I'm trying to replace :
#/*!40101 SET #OLD_SQL_MODE=##SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO' */;
With :
SET #OLD_SQL_MODE=##SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO';
Here is my sed command which doesn't work...
sed 's|#/\*\!40101 SET #OLD_SQL_MODE=##SQL_MODE\, SQL_MODE=`NO_AUTO_VALUE_ON_ZERO` \*/;|SET #OLD_SQL_MODE=##SQL_MODE\, SQL_MODE='NO_AUTO_VALUE_ON_ZERO'\;|' file.sql > filenew.sql
I guess my problem is the caracter ' but i can't find the solution
Can you help me !
Thank you !
To bypass the problem of using single quotes inside the sed command, surround it between double quotes:
sed "s|#/\*\!40101 SET #OLD_SQL_MODE=##SQL_MODE\, SQL_MODE='NO_AUTO_VALUE_ON_ZERO' \*/;|SET #OLD_SQL_MODE=##SQL_MODE\, SQL_MODE='NO_AUTO_VALUE_ON_ZERO'\;|" file.sql > filenew.sql
It yields:
SET #OLD_SQL_MODE=##SQL_MODE, SQL_MODE='NO_AUTO_VALUE_ON_ZERO';
Related
I am trying to do a find and replace using sed. I am trying to find that : purge: [], to replace by purge: ["./src/**/*.{js,jsx,ts,tsx}", "./public/index.html"], but it does not work, here is my commande :
sed -i -e 's/purge: [],/purge: ["./src/**/*.{js,jsx,ts,tsx}", "./public/index.html"],/g' myfile.txt
Could you help me please ?
Thank you very much !
You need to:
Change delimiters to a char other than a /, like ~ or !, or escape / delimiter chars inside the pattern (I'd suggest the former)
Escape the [ char in the pattern.
You can use
sed -i 's!purge: \[],!purge: ["./src/**/*.{js,jsx,ts,tsx}", "./public/index.html"],!g' myfile.txt
See the online demo:
#!/bin/bash
s='Blah..purge: [], blah...'
sed 's!purge: \[],!purge: ["./src/**/*.{js,jsx,ts,tsx}", "./public/index.html"],!g'<<< "$s"
# => Blah..purge: ["./src/**/*.{js,jsx,ts,tsx}", "./public/index.html"], blah...
I have the following header :
#SRR1561197.1/1
#SRR1561197.2/1
#SRR1561197.3/1
#SRR1561197.4/1
I want to Add few letters after # and before SRR like this:
#MexD1SRR1561197.1/1
#MexD1SRR1561197.2/1
#MexD1SRR1561197.3/1
#MexD1SRR1561197.4/1
I tried:
sed 's/#/#MexD1/File,fastq > change.fastq
This results in empty file..
Use sed with the in file replacement option. The g at the end makes it global.
sed -i 's/#/#MexD1/g' file
To fix your code.
sed 's/#/#MexD1/g' File.fastq > change.fastq
You have to escape it: sed s/\#/\#MexD1/g source-file-name > change.fastq
i want to replace lines which contains a string that has some special characters.
i used \ and \ for escape special characters but nothing changes in file.
i use sed like this:
> sed -i '/pnconfig\[\'dbhost\'\] = \'localhost\'/c\This line is removed.' tco.php
i just want to find lines that contains :
$pnconfig['dbhost'] = 'localhost';
and replace that line with:
$pnconfig['dbhost'] = '1.1.1.1';
Wrap the sed in double quotes as
sed -i "s/\(pnconfig\['dbhost'\] = \)'localhost'/\1'1.1.1.1'/" filename
Test
$ echo "\$pnconfig['dbhost'] = 'localhost';" | sed "s/\(pnconfig\['dbhost'\] = \)'localhost'/\1'1.1.1.1'/"
$pnconfig['dbhost'] = '1.1.1.1';
Use as below:
sed -i.bak '/pnconfig\[\'dbhost\'\] = \'localhost\'/pnconfig\[\'dbhost\'\] = \'1.1.1.1\'/' tco.php
Rather than modifying the file for the first time, create back up and then search for your pattern and then replace it with the other as above in your file tco.php
You don't have to worry about backslashing single quotes by using double quotes for sed.
sed -i.bak "/pnconfig\['dbhost'\] = 'localhost'/s/localhost/1.1.1.1/g" File
Try this one.
sed "/$pnconfig\['dbhost']/s/localhost/1.1.1.1/"
I need to replace if ($_SESSION['POST']['*']==1){ with if (isset($_SESSION['POST']['*']) && $_SESSION['POST']['*']==1){
(I'm using * as a wild card)
I've tried sed -i "s/if ($_SESSION['POST']['.*']/if (isset($_SESSION['POST']['.*']) && $_SESSION['POST']['.*']/g" *.php and a few other variations without success.
Here goes...
sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
Using double quotes means that the $ symbols must be escaped, otherwise they will be interpreted as shell variables. The square brackets need to be escaped, otherwise they will be interpreted as the beginning of a range. It's OK to leave the closing square brackets as they are.
In order to capture the key, I have used a character class [^']*. This means zero or more characters that are not a single quote.
In the replacement, the captured groups (the parts between parentheses in the match) are referred to using \1, \2, etc.
Testing it out:
$ cat file
if ($_SESSION['POST']['foo']==1){
// do something
}
if ($_SESSION['POST']['bar']==1){
// do something else
}
$ sed "s/\(if (\)\(\$_SESSION\['POST']\['\([^']*\)']\)==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
if (isset($_SESSION['POST']['foo']) && $_SESSION['POST']['foo']==1){
// do something
}
if (isset($_SESSION['POST']['bar']) && $_SESSION['POST']['bar']==1){
// do something else
}
By the way it makes the command a few characters shorter if you use extended regexp mode (-r or -E). In extended mode, the parentheses enclosing capture groups don't have to be escaped but literal ones do, so your command would then be:
sed -r "s/(if \()(\$_SESSION\['POST']\['([^']*)'])==1/\1isset(\2) \&\& \$_SESSION['POST']['\3']==1/" file
This sed should work:
s="if (\$_SESSION['POST']['name']==1){"
sed -r 's/(if +)\((([^=]+)[^\)]+)/\1(isset(\3) \&\& \2/' <<< "$s"
if (isset($_SESSION['POST']['name']) && $_SESSION['POST']['name']==1){
PS: Use sed -E instead of sed -r on OSX.
Here's another.
This is what we need to produce:
Pattern: if (\$_SESSION\['POST'\]\['\([^']*\)'\]
Replacement: if (isset($_SESSION['POST']['\1']) \&\& $_SESSION['POST']['\1']
When quoted in shell level:
Pattern: "if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]"
Replacement: "if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']"
Putting it together:
sed -i "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" file
Test:
# sed "s|if (\\\$_SESSION\['POST'\]\['\([^']*\)'\]|if (isset(\$_SESSION['POST']['\1']) \\&\\& \$_SESSION['POST']['\1']|g" <<'EOF'
> if ($_SESSION['POST']['ABC']==1){
> EOF
if (isset($_SESSION['POST']['ABC']) && $_SESSION['POST']['ABC']==1){
I'm using OS X, want to replace
[self.lang getAppLanguageString:#"foo bar"]
to
LocalizedString(#"foo bar", nil)
I use sed like the below:
sed -i '' s/[self\.lang getAppLanguageString:#"([a-zA-Z]+)"]/LocalizedString(#"\1", nil)/g somefile
but not work, how can I do that?
You've already escaped . in the pattern, but also need to escape [ and ].
Try:
sed -i 's/\[self\.lang getAppLanguageString:#\("[^"]*"\)\]/LocalizedString(#\1, nil)/' somefile