I have the below query that get results from more than one select.
Now I want these to be in a temp table.
Is there any way to insert these into a temp table without creating the table?
I know how to do that for select
Select * into #s --like that
However how to do that one more than one select?
SELECT Ori.[GeoBoundaryAssId], Ori.[FromGeoBoundaryId], Ori.Sort
From [GeoBoundaryAss] As Ori where Ori.[FromGeoBoundaryId] = (select distinct [FromGeoBoundaryId] from inserted )
Union
SELECT I.[GeoBoundaryAssId], I.[FromGeoBoundaryId], I.Sort
From [inserted] I ;
Add INTO after the first SELECT.
SELECT Ori.[GeoBoundaryAssId], Ori.[FromGeoBoundaryId], Ori.Sort
INTO #s
From [GeoBoundaryAss] As Ori where Ori.[FromGeoBoundaryId] = (select distinct [FromGeoBoundaryId] from inserted )
Union
SELECT I.[GeoBoundaryAssId], I.[FromGeoBoundaryId], I.Sort
From [inserted] I ;
Try this,
INSERT INTO #s ([GeoBoundaryAssId], [FromGeoBoundaryId], Sort)
(
SELECT Ori.[GeoBoundaryAssId], Ori.[FromGeoBoundaryId], Ori.Sort
FROM [GeoBoundaryAss] AS Ori WHERE Ori.[FromGeoBoundaryId] in (SELECT DISTINCT [FromGeoBoundaryId] FROM inserted )
UNION
SELECT I.[GeoBoundaryAssId], I.[FromGeoBoundaryId], I.Sort
FROM [inserted] I
)
Related
I have an add request:
INSERT INTO LIKES_PRODUCTS AS L (L.USER_ID, L.PRODUCT_ID) VALUES('7', '1')
There is a request for the number of rows in the table:
SELECT COUNT(L.USER_ID) AS LIKES FROM LIKES_PRODUCTS AS L
Is it possible to combine them into a single query, so that the addition occurs first, and then only the counting of rows in the table?
You can do that with a data modifying CTE
with new_row as (
insert into likes_products (user_id, product_id)
values (7,1)
)
select count(user_id) as likes
from likes_products;
However, the final select does not see the effects of the previous CTE. If you always insert one row, you can simply count(user_id) + 1 in the select. Another option is to return the inserted rows and add them to the count:
with new_rows as (
insert into likes_products (user_id, product_id)
values (7,1),(8,2)
returning *
)
select count(user_id) + (select count(*) from new_rows) as likes
from likes_products;
I have multiple tables that all have the same columns, but in different order. I want to merge them all together. I've created an empty table with the standard columns in the order I would like. I've tried inserting with
insert into master_table select * from table1;
but that doesn't work because of the differing column order - some of the values end up in the wrong columns. What is the best way to create one table out of them all in the order specified in my empty master table?
If you are dealing with many columns and many tables, you can use the information_schema to get the columns. You can loop through all the tables you want to insert from and run this in a plpgsql procedure, replacing table1 with a variable:
EXECUTE (
SELECT
'insert into master_table
(' || string_agg(quote_ident(column_name), ',') || ')
SELECT ' || string_agg('p.' || quote_ident(column_name), ',') || '
FROM table1 p '
FROM information_schema.columns raw
WHERE table_name = 'master_table');
just indicate the proper order in the select
instead of
select *
if you want 3 field on second posiition.
select field1, field3, field2
or you can use the INSERT sintaxis
INSERT INTO master_table (field1, field3, field2)
SELECT *
Hello with this query I'm getting one result with four rows, how can I change it in order to get four named columns with their own result every one?
SELECT COUNT(*) FROM vehicles WHERE cus=1
UNION ALL
SELECT COUNT(*) FROM user WHERE cus=1
UNION ALL
SELECT COUNT(*) FROM vehicle_events WHERE cus=1
UNION ALL
SELECT COUNT(*) FROM vehicle_alerts WHERE cus=1
Thanks in advance.
SELECT a.ct veh_count, b.ct user_count, c.ct event_count, d.ct alert_count
FROM
( SELECT COUNT(*) ct FROM vehicles WHERE cus=1 ) a,
( SELECT COUNT(*) ct FROM user WHERE cus=1 ) b,
( SELECT COUNT(*) ct FROM vehicle_events WHERE cus=1 ) c,
( SELECT COUNT(*) ct FROM vehicle_alerts WHERE cus=1 ) d;
UNION only adds rows; it has no effect on the columns.
Columns, which define the "shape" of the row tuples, must appear as selected columns1.
For example:
SELECT
(SELECT COUNT(*) FROM vehicles WHERE cus=1) as veh_count
,(SELECT COUNT(*) FROM users WHERE cus=1) as user_count
..
1 There are other constructs that can allow this, see crosstab for example - but the columns are fixed by the query command. It takes dynamic SQL to get a variable number of columns.
I have a field called "Users", and I want to run SUM() on that field that returns the sum of all DISTINCT records. I thought that this would work:
SELECT SUM(DISTINCT table_name.users)
FROM table_name
But it's not selecting DISTINCT records, it's just running as if I had run SUM(table_name.users).
What would I have to do to add only the distinct records from this field?
Use count()
SELECT count(DISTINCT table_name.users)
FROM table_name
SQLFiddle demo
This code seems to indicate sum(distinct ) and sum() return different values.
with t as (
select 1 as a
union all
select '1'
union all
select '2'
union all
select '4'
)
select sum(distinct a) as DistinctSum, sum(a) as allSum, count(distinct a) as distinctCount, count(a) as allCount from t
Do you actually have non-distinct values?
select count(1), users
from table_name
group by users
having count(1) > 1
If not, the sums will be identical.
You can see for yourself that distinct works with the following example. Here I create a subquery with duplicate values, then I do a sum distinct on those values.
select DistinctSum=sum(distinct x), RegularSum=Sum(x)
from
(
select x=1
union All
select 1
union All
select 2
union All
select 2
) x
You can see that the distinct sum column returns 3 and the regular sum returns 6 in this example.
You can use a sub-query:
select sum(users)
from (select distinct users from table_name);
SUM(DISTINCTROW table_name.something)
It worked for me (innodb).
Description - "DISTINCTROW omits data based on entire duplicate records, not just duplicate fields." http://office.microsoft.com/en-001/access-help/all-distinct-distinctrow-top-predicates-HA001231351.aspx
;WITH cte
as
(
SELECT table_name.users , rn = ROW_NUMBER() OVER (PARTITION BY users ORDER BY users)
FROM table_name
)
SELECT SUM(users)
FROM cte
WHERE rn = 1
SQL Fiddle
Try here yourself
TEST
DECLARE #table_name Table (Users INT );
INSERT INTO #table_name Values (1),(1),(1),(3),(3),(5),(5);
;WITH cte
as
(
SELECT users , rn = ROW_NUMBER() OVER (PARTITION BY users ORDER BY users)
FROM #table_name
)
SELECT SUM(users) DisSum
FROM cte
WHERE rn = 1
Result
DisSum
9
If circumstances make it difficult to weave a "distinct" into the sum clause, it will usually be possible to add an extra "where" clause to the entire query - something like:
select sum(t.ColToSum)
from SomeTable t
where (select count(*) from SomeTable t1 where t1.ColToSum = t.ColToSum and t1.ID < t.ID) = 0
May be a duplicate to
Trying to sum distinct values SQL
As per Declan_K's answer:
Get the distinct list first...
SELECT SUM(SQ.COST)
FROM
(SELECT DISTINCT [Tracking #] as TRACK,[Ship Cost] as COST FROM YourTable) SQ
SELECT
MEM_ID, [C1],[C2]
from
(select
MEM_ID, Condition_id, condition_result
from tbl_GConditionResult
) x
pivot
(
sum(condition_result)
for condition_id in ([C1],[C2])
) p
The above query returns three columns of data. Until runtime I will not know how many columns in the select statement. Is it possible to load the data from the select statement into a dynamically created table? After processing the data from the dynamically created table I want to drop the table.
Thank you for your help.
Smith
Yes, do a SELECT INTO e.g.
SELECT
MEM_ID, [C1],[C2]
into #TEMP
from
(select
MEM_ID, Condition_id, condition_result
from tbl_GConditionResult
) x
pivot
(
sum(condition_result)
for condition_id in ([C1],[C2])
) p
-- Do what you need with the TEMP table
DROP TABLE #TEMP