I am new to Matlab. I am trying to use datenum function to parse date string and convert to timestamps(like in Java, getTime()).Then, I want to find out the difference between two dates in seconds.
datenum('2013-02-21T00:39:19Z','yyyy-mm-ddTHH:MM:ss')-datenum('2013-02-21T00:34:19Z','yyyy-mm-ddTHH:MM:ss')
If I run the function above, I get 0.0035 which I have no idea what kind of value it is.
Can someone help please?
Thanks!
Matlab help says:
A serial date number represents the whole and fractional number of
days from a fixed, preset date (January 0, 0000).
I reckon your answer is maybe 0.0035 days so to get seconds I guess its
ans*24*60*60
Your result is in datenum format as Dan says. But if you want to find elapsed time in seconds, there is a function that does exactly what you want.
You can use etime to find elapsed time between two date vectors.
d1 = datevec('2013-02-21T00:39:19Z','yyyy-mm-ddTHH:MM:ss');
d2 = datevec('2013-02-21T00:34:19Z','yyyy-mm-ddTHH:MM:ss');
elapsedTime = etime(d1,d2) % Elapsed time in seconds
elapsedTime =
300
Related
I have the following values in Excel:
Bed time 19:34:00
Get up time 07:04:00
Time in bed 11:30:00
Sleep start 19:42:00
Sleep end 07:00:00
I want to import them into MATLAB and do some calculation on these time values such as subtraction. The time values look like this after importing:
0.8153
0.2944
0.4792
0.8208
0.2917
and obviously doing calculation on them would be nonsense. Would any body help me with this issue? I have stuck with it for few days, and no progress yet.
Thanks in advance,
As assylias pointed out, these are fractions of days. You can use the datestr function to convert it to human-readable strings with formatting option conveniently.
e.g.:
datestr(0.2917, 'HH:MM:SS')
ans =
07:00:02
Calculations such as subtractions can be done on the raw values before
conversion.
E.g: get duration of sleep.
start = 0.8208
stop = 0.2917
datestr(stop-start, 'HH:MM')
ans =
11:18
Even works for intervals that span over midnight.
I am trying to read time-coordinate data from a netCDF file using matlab. I have a netCDF file (which I created) that has a time variable in the format of a double corresponding to the number of hours from a specific time (see below).
Variable attributes:
double time(Time) ;
time:standard_name = "Time" ;
time:units = "hours since 2002-01-01 0:0:0" ;
time:calendar = "proleptic_gregorian" ;
When I read the time variable using ncread) into matlab, it just prints out an integer e.g.,1. However, if I use "ncdump" to explore the file, I see the time variable in it's coordinate time e.g., 2002-01-01 01.
Specifically: "ncdump -t -v time ncfile.nc"
I'm relatively new to matlab, and I was wondering if anyone knew if there was a similar, or an equally simple, way to read this time variable as its coordinate time into matlab, either as a string, or numerical date. Specifically, I would like to avoid having to parse the attribute string and code up a bunch of pointers and conditions to convert the integer data to an actual date.
Alternatively, should I just create a new time variable in these files that is just an array of dates as strings?
Any information is very much appreciated!
Thanks!
NetCDF stores time as an offset from an epoch. From your variable attribute, your epoch is 2002-01-01 0:0:0, and the time is hours since then. Matlab has a similar methodology called date numbers, although it is based off of days since an epoch (which they call pivot years). There are two functions that you should look into: datenum and datestr. The first converts a string into a date number and the other converts a date number into a date string.
You can convert your time variable into a compatible Matlab date number by dividing by 24 and then use the datestr function to format it however you like. Here is a simple example:
>> time = [1;2;3;4];
>> datestr(time./24+datenum('2002-01-01 0:0:0'))
ans =
01-Jan-2002 01:00:00
01-Jan-2002 02:00:00
01-Jan-2002 03:00:00
01-Jan-2002 04:00:00
Look at the Matlab help files associated with the two functions and you can format the date output however you like.
i got a question :
How can i convert an elapsed time like 835:0:44
to numeric for summing and average ?
i tried things like instr and then tonumber and then avergae the outcome.
but i miss the minutes and seconds then.
I am writing a for loop to average 10 years of hourly measurements made on the hour. The dates of the measurements are recorded as MATLAB datenums.
I am trying to iterate through using 0.0417 as it is the datenum for 1AM 00/00/00 but it is adding in a couple of seconds of error each time I iterate.
Can anyone recommend a better way for me to iterate by hour?
date = a(:,1);
load = a(:,7);
%loop for each hour of the year
for i=0:0.0417:366
%set condition
%condition removes year from current date
c = date(:)-datenum(year(date(:)),0,0)==i;
%evaluate condition on load vector and find mean
X(i,2)=mean(load(c==1));
end
An hour has a duration of 1/24 day, not 0.0417. Use 1/24 and the precision is sufficient high for a year.
For an even higher precision, use something like datenum(y,1,1,1:24*365,0,0) to generate all timestamps.
To avoid error drift entirely, specify the index using integers, and divide the result down inside the loop:
for hour_index=1:365*24
hour_datenum = (hour_index - 1) / 24;
end
How can I convert this kind of data 08:00:43.771 given as string into a number specifying the number of milliseconds since midnight corresponding to this time instance?
I generally use the Matlab datenum outputs for timestamping in Matlab. Datenums are the number of days since 0/0/0000, expressed as a double (double precision numbers are precise to about 14 usec for contemporary dates).
Using datenums.
currentDateTime1 = datenum('08:00:43.771'); %Assumes today
currentDateTime2 = datenum('6/8/1975 08:00:43.771'); %Using an explicit date
millisecondsSinceMidnight = mod(currentDateTime1 ,1) *24*60*60*1000; %Mod 1 removes any day component
millisecondsSinceMidnight = mod(currentDateTime2 ,1) *24*60*60*1000; %Then this is just a unit conversion
For unusual string formats, use the extended form of datenum, which can accept a string format specifier.
Use 1000*etime(datevec('08:00:43.771'),datevec('0:00')) to give the number of milliseconds since midnight. etime gives the number of seconds between two date vectors, datevec converts strings to date vectors (assuming Jan 1 this year if only a time is given).