This is my code. I am not using Maven or curl.
String encoding = Base64.encodeBase64String((clientId + ":" + clientSecret).getBytes());
encoding = encoding.replaceAll("\n", "");
URL url1 = new URL("https://api.sandbox.paypal.com/v1/oauth2/token");
HttpURLConnection conn = (HttpURLConnection) url1.openConnection();
conn.setRequestMethod("POST");
conn.setRequestProperty("grant_type", "client_credentials");
conn.setRequestProperty("Authorization", "Basic " + encoding);
System.out.println(conn.getResponseCode());
if (conn.getResponseCode() == 500) {
InputStream error = conn.getErrorStream();
BufferedReader er = new BufferedReader(new InputStreamReader(error));
String erLine;
while ((erLine = er.readLine()) != null) {
System.out.println(erLine);
}
}
InputStream content = conn.getInputStream();
BufferedReader in = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = in.readLine()) != null) {
System.out.println(line);
}
conn.disconnect();
OUTPUT:
500
{"name":"INTERNAL_SERVICE_ERROR","information_link":"https://api.sandbox.paypal.com/docs/api/#INTERNAL_SERVICE_ERROR","debug_id":"023ff49775e72"}
PROBLEM:
Well, when I do this call using curl, it gives me an appropriate response. Are the services not equipped to do communication is this way ?
Can you print your Authorization header and inspect whether it's correctly populated? We are currently returning a HTTP500 if your Authorization header is empty (which we'll change to return a more appropriate error obviously).
Related
I am using the admin sdk API to retrieve all G Suite users. We require an access token for this. AWS is used to host our website. I've tried a few different codes to generate access token, but they always return error
"Server returned HTTP response code: 401 for URL: https://accounts.google.com/o/oauth2/token."
I have no idea why this error is occurring. My code is running smoothly, generating access token and retrieving every user domain wise in a local environment. Any help in why actually I am getting this error. have i missed something? any help in it.
This is my code.
private String getAccessToken()
{
String accessToken="";
try
{
Map<String,Object> params = new LinkedHashMap<>();
params.put("grant_type","refresh_token");
params.put("client_id",client_id);
params.put("client_secret",client_secret);
params.put("refresh_token",refresh_token);
StringBuilder postData = new StringBuilder();
for(Map.Entry<String,Object> param : params.entrySet())
{
if(postData.length() != 0)
{
postData.append('&');
}
postData.append(URLEncoder.encode(param.getKey(),"UTF-8"));
postData.append('=');
postData.append(URLEncoder.encode(String.valueOf(param.getValue()),"UTF-8"));
}
byte[] postDataBytes = postData.toString().getBytes("UTF-8");
URL url = new URL("https://accounts.google.com/o/oauth2/token");
HttpURLConnection con = (HttpURLConnection)url.openConnection();
con.setDoOutput(true);
con.setUseCaches(false);
con.setRequestMethod("POST");
con.getOutputStream().write(postDataBytes);
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBuffer buffer = new StringBuffer();
for (String line = reader.readLine(); line != null; line = reader.readLine())
{
buffer.append(line);
}
JSONObject json = new JSONObject(buffer.toString());
accessToken = json.getString("access_token");
return accessToken;
}
catch (Exception ex)
{
ex.printStackTrace();
}
return accessToken;
}
I'm trying to use Bing Spatial Data Service of Microsoft by using Java from my server. (I used this code : How to send HTTP request in java?) but it doesnt work at all.
What I want to do: get latitude and longitude from a given adress
public static void main(String[] args) throws IOException {
System.out.println(SendRequete());
}
static String SendRequete(){
String bingMapsKey = "zzzzzzzzzz";
String contentType="text/plain";
String targetURL = "http://dev.virtualearth.net/";
String urlParameters="REST/v1/Locations?countryRegion=France&locality=Paris&postalCode=75001&addressLine=rue%20de%20la%20paix&key=" + bingMapsKey;
System.out.println(targetURL+urlParameters);
try{
HttpURLConnection connection = null;
URL url = new URL(targetURL);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setRequestProperty("Content-Type", contentType);
connection.setRequestProperty("Content-Length",
Integer.toString(urlParameters.getBytes().length));
connection.setRequestProperty("Content-Language", "en-US");
connection.setUseCaches(false);
connection.setDoOutput(true);
//request
DataOutputStream wr = new DataOutputStream(connection.getOutputStream());
wr.writeBytes(urlParameters);
wr.close();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
StringBuffer response = new StringBuffer(); // or StringBuffer if Java version 5+
String line;
while ((line = rd.readLine()) != null) {
System.out.println(line);
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
I keep having the same results:
<html><head><title>Object moved</title></head><body>
<h2>Object moved to here.</h2>
</body></html>
</body></html>ed to here.</h2>
ml><head><title>Object moved</title></head><body>
If I copy and paste on y browser it works fine... Any idea of where the problem is
Looks like you are using the Bing Maps REST services not the Bing Spatial Data Services. The REST services can geocode individual locations on demand, while the Spatial Data Services can geocode up to 200,000 locations in a single request.
Assuming you mean the REST services, yes, the URL you are creating is correct. However you are passing in part of the URL as URL parameters when you shouldn't be. Also, you need to make a GET request, not a POST request. Here is a modified version of your code that should work.
static String SendRequete(){
String bingMapsKey = "zzzzzzzzzz";
String contentType="text/plain";
String targetURL = "http://dev.virtualearth.net/";
String urlParameters="REST/v1/Locations?countryRegion=France&locality=Paris&postalCode=75001&addressLine=rue%20de%20la%20paix&key=" + bingMapsKey;
System.out.println(targetURL+urlParameters);
try{
URL url = new URL(targetURL + urlParameters);
URLConnection connection = url.openConnection();
//Get Response
InputStream is = connection.getInputStream();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
StringBuffer response = new StringBuffer(); // or StringBuffer if Java version 5+
String line;
while ((line = rd.readLine()) != null) {
System.out.println(line);
response.append(line);
response.append('\r');
}
rd.close();
return response.toString();
} catch (Exception e) {
e.printStackTrace();
return null;
}
}
String reqURL = baseUrl + data_oauth.get(PropLoad.getTestXmlData("URL"));
Template template = new Template();
String updatedUrl = template.getUpdatedURL(reqURL);
Map<String, String> headers = Template.getRequestData(data_oauth,PropLoad.getTestXmlData("HEADER"));
headers.entrySet().toString();
String updatedAuthor = template.getAuthorizationHeader(headers, methodDesc);
headers.put("Authorization", updatedAuthor);
String xmlRequest = Template.generateStringFromResource(data_oauth,"xmlbody");
Response response = webCredentials_rest.postCallWithHeaderAndBodyParamForXml(headers, xmlRequest, updatedUrl);
// am getting Unmarshalled as in response, can any help me on posting an POST request with XML body in it
You can send it like this:
URL url = new URL(urlString);
URLConnection connenction = url.openConnection();
OutputStream output = connenction.getOutputStream();
InputStream input = new FileInputStream(xmlFile);
byte[] buffer = new byte[4096];
int len;
while ((len = input .read(buffer)) >= 0) {
out.write(buffer, 0, len);
}
input .close();
output.close();
And read the response like this:
StringBuilder stringBuilder = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(connenction.getInputStream()));
String readLine = reader.readLine();
while (readLine != null) {
stringBuilder.append(readLine);
readLine = br.readLine();
}
I've been working on a portlet that calls Rest API. When the API is called and the requested data doesn't exist, it returns an appropriate error message in JSON format (with Bad request http code - 400), and if the id exists, it returns the requested data in json (with code 200).
How can I get the body of response (that contains error description) because invoking httpConn.getInputStream() method throws exception in case the response is bad request error.
Code:
HttpURLConnection httpConn = null;
URL url = new URL("http://192.168.1.20/personinfo.html?id=30");
URLConnection connection = url.openConnection();
httpConn = (HttpURLConnection) connection;
httpConn.setRequestProperty("Accept", "application/json");
httpConn.setRequestMethod("GET");
httpConn.setRequestProperty("charset", "utf-8");
BufferedReader br = null;
if (!(httpConn.getResponseCode() == 400)) {
br = new BufferedReader(new InputStreamReader((httpConn.getInputStream())));
String output;
StringBuilder builder = new StringBuilder();
System.out.println("Output from Server .... \n");
while ((output = br.readLine()) != null)
builder.append(output);
return builder.toString();
}else
here should catch the error message. :)
In case of non-successful response codes, you have to read the body with HttpURLConnection.getErrorStream().
you can get body of Bad Request in HttpURLConnection using this code :
InputStream errorstream = connection.getErrorStream();
String response = "";
String line;
BufferedReader br = new BufferedReader(new InputStreamReader(errorstream));
while ((line = br.readLine()) != null) {
response += line;
}
Log.d("body of Bad Request HttpURLConnection", "Response: " + response);
Use Apache Httpclient:
String url = "http://192.168.1.6:7003/life/lifews/getFirstInstallment.html?rootPolicyNo=1392/2126/2/106/9995/1904&token=1984";
HttpClient client = HttpClientBuilder.create().build();
HttpGet request = new HttpGet(url);
// add request header
HttpResponse response = client.execute(request);
System.out.println("Response Code : " + response.getStatusLine().getStatusCode());
BufferedReader rd = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer result = new StringBuffer();
String line = "";
while ((line = rd.readLine()) != null)
result.append(line);
System.out.println(result);
I wanted to use the Rapidshare API in my .NET app, but I am confused on how you send the request and bring back the result. Do you use Winsock or another method?
URLs are like this:
http://api.rapidshare.com/cgi-bin/rsapi.cgi?sub=checkfiles_v1&files=288725357&filenames=my_upload.txt
Thanks.
Check out the System.Net namespace, specifically System.Net.WebClient.
http://msdn.microsoft.com/en-us/library/system.net.webclient(VS.80).aspx
Use the WebClient Class.
http://msdn.microsoft.com/en-us/library/system.net.webclient%28VS.80%29.aspx
You can use this class to programatically interact with webpage. Here's some example code to log into a website. You can adapt this to interact with their web API:
HttpWebRequest request;
HttpWebResponse response;
CookieContainer cookies;
string url = "http://www.jaxtr.com/user/login.jsp";
try
{
request = (HttpWebRequest)WebRequest.Create(url);
request.AllowAutoRedirect = true;
request.CookieContainer = new CookieContainer();
response = (HttpWebResponse)request.GetResponse();
if (response.StatusCode == HttpStatusCode.OK)
{
StringBuilder sb = new StringBuilder();
StreamReader reader = new StreamReader(response.GetResponseStream());
while (!reader.EndOfStream)
{
sb.AppendLine(reader.ReadLine());
}
//Get the hidden value out of the form.
String fp = Regex.Match(sb.ToString(), "\"__fp\"\\svalue=\"(([A-Za-z0-9+/=]){4}){1,19}\"", RegexOptions.None).Value;
fp = fp.Substring(14);
fp = fp.Replace("\"", String.Empty);
cookies = request.CookieContainer;
//response.Close();
String requestString = "http://www.jaxtr.com/user/Login.action?tzOffset=6&navigateURL=&refPage=&jaxtrId=" + HttpUtility.UrlEncode(credentials.Username) + "&password=" + HttpUtility.UrlEncode(credentials.Password) + "&Login=Login&_sourcePage=%2Flogin.jsp&__fp="+HttpUtility.UrlEncode(fp);
request = (HttpWebRequest)WebRequest.Create(requestString);
request.CookieContainer = cookies; //added by myself
response = (HttpWebResponse)request.GetResponse();
Console.WriteLine("Response from login:" + response.StatusCode);
String messageText = (message.TruncateMessage && message.MessageText.Length > JaxtrSmsMessage.MAX_MESSAGE_LENGTH ? message.MessageText.Substring(JaxtrSmsMessage.MAX_MESSAGE_LENGTH) : message.MessageText);
String messageURL = "http://www.jaxtr.com/user/sendsms?CountryName=" + HttpUtility.UrlEncode(message.CountryName) + "&phone=" + HttpUtility.UrlEncode(message.DestinationPhoneNumber) + "&message=" + HttpUtility.UrlEncode(messageText) + "&bySMS=" + HttpUtility.UrlEncode(message.BySMS.ToString().ToLower());
request = (HttpWebRequest)WebRequest.Create(messageURL);
request.CookieContainer = cookies;
response = (HttpWebResponse)request.GetResponse();
Console.WriteLine("Response from send SMS command=" + response.StatusCode);
StringBuilder output = new StringBuilder();
using (Stream s = response.GetResponseStream())
{
StreamReader sr = new StreamReader(s);
while (!sr.EndOfStream)
{
output.AppendLine(sr.ReadLine());
}
}
response.Close();
}
else
{
Console.WriteLine("Client was unable to connect!");
}
}
catch (System.Exception e)
{
throw new SMSDeliveryException("Unable to deliver SMS message because "+e.Message, e);
}
This particular code logs into Jaxtr, a SMS messaging service, and sends an SMS message.