Converting MongoCursor to JSON - mongodb

Question

Using Casbah, I query Mongo.
val mongoClient = MongoClient("localhost", 27017)
val db = mongoClient("test")
val coll = db("test")
val results: MongoCursor = coll.find(builder)
var matchedDocuments = List[DBObject]()
for(result <- results) {
matchedDocuments = matchedDocuments :+ result
}
Then, I convert the List[DBObject] into JSON via:
val jsonString: String = buildJsonString(matchedDocuments)
Is there a better way to convert from "results" (MongoCursor) to JSON (JsValue)?
private def buildJsonString(list: List[DBObject]): Option[String] = {
def go(list: List[DBObject], json: String): Option[String] = list match {
case Nil => Some(json)
case x :: xs if(json == "") => go(xs, x.toString)
case x :: xs => go(xs, json + "," + x.toString)
case _ => None
}
go(list, "")
}

Answer 1

Assuming you want implicit conversion (like in flavian's answer), the easiest way to join the elements of your list with commas is:
private implicit def buildJsonString(list: List[DBObject]): String =
list.mkString(",")
Which is basically the answer given in Scala: join an iterable of strings
If you want to include the square brackets to properly construct a JSON array you'd just change it to:
list.mkString("[", ",", "]") // punctuation madness
However if you'd actually like to get to Play JsValue elements as you seem to indicate in the original question, then you could do:
list.map { x => Json.parse(x.toString) }
Which should produce a List[JsValue] instead of a String. However, if you're just going to convert it back to a string again when sending a response, then it's an unneeded step.