I have a Calendar program, that reside on the server, this program stores the dates into the database in the format :
YYYYMMDD
is there a "easy" way to manage these dates in asp? for example, let's assume we have the April 20th 2013 as a date:
20130420
we want to add 20 days to this date, so we want to produce:
20130510
any idea? is there a integerTOdate conversion in asp? or something i could use to add "days" to the number 20130420 ?
Something like this (untested):
Dim strDate, theDate, theDatePlusTwentyDays
Dim Year, Month, Day
' The date is stored as a string...
strDate = "20130420"
' Extract the components of the date
Year = Mid(strDate, 1, 4)
Month = Mid(strDate, 5, 2)
Day = Mid(strDate, 7, 2)
' Convert the components of the date into a datetime object
theDate = DateSerial(Year, Month, Day)
' Add 20 days using DateAdd
theDatePlusTwentyDays = DateAdd("d", 20, theDate)
Yes, you can use the DateAdd function
Response.Write(DateAdd("d",1,Now()))
You need to format your date first though into something like
<%
dim _dateOnServer
dim _formattedDate
dim _day
dim _month
dim _year
_dateOnServer = 20130420
_year = Left(_dateOnServer,4)
_month = Mid(_dateOnServer,5,2)
_day = Right(_dateOnServer,2)
_formattedDate = _month &"-"& _day &"-"& _year
dim _newDate
_newDate = DateAdd("d",20, _formattedDate )
_day = Left(_newDate,2)
_month = Mid(_newDate,4,2)
_year = Right(_newDate,4)
dim _newDateFormat
_newDateFormat = _year & _month & _day
%>
A solution that enables full control over order and format...
strDay = Day(Date)
strMonth = Month(Date)
strYear = Year(Date)
strHours = Hour(Now)
strMins = Minute(Now)
strSecs = Second(Now())
if len(strMonth) = 1 then
strMonth = "0" & strMonth
end if
if len(strDay) = 1 then
strDay = "0" & strDay
end if
if len(strHours) = 1 then
strHours = "0" & strHours
end if
if len(strMins) = 1 then
strMins = "0" & strMins
end if
if len(strSecs) = 1 then
strSecs = "0" & strSecs
end if
strDateAdded = strYear & "-" & strMonth & "-" & strDay
strDateAddedTime = strDateAdded & " " & strHours & ":" & strMins
Using this method you have complete control over the order and even when running your web app in different time zones, you still maintain DD/MM format... or whatever order you want such as MM-DD-YY (by reordering and trimming the year). Personally I prefer YYYY-MM-DD because sorting by ASC and DESC is a lot easier to work with, ie: easier to read because all rows will have the same number of characters like:
2013-04-01 03:15
2013-04-09 10:15
2013-04-22 07:15
2013-04-23 10:15
2013-04-23 10:60
2013-10-25 12:01
2013-10-25 12:59
Instead of:
2013-4-1 3:15
2013-4-9 10:15
2013-4-22 7:15
2013-4-23 10:15
2013-4-23 10:60
2013-10-25 12:1
2013-1-25 12:59
Related
In Access, I would like to convert a date column in format yywwd to dd-mm-yy. (weekday nr. 1 is monday, and years can only from 2000 and later, so e.g. today (monday 15-06-2020) would be 20251 what I would like to be converted to 15-06-2020.
I'm not much of a coder so honestly asside from messing with Datepart I have not tried a whole lot. Does anyone have suggestion?
It seems that the function 'GetDayFromWeekNumber' mentioned here vba convert week number (and year) to date? could work but how is this used in MSAccess?
Thanks a lot in advance!
I have a function that works in Excel to convert YYWWD to a date, this should be very similar if not identical to the code needed in Access. It is quite verbose so you could probably make it simpler, but at least the calculation steps are clearly set out.
The function assumes the ISO definition of week number - i.e. the first week of the year is the week in which the 4th of Jan falls. The first day of a week is Monday, the last day of a week is Sunday.
Function dateFromYYWWD(yywwd)
Dim sYYWWD As String
Dim sYYYY As String
Dim ww As Integer
Dim d As Integer
Dim fourthOfJan As Date
Dim fourthOfJanWeekday As Integer
Dim week1StartDate As Date
Dim targetWeekStartDate As Date
Dim targetDate As Date
' Convert to string if not already
sYYWWD = "" & yywwd
' Get the year in full
sYYYY = "20" + Left(sYYWWD, 2)
' Get the week number and day in the week
ww = CInt(Mid(sYYWWD, 3, 2))
d = CInt(Right(sYYWWD, 1))
' Calculate the date of 4th Jan in the same year
fourthOfJan = CDate(sYYYY & "-01-04")
' Get the day of week of the 4th Jan
' NOTE - CALCULATES MONDAY AS DAY 1 OF THE WEEK, SUNDAY AS DAY 7
fourthOfJanWeekday = Weekday(fourthOfJan, vbMonday)
' Date of the first day of week #1 in the target year
week1StartDate = fourthOfJan - fourthOfJanWeekday + 1
' First day of the target week
targetWeekStartDate = week1StartDate + (ww - 1) * 7
' Target date
targetDate = targetWeekStartDate + d - 1
dateFromYYWWD = targetDate
End Function
It's as simple as this:
Public Function ConvertFromYYWWD(s) As Date
Dim t&
t = DateSerial(2000 + Mid(s, 1, 2), 1, 1) + 7 * (Mid(s, 3, 2) - 1)
ConvertFromYYWWD = t - Weekday(t, vbMonday) + Mid(s, 5, 1)
End Function
Just place the above function in a code module in the database project.
You mentioned in the comments under your question that the week number is always two digits. I am assuming the the year number is likewise always two digits.
The first task is to split the value:
YWDDate = 20251
Year = YWDDate \ 1000 + 2000
2020
Week = (YWDDate Mod 1000) \ 10
25
Weekday = YWDDate Mod 10
1
Then, as this probably is ISO 8601 week numbering, the year is not the calendar year but the ISO 8601 year, which native VBA knows nothing about, thus a custom function is needed:
' First day of the week.
WeekStart = DateYearWeek(25, 2020, vbMonday)
' Requested day of week (which here is the same)
WeekDate = DateAdd("d", 1 - 1, WeekStart)
The function is not that convoluted:
' Returns the date of Monday for the ISO 8601 week of IsoYear and Week.
' Optionally, returns the date of any other weekday of that week.
'
' 2017-05-03. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function DateYearWeek( _
ByVal IsoWeek As Integer, _
Optional ByVal IsoYear As Integer, _
Optional ByVal DayOfWeek As VbDayOfWeek = VbDayOfWeek.vbMonday) _
As Date
Dim WeekDate As Date
Dim ResultDate As Date
If IsoYear = 0 Then
IsoYear = Year(Date)
End If
' Validate parameters.
If Not IsWeekday(DayOfWeek) Then
' Don't accept invalid values for DayOfWeek.
Err.Raise DtError.dtInvalidProcedureCallOrArgument
Exit Function
End If
If Not IsWeek(IsoWeek, IsoYear) Then
' A valid week number must be passed.
Err.Raise DtError.dtInvalidProcedureCallOrArgument
Exit Function
End If
WeekDate = DateAdd(IntervalSetting(dtWeek), IsoWeek - 1, DateFirstWeekYear(IsoYear))
ResultDate = DateThisWeekPrimo(WeekDate, DayOfWeek)
DateYearWeek = ResultDate
End Function
but - as you can see - it calls some helper functions, which again call other functions, which will be too much to post here.
I can upload it somewhere, if you feel this will provide a solution for you.
i have problem finding solution on getting previous date from current's date. but i only want the months to change. for example, now is August, i want the output to display 3 months ago = May.
Heres my code that i wrote
givenDate= "14-August-15"
DD = Day (givenDate)
'MsgBox DD
MM = Month (givenDate)
'MsgBox MM
YY = Year (givenDate)
'MsgBox YY
SysDate = DD&"/"&MM&"/"&YY
MsgBox Month(DateAdd("m", -3, "14-August-2015"))
'MsgBox(FormatDateTime(SysDate,1))
If you just need to display the name of the month that was 3 months ago, combine DateAdd(), Month(), and MonthName(). For example:
Dim dt1, dt2
dt1 = Date() ' Use today's date, for example
dt2 = DateAdd("m", -3, dt1) ' Subtract 3 months
WScript.Echo MonthName(Month(dt2)) ' Display the name of the month
Month() returns the month number (1 - 12). MonthName() takes that number and returns the name of the month ("January" - "December").
I have a Microsoft Access database where the user is required to enter a Date Opened: value. Once entered, this triggers a calculation in another field, Deadline (25 WD):. This works via the following function in the latter field:
=DateAdd("d",25,[Date opened])
What I want to do, however, is to count 25 working days from the date entered in Date Opened:. I have a table holidays which contains a list of UK holidays up until 2020.
How can I merge to two, so-to-speak, in order to produce a valid Deadline (25 WD): value which does not count any of the dates listed in holidays?
For example, if the date entered is 01/01/2015, then the function would count 25 working days from 01/01/2015, meaning that it would exclude all weekends and any bank holidays that fall within that period and the resulting date value in the field Deadline (25 WD) will also be a working day (i.e. not a weekend or bank holiday).
You might need a UDF to get you through this. Something like,
Function addWorkDays(addNumber As Long, Date2 As Date) As Date
'********************
'Code Courtesy of
' Paul Eugin
'********************
Dim finalDate As Date
Dim i As Long, tmpDate As Date
tmpDate = Date2
i = 1
Do While i <= addNumber
If Weekday(tmpDate) <> 1 And Weekday(tmpDate) <> 7 And _
DCount("*", "tbl_BankHolidays", "bankDate = " & Format(tmpDate, "\#mm\/dd\/yyyy\#")) = 0 Then i = i + 1
tmpDate = DateAdd("d", 1, tmpDate)
Loop
Do While Weekday(tmpDate) = 1 Or Weekday(tmpDate) = 7 Or _
DCount("*", "tbl_BankHolidays", "bankDate = " & Format(tmpDate, "\#mm\/dd\/yyyy\#")) <> 0
tmpDate = DateAdd("d", 1, tmpDate)
Loop
addWorkDays = tmpDate
End Function
So, when you add 25 days to a date, it will skip all weekends and bank holidays stored in your table - tbl_BankHolidays.
? addWorkDays(25, Date())
25/06/2015
Hope this helps !
EDIT: I have added another loop to see if the end date falls on a bank holiday or weekend, if it does it will add one more day until it reaches a weekday.
You can use this function:
Public Function DateAddWorkdays( _
ByVal lngNumber As Long, _
ByVal datDate As Date, _
Optional ByVal booWorkOnHolidays As Boolean) _
As Date
' Adds lngNumber of workdays to datDate.
' 2014-10-03. Cactus Data ApS, CPH
' Calendar days per week.
Const clngWeekdayCount As Long = 7
' Workdays per week.
Const clngWeekWorkdays As Long = 5
' Average count of holidays per week maximum.
Const clngWeekHolidays As Long = 1
' Maximum valid date value.
Const cdatDateRangeMax As Date = #12/31/9999#
' Minimum valid date value.
Const cdatDateRangeMin As Date = #1/1/100#
Dim aHolidays() As Date
Dim lngDays As Long
Dim lngDiff As Long
Dim lngDiffMax As Long
Dim lngSign As Long
Dim datDate1 As Date
Dim datDate2 As Date
Dim datLimit As Date
Dim lngHoliday As Long
lngSign = Sgn(lngNumber)
datDate2 = datDate
If lngSign <> 0 Then
If booWorkOnHolidays = True Then
' Holidays are workdays.
Else
' Retrieve array with holidays between datDate and datDate + lngDiffMax.
' Calculate the maximum calendar days per workweek.
lngDiffMax = lngNumber * clngWeekdayCount / (clngWeekWorkdays - clngWeekHolidays)
' Add one week to cover cases where a week contains multiple holidays.
lngDiffMax = lngDiffMax + Sgn(lngDiffMax) * clngWeekdayCount
datDate1 = DateAdd("d", lngDiffMax, datDate)
aHolidays = GetHolidays(datDate, datDate1)
End If
Do Until lngDays = lngNumber
If lngSign = 1 Then
datLimit = cdatDateRangeMax
Else
datLimit = cdatDateRangeMin
End If
If DateDiff("d", DateAdd("d", lngDiff, datDate), datLimit) = 0 Then
' Limit of date range has been reached.
Exit Do
End If
lngDiff = lngDiff + lngSign
datDate2 = DateAdd("d", lngDiff, datDate)
Select Case Weekday(datDate2)
Case vbSaturday, vbSunday
' Skip weekend.
Case Else
' Check for holidays to skip.
' Ignore error when using LBound and UBound on an unassigned array.
On Error Resume Next
For lngHoliday = LBound(aHolidays) To UBound(aHolidays)
If Err.Number > 0 Then
' No holidays between datDate and datDate1.
ElseIf DateDiff("d", datDate2, aHolidays(lngHoliday)) = 0 Then
' This datDate2 hits a holiday.
' Subtract one day before adding one after the loop.
lngDays = lngDays - lngSign
Exit For
End If
Next
On Error GoTo 0
lngDays = lngDays + lngSign
End Select
Loop
End If
DateAddWorkdays = datDate2
End Function
Public Function GetHolidays( _
ByVal datDate1 As Date, _
ByVal datDate2 As Date, _
Optional ByVal booDesc As Boolean) _
As Date()
' Finds the count of holidays between datDate1 and datDate2.
' The holidays are returned as an array of dates.
' DAO objects are declared static to speed up repeated calls with identical date parameters.
' 2014-10-03. Cactus Data ApS, CPH
' The table that holds the holidays.
Const cstrTable As String = "tblHoliday"
' The field of the table that holds the dates of the holidays.
Const cstrField As String = "HolidayDate"
' Constants for the arrays.
Const clngDimRecordCount As Long = 2
Const clngDimFieldOne As Long = 0
Static dbs As DAO.Database
Static rst As DAO.Recordset
Static datDate1Last As Date
Static datDate2Last As Date
Dim adatDays() As Date
Dim avarDays As Variant
Dim strSQL As String
Dim strDate1 As String
Dim strDate2 As String
Dim strOrder As String
Dim lngDays As Long
If DateDiff("d", datDate1, datDate1Last) <> 0 Or DateDiff("d", datDate2, datDate2Last) <> 0 Then
' datDate1 or datDate2 has changed since the last call.
strDate1 = Format(datDate1, "\#yyyy\/mm\/dd\#")
strDate2 = Format(datDate2, "\#yyyy\/mm\/dd\#")
strOrder = Format(booDesc, "\A\s\c;\D\e\s\c")
strSQL = "Select " & cstrField & " From " & cstrTable & " " & _
"Where " & cstrField & " Between " & strDate1 & " And " & strDate2 & " " & _
"Order By 1 " & strOrder
Set dbs = CurrentDb
Set rst = dbs.OpenRecordset(strSQL, dbOpenSnapshot)
' Save the current set of date parameters.
datDate1Last = datDate1
datDate2Last = datDate2
End If
lngDays = rst.RecordCount
If lngDays = 0 Then
' Leave adatDays() as an unassigned array.
Else
ReDim adatDays(lngDays - 1)
' As repeated calls may happen, do a movefirst.
rst.MoveFirst
avarDays = rst.GetRows(lngDays)
' rst is now positioned at the last record.
For lngDays = LBound(avarDays, clngDimRecordCount) To UBound(avarDays, clngDimRecordCount)
adatDays(lngDays) = avarDays(clngDimFieldOne, lngDays)
Next
End If
' DAO objects are static.
' Set rst = Nothing
' Set dbs = Nothing
GetHolidays = adatDays()
End Function
Ok so my code works fine, however I need it to add one day to the OrderDate , while keeping it in the same format yyyy-mm-dd any help is greatly appreciated!
<%
inDate = oRS("ordDate")
' get each date component
thisMonth = datepart("M",inDate)
thisDay = datepart("D",inDate)
thisYear = datepart("yyyy",inDate)
' check for the length of the month and day components
if len(thisMonth) < 2 then thisMonth = "0" & thisMonth
if len(thisDay) < 2 then thisDay = "0" & thisDay
' Create the date in your format you posted above
OrderDate = thisYear & "-" & thisMonth & "-" & thisDay
%>
Using your code as an example just use DateAdd() to increment the day by 1 calendar day;
<%
inDate = oRS("ordDate")
'Add one day
inDate = DateAdd("d", 1, inDate)
' get each date component
thisMonth = datepart("M",inDate)
thisDay = datepart("D",inDate)
thisYear = datepart("yyyy",inDate)
' check for the length of the month and day components
if len(thisMonth) < 2 then thisMonth = "0" & thisMonth
if len(thisDay) < 2 then thisDay = "0" & thisDay
' Create the date in your format you posted above
OrderDate = thisYear & "-" & thisMonth & "-" & thisDay
%>
For more information of working with dates see Classic ASP - Format current date and time.
try this:
dim sOrderDate
sOrderDate=cInt(thisDay)+1
if len(thisDay) < 2 then thisDay = "0" & thisDay
if len(sOrderDate) < 2 then sOrderDate = "0" & sOrderDate
OrderDate = thisYear & "-" & thisMonth & "-" & sOrderDate
this way you preserve original date(thisDay) for manipulation and order date became tomorrow (or whatever) date.
I'm trying to find all Thursdays within a given Month using VBScript.
Can anyone help?
Here is one way;
base_date = cdate("21 aug 2011")
'get 1st thursday;
thurs = dateserial(year(base_date), month(base_date), 1)
if (weekday(thurs) <> 1) then thurs = 5 - weekday(thurs) + thurs
'loop subsequent;
do until month(thurs) <> month(base_date)
msgbox thurs
thurs = dateadd("d", 7, thurs)
loop
While the accepted answer does the job it's overly complicated for something that can be accomplished with WeekDay() function and a For loop.
Dim day
Dim startdate: startdate = CDate("21 aug 2011")
Dim enddate
'Get first day of month.
startdate = DateSerial(Year(startdate), Month(startdate), 1)
'Get last day of month.
enddate = DateAdd("m", 1, startdate) - 1
For day = startdate To enddate
If WeekDay(day) = vbThursday Then WScript.Echo day & " = " & WeekDayName(WeekDay(day))
Next
Output:
04/08/2011 = Thursday
11/08/2011 = Thursday
18/08/2011 = Thursday
25/08/2011 = Thursday
Any Date and Time constant can be used here to look for different or multiple weekdays with a little tinkering.