Pattern Matching in perl - perl

Question

I want to parse some information from the file.
Information in the file:
Rita_bike_house_Sha9
Rita_bike_house
I want to have output like dis
$a = Rita_bike_house and $b = Sha9,
$a = Rita_bike_house and $b = "original"
In order to get that I have used the below code:
$name = #_; # This #_ has all the information from the file that I have shown above.
#For matching pattern Rita_bike_house_Sha9
($a, $b) = $name =~ /\w\d+/;
if ($a ne "" and $b ne "" ) { return ($a,$b) }
# this statement doesnot work at all as its first condition
# before the end is not satisified.
Is there any way where I can store "Rita_bike_house" in $a and "Sha9" in $b? I think my regexp is missing with something. Can you suggest anything?

Answer 1

Please don't use the variables $a and $b in your code. There are used by sort and will confuse you.
Try:
while( my $line = <DATA> ){
chomp $line;
if( $line =~ m{ \A ( \w+ ) _ ( [^_]* \d [^_]* ) \z }msx ){
my $first = $1;
my $second = $2;
print "\$a = $first and \$b = $second\n";
}else{
print "\$a = $line and \$b = \"original\"\n";
}
}
__DATA__
Rita_bike_house_Sha9
Rita_bike_house

Answer 2

Not very nice, but the next:
use strict;
use warnings;
while(<DATA>) {
chomp;
next if /^\s*$/;
my #parts = split(/_/);
my $b = pop #parts if $parts[$#parts] =~ /\d/;
$b //= '"original"';
my $a = join('_', #parts);
print "\$a = $a and \$b = $b,\n";
}
__DATA__
Rita_bike_house_Sha9
Rita_bike_house
prints:
$a = Rita_bike_house and $b = Sha9,
$a = Rita_bike_house and $b = "original",

Answer 3

If you are sure that the pattern which is required will always be similar to 'Sha9' and also it will appear at the end then just do a greedy matching....
open FILE, "filename.txt" or die $!;
my #data = <FILE>;
close(<FILE>);
#my $line = "Rita_bike_house_Sha9";
foreach $line (#data)
{
chomp($line);
if ($line =~ m/(.*?)(_([a-zA-Z]+[0-9]+))?$/)
{
$a = $1;
$b = $3 ? $3 : "original";
}
}