I want to store 6 decimal digits into an array, but when I store it into array it only stores up to 4 decimal digits instead of 6. How can I store up to 6 digits into an array?
For example, if
e=0.059995;
W(l,i)=e;
but W(l,i) gives me the result as 4 decimal places
disp(W(l,i))
0.0600
How can I store 6 decimal digits into an array, i.e when I print the array it prints
6 decimal places?
disp(W(l,i))
0.059995
Can anyone help me?
Matlab on default settings stores up to 15 digits. It only your display format. Have a look at the format command.
Or just type at the Matlab command prompt:
format long
If you know you have only 6 digits you can use
sprintf('%0.6f', W(l,i))
instead of disp
Related
I want to convert a floating point number to string.
f=0.0000
str=num2str(f,4);
This give me this-
str=
0
But I wanted to keep the result till 4 decimal points.I understand using num2str(f,4) results in precision of maximum 4 significant digits after decimal.It is not equal to 4 but maximum and that is why I get this answer.I want to know is there any way to convert this number to string with exactly 4 significant digits after decimal point?
Try using sprintf instead:
str = sprintf('%.4f', f)
If I set a variable in Matlab, say var1 = 2.111, after running the script, Matlab returns var1 = 2.1110. I want Matlab to return the original number, with no trailing zero. Anyone know how to do this. Thanks in advance.
By default Matlab displays results in Short fixed decimal format, with 4 digits after the decimal point.
You can change that to various other format such as:
long
Long fixed decimal format, with 15 digits after the decimal point for double values, and 7 digits after the decimal point for single values.
3.141592653589793
shortE
Short scientific notation, with 4 digits after the decimal point.
Integer-valued floating-point numbers with a maximum of 9 digits do not display in scientific notation.
3.1416e+00
longE
Long scientific notation, with 15 digits after the decimal point for double values, and 7 digits after the decimal point for single values.
Integer-valued floating-point numbers with a maximum of 9 digits do not display in scientific notation.
3.141592653589793e+00
shortG
The more compact of short fixed decimal or scientific notation, with 5 digits.
3.1416
longG
The more compact of long fixed decimal or scientific notation, with 15 digits for double values, and 7 digits for single values.
3.14159265358979
shortEng
Short engineering notation, with 4 digits after the decimal point, and an exponent that is a multiple of 3.
3.1416e+000
longEng
Long engineering notation, with 15 significant digits, and an exponent that is a multiple of 3.
3.14159265358979e+000
However I don't think other options are available. If you absolutely want to remove those zeros you would have to cast you result in a string and remove the trailing 0 characters and then display your result as a string and not a number.
I have numbers with upto 10 decimal points stored in a text file.
I read it in MATLAB and then do str2double on the number but i get only upto 4 decimal points. What should I do to get all the values after decimal.
Forexample:
str2double('-122.345464646')
ans =
-122.3455
but I need the entire number
Thanks
Please follow the below steps:
Go to preference
List item
Go to Command Window Option
Then change the numeric format to long g
Alternatively, type long g in command window
I am trying to save decimal number to the core data NSNumber object but decimal value had saved with rounding digits when we enter a 5 digit number with its decimal part.
If I enter up to 9999,999 getting save same value to database but in case of a 5 digit (e.g.,10000.999) it will be save as 10001 in the database.
chargeFloat=10000.999;
value.fees = [NSNumber numberWithFloat:chargeFloat];//value is an entity object
//fees is nsnumber
but in database showing this value as 10001.
I need a solution.
Floats give you 6 to 9 significant digits, doubles give you 15 to 17 significant digits and NSDecimal gives you 38 significant digits. I suggest that you either use doubles of NSDecimals.
how to write a lisp program to convert given hexadecimal number into decimal. can somebody give me a clue.
thank you
I'm assuming its a homework problem so i'll give you a hint in the right direction.
Here is how to convert decimal to binary ->
Lets say you start with the number 9 in binary its 1001.
Start of by dividing 9 by 2. You get 4 with remainder 1. Save the remainder.
Now divide that 4 by 2 again, you get 2 with remainder 0. Save the remainder.
Divide that 2 again by 2, you get 1 with remainder 0. Save the remainder.
Divide that 1 by 2 and finally you get 0 with reaminder 1. Save the remainder.
If you read the saved remainders backwards you get 1001! The binary number you've been looking for. Best to push the remainders on the stack and pop them back out, that way they'll come out backwards.
It's already provided by Common Lisp.
The input is the string for the hex integer.
Then you parse the integer with radix 16
the result is the number
if you write the number with base 10 to an output stream, then you can get the number as a string in base 10