mongoose: myModel.find always return subdocument - find

Question

var myschema = new Schema({
name: {type:String, default:'fullname'},
subdoc: {
day1: {type:Array, default:[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]},
day2: {type:Array, default:[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]}
}
});
var mymodel = Mongoose.model('mytest',myschema);
//mongoose 3.5.6: find
mymodel.find({},{'name'}, function(err,docs){
logger.info("---> " + docs);
});
results:
---> { _id: 512da190ba48050f2e000001, **subdoc: {}**, name: 'fullname' }
Only name field is requested to be returned, but this function always returns subdoc: {}. Can someone explain this?
use mongodb shell, it looks fine
db.mytests.find({},{"name":1})
{ "_id" : ObjectId("512da190ba48050f2e000001"), "name" : "fullname" }
Then I change the model to:
var myschema = new Schema({
name: {type:String, default:'fullname'},
subdoc: [
day1: {type:Array, default:[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]},
day2: {type:Array, default:[0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]}
] // **note: not {} here**
})
use the same mongoose api find, the result is just what I expected:
--->{ _id: 512da46fffebd24b30000002, name: 'fullname' }
My questions is: Why field 'subdoc' is returned with the former schema?

Answer 1

According to the docs, it appears as if you are a little bit off.
Example:
// name LIKE john and only selecting the "name" and "friends" fields, executing immediately
MyModel.find({ name: /john/i }, 'name friends', function (err, docs) { })
With that, I would do something like this:
myModel.find( {}, 'name', callback);
Edit
To address your comments: In mongodb console, the proper way to format it would be {'name':1, 'friend':1}. Using:
db.collection.find({}, {'name friend'})
will throw an error. To do this properly, you would do:
db.collection.find({}, {'name':1, 'friend':1})
However, if you prefer this way of field selection, mongoose does allow you to do that as well.
myModel.find({}, {'name':1, 'friend': 1}, callback);
See: API Docs