identify iPhone 3, 4 and 5 in the same #define - iphone

Question

I've been using the next line in my constants
to differentiate between devices and get back the number of the device.
What's the appropriate way to identify iPhone 5 and still keep it in a one line format?
#define iPhoneType [[UIScreen mainScreen] scale]==2 || [UIDevice currentDevice].userInterfaceIdiom == UIUserInterfaceIdiomPad ? #"4" : #"3"
Thanks
Edit: A lot of good answers but my goal is to keep it in a one line format for all devices.
Edit:
Based on the comments, this question needs some clarification. Here are the requirements:
A single-line macro that returns either #"3", #"4", or #"5" depending on the iOS device.
The 4" devices (currently iPhone 5 and 5th gen iPod touch) should return #"5".
All iPads and all remaining retina iPhones and iPod touches should return #"4".
All remaining non-retina iPhones and iPod touches should return #"3".

Answer 1

According to your question I'm assuming you want to identify the hardware device, not the iOS version.
/*
Erica Sadun, http://ericasadun.com
iPhone Developer's Cookbook, 6.x Edition
BSD License, Use at your own risk
*/
#include <sys/sysctl.h>
NSString* getSysInfoByName(char* typeSpecifier) {
size_t size;
sysctlbyname(typeSpecifier, NULL, &size, NULL, 0);
char *answer = malloc(size);
sysctlbyname(typeSpecifier, answer, &size, NULL, 0);
NSString *results = [NSString stringWithCString:answer encoding: NSUTF8StringEncoding];
free(answer);
return results;
}
NSString* platform() {
return getSysInfoByName("hw.machine");
}
Import those functions in the .pch, then you are free to call this one liner:
BOOL isIphone5 = [platform() hasPrefix:#"iPhone5"];
It works for any device. See UIDevice-Hardware.m for a list of the strings returned.

Answer 2

Assuming the updated requirements are correct, the following should work:
#define iPhoneType (fabs((double)[UIScreen mainScreen].bounds.size.height - (double)568) < DBL_EPSILON) ? #"5" : ([UIScreen mainScreen].scale==2 || UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad ? #"4" : #"3")
This will return #"5" for the 4" screened iPhones and iPod touches. This will return #"4" for all iPads and retina iPhones and iPod touches. And it will return #"3" for non-retina iPhones and iPod touches.

Answer 3

Define Following Constants in .pch file of your project
#define IS_IPHONE5 ([[UIScreen mainScreen] bounds].size.width >= 568 || [[UIScreen mainScreen] bounds].size.height >= 568)?YES:NO
#define IS_IPHONE (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone)?YES:NO
#define IS_IPAD (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)?YES:NO
#define DeviceType ((IS_IPAD)?#"IPAD":(IS_IPHONE5)?#"IPHONE 5":#"IPHONE")
Now Check device type
NSLog(#"%# %#",DeviceType,[DeviceType isEqualToString:#"IPAD"]?#"YES":#"NO");
Use following sequence to Identify Device Type
if(IS_IPAD)
NSLog(#"IPAD");
else if(IS_IPHONE5)
NSLog(#"IPHONE 5");
else
NSLog(#"IPHONE");

Answer 4

The best way to identify the different iOS devices programatically is their screen resolution. I done same in my application it is working great. Please refer my code.
- (NSString *) getDeviceScreenWidth
{
CGRect screenBounds = [[UIScreen mainScreen] bounds];
CGFloat width = CGRectGetWidth(screenBounds);
NSNumber* number = [NSNumber numberWithFloat:width];
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:kCFNumberFormatterDecimalStyle];
NSString* commaString = [numberFormatter stringForObjectValue:number];
NSString *screenWidth = [NSString stringWithFormat:#"%#",commaString];
NSLog(#"screen Width is: %#",screenWidth);
return screenWidth;
}
- (NSString *) getDeviceScreenHeight
{
CGRect screenBounds = [[UIScreen mainScreen] bounds];
CGFloat height = CGRectGetHeight(screenBounds);
NSNumber* number = [NSNumber numberWithFloat:height];
NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:kCFNumberFormatterDecimalStyle];
NSString* commaString = [numberFormatter stringForObjectValue:number];
NSString *screenHeight = [NSString stringWithFormat:#"%#",commaString];
NSLog(#"screen height is: %#",screenHeight);
return screenHeight;
}

Answer 5

As sample you may found this code in cocos2d framework:
-(NSInteger) runningDevice
{
NSInteger ret=-1;
#ifdef __CC_PLATFORM_IOS
if( UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad)
{
ret = (CC_CONTENT_SCALE_FACTOR() == 2) ? kCCDeviceiPadRetinaDisplay : kCCDeviceiPad;
}
else if( UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone )
{
// From http://stackoverflow.com/a/12535566
BOOL isiPhone5 = CGSizeEqualToSize([[UIScreen mainScreen] preferredMode].size,CGSizeMake(640, 1136));
if( CC_CONTENT_SCALE_FACTOR() == 2 ) {
ret = isiPhone5 ? kCCDeviceiPhone5RetinaDisplay : kCCDeviceiPhoneRetinaDisplay;
} else
ret = isiPhone5 ? kCCDeviceiPhone5 : kCCDeviceiPhone;
}
#elif defined(__CC_PLATFORM_MAC)
// XXX: Add here support for Mac Retina Display
ret = kCCDeviceMac;
#endif // __CC_PLATFORM_MAC
return ret;
}
I hope this code helps change your macro.