I'm look for a query in T-Sql to count the number of consecutive dates, backwards where the pop is the same, starting at the latest date and stopping when there is a gap in the date.
This is an example of the data:
Name village Population Date
Rob village1 432 01/07/2013
Rob village2 432 30/06/2013
Rob village3 432 29/06/2013
Rob village3 432 28/06/2013
Rob village3 432 27/06/2013
Rob village3 430 26/06/2013
Rob village3 430 25/06/2013
Rob village3 430 24/06/2013
Rob village3 430 23/06/2013
Rob village3 425 22/06/2013
Rob village3 422 21/06/2013
Rob village3 422 20/06/2013
Rob village3 411 19/06/2013
Harry Village1 123 01/07/2013
Harry Village2 123 30/06/2013
Harry Village3 122 29/06/2013
Pat Village1 123 01/07/2013
Pat Village2 123 30/06/2013
Pat Village3 123 29/06/2013
Pat Village4 100 20/06/2013
Tom Village1 123 01/07/2013
Tom Village2 123 30/06/2013
Tom Village3 123 29/06/2013
Tom Village4 123 28/06/2013
I would expect to get the following results:
Rob 5
Harry 2
Pat 3
Tom 3
The data should be more complex, but there will be 1000's of rows, 100's per person and groups of pop with consecutive dates, but i only want the first set of consecutive dates with the same pop, from the latest downwards.
with dd as
(
select distinct * from table
);
select name, max(count) + 1
from
(
select t1.name, t1.village, t1.pop, count(*) as count
from dd t1
join dd t2
on t2.village = t1.village
and t2.pop = t1.pop
and t2.pop = t1.pop
and t2.date = dateadd(day,-1,t1.date)
group by t1.name, t1.village, t1.pop
) dates
group by name
;with a as
(
select name, village, population, date, cast(date as datetime) + dense_rank() over(partition by Population, name order by date desc) grp
from <your table>
), b as
(
select name, village, population, date, dense_rank() over (partition by name order by grp desc) rk
from a
)
select name, count(distinct date) from b
where rk = 1
group by name
Related
I am using PostgreSQL and I am trying to calculate the percentage change for two values in the same column and group them by the name column and I am having trouble.
Suppose I have the following table:
name
day
score
Allen
1
87
Allen
2
89
Allen
3
95
Bob
1
64
Bob
2
68
Bob
3
75
Carl
1
71
Carl
2
77
Carl
3
80
I want the result to be the name and the percentage change for each person between day 3 and day 1. So Allen would be 9.2 because from 87 to 95 is a 9.2 percent increase.
I want the result to be:
name
percent_change
Allen
9.2
Bob
17.2
Carl
12.7
Thanks for your help.
Try this...
with dummy_table as (
select
name,
day,
score as first_day_score,
lag(score, 2) over (partition by name order by day desc) as last_day_score
from YOUR_TABLE_NAME
)
select
name,
(last_day_score - first_day_score) / first_day_score::decimal as percentage_change
from dummy_table where last_day_score is not null
Just replace YOUR_TABLE_NAME. There are likely more performant and fancier solutions, but this works.
You can try with lag function, something like this:
select name, day, score, 100*(score - lag(score, 1) over (partition by name order by day))/(lag(score, 1) over (partition by name order by day)) as growth_percentage
I'm new to this forum and I hope to find my solution about my problem.
I have this table :
name time points car date
Daniel | 55s | 210 | red |20/01/2018
Daniel | 45s | 250 | green |21/01/2018
Julie | 54s | 220 | red |19/01/2018
Julie | 33s | 150 | yellow|22/01/2018
and I wish to sort it like this
name time points car date
Daniel | 45s | 250 |green |21/01/2018
Julie | 54s | 220 |red |19/01/2018
first sorting by points, than sorting by time and group by name (optional the count)
I use this
SELECT NAME, MAX(POINTS) POINTS, MAX(TIME) TIME, MAX(CAR) CAR, MAX(DATE) DATE
FROM ( SELECT A.* FROM test A LEFT OUTER JOIN test B ON A.NAME=B.NAME AND
A.POINTS<B.POINTS AND A.TIME>B.TIME WHERE B.NAME IS NULL ) as sub GROUP BY NAME
and I get this :
name POINTS TIME CAR DATE
Daniel 250 45 green 2018-01-21
Julie 220 54 yellow 2018-01-22
Julie should have car=red & 2018-01-19
For Daniel it looks good
how can I get thise values (car & date) ?
thanks
Nico
You could give this a shot. It contains the table against itself and gets only records with the highest points and lowest time.
SELECT NAME, MAX(POINTS) POINTS, MAX(TIME) TIME
FROM
(
SELECT A.* FROM test A
LEFT OUTER JOIN test B ON A.NAME=B.NAME AND A.POINTS<B.POINTS AND A.TIME>B.TIME
WHERE B.NAME IS NULL
) GROUP BY NAME
For additional, try this:
SELECT * FROM
(
SELECT OUTERTEST.*,
#row_num := IF(#prev_value=OUTERTEST.name,#row_num+1,1) AS RowNumber,
#prev_value := OUTERTEST.name
FROM (SELECT * FROM TEST ORDER BY NAME, TEST.POINTS DESC, TEST.TIME ASC) OUTERTEST, (SELECT #row_num := 1, #prev_value := '') x
) A
WHERE A.ROWNUMBER=1
I did more test with this table
id name time points
1 Daniel 55 1140
2 Judie 54 1144
3 Judie 33 1028
4 Daniel 45 1180
5 Judie 53 1148
I apply this request
SELECT NAME, MAX(POINTS) POINTS, sub.TIME FROM (SELECT * FROM Testpoint ORDER BY POINTS DESC, TIME ASC) AS sub
GROUP BY sub.name
I have the max point for each name but the time is not the right one
name POINTS time
Daniel 1180 55
Judie 1148 54
Judie should have 53 for time and not 54
What I did wrong?
thankyou
Nico
I have 3 columns. SSN|AccountNumber|OpenDate
1 SSN may have multiple AccountNumbers
Each AccountNumber has a corresponding OpenDate
In my list I have many SSN's, each containing several account numbers which may have been opened on different days.
I want the results of my query to be SSN|earlest OpenDate|AccountNumber that corresponds with the earliest opendate.
I'm dealing with about 200,000 records.
EDIT: First I did
select SSN, min(OpenDate), AcctNumber from Table Group By SSN, AccountNumber
but that didn't quite give me the correct data.
The raw data gives me something like this:
SSN | AcctNumber | OpenDate
---------------------------
10 101 Jan
10 102 Feb
10 103 Mar
Where I got 10, Jan, and AccNumber 102 which is not the account number that is associated with Jan OpenDate After looking at others, I found that the account number I got was just one of the account numbers associated with that SSN rather than the one that corresponds with the min(OpenDate)
WITH CTE AS ( SELECT SSN, AcctNumber, OpenDate, ROW_NUM() OVER (PARTITION BY SSN ORDER BY OpenDate DESC) AS RN ) SELECT SSN, AcctNumber, OpenDate FROM CTE WHERE RN=1;
If your table is like this:
SSN | AcctNumber | OpenDate
---------------------------
10 101 April
10 101 May
10 102 April
20 201 June
20 201 July
Do you want your query to return this?
SSN | AcctNumber | OpenDate
---------------------------
10 101 April
10 102 April
20 201 June
Then you would use this query:
select ssn, min(OpenDate), acctNumber from tbl group by ssn, acctNumber
You can try this..
select SSN , AcctNumber, OpenDate
from (SELECT SSN , AcctNumber, OpenDate
, ROW_NUMBER() OVER ( PARTITION BY SSN, ORDER BY OpenDate ASC ) AS RN
FROM table) AS temp
WHERE temp.RN= 1
SELECT
distinct
HRM_Employee.EmployeeId EmployeeXId,
([HRM_Employee].[FirstName] +' '+ISNULL([HRM_Employee].[MiddleName],' ')+' '+ISNULL([HRM_Employee].[LastName],' ')) AS FirstName
-- ,[FirstName]
,[HRM_Employee].[MiddleName]
,[HRM_Employee].[LastName]
,[HRM_Employee].[Code]
,[HRM_Employee].[UserName]
,[HRM_Employee].[Password]
,[HRM_Employee].[DateOfBirth]
,[HRM_Employee].[OriginalBirthDate]
,[HRM_Employee].[Gender]
,[HRM_Employee].[BloodGroup]
,[HRM_Employee].[Height]
,[HRM_Employee].[MaritalStatus]
,[HRM_Employee].[DateOfMarriage]
,[HRM_Employee].[IdentificationMark1]
,[HRM_Employee].[IdentificationMark2]
,[HRM_Employee].[Religion]
,(SELECT [A].[FirstName] +' '+ [A].[MiddleName] +' '+ [A].[LastName]
FROM [dbo].[HRM_Employee] [A] WHERE [A].EmployeeId = [HRM_Transfer].[ReportingOfficerXId]
) [PersonInCharge]
,[HRM_Department].[Name] [DepartmentName]
,[HRM_Branch].[Name] [BranchName]
,[HRM_Division].[Name] [DivisionName]
,[HRM_Designation].[Name] [DesignationName]
,HRM_Transfer.TransferDate
from HRM_Employee
LEFT join [dbo].[HRM_Division]
ON [HRM_Employee].DivisionXId = [HRM_Division].DivisionId
JOIN [dbo].[HRM_Designation]
ON [HRM_Employee].DesignationXId = [HRM_Designation].DesignationId
JOIN [HRM_Department]
ON [HRM_Employee].[DepartmentXId] = [HRM_Department].[DepartmentId]
JOIN [HRM_Branch]
ON [HRM_Employee].[BranchXId] = [HRM_Branch].[BranchId]
INNER JOIN HRM_Transfer
ON HRM_Transfer.EmployeeXId=HRM_Employee.EmployeeId
WHERE
Convert(varchar(11),HRM_Transfer.TransferDate,103) <=Convert(varchar(11), getdate(),103)
END
When I excecute this i got the output as follows
EmployeeXId FirstName TransferDate
34 Ambarish V 2012-08-09 00:00:00.000
54 Anil N P 2012-08-09 00:00:00.000
55 Ann Rose Abraham 2012-08-08 00:00:00.000
55 Ann Rose Abraham 2012-08-09 00:00:00.000
74 Anees M S 2012-08-09 00:00:00.000
From this I want to display data with latest Transfer date only. That is in EmployeeId 55 I need to display data with Transfer date 2012-08-09 00:00:00.000 only. What modification is I want to do in above SP to get required answer?. Please help me to solve this.
Group by EmployeeXId and select MAX(TransferDate).
Below is a table.
stu_id meet_doc_id doc_name stu_name dob value date
101 0104 AD AM 15/06/1950 LMDO 2011-02-15
101 0105 AD AM 15/06/1950 CLEAR 2011-02-18
101 0106 AD AM 15/06/1950 CLEAR 2011-02-25
102 0107 AD AK 12/08/1987 CLEAR 2011-03-28
102 0108 AD AK 12/08/1987 LDMO 2011-04-29
103 0109 PK LMP 13/07/1970 CLEAR 2011-03-28
103 0110 PK LMP 13/07/1970 CLEAR 2011-05-12
What will be the resulting query if I expect to see a result set of
stu_id meet_doc_id doc_name stu_name dob value date
101 0104 AD AM 15/06/1950 LMDO 2011-02-15
102 0107 AD AK 12/08/1987 CLEAR 2011-03-28
103 0110 PK LMP 13/07/1970 CLEAR 2011-05-12
Your table looks extremely un-normalised with lots of repeating groups but I think you need
;WITH CTE
AS (SELECT stu_id,
meet_doc_id,
doc_name,
stu_name,
dob,
value,
date,
ROW_NUMBER () OVER (PARTITION BY stu_id ORDER BY meet_doc_id) AS
RN
FROM YourTable)
select stu_id,
meet_doc_id,
doc_name,
stu_name,
dob,
value,
date
FROM CTE
WHERE RN = 1