powershell get-childitem to csv with details - powershell

Question

I am trying to create a CSV file for a file share that has deep folder structure.
I want the CSV to look like:
filename, filepath, file type, folderStructure
So far I have the following:
#Get-ChildItem -Path D:\ -Recurse
$directory="d:\"
gci $directory -recurse |
where {$_.psiscontainer} |
foreach {
get-childitem $_.fullname |
sort creationtime |
select -expand fullname -last 1
}

Answer 1

You don't need to recurse a recursive in Powershell. It will automatically go through all of the subdirectories of subdirectories.
I am also a little unsure of some of the information you wanted, but here is a script that does what you want mostly I believe and is IMO a little better to read.
Get-ChildItem -Path X:\Test -Recurse |`
foreach{
$Item = $_
$Type = $_.Extension
$Path = $_.FullName
$Folder = $_.PSIsContainer
$Age = $_.CreationTime
$Path | Select-Object `
#{n="Name";e={$Item}},`
#{n="Created";e={$Age}},`
#{n="filePath";e={$Path}},`
#{n="Extension";e={if($Folder){"Folder"}else{$Type}}}`
}| Export-Csv X:\Test\Results.csv -NoTypeInformation
You will need to change your path, as I created this for a test. My results look like this in Excel:
+-------------------------------+----------------+-------------------------------------+-----------+
| Name | Created | filePath | Extension |
+-------------------------------+----------------+-------------------------------------+-----------+
| test2 | 3/6/2013 19:21 | X:\Test\test2 | Folder |
| Results.csv | 3/6/2013 19:51 | X:\Test\Results.csv | .csv |
| test3 | 3/6/2013 19:21 | X:\Test\test2\test3 | Folder |
| New Text Document.txt | 3/6/2013 19:21 | X:\Test\test2\New Text Document.txt | .txt |
+-------------------------------+----------------+-------------------------------------+-----------+
Where it says "Folder" for the Extension just it returning that it is a directory instead of a blank (No extension).

Answer 2

OK, I changed the way it checks for the parent. It is no longer looking directly at the Parent attribute, and it should correct it now.
Get-ChildItem -Path D:\ -Recurse |`
foreach{
$Item = $_
$Type = $_.Extension
$Path = $_.FullName
$ParentS = ($_.Fullname).split("\")
$Parent = $ParentS[#($ParentS.Length - 2)]
$Folder = $_.PSIsContainer
$Age = $_.CreationTime
$Path | Select-Object `
#{n="Name";e={$Item}},`
#{n="Created";e={$Age}},`
#{n="Folder Name";e={if($Parent){$Parent}else{$Parent}}},`
#{n="filePath";e={$Path}},`
#{n="Extension";e={if($Folder){"Folder"}else{$Type}}}`
}| Export-Csv X:\Test\ResultsC.csv -NoTypeInformation
It is now taking the path to the current item, turning it into an array by splitting on the \, and then giving you the value at ArryLength - 2

Answer 3

I am not sure if this is the best approach but it works. I have a feeling code could be shorten to get the full path of a file.
$myDirectory = "D:\"
Get-ChildItem -Path $myDirectory -Recurse |`
foreach{
$Item = $_
$Type = $_.Extension
$Path = $_.FullName
$ParentS = ($_.Fullname).split("\")
$Parent = $ParentS[#($ParentS.Length - 2)]
$ParentPath = $_.PSParentPath
$ParentPathSplit = ($_.PSParentPath).split("::")
$ParentPathFinal = $ParentPathSplit[#($ParentPathSplit.Length -1)]
#$ParentPath = [io.path]::GetDirectoryName($myDirectory)
$Folder = $_.PSIsContainer
$Age = $_.CreationTime
$Path | Select-Object `
#{n="Name";e={$Item}},`
#{n="Created";e={$Age}},`
#{n="Folder Name";e={if($Parent){$Parent}else{$Parent}}},`
#{n="filePath";e={$Path}},`
#{n="Extension";e={if($Folder){"Folder"}else{$Type}}},`
#{n="Folder Name 2";e={if($Parent){$Parent}else{$Parent}}},`
##{n="Folder Path";e={$ParentPath}},`
#{n="Folder Path 2";e={$ParentPathFinal}}`
}| Export-Csv d:\ResultsC_2_F.csv -NoTypeInformation