I have a word template and I want to create doc file from that, also I want to replace add data in place of bookmarks present in the template.
I have been able to create a doc file, but I am not able to understand, how to add data in place of bookmarks?
My code till now:
private void CreateSampleWordDocument()
{
string sourceFile = Path.Combine(Environment.CurrentDirectory, "GeneralWelcomeLetter.dotx");
string destinationFile = Path.Combine(Environment.CurrentDirectory, "Sample.docx");
try
{
File.Copy(sourceFile, destinationFile, true);
WordprocessingDocument document = WordprocessingDocument.Open(destinationFile, true);
document.ChangeDocumentType(DocumentFormat.OpenXml.WordprocessingDocumentType.Document);
MainDocumentPart mainPart = document.MainDocumentPart;
DocumentSettingsPart documentSettingPart1 = mainPart.DocumentSettingsPart;
AttachedTemplate attachedTemplate1 = new AttachedTemplate() { Id = "relationId1" };
documentSettingPart1.Settings.Append(attachedTemplate1);
}
catch
{
}
}
Now to add data from database in place of bookmarks?
Related
I have made an application that fills wordfiles with customxmlparts now I am trying to put text into a textfield, but it has HTML in it and I want it to show the styling of it. I tried converting it to rich text format but that just gets pasted in the word file. Here is an example of the code:
var taskId = Guid.NewGuid();
var tempFilePath = $"{Path.GetTempPath()}/{taskId}";
using (var templateStream = new FileStream($"{tempFilePath}.docx", FileMode.CreateNew))
{
templateStream.Write(template, 0, template.Length);
// 1. Fill template.
using (WordprocessingDocument doc = WordprocessingDocument.Open(templateStream, true))
{
MainDocumentPart mainDocument = doc.MainDocumentPart;
if (mainDocument.CustomXmlParts != null)
{
mainDocument.DeleteParts<CustomXmlPart>(mainDocument.CustomXmlParts);
}
CustomXmlPart cxp = mainDocument.AddCustomXmlPart(CustomXmlPartType.CustomXml);
foreach (var line in data.Lines)
{
if (line.MoreInfo != null && line.MoreInfo != " ") {
}
}
var xmlData = ObjectToXml(data);
using (var stream = GenerateStreamFromString(tempFilePath, xmlData))
{
cxp.FeedData(stream);
}
mainDocument.Document.Save();
}
}
You can't just write the HTML formatted text into a DOCX field, you would need to convert it into a WordprocessingML format.
However, there is another way that you could try and that is to insert an "AltChunk" element. That element represents a sort of like a placeholder which can reference a HTML file and then when the DOCX file is opened in MS Word, it will make that HTML to WordprocessingML conversion for you. For details see: How to Use altChunk for Document Assembly
Alternatively you could use some third party, like GemBox.Document, which can make that HTML to WordprocessingML conversion for you.
For example check this Set Content example:
// Set content using HTML tags
document.Sections[0].Blocks[4].Content.LoadText(
"Paragraph 5 <b>(part of this paragraph is bold)</b>", LoadOptions.HtmlDefault);
i would like to access some built in properties(like author,last modified date,etc.) of an open xml word doc file. i would like to use open xml sdk2.0 for this purpose. so i wonder if there is any class or any way i could programmatically access these builtin properties.
An explanation of the following method can be found here, but pretty much you need to pass in the properties that you want to get out of the core.xml file to this method and it will return the value:
public static string WDRetrieveCoreProperty(string docName, string propertyName)
{
// Given a document name and a core property, retrieve the value of the property.
// Note that because this code uses the SelectSingleNode method,
// the search is case sensitive. That is, looking for "Author" is not
// the same as looking for "author".
const string corePropertiesSchema = "http://schemas.openxmlformats.org/package/2006/metadata/core-properties";
const string dcPropertiesSchema = "http://purl.org/dc/elements/1.1/";
const string dcTermsPropertiesSchema = "http://purl.org/dc/terms/";
string propertyValue = string.Empty;
using (WordprocessingDocument wdPackage = WordprocessingDocument.Open(docName, true))
{
// Get the core properties part (core.xml).
CoreFilePropertiesPart corePropertiesPart = wdPackage.CoreFilePropertiesPart;
// Manage namespaces to perform XML XPath queries.
NameTable nt = new NameTable();
XmlNamespaceManager nsManager = new XmlNamespaceManager(nt);
nsManager.AddNamespace("cp", corePropertiesSchema);
nsManager.AddNamespace("dc", dcPropertiesSchema);
nsManager.AddNamespace("dcterms", dcTermsPropertiesSchema);
// Get the properties from the package.
XmlDocument xdoc = new XmlDocument(nt);
// Load the XML in the part into an XmlDocument instance.
xdoc.Load(corePropertiesPart.GetStream());
string searchString = string.Format("//cp:coreProperties/{0}", propertyName);
XmlNode xNode = xdoc.SelectSingleNode(searchString, nsManager);
if (!(xNode == null))
{
propertyValue = xNode.InnerText;
}
}
return propertyValue;
}
You can also use the packaging API:
using System.IO.Packaging.Package;
[...]
using (var package = Package.Open(path))
{
package.PackageProperties.Creator = Environment.UserName;
package.PackageProperties.LastModifiedBy = Environment.UserName;
}
That works also for other open XML formats like power point.
package.Save();
Then
package.closed;
I think that Is the best way.
I have written
List<Attachment> lstAttachment = new List<Attachment>();
//Check if any error file is present in which case it needs to be send
if (new FileInfo(Path.Combine(errorFolder, errorFileName)).Exists)
{
Attachment unprocessedFile = new Attachment(Path.Combine(errorFolder, errorFileName));
lstAttachment.Add(unprocessedFile);
}
//Check if any processed file is present in which case it needs to be send
if (new FileInfo(Path.Combine(outputFolder, outputFileName)).Exists)
{
Attachment processedFile = new Attachment(Path.Combine(outputFolder, outputFileName));
lstAttachment.Add(processedFile);
}
Working fine and is giving the expected output.
Basically I am attaching the file to the list based on whether the file is present or not.
I am looking for any other elegant solution than the one I have written.
Reason: Want to learn differnt ways of representing the same program.
I am using C#3.0
Thanks.
Is it looks better?
...
var lstAttachment = new List<Attachment>();
string errorPath = Path.Combine(errorFolder, errorFileName);
string outputPath = Path.Combine(outputFolder, outputFileName);
AddAttachmentToCollection(lstAttachment, errorPath);
AddAttachmentToCollection(lstAttachment, outputPath);
...
public static void AddAttachmentToCollection(ICollection<Attachment> collection, string filePath)
{
if (File.Exists(filePath))
{
var attachment = new Attachment(filePath);
collection.Add(attachment);
}
}
How about a little LINQ?
var filenames = new List<string>()
{
Path.Combine(errorFolder, errorFilename),
Path.Combine(outputFolder, outputFilename)
};
var attachments = filenames.Where(f => File.Exists(f))
.Select(f => new Attachment(f));
I have been using Syncfusion DocIO for generating MS Word documents from my .net applications (winforms). So far I have dealt with plain text and it is fairly straightforward to insert text in a word document template where bookmarks serve as reference points for text insertion.
I am navigating the bookmarks using BookmarksNavigator.MoveToBookmark() . Now I need to insert an image at a bookmark but I am at a loss at how to go about it.
Please help...
Thanks.
Specifically for adding it to a bookmark :
//Move to the specified bookmark
bk.MoveToBookmark(bookmark);
//Insert the picture into the specified bookmark location
bk.DeleteBookmarkContent(true);
// we assume the text is a full pathname for an image file
// get the image file
System.Drawing.Image image = System.Drawing.Image.FromFile(sText);
IWParagraph paragraph = new WParagraph(document);
paragraph.AppendPicture(image);
bk.InsertParagraph(paragraph);
private System.Drawing.Image LoadSignature(string sFileName)
{
string sImagePath = sFileName;
System.Drawing.Image image = System.Drawing.Image.FromFile(sImagePath);
return image;
}
private void MergeSignature(WordDocument doc, string sFile, string sBalise)
{
System.Drawing.Image iSignature = LoadSignature(sFile);
WordDocument ImgDoc = new WordDocument();
ImgDoc.AddSection();
ImgDoc.Sections[0].AddParagraph().AppendPicture(iSignature);
if (iSignature != null)
{
TextSelection ts = null ;
Regex pattern = new Regex(sBalise);
ts = doc.Find(pattern);
if (ts != null)
{
doc.ReplaceFirst = true;
doc.Replace(pattern, ImgDoc, false);
}
}
iSignature.Dispose();
}
See here: https://help.syncfusion.com/file-formats/docio/working-with-mailmerge
1) You should create docx file with name "Template.docx". This file will use as template.
In your docx file create Field of type MergeField.
2) Create MergeFiled with name Image:Krishna
3)
using Syncfusion.DocIO.DLS;
using System.Drawing;
public class Source
{
public Image Krishna { get; set; } = Image.FromFile(#"C:\1.png");
}
and generating code:
public static void Generate()
{
WordDocument doc = new WordDocument("Template.docx");
Source data = new Source();
var dataTable = new MailMergeDataTable("", new Source[] { data });
doc.MailMerge.ExecuteGroup(dataTable);
doc.Save("result.docx");
doc.Close();
}
To load XML files with arbitrary encoding I have the following code:
Encoding encoding;
using (var reader = new XmlTextReader(filepath))
{
reader.MoveToContent();
encoding = reader.Encoding;
}
var settings = new XmlReaderSettings { NameTable = new NameTable() };
var xmlns = new XmlNamespaceManager(settings.NameTable);
var context = new XmlParserContext(null, xmlns, "", XmlSpace.Default,
encoding);
using (var reader = XmlReader.Create(filepath, settings, context))
{
return XElement.Load(reader);
}
This works, but it seems a bit inefficient to open the file twice. Is there a better way to detect the encoding such that I can do:
Open file
Detect encoding
Read XML into an XElement
Close file
Ok, I should have thought of this earlier. Both XmlTextReader (which gives us the Encoding) and XmlReader.Create (which allows us to specify encoding) accepts a Stream. So how about first opening a FileStream and then use this with both XmlTextReader and XmlReader, like this:
using (var txtreader = new FileStream(filepath, FileMode.Open))
{
using (var xmlreader = new XmlTextReader(txtreader))
{
// Read in the encoding info
xmlreader.MoveToContent();
var encoding = xmlreader.Encoding;
// Rewind to the beginning
txtreader.Seek(0, SeekOrigin.Begin);
var settings = new XmlReaderSettings { NameTable = new NameTable() };
var xmlns = new XmlNamespaceManager(settings.NameTable);
var context = new XmlParserContext(null, xmlns, "", XmlSpace.Default,
encoding);
using (var reader = XmlReader.Create(txtreader, settings, context))
{
return XElement.Load(reader);
}
}
}
This works like a charm. Reading XML files in an encoding independent way should have been more elegant but at least I'm getting away with only one file open.
Another option, quite simple, is to use Linq to XML. The Load method automatically reads the encoding from the xml file. You can then get the encoder value by using the XDeclaration.Encoding property.
An example from MSDN:
// Create the document
XDocument encodedDoc16 = new XDocument(
new XDeclaration("1.0", "utf-16", "yes"),
new XElement("Root", "Content")
);
encodedDoc16.Save("EncodedUtf16.xml");
Console.WriteLine("Encoding is:{0}", encodedDoc16.Declaration.Encoding);
Console.WriteLine();
// Read the document
XDocument newDoc16 = XDocument.Load("EncodedUtf16.xml");
Console.WriteLine("Encoded document:");
Console.WriteLine(File.ReadAllText("EncodedUtf16.xml"));
Console.WriteLine();
Console.WriteLine("Encoding of loaded document is:{0}", newDoc16.Declaration.Encoding);
While this may not server the original poster, as he would have to refactor a lot of code, it is useful for someone who has to write new code for their project, or if they think that refactoring is worth it.