I'm reading the documentation for tree structures here:
http://docs.mongodb.org/manual/tutorial/model-tree-structures/
The hierarchy is:
Books -> Programming -> [Languages, Databases -> [Postgres, MongoDB]]
In the documentation it says:
The query to retrieve the parent of a node is fast and straightforward:
db.categories.findOne( { _id: "MongoDB" } ).parent
That makes sense. However, how can I run a query based on attributes of the ancestor? For example, instead of just retrieving the parent, suppose I wish to find all documents where the grandfather has an _id of "Books" how would I do that? The answer should be "Languages" and "Databases".
If your tree structure is fixed. You can query by following way, before that, just change your MongoDB structure by following URL,
http://docs.mongodb.org/manual/tutorial/model-tree-structures-with-nested-sets/
to get all ancestor of Databases,
var databaseCategory = db.categories.findOne( { _id: "Databases" } );
db.categories.find( { left: { $lt: databaseCategory.left }, right: { $gt: databaseCategory.right } } );
Result:
{ "_id" : "Books", "parent" : 0, "left" : 1, "right" : 12 }
{ "_id" : "Programming", "parent" : "Books", "left" : 2, "right" : 11 }
to get all descendant of Databases,
var databaseCategory = db.categories.findOne( { _id: "Databases" } );
db.categories.find( { left: { $gt: databaseCategory.left }, right: { $lt: databaseCategory.right } } );
Result:
{ "_id" : "MongoDB", "parent" : "Databases", "left" : 6, "right" : 7 }
{ "_id" : "dbm", "parent" : "Databases", "left" : 8, "right" : 9 }
Related
Hello im learning MongoDB and my exercise is to update id in one of my collection to another id. I Have two collection
First collection "workers" :
{
"_id" : ObjectId("6224ec342c2d7202b9ad9af6"),
"id_worker" : 180,
"id_boss" : 100,
"hired" : ISODate("2005-02-20T00:00:00Z"),
"id_group" : 10
}
Second collection "groups":
{
"_id" : ObjectId("6224ebe12c2d7202b9ad9af1"),
"id_group" : 10,
"name" : "Administrators",
"addres" : "Example"
}
I would like to change an "_id" of my worker to its "identifiaction id" from collection "groups"
So my worker should look like:
{
"_id" : ObjectId("6224ec342c2d7202b9ad9af6"),
"id_worker" : 180,
"id_boss" : 100,
"hired" : ISODate("2005-02-20T00:00:00Z"),
"id_group" : ObjectId("6224ebe12c2d7202b9ad9af1")
}
I have query like this. When i use print it shows list of my workers with name of the group. How to change it to modify this collection? use update?
var workers = db.workers.find();
while (workers.hasNext()) {
worker = workers.next();
group = db.groups.findOne({"id_group": worker.id_group});
print(group.name);
}
Try this:
db.workers.aggregate([
{
$lookup: {
from: "groups",
localField: "id_group",
foreignField: "id_group",
as: "group"
}
},
{
$project: {
id_worker: 1,
id_boss: 1,
hired: 1,
id_group: { $first: "$group.name" }
}
}
])
Mongo Playground
and think you in advance for the help. I have recently started using mongoDB for some personal project and I'm interested in finding a better way to query my data.
My question is: I have the following collection:
{
"_id" : ObjectId("5dbd77f7a204d21119cfc758"),
"Toyota" : {
"Founder" : "Kiichiro Toyoda",
"Founded" : "28 August 1937",
"Subsidiaries" : [
"Lexus",
"Daihatsu",
"Subaru",
"Hino"
]
}
}
{
"_id" : ObjectId("5dbd78d3a204d21119cfc759"),
"Volkswagen" : {
"Founder" : "German Labour Front",
"Founded" : "28 May 1937",
"Subsidiaries" : [
"Audi",
"Volkswagen",
"Skoda",
"SEAT"
]
}
}
I want to get the object name for example here I want to return
[Toyota, Volkswagen]
I have use this method
var names = {}
db.cars.find().forEach(function(doc){Object.keys(doc).forEach(function(key){names[key]=1})});
names;
which gave me the following result:
{ "_id" : 1, "Toyota" : 1, "Volkswagen" : 1 }
however, is there a better way to get the same result and also to just return the names of the objects. Thank you.
I would suggest you to change the schema design to be something like:
{
_id: ...,
company: {
name: 'Volkswagen',
founder: ...,
subsidiaries: ...,
...<other fields>...
}
You can then use the aggregation framework to achieve a similar result:
> db.test.find()
{ "_id" : 0, "company" : { "name" : "Volkswagen", "founder" : "German Labour Front" } }
{ "_id" : 1, "company" : { "name" : "Toyota", "founder" : "Kiichiro Toyoda" } }
> db.test.aggregate([ {$group: {_id: null, companies: {$push: '$company.name'}}} ])
{ "_id" : null, "companies" : [ "Volkswagen", "Toyota" ] }
For more details, see:
Aggregation framework
$group
Accumulator operators
As a bonus, you can create an index on the company.name field, whereas you cannot create an index on varying field names like in your example.
I am new to MongoDB so this is probably a basic question (hopefully). I currently have 10 million records with 410 fields loaded in a mongodb collection like so:
{
"_id" : ObjectId("........"),
"AddressID" : 123455,
"IndividualId" : 1,
"personfirstname" : "FirstName",
"personmiddleinitial" : "M",
"personlastname" : "LastName",
"etc": "....."
}
I need to wrap all of this data into an embedded document like so:
{
"_id" : ObjectId("........"),
"data" : {
"AddressID" : 123455,
"IndividualId" : 1,
"personfirstname" : "FirstName",
"personmiddleinitial" : "M",
"personlastname" : "LastName",
"etc": "....."
}
I don't necessarily need to update this data in-place but that would be nice. If I need to export this data somehow specifying the new format and then re-import the new, updated data that is fine. Performing this via the MongoDB shell would be ideal.
As suggested by chridam within comments you can execute the following aggregation pipeline:
db.collectionName.aggregate([
{ $project: { _id: "$_id", data: "$$ROOT" } },
{ $out: "newCollectionName" }
]);
This way you have the _id field both at root level and in the data object. Thus, you can execute a massive update to unset the second one:
db.newCollectionName.updateMany(
{},
{ $unset: { "data._id": "" } }
);
Finally, you can drop the first collection and rename the second to restore the original name on the updated collection:
db.collectionName.drop();
db.newCollectionName.rename("collectionName");
This approach fully works within the database, avoiding fetching any of your 10 million documents.
You can simply do this in the shell with the following
db.test.find().forEach(function(doc){
doc = { _id: doc._id, data: doc };
delete doc.data._id;
db.test.save(doc);
});
For example, if we insert the following documents:
> db.test.insertMany([
... {
... _id: ObjectId("5a91af8908e17c5997e03b7e"),
... field1: false,
... field2: 0,
... field3: "No"
... },
... {
... _id: ObjectId("5a91afbc08e17c5997e03b7f"),
... field1: true,
... field2: 1,
... field3: "Yes"
... }])
{
"acknowledged" : true,
"insertedIds" : [
ObjectId("5a91af8908e17c5997e03b7e"),
ObjectId("5a91afbc08e17c5997e03b7f")
]
}
Then run:
db.test.find().forEach(function(doc){
doc = { _id: doc._id, data: doc };
delete doc.data._id;
db.test.save(doc);
});
Our documents now look like this:
> db.test.find().pretty()
{
"_id" : ObjectId("5a91af8908e17c5997e03b7e"),
"data" : {
"field1" : false,
"field2" : 0,
"field3" : "No"
}
}
{
"_id" : ObjectId("5a91afbc08e17c5997e03b7f"),
"data" : {
"field1" : true,
"field2" : 1,
"field3" : "Yes"
}
}
I have a Mongo collection the consists of a document and a nested object describing what collections the document is in and when it was added. I would like to remove key-value pairs from a nested object based on a condition, e.g. is the value (a date) before 1-1-2016.
Example:
{
"_id" : ObjectId("581214940911ad3de98002db"),
"collections" : {
"c01" : ISODate("2016-10-27T15:52:04.512Z"),
"c02" : ISODate("2015-11-21T16:06:06.546Z")
}
}
needs to become
{
"_id" : ObjectId("581214940911ad3de98002db"),
"collections" : {
"c01" : ISODate("2016-10-27T15:52:04.512Z"),
}
}
One alternative would be to change the schema to something like this:
{
"_id" : ObjectId("581214940911ad3de98002db"),
"collections" : [
{
"id": "c01",
"date": ISODate("2016-10-27T15:52:04.512Z")
},
{
"id": "c02",
"date" : ISODate("2015-11-21T16:06:06.546Z")
}
]
}
in which case removing a document from a would be easy. I am a bit reluctant to do that because it would complicate some of the other queries I would like to support. Thanks!
I prefer the second structure for your schema
{
"_id" : ObjectId("581214940911ad3de98002db"),
"collections" : [
{
"id": "c01",
"date": ISODate("2016-10-27T15:52:04.512Z")
},
{
"id": "c02",
"date" : ISODate("2015-11-21T16:06:06.546Z")
}
]
}
then able to remove from collections like this
db.collectionName.update(
{ },// if you want can add query for specific Id {"_id" : requestId},
{ $pull: { collections: { date: {$lt: yourDate} } } }, // if need can convert iso date string like: new Date(yourDate).toISOString()
{ multi: true }
)
I create players the following way.
Players.insert({
name: name,
score: 0,
items: [{'name': 0}, {'name2': 0}...]
});
How do I increment the score in a specific player and specific item name (upserting if necessary)?
Sorry for the terrible wording :p
Well, the answer is - as in life - to simplify the problem by breaking it up.
And to avoid arrays in mongoDB - after all, objects can have as many keys as you like. So, my structure became:
{
"_id": <id>,
"name": <name>,
"score": <score>,
"items": {}
}
And to increment the a dynamic key in items:
// create your update skeleton first
var ud = { $inc: {} };
// fill it in
ud.$inc['item.' + key] = value;
// call it
db.Players.update(player, ud, true);
Works a charm :)
Lets say you have:
{
"_id" : ObjectId("5465332e6c3e2eeb66ef3683"),
"name" : "Alex",
"score" : 0,
"items" : [
{
"food" : 0
}
]
}
To update you can do:
db.Players.update({name: "Alex", "items.food": {$exists : true}},
{$inc: {score: 1, "items.$.food": 5}})
Result:
{
"_id" : ObjectId("5465332e6c3e2eeb66ef3683"),
"name" : "Alex",
"score" : 1,
"items" : [
{
"food" : 5
}
]
}
I am not sure you can upsert if the document doesn't exist because of the positional operator needed to update the array.