This question already has an answer here:
Create a "counter" on matlab from 0:limit-1. The length of counter is not determined in the program
(1 answer)
Closed 9 years ago.
Q- Create a "counter" from 0:limit-1 (for example if you choose 3 it will display 0,1,2). The length of counter is not determined in the program and it should be determined when it is being run and the inputs can differ from each other
not really sure what you mean...but
for i = 0:limit-1
disp(i)
end
will display 0,1,2 ... limit-1
Related
This question already has answers here:
Generate random numbers with a given distribution
(4 answers)
how to generate random numbers from 1 to 4 and 8 in swift
(2 answers)
Closed 4 months ago.
It seems like randomElement() in Swift only allows for an equally weighted selection. What would be the best (and most efficient way, as I need to repeat this very often) to select from a collection with pre-specified probabilities/weights?
This question already has answers here:
Replace all zeros in vector by previous non-zero value
(6 answers)
Closed 3 years ago.
I'm trying to replace a zero value with the previous value while storing it in a variable. I imported the csv file as a Numeric Matrix.
I think your code should be something like below:
Stocks = Stock_Market;
for i = 2:length(Stocks(:,1))
if Stocks(i,1)==0
Stocks(i,1) = Stocks(i-1,1);
end
end
This question already has answers here:
Create variables with names from strings
(6 answers)
How to Dynamically Create Variables in MATLAB [duplicate]
(3 answers)
Closed 5 years ago.
I run an algorithm that result of it is a matrix as A. I run an algorithm 50 times and I want to save results as A1 to A50 matrix. how can I write?
This question already has answers here:
Run-length decoding in MATLAB
(4 answers)
Closed 6 years ago.
I have a variable distr=[0 3 1 0 2];, and I have a variable full which should contrain distr(i) times i, for all i.
In this example, i want:
full=[2 2 2 3 5 5];
because distr(2)=3, therefore 3x 2, and so on.
Of course I can do it in a for-loop:
full=zeros([1,sum(distr)]);
cc=1;
for i=1:length(distr)
curr=distr(i);
full(cc:cc+curr-1)=i*ones([1,curr]);
cc=cc+curr;
end
but that is very slow. Do you know of a fast way, using MATLAB's awesome array-oriented style? Thanks!
Not sure, but maybe this will work. I can't check it since I currently don't have MATLAB:
full_tmp = arrayfun(#(i,n) i*ones(1,n),1:length(distr),distr,'uniformoutput',false);
full = cat(2,full_tmp{:});
This question already has an answer here:
matlab based program where output comprises of sum of rows of input
(1 answer)
Closed 8 years ago.
I am trying to implement a vectorised solution in matlab for adding all elements above the current element in a vector. For eg.
I have a vector a as follows
a =
1
2
3
4
I would like a vector b like
b =
1
3
6
10
I know this can be done very easily using a loop but I was wondering if there are indexing options which can allow me to do the same in matlab/ octave?
You can use the Cumulative Summation function (cumsum):
b = cumsum(a)