I'm trying to send a message to a remote queue.
// Send a message to the queue.
if (myQueue.Transactional)
{
var myTransaction = new MessageQueueTransaction();
myTransaction.Begin();
Message objMessage = new Message();
objMessage.UseDeadLetterQueue = true;
objMessage.Body = message;
myQueue.Send(objMessage, myTransaction);
myTransaction.Commit();
}
else
{
Message objMessage = new Message();
objMessage.UseDeadLetterQueue = true;
objMessage.Body = message;
myQueue.Send(message);
}
but I get an exception
The specified format name does not support the requested operation. For example, a direct queue format name cannot be deleted.
I assume that my queue name is incorrect or I have a permission error so I enabled the dead letter queue but it's empty. My queue name is "FormatName:Direct=TCP:xx.xxx.xx.xx\private$\Test"
Thanks
You can't query information about a remote private queue.
Local queues, yes. Remote public queues, yes, but not with Formatname.
Related
When device1 is sending the message to the conference room "del#conference.jabber.org"
the message is dispalyed in the chat list as well as a duplicated message is also displayed that is being send by the conference room "del#conference.jabber.org". I'm stuck, why i'm getting duplicate message.
public void setConnection(XMPPConnection connection) {
this.connection = connection;
if (connection != null) {
PacketFilter filter = new MessageTypeFilter(Message.Type.groupchat);
connection.addPacketListener(new PacketListener() {
#Override
public void processPacket(Packet packet) {
Message message = (Message) packet;
if (message.getBody() != null) {
String fromName = StringUtils.parseBareAddress(message.getFrom());
String[] parts = fromName.split("#");
String from = parts[0].trim();
messages.add(from + ":");
messages.add(message.getBody());
// Add the incoming message to the list view
mHandler.post(new Runnable() {
public void run() {
setListAdapter();
}
});
}
}
}, filter);
}
}
The send message is on button click, which is as follows
Button send = (Button) this.findViewById(R.id.sendBtn);
send.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
Message mg = muc.createMessage();
String text = textMessage.getText().toString();
mg.setBody(text);
Log.i("XMPPChatDemoActivity ", "Sending text ");
if (connection != null) {
connection.sendPacket(mg);
messages.add("Me :");
messages.add(text);
setListAdapter();
}
textMessage.setText("");
}
});
and this is what i have written to connect the conference room
muc = new MultiUserChat(connection, "del#conference.jabber.org");
muc.join("alias name","password");
output what i'm getting when sending message
me: hello
del: hello
what i want i no duplicate message when i send the message i.e
me: hello
When you're in a MUC room you receive copies of all the messages, including your own.
http://xmpp.org/extensions/xep-0045.html#message - "and reflect the message out to the full JID of each occupant."
So for MUCs (not for direct messages) you will get a duplicate if you log both on send and on receive (assuming you have sufficient access to post, etc.). Your options are, largely, either to not log it on send (which is the option most clients go for) or to attempt to do smart message matching to detect when you receive your own message and elide it. The former option ensures that everyone sees a consistent view of message ordering, which some people find very useful.
Maybe your chat server sent your message to you also?
So you add one message manually in onClickListener and then the same message received from server.
I think, it will be right not to add messages from onClickListener - add only those that server sends.
I am developing a chat using quickblox but I am having some problems when I open a new chat. Suddenly I received all the messages that others users sends to me when I was desconnected. The problem is that when I start a chat with user A, I receive the chats from users B, C, D.. in user A chat room.
I have find the way to only show the A users. But the problem is that the server has already sent to me the "disconnected" messages, so when I start a chat to B I do not receive any text because the message that the user B sent to me has been delivered (and ommitted) while I was chating with user A.
How can I do to receive the pending messages (kind of history) or to just retreive the message of the chat I am logged in?
A piece of my code:
// Create Connection.
Connection.DEBUG_ENABLED = true;
config = new ConnectionConfiguration(CHAT_SERVER);
connection = new XMPPConnection(config);
try {
connection.connect();
connection.login(chatLogin, password);
// Create Chat Manager.
chatManager = connection.getChatManager();
// Create Chat.
chat = chatManager.createChat(friendLogin, null);
// // Set listener for outcoming messages.
// chatManager.addChatListener(chatManagerListener);
// Accept only messages from
String from_messages = Integer.toString(receiver_chat_id);
PacketFilter filter = new AndFilter(new PacketTypeFilter(Message.class),
new FromContainsFilter(from_messages+"-3758#chat.quickblox.com"));
// Collect these messages
PacketCollector collector = connection.createPacketCollector(filter);
Packet packet = collector.pollResult();
PacketListener myListener = new PacketListener() {
public void processPacket(Packet packet) {
if (packet instanceof Message) {
Message msg = (Message) packet;
if(msg!=null){
// Process message
System.out.println("Rebem missatge: " +msg.getBody());
}
}
}
};
// Register the listener.
connection.addPacketListener(myListener, filter);
// Set listener for detect Receiver Status
if (connection.isConnected()){
roster = connection.getRoster();
roster.addRosterListener(new RosterListener() {
public void entriesDeleted(Collection<String> addresses) {}
public void entriesUpdated(Collection<String> addresses) {}
public void presenceChanged(Presence presence) {}
public void entriesAdded(Collection<String> arg0) {}
});
}
Make a arraylist and store the receiving offline messages into that array-list. you could add a code in your processPacket(Packet packet) function to add incoming messages to the array-list. or you could use Multimaps(Google Guava) to store all the incoming messages with the key. and when you open the activity that displays the messages from the certain person you could match the name of that person with the key(stored in multimap) and displays the message of that certain person. And the better option is to store all the incomming and outgoing message chat with the certain person so that you could show all the previous chat then you open up the activity.
I am using .net framework to work with ws queues. Is it possible to remove/delete a message from a queue?
Retrieving it will remove it from the queue. You can then discard the retrieved message if you don't want to do anything with it.
// Hit up MSMQ for list of new messages
var queuedMessages = myMessageQueue.GetAllMessages();
// Receive actual message to remove from the message queue
var messages = new List<Message>();
foreach (var queuedMessage in queuedMessages)
{
// Receive the message, which removes it from the queue.
try
{
messages.Add(this.messageQueue.ReceiveById(queuedMessage.Id));
}
// If it's already been removed, we skip over it.
// TODO: Should try to catch only the "removed" exception
catch (Exception)
{
continue;
}
}
return messages;
This is my method to send message to a private Q
using (MessageQueue msgQ = new MessageQueue(MessageQueueName))
{
using (System.Messaging.Message newMessage = new System.Messaging.Message(MessageBody,
new System.Messaging.ActiveXMessageFormatter()))
{
newMessage.Label = MessageLabel;
newMessage.Priority = Priority;
msgQ.Send(newMessage);
}
}
I have an order object which i serialize and send as message body. The serialized object is
<?xml version="1.0"?>
<OrderInfo>
<OrderID>11111</OrderID>
<OrderDetails>
<LineItem>
<ProductDetails>
<Name>qwqwqw</Name>
<Manufacturer>asasas</Manufacturer>
<UPC>12222222222</UPC>
<sku>2132</sku>
<Price>12.21</Price>
</ProductDetails>
<Quantity>1</Quantity>
</LineItem>
</OrderDetails>
</OrderInfo>
This is my method to receive that message in a windows service
void queue_ReceiveCompleted(object sender, ReceiveCompletedEventArgs asyncResult)
{
// Connect to the queue.
MessageQueue mq = (MessageQueue)sender;
// End the asynchronous Receive operation.
Message m = mq.EndReceive(asyncResult.AsyncResult);
m.Formatter = new System.Messaging.ActiveXMessageFormatter()
//Get Filedata from body
OrdrInfo qMessage = (OrdrInfo)XMLUtil.Deserialize(m.Body.ToString(), typeof(OrdrInfo));
}
when I try to look at m.Body in quickwatch this is what it states
m.Body.Message = Cannot find a formatter capable of reading this message.
m.Body.StackTrace = at System.Messaging.Message.get_Body()
Hopefully you're not still stuck on this, but as it came up top of my search when running into the same problem.
As no one had answered it, here is one answer that I've just found else where (thanks TechRepublic). This code assume that "MyType" is a typically basic message that can be read by XML Serialisation - this means it is marked as serializable and all data to be sent/reconstructed is in public get/set properties.
Code is:
MessageQueue msgQ = new MessageQueue(#".\private$\CreateNewEntity");
msgQ.Formatter = new XmlMessageFormatter(new []{typeof(MyType)});
var msg = msgQ.Receive();
msgQ.Close();
return msg.Body as MyType;
Is there a way to resend expired messages in a JBoss 4.2.2 message queue? The issue is they exceeded their retry amounts, but now the problem is fixed, so is there a way to resend them?
In JBoss 3 they were just text files that you could move around. Now that it is stored in a database, how can you do it?
Have a look at Hermes JMS. It's an open source tool for browsing JMS queues and topics. It can replay messages that end up on the broker's undeliverable queue.
This is what I ended up doing:
Hashtable t = new Hashtable();
t.put(Context.PROVIDER_URL, "localhost:1099");
t.put(Context.INITIAL_CONTEXT_FACTORY, "org.jnp.interfaces.NamingContextFactory");
Context ctx = new InitialContext(t);
Queue q = (Queue) ctx.lookup("/queue/DLQ");
//----------------------------
ConnectionFactory cf = (ConnectionFactory) ctx.lookup("/ConnectionFactory");
Connection connection = cf.createConnection();
Session session = connection.createSession(true, 0);
//---------------------------------
MessageConsumer consumer = session.createConsumer(q);
connection.start();
SpyObjectMessage m;
Queue originialDestination = null;
//There can only be one in my case, but really you have to look it up every time.
MessageProducer producer = null;
while ((m = (SpyObjectMessage) consumer.receive(5000)) != null) {
Object o = m.getObject();
Date messageDate = new Date(m.getJMSTimestamp());
String originalQueue = m.getStringProperty("JBOSS_ORIG_DESTINATION");
if (originialDestination == null) {
originialDestination = (Queue) ctx.lookup("/queue/" +
originalQueue.substring(originalQueue.indexOf('.') + 1));
producer = session.createProducer(originialDestination);
}
producer.send(session.createObjectMessage((Serializable) o));
m.acknowledge();
}
//session.commit(); //Uncomment to make this real.
connection.close();
ctx.close();
Note: I work for CodeStreet
Our 'ReplayService for JMS' product is built exactly for this use case: search and retrieve previously published messages (n-times delivery) - JMS is really designed for a 1-time delivery.
With ReplayService for JMS, you would configure a WebLogic recording to record all messages published to your topic or queue. Through a Web-based GUI, you can then search for individual messages (by substring, XPath or JMS Selector) and then replay them again to the original JMS destination.
See http://www.codestreet.com/marketdata/jms/jms_details.php for further details.