I need to convert string from varchar to Date in 'MM/DD/YYYY' format. My input string is '4/9/2013' and my expected output is '04/09/2013'. i.e. 2 digit month, 2 digit date and 4 digit year seperated by'/'
I have below data:
DOJ varchar2(10 Byte)column has '4/9/2013' value.
I am using 'select TO_DATE(DOJ,'MM/DD/YYYY') from EmpTable. But I am getting result as 09-APR-13. I want it in 04/09/2013 format.
Please advise. Thanks in advance.
Easiest way is probably to convert from a VARCHAR to a DATE; then format it back to a VARCHAR again in the format you want;
SELECT TO_CHAR(TO_DATE(DOJ,'MM/DD/YYYY'), 'MM/DD/YYYY') FROM EmpTable;
An SQLfiddle to test with.
First you convert VARCHAR to DATE and then back to CHAR. I do this almost every day and never found any better way.
select TO_CHAR(TO_DATE(DOJ,'MM/DD/YYYY'), 'MM/DD/YYYY') from EmpTable
Example query:
SELECT TO_CHAR(TO_DATE('2017-08-23','YYYY-MM-DD'), 'MM/DD/YYYY') FROM dual;
Related
I have create a datetime with type timestamp. datetime timestamp NOT NULL I am not sure why the output is like this:
I want to extract the day part. I have tried these different approach but in both cases I am getting an error. How can I fix it?
extract(DAY FROM TIMESTAMP min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI'))::timestamp)
EXTRACT(DAY FROM TIMESTAMP min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI')))
date_part('day', min(to_char(u.datetime ,'YYYY-MM-DD HH24:MI')))
As mentioned in response I modified query to be like below and it does work.
extract(day from MIN(datetime)) as Day
All you need is:
select *, extract(day from activated_at) as Day from yourTable;
What you are seeing is a timestamp formatted as text for the display. Underlying data is timestamp as you said, directly use it.
Hi I have a date format in one table in Text 'YYYY/MM'. example 2018/01, 2020/08 etc.
I need to join it with another table where the date is in Number type( and DATETIME20 format attached it it) and convert it to month and compare.
Is there any way to do it in PROC SQL as the rest of my query is in PROC SQL?
eg. Table 1: Month= 2018/01; Table 2: Date =20.01.2018 10:48:17 . They should be joined in the PROC SQL query.
I would also like to calculate difference in Months between these two dates.
Thank you in advance.
Convert both to the same DATE value. To convert a datetime value to a date use the DATEPART() function. To move to the first day of the month use the INTNX() function with the month interval. To convert a string like '2018/01' to a date you could use INPUT() function with YYMMDD informat by appending '/01'.
proc sql ;
create table want as
select *
from table1,table2
where input(cats(table1.month,'/01'),yymmdd10.)=intnx('month',datepart(table2.date),0)
;
quit;
I have column 'jobstarttimeiso' and I want to create another column for Weeks of the year based on the date. How would I go about doing that? I am using Redash to query from redshift database. Please help! Thank you.
The extract function will return a week number e.g.
select extract(week from jobstarttimeiso) as weeknumber
In general:
EXTRACT ( datepart FROM { TIMESTAMP 'literal' | timestamp } )
See: https://docs.aws.amazon.com/redshift/latest/dg/r_EXTRACT_function.html
alternatively you can also use to_char()
TO_CHAR (timestamp_expression | numeric_expression , 'format')
with the parameter IYYY as the format for ISO 8601 week-numbering year (4 or more digits)
I am trying to convert a character varying date field to the format YYYYMMDD and below is the select query I tried. The output format is 1999-04-27 (YYYY-MM-DD). Admindate is the field name in the table.
select to_date( admindate,'MMDDYYYY') from test;
Can someone please advice what I am doing wrong?
Use to_char to convert the converted date into the desired format.
select to_char(to_date(admindate, 'MMDDYYYY'), 'YYYYMMDD')
from test;
you can try this
SELECT TO_CHAR(NOW() :: DATE, 'dd/mm/yyyy');
I want to know what other MONTH formats exist except MM , MONTH or MON.
When the query below runs it gives me an error ORA-01843: not a valid month and I can understand why, because the server removes the "0" from the month "07" and leaves only the number "7", so the MM format is not the right one.
But which one is it?
select to_char(to_date(START_DATE,'MM/DD/YYYY '), 'DD-MM-YYYY')
from PER_ALL_PEOPLE_F
WHERE person_id=12345
The START_DATE column is DATE TYPE and it provides results like: 7/17/2012 .
Your assumption that the single-digit 7 for the month is a problem is not correct; Oracle is generally quite flexible and will happily parse a single digit month with the MM model:
select to_date('7/17/2012', 'MM/DD/YYYY') from dual;
TO_DATE('7/17/2012'
-------------------
2012-07-17 00:00:00
If start_date is already a DATE type then you should not be calling to_date() for it. You're doing an implicit conversion to a string using your NLS_DATE_FORMAT moodel, and then back to a date with your specified format. So really you're doing:
select to_char(to_date(to_char(START_DATE, <NLS_DATE_FORMAT>),
'MM/DD/YYYY '), 'DD-MM-YYYY')
If your NLS_DATE_FORMAT is something other than MM/DD/YYYY, e.g. DD-MON-YYYY, then you'll get an ORA-1843 error for at least some values.
You can see this with:
select to_date(date '2014-01-16', 'MM/DD/YYYY') from dual;
or the expanded:
select to_date(to_char(date '2014-01-16', 'DD-MON-YYYY'),
'MM/DD/YYYY') from dual;
Dates do not have any specific format, they're stored in an internal representation and then converted to a formatted string for display. You said your dates display like 7/12/2012, but given the error you're seeing your client seems to be doign that formatting, and it isn't related to the session NLS_DATE_FORMAT.
You only need to do:
select to_char(START_DATE, 'DD-MM-YYYY')