How to write a correct name using combination of variable and string as a filehandler? - perl

Question

I want to make a tool to classify each line in input file to several files
but it seems have some problem in naming a filehandler so I can't go ahead , how do I solve?
here is my program
ARGV[0] is the input file
ARGV[1] is the number of classes
#!/usr/bin/perl
use POSIX;
use warnings;
# open input file
open(Raw,"<","./$ARGV[0]") or die "Can't open $ARGV[0] \n";
# create a directory class to store class files
system("mkdir","Class");
# create files for store class informations
for($i=1;$i<=$ARGV[1];$i++)
{
# it seems something wrong in here
open("Class$i",">","./Class/$i.class") or die "Can't create $i.class \n";
}
# read each line and random decide which class to store
while( eof(Raw) != 1)
{
$Line = readline(*Raw);
$Random_num = ceil(rand $ARGV[1]);
for($k=1;$k<=$ARGV[1];$k++)
{
if($Random_num == $k)
{
# Store to the file
print "Class$k" $Line;
last;
}
}
}
for($h=1;$h<=$ARGV[1];$h++)
{
close "Class$h";
}
close Raw;
thanks
Later I use the advice provided by Bill Ruppert
I put the name of filehandler into array , but it seems appear a syntax bug , but I can't correct it
I label the syntax bug with ######## A syntax error but it looks quite OK ########
here is my code
#!/usr/bin/perl
use POSIX;
use warnings;
use Data::Dumper;
# open input file
open(Raw,"<","./$ARGV[0]") or die "Can't open $ARGV[0] \n";
# create a directory class to store class files
system("mkdir","Class");
# put the name of hilehandler into array
for($i=0;$i<$ARGV[1];$i++)
{
push(#Name,("Class".$i));
}
# create files of classes
for($i=0;$i<=$#Name;$i++)
{
$I = ($i+1);
open($Name[$i],">","./Class/$I.class") or die "Can't create $I.class \n";
}
# read each line and random decide which class to store
while( eof(Raw) != 1)
{
$Line = readline(*Raw);
$Random_num = ceil(rand $ARGV[1]);
for($k=0;$k<=$#Name;$k++)
{
if($Random_num == ($k+1))
{
print $Name[$k] $Line; ######## A syntax error but it looks quite OK ########
last;
}
}
}
for($h=0;$h<=$#Name;$h++)
{
close $Name[$h];
}
close Raw;
thanks

Answer 1

To quote the Perl documentation on the print function:
If you're storing handles in an array or hash, or in general whenever you're using any expression more complex than a bareword handle or a plain, unsubscripted scalar variable to retrieve it, you will have to use a block returning the filehandle value instead, in which case the LIST may not be omitted:
print { $files[$i] } "stuff\n";
print { $OK ? STDOUT : STDERR } "stuff\n";
Thus, print $Name[$k] $Line; needs to be changed to print { $Name[$k] } $Line;.

Answer 2

How about this one:
#! /usr/bin/perl -w
use strict;
use POSIX;
my $input_file = shift;
my $file_count = shift;
my %hash;
open(INPUT, "<$input_file") || die "Can't open file $input_file";
while(my $line = <INPUT>) {
my $num = ceil(rand($file_count));
$hash{$num} .= $line
}
foreach my $i (1..$file_count) {
open(OUTPUT, ">$i.txt") || die "Can't open file $i.txt";
print OUTPUT $hash{$i};
close OUTPUT;
}
close INPUT;