3", "name":"Katherine", "bio":"Katherines bio"},{"ID":"3", "name":"Katherine", "age":"22"}]
You are doing it wrong. Its a NSArray of NSDictionaries. So first you need to assign it to NSArray and then loop over it to get each individual NSDictionary. See below.
NSArray *results = [returnString JSONValue];
for(NSDictionary *record in results)
{
NSLog(#"ID: %#", [record objectForKey:#"ID"]);
}
You'll probably be better off just using NSJSONSerialization if your app is targeted for at or over iOS 5.0:
NSArray *JSONArray = [NSJSONSerialization JSONObjectWithData:returnData options:0 error:&error];
You might need to experiment with using NSArray vs. NSDictionary, etc., but this should be an overall simpler solution.
Try this :
NSArray *results = [returnString JSONValue];
for (int i=0; i<[results count];i++) {
NSDictionary *DetailDictonary=[results objectAtIndex:i];
NSString *strid=[DetailDictonary objectForKey:#"ID"];
NSString *strName=[DetailDictonary objectForKey:#"name"];
NSString *strBio=[DetailDictonary objectForKey:#"bio"];
// Or You can set it in Your ClassFile
MyClass *classObj=[[MyClass alloc] init];
classObj.strid=[DetailDictonary objectForKey:#"ID"];
classObj.strName=[DetailDictonary objectForKey:#"name"];
classObj.strBio=[DetailDictonary objectForKey:#"bio"];
[YourMainArray addObject:classObj]; //set YourClass to Array
[classObj release];
}

NSJSONSerialization Not Creating Key Value Pairs

I am using iOS 5 new feature to parse JSON and I have no idea that why I am not getting any key value pairs. "aStr" (string representation of data) is putting the right JSON on the output window but I am getting nothing in "dicData" and there is no error either.
Any help is greatly appreciated.
This is what I am using
NSError *error = nil;
NSData *data = [NSData dataWithContentsOfURL:[NSURL URLWithString:#"http://www.macscandal.com/?json=get_post&post_id=436"]];
NSString* aStr;
aStr = [[NSString alloc] initWithData:data encoding:NSASCIIStringEncoding];
//NSLog(#"data = %#",aStr);
NSDictionary *dicData = [NSJSONSerialization
JSONObjectWithData:data
options:NSJSONReadingAllowFragments
error:&error];
//NSLog(#"error = %#",error);
NSString *title = [dicData objectForKey:#"title"];
Your JSON is formatted this way:
{
"status": "ok",
"post": {
"id": 436,
"type": "post",
"slug": "foxconn-likely-to-get-assembly-contract-for-apple-tv-set",
"url": "http:\/\/www.macscandal.com\/index.php\/2011\/12\/28\/foxconn-likely-to-get-assembly-contract-for-apple-tv-set\/",
"status": "publish",
"title": "Foxconn Likely to get Assembly Contract for Apple TV Set",
...
I haven't used NSJSONSerialization but just following the natural JSON parsing alg this is how I would try to get it.
NSDictionary *dicData = [NSJSONSerialization
JSONObjectWithData:data
options:NSJSONReadingAllowFragments
error:&error];
NSDictionary *postData = [dicData objectForKey:#"post"];
NSString *title = [postData objectForKey:#"title"];
EDIT
Just a simple check method:
-(void)check{
NSError *error = nil;
NSData *data = [NSData dataWithContentsOfURL:[NSURL URLWithString:#"http://www.macscandal.com/?json=get_post&post_id=436"]];
NSDictionary *dicData = [NSJSONSerialization
JSONObjectWithData:data
options:NSJSONReadingAllowFragments
error:&error];
NSDictionary *postData = [dicData objectForKey:#"post"];
NSString *title = [postData objectForKey:#"title"];
NSLog(#"%#", title);
}

Cannot access a dictionary created with TouchJSON

I am trying to use TouchJSON and here is what I have done to test it :
NSString *jsonString = #"{\"firtname\": \"Matthieu\",\"lastname\": \"Ravey\",\"age\": 22}";
NSData *jsonData = [jsonString dataUsingEncoding:NSUTF8StringEncoding];
NSError *error = nil;
NSDictionary *dictionary = [[CJSONDeserializer deserializer] deserializeAsDictionary:jsonData error:&error];
NSString *firstname = [dictionary objectForKey:#"firstname"];
NSLog(#"%#", firstname);
But it logs null instead of Matthieu, what am I missing ?
Thanks
In your json string - NSString *jsonString = #"{\"firtname\": \"Matthieu\",\"lastname\": \"Ravey\",\"age\": 22}"; it says firtstring.
Try accessing this dictionary with same keys !
So the change would be -
NSString *firstname = [dictionary objectForKey:#"firtname"];