Datetime to Date (MySQL) in JPA createQuery error Exception [EclipseLink-8025] - jpa

Question

I'am new in JAVA and JPA.
I use command
select * from asm.attendant where staff_no='0004' and node_code='KT1' and date(attendant_date) = '2013-05-13';
in MySQL it's work
but
when i use in JPA
public List<Attendant> listAttendantByStaffNoAndNodeCodeAndDateWs(String staffNo,String nodeCode,String attendantDateData) throws ParseException {
Date attendantDate = new SimpleDateFormat("yyyy-MM-dd").parse(attendantDateData);
Query result = em.createQuery("SELECT a FROM Attendant a WHERE a.staffNo = :staffNo AND a.nodeCode = :nodeCode AND DATE(a.attendantDate) = :attendantDate", Attendant.class);
result.setParameter("staffNo", staffNo);
result.setParameter("nodeCode", nodeCode);
result.setParameter("attendantDate", attendantDate);
return result.getResultList();
}
it's not work.
error
Caused by: Exception [EclipseLink-8025] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.JPQLException
Exception Description: Syntax error parsing the query [SELECT a FROM Attendant a WHERE a.staffNo = :staffNo AND a.nodeCode = :nodeCode AND DATE(a.attendantDate) = :attendantDate], line 1, column 88: unexpected token [(].
Internal Exception: NoViableAltException(83#[()* loopback of 383:9: (d= DOT right= attribute )*])

Answer 1

DATE() is not valid JPQL. In JPA createQuery() takes JPQL not SQL. If you want SQL use createNativeQuery().
Or, in JPQL just mark the date as a parameter :date any set the parameter to your instance of java.sql.Date.