How to get the index of an item at a specific offset from the top in Android ListView - android-widget

Question

Is there a simple way for getting the index of a list item which is in a specific offset from the top?
For example, get the index of an item which appears 150 pixels from the top.

Answer 1

Since your goal is to find which list item is in the center of the screen, you could try something like the following:
(Make a custom class that extends ListView, such as MyListView.java)
public class MyListView extends ListView implements OnScrollListener {
public MyListView(Context context, AttributeSet attrs) {
super(context, attrs);
setOnScrollListener(this);
}
#Override
public void onScrollStateChanged(AbsListView view, int scrollState) {
// Center the child currently closest to the center of the ListView when
// the ListView stops scrolling.
if (scrollState == OnScrollListener.SCROLL_STATE_IDLE) {
int listViewCenterX = getWidth() / 2;
int listViewCenterY = getHeight() / 2;
Rect rect = new Rect();
// Iterate the children and find which one is currently the most
// centered.
for (int i = 0; i < getChildCount(); ++i) {
View child = getChildAt(i);
child.getHitRect(rect);
if (rect.contains(listViewCenterX, listViewCenterY)) {
// this listitem is in the "center" of the listview
// do what you want with it.
final int position = getPositionForView(child);
final int offset = listViewCenterY - (child.getHeight() / 2);
break;
}
}
}
}
#Override
public void onScroll(AbsListView view, int firstVisibleItem, int visibleItemCount, int totalItemCount) {
}
}

Answer 2

You can iterate through children and check each ones hit rectangle against the point you have.