scala override trait with generic method - scala

I have 3 classes:
class AClass
class Base { val a = "a" }
class BaseOne extends Base { val b = "b" }
class BaseTwo extends Base { val c = "c" }
I want to extend a trait which contains a generic method, I'm not allowed to change the trait
trait Converter {
def toAClass[T <: Base](e: T): AClass
def fromAClass[T <: Base](s: AClass): T
}
I want to extend it in several different objects
object ConverterBaseOne extends Converter {
// ERROR
override def toAClass(e: BaseOne) : AClass = { printf(e.b) } // b is known
override def fromAlcass(a: AClass) : BaseTwo = {....}
}
I know there is a way to do it with class parameter: trait Converter[T <: Base]
and also saw this post https://stackoverflow.com/a/4627144/980275
I'm asking if there is a solution without changing the trait ???
Thank you

You are changing the signature of the method, so it is not a legal override, it would break polymorphism. You must either parametrize the Converter trait or use another method name.
You can, however, receive a Base object and cast it, but it is not recommended practice since it may result in an exception at runtime:
object ConverterBaseOne extends Converter {
override def toAClass[T <: Base](e: T): AClass = {
printf(e.asInstanceOf[BaseOne].b)
// ...
}
}

Related

Scala generics - simplify number of generic arguments

I have this class defined as follows:
abstract class MyHelper[T, E <: BaseHelper[T]](implicit clsTag: ClassTag[E]) {
val all: Array[E]
def parse(t: T): Try[E] = { ... }
}
and this is how I am using it:
trait IntHelper extends BaseHelper[Int] {}
object MyIntHelper extends MyHelper[Int, IntHelper] { }
How do I simplify MyHelper class definition to accept only the inner generic type T instead of passing two types, E and T?
There's no need for you to directly enforce T in MyHelper since you're only using E itself.
So something like this should be fine.
abstract class MyHelper[E <: BaseHelper[_]](implicit clsTag: ClassTag[E]) {
val all: Array[E]
}
A more fleshed out example looks like:
trait BaseHelper[T] {}
trait IntHelper extends BaseHelper[Int]
abstract class MyHelper[E <: BaseHelper[_]](implicit clsTag: ClassTag[E]) {
val all: Array[E]
}
object MyIntHelper extends MyHelper[IntHelper] {
override val all = Array(new IntHelper{}, new IntHelper{})
}
// just to ensure it works
MyIntHelper.all

Scala abstract types implement trait that extends from generic trait

I am new to scala and thus my question might be due to a lack of understanding of abtract types and traits.
I currently have a Sensor trait which is generic and defines a value and newValue method.
trait Sensor[T] {
def value: T
def newValue(): Unit = {}
}
One concrete implementation of Sensor is MemorySensor, which just uses a variable to store the value and has a set value method which sets the value and fires the newValue method.
class MemorySensor[T] extends Sensor[T] {
var internalValue: T = null.asInstanceOf[T]
def setValue(newVal: T): Unit = {
internalValue = newVal
newValue()
}
def value: T = internalValue
}
There is also an AbstractSO (SO = subject + Observer) class which uses abstract types to implement Subject/Observer pairs.
class AbstractSO {
type O <: AbstractObserver
type S <: AbstractSubject
trait AbstractSubject {
this: S =>
def register(observer: O) = {
//we could use mutable collection here too
observers = observer :: observers
}
var observers: List[O] = List[O]()
def notifyObservers() = {
observers.foreach(o => o.notifyObserver(this))
}
}
trait AbstractObserver {
def notifyObserver(subject: S)
}
}
One example of a concrete Subject/Observer is the ActionSO
object ActionSO extends AbstractSO {
type S = ActionSubject
type O = ActionObserver
trait ActionSubject extends AbstractSubject {
def action() = {
notifyObservers()
}
}
trait ActionObserver extends AbstractObserver {
override def notifyObserver(actionSubject: ActionSubject) = {
println("action observer called")
}
}
}
Now I want to implement a concrete Subject/Observer-Pair for Sensors with the requirement that the SensorSubject should be a mixin trait for sensors.
So I guess the target would be to use the SensorSubject like this:
val x = new MemorySensor[Int] with SensorSubject[Int]
However whatever I try to implement the SensorSO, I always get either some kind of "illegal inheritance" error or "self-type does not conform to..".
As far as I know this cannot be done without creating an extra class that extends from AbstractSO, but uses generic types. (but I don´t know how this helps me to achieve my target anyways)
It would be very nice if someone could help me out!
EDIT:
As SergGr wanted to see my SensorSubject (which is what I don´t know how to implement, I will post one of my various tries)
Note however that this does NOT COMPILE
object SensorSO extends AbstractSensorSO {
//TODO: i shouldn´t use "Any" here - this won´t work
override type S = SensorSubject[Any]
trait SensorSubject[T] extends AbstractSensorSubject with Sensor[T] {
this: S => //this generates problems as well
}
}
Here is my AbstractSensorSO
class AbstractSensorSO extends AbstractSO {
type S <: AbstractSensorSubject
type O <: AbstractSensorObserver
trait AbstractSensorSubject extends AbstractSubject {
this: S =>
}
trait AbstractSensorObserver extends AbstractObserver {
}
}
As you can see the AbstractSensorSO basically doesn´t do anything, I just added it because it was mentioned in a hint to the solution that one needs an subclass of AbstractSO, before creating the concrete SensorSO object.
One problem I am facing is that the Sensor trait is generic so for the SensorSubject to use the Sensor trait AFAIK i have to make the SensorSubject generic too.
Normally this wouldn´t be a problem, but as i use abstract types I would have to define the "S" type in the SensorSO with generics too (e.g.
type S = SensorSubject[T]
But as the generic type "T" is not known in that context it obviously gives an error (as the generic "T" is only available the context of the generic trait SensorSubject)
If I try to drop the generic paramater when defining the type S, I also get an error message that the generic type parameter is missing.
And just writing
type S = SensorSubject[Any]
doesn´t solve the problem either
EDIT2:
To clarify what my target is:
SensorSubject should be an Mixin Trait, such that i can use normal Sensors(not only MemorySensors) and that if I want I can add "with SensorSubject[Int]" to the creation of the Sensor and then it functions as a SensorSubject
Which means i can register an observer and the observer is notified when i change the value of the Sensors(that now functions as SensorSubject)
Here is an example how I would like to use the SensorSubject[T] Trait:
//creating a sensor WITH the SensorSubject Trait
val sensorWithSubject= new MemorySensor[Int] with SensorSubject[Int]
sensorWithSubject.registerObserver(..)
//creating a normal Sensor WITHOUT SensorSubject
val normalMemSensor = new MemorySensor[Int]
You didn't provide any example of expected usage so my guess might be wrong. Still here is my attempt:
trait Sensor[T] {
def value: T
def newValue(): Unit = {}
}
class MemorySensor[T] extends Sensor[T] {
var internalValue: T = null.asInstanceOf[T]
def setValue(newVal: T): Unit = {
internalValue = newVal
newValue()
}
def value: T = internalValue
}
//////////////////////////////////
trait AbstractSubject[S <: AbstractSubject[S, O], O <: AbstractObserver[S, O]] {
this: S =>
def register(observer: O) = {
//we could use mutable collection here too
observers = observer :: observers
}
private var observers: List[O] = List[O]()
def notifyObservers() = {
observers.foreach(o => o.notifyObserver(this))
}
}
trait AbstractObserver[S <: AbstractSubject[S, O], O <: AbstractObserver[S, O]] {
def notifyObserver(subject: S)
}
//////////////////////////////////
trait SensorSubject[T, S <: SensorSubject[T, S, O], O <: SensorObserver[T, S, O]] extends Sensor[T] with AbstractSubject[S, O] {
this: S =>
}
trait SensorObserver[T, S <: SensorSubject[T, S, O], O <: SensorObserver[T, S, O]] extends AbstractObserver[S, O]
//////////////////////////////////
class MemorySensorSubject[T] extends MemorySensor[T] with AbstractSubject[MemorySensorSubject[T], MemorySensorObserver[T]] {
override def setValue(newVal: T): Unit = {
super.setValue(newVal)
notifyObservers()
}
}
trait MemorySensorObserver[T] extends AbstractObserver[MemorySensorSubject[T], MemorySensorObserver[T]]
and with that you can do
def test(): Unit = {
val sensor = new MemorySensorSubject[Int]
val observer = new MemorySensorObserver[Int] {
override def notifyObserver(subject: MemorySensorSubject[Int]): Unit = {
println(s"New value of $subject is ${subject.value}")
}
}
sensor.register(observer)
sensor.setValue(42)
}
and the output will be
New value of so.Main$MemorySensorSubject#363ee3a2 is 42
Probably the most important thing here is that MemorySensorSubject is an explicitly named type that thus can be used as S in F-bound generic constraint

Extract parameterised type from self in scala

I have class with parameterised type
abstract class Worker[T] {
def conf1: ...
def conf2: ...
def doWork ...
}
abstract class SpecializedWorker[T: TypeTag] extends Worker[T] {
//some behavior overriden (used fields from Trait that i want create)
}
I want to create trait that can be mixed to Worker.
trait Extension {
self: Worker[_] =>
def someParameter: ... // only several workers can have that. thats why i need trait
def produceSpecializedWorker = new SpecializedWorker[???]() {}
}
How to extract type information from self to replace ???
Here is a way to extract a type parameter:
trait Extension {
self: Worker[_] =>
def mkSpWorker[T](implicit ev: this.type <:< Worker[T]) = new SpecializedWorker[T]() {}
}
But I wouldn't recommend that :) You could define a type member in Worker that can be used in Extension.
abstract class Worker[T] {
type TT = T
}
trait Extension {
self: Worker[_] =>
def mkSpWorker = new SpecializedWorker[TT]() {}
}
Or you could just consider giving Extension a type parameter. It's not such a big deal, I think.

Add a trait to parametric type in a class

I have a library where an abstract class Base[T] is over a type T supplied by the user. There are many specific Base[T] sub-classes, some are over types T and S, like Specific[T, S], but this is irrelevant. The user might specify any T of course while creating and instance, but I want to treat it as T with a trait AdditionalAbilities or in other words I want to 'gift' the user's type with AdditionalAbilities. How can I do that in Scala? I hope the title is correct for this question.
Example (might not be syntactically correct)
class Specific[T **with trait Additional**]() extends Base[T](){
def doSomething() : T = {
val something = new T()
something.ability(2)
println(something.additional)
something
}
}
trait Additional{
var additional : Integer
def ability(i : Integer) : Unit = {
additional = i
}
}
Would work with any T.
When you define a parametric class you can require the parameter type to descend from a certain type:
trait AdditionalAbilities {
def doStuff(): Unit = println("Hey There")
}
object NoAbility extends AdditionalAbilities {
override def doStuff(): Unit = ()
}
abstract class Base[T] { ... }
class Specific[T <: AdditionalAbilities] extends Base[T] {
def f(t: T): Unit = t.doStuff()
}
Then when you try to instantiate a Specific type:
scala> new Specific[Int] {}
<console>:13: error: type arguments [Int] do not conform to class Specific's type parameter bounds [T <: AdditionalAbilities]
scala> val b = new Specific[NoAbility.type] {}
b: Specific[NoAbility.type] = $anon$1#517cd4b
scala> b.f(NoAbility)
//did nothing
Also, if you want to add a behaviour to an existing concrete class, you can do so at the time of instantiation:
trait CoolAbilities { def doStuff(): Unit = println("Hey there") }
class A { }
scala> val a = new A with CoolAbilities
a: A with CoolAbilities = $anon$1#6ad3381f
scala> a.doStuff()
Hey there
Perhaps implicit classes could help? Implicit classes allow you to add functionality to an existing type without needing to modify the existing type, or be the one instantiating it (so that you could mix in a trait).
The following compiles, and prints: 3
class Specific[T] {
implicit class TAdditional(t: T) {
var additional: Integer = 0
def ability(i: Integer) = {
additional = i
}
}
def doSomething(t: T) = {
doSomethingAdditional(t)
}
private def doSomethingAdditional(t: TAdditional) = {
t.ability(3)
println(t.additional)
}
}
val s = new Specific[Int]
s.doSomething(5)
Note: We need to do something to make sure we are accessing the same instance
of TAdditional, that's why I made the private doSomethingAdditional method that takes a TAdditional as an argument. If we call ability and additional in 'doSomething', separate instances of TAdditional would be created when we try to access #ability and #additional, and '0' would be printed.

How can I return a generic class from a method?

I'm trying to write a method "get" that will return a class. But instead of a concrete class I want to be able to return any subclass of a certain concrete class. Here is the concrete case:
def get(): Class[Base] = {
classOf[Base]
}
Now I want to turn this into a generic method, something like this:
def get[T <: Base](): Class[T] = {
classOf[Derived]
}
How can I do this?
For completeness:
class Base
class Derived extends Base
This should work:
def get(): Class[_ <: Base] = {
classOf[Derived]
}