DATEDIFF On Dates - tsql

Question

I've been struggling with this but I'm not really good at tsql.
This is what I got, and I can't have the DateTime calculates all right. I'm getting the sum between A and B but not the total sum. For example in the last column I have a 0 which is getting me back to -x.
Here is the procedure, and some of the data are like this:
Code_Procedure date_evenement codes_situation
---------------------------------------------------------------
000079500000 2013-05-21 13:07:00.000 COMCFM
000079500000 2013-05-21 20:24:00.000 PCHCFM
000079500000 2013-05-22 09:58:00.000 PCHCFM
000079500000 2013-05-23 00:00:00.000 AARCFM
000079500000 2013-05-23 00:00:00.000 LIVCFM
000079600000 2013-05-21 13:07:00.000 COMCFM
000079600000 2013-05-21 20:24:00.000 PCHCFM
000079600000 2013-05-22 11:18:00.000 PCHCFM
000079600000 2013-05-23 00:00:00.000 AARCFM
000079600000 2013-05-23 00:00:00.000 LIVCFM
Here is the proc:
DECLARE #COMCFM TABLE(numero_colis VARCHAR(25), date_evenement DATETIME);
INSERT #COMCFM SELECT TOP(5) numero_colis, date_evenement FROM cartitem_colis_postaux_etats WHERE (code_situation = 'PCH' AND code_justification = 'CFM')
WHILE (SELECT COUNT(*) FROM #COMCFM) > 0
BEGIN
DECLARE #Colis TABLE(numero_colis VARCHAR(25), date_evenement DATETIME, code_situation_code_justification NVARCHAR(32));
INSERT #Colis SELECT numero_colis, date_evenement, code_situation + code_justification FROM cartitem_colis_postaux_etats WHERE numero_colis = (SELECT TOP(1) numero_colis FROM #COMCFM) ORDER BY numero_colis, date_evenement
;WITH CTE AS
(
Select DISTINCT
*
,ROW_NUMBER() OVER(PARTITION BY numero_colis ORDER BY date_evenement ASC) Rn FROM #Colis
),CTE1 AS
(
SELECT DISTINCT
A.*
,DATEDIFF(mi, B.date_evenement, A.date_evenement) AS DIFF
FROM CTE A INNER JOIN CTE B On B.Rn + 1 = A.Rn
UNION All
SELECT A.*, 0 FROM CTE A Where Rn = 1
)
SELECT
A.*
,ISNULL((
SELECT
A.DIFF + B.DIFF
FROM CTE1 AS B
WHERE A.numero_colis = B.numero_colis
AND A.Rn = B.Rn + 1), 0) AS Sums
FROM CTE1 AS a
ORDER BY numero_colis, Rn ASC
DELETE FROM #Colis
DELETE FROM #COMCFM WHERE numero_colis = (SELECT TOP(1) numero_colis FROM #COMCFM)
END

Answer 1

I'm not really sure what you would like to achieve. Do you need date differencies as a cummulated value? If you need this, change your BEGIN-END block of your stored procedure with this code
BEGIN
DECLARE #Colis TABLE(numero_colis VARCHAR(25), date_evenement DATETIME, code_situation_code_justification NVARCHAR(32));
INSERT #Colis SELECT numero_colis, date_evenement, code_situation + code_justification FROM cartitem_colis_postaux_etats WHERE numero_colis = (SELECT TOP(1) numero_colis FROM #COMCFM) ORDER BY numero_colis, date_evenement
;WITH CTE AS
(
SELECT DISTINCT
*,
ROW_NUMBER() OVER(PARTITION BY numero_colis ORDER BY date_evenement ASC) Rn
FROM #Colis
),CTE1 AS
(
SELECT A.*, 0 AS CummulatedDiff
FROM CTE A
WHERE Rn = 1
UNION ALL
SELECT DISTINCT A.*, B.CummulatedDiff + DATEDIFF(mi, B.date_evenement, A.date_evenement) AS CummulatedDiff
FROM CTE AS A INNER JOIN
CTE1 AS B ON B.Rn + 1 = A.Rn AND B.numero_colis = A.numero_colis
)
SELECT *
FROM CTE1 AS a
ORDER BY numero_colis, Rn ASC
DELETE FROM #Colis
DELETE FROM #COMCFM WHERE numero_colis = (SELECT TOP(1) numero_colis FROM #COMCFM)
END
I hope this takes you further to your goal.