Does a CPU cache deal with physical or virtual addresses? And if it deals with virtual addresses, does that mean that it has be to emptied on context switch, assuming that the new thread is from another process.
This depends on the processor model. Some processors use both. (See “SPARC” in the “Virtual tags and vhints” section.)
You have tagged this question with x86-64, and an answer could be given for all x86-64 models to date, but I am not sure whether the architecture specification specifies whether processors conforming to the specification must use one or the other for cache information.
Related
This isn't quite a question about a specific OS, but let's take Windows as an example. A userspace program uses the Windows API to communicate with kernelspace. However, I don't understand how that's possible. The API, according to MS websites, lives in userspace. In order to access kernelspace it has to be in kernelspace, if I understand it correctly. So what is the mechanism by which the windows API gets extra privileges to speak to kernelspace? In which space does that mechanism operate? Is this sort of thing universal to all modern PC OS's?
As you're already aware there a bunch of facilities exposed to userspace programs by the Windows kernel. (If you're curious there's a list of system calls). These system calls are all identified by a unique number, which isn't part of the publicly documented interface given by Microsoft. Instead when you call a publicly exposed function from your program there's a DLL installed when you install (or update) Windows that has an entry point which is just a normal, unprivileged user mode function call. This DLL knows the mappings between public interfaces and the available system calls in the currently running kernel. These mappings are not always 1:1 which allows for tweaks and enhancements without breaking existing code using stable interfaces.
When some userland code calls one of these functions its role is to prepare arguments for the system call and then initiate the jump into kernel mode. How exactly that jump occurs is specific to the architecture that Windows is currently running on. In fact it varies not just between x86 and Arm but between AMD and Intel x86 systems even. I'll talk just about the modern Intel x86 32-bit case (using the SYSENTER instruction) here for simplicity. On x86 most of the other variations are relatively minor, for instance int 2Eh was used prior to SYSENTER support.
Early in boot up the operating system does a bunch of work to prepare for enabling a userland and system calls from it. Understanding this is critical to understanding how system calls really work.
First let's rewind a little and consider what exactly we mean by userland and kernelmode. On x86 when we talk about privileged vs un-privileged code we talk about "rings". There are actually 4 (ignoring hypervisors) but for various reasons nobody really used anything but ring0 (kernel) and ring3 (userland). When we run code on x86 the address that's being executed (EIP) and data that's being read/written come from segments.
Segments are mostly just a historical accident left over from the days before virtual addressing on x86 was a thing. They are however important for us here because there are special registers that define which segments are currently being used when we execute instructions or otherwise reference memory. Segments on x86 are all defined in a big table, called the Global Descriptor Table or GDT. (There's also a local descriptor table, LDT, but that's not going to further the current discussion here). The important point for our discussion here is that the (arcane) layout of the table entries include 2 bits, called DPL which define the privilege level of the currently active segment. You'll notice that 2 bits is exactly enough to define 4 levels of privilege.
So in short when we talk about "executing in kernel mode" we really just mean that our active code segment (CS) and data segment selectors point to entries in the GDT which have DPL set to 0. Likewise for userland we have a CS and data segment selectors pointing to GDT entries with DPL set to 3 and no access to kernel addresses. (There are other selectors too, but to keep it simple we'll just consider "code" and "data" for now).
Back to early on during kernel boot up: during start up the kernel creates the GDT entries we need. (These have to be laid out in a specific order for SYSENTER to work, but that's mostly just an implementation detail). There are also some "machine specific registers" that control how our processor behaves. These can only be set by privileged code. Three of them that are important here are:
IA32_SYSENTER_ESP
IA32_SYSENTER_EIP
IA32_SYSENTER_CS
Recall that we've got some code runnig in userland (ring3) that wants to transition to ring0. Let's assume that it has saved any registers that it needs to per the calling convention and put arguments into the right registers that the call expects. We then hit the SYSENTER instruction. (Actually it uses KiFastSystemCall I think). The SYSENTER instruction is special. It modifies the current code and data segment selectors based on the value that the kernel setup in the machine specific register IA32_SYSENTER_CS. (The stack/data segument values are computed as an offset of IA32_SYSENTER_CS). Subsequently the stack pointer itself (ESP) is set to the kernel stack that was setup for handling system calls earlier on and saved into the MSR IA32_SYSENTER_ESP and likewise for EIP the instruction pointer from IA32_SYSENTER_EIP.
Since the CS selector now points to a GDT entry with DPL set to 0 and EIP points to kernel mode code on a kernel stack we're running in the kernel at this point.
From here onwards the kernel mode code can read and write memory from both kernel and userspace (with some appropriate caution) to undertake the actual work needed to perform the system call. The arguments to the system call can be read from registers etc. according to the calling convention, but any arguments that are actually pointers back to userland or handles to kernel objects can be accessed to read larger blocks of data too.
When the system call is over the process is basically reversed and we end up back in userland with DPL 3 for the selectors.
Its the CPU that is acts as intermediate for transfer of information between user memory space(accessible in user mode) to protected memory space(accessible in kernel mode), via CPU registers.
Here's an Example:
Suppose a user writes a program in higher level language. Now when execution of the program happens, CPU generates the virtual addresses.
Now before any read/write operation occurs, the virtual address, is converted to physical address. Because the translation mechanism(memory management unit), is only accessible in kernel mode, cause its stored in protected memory, the translation occurs in kernel mode and the physical address is finally saved into some register of the CPU, and only then a read/write operation occurs.
In the movie The Social Network, when Mark Zuckberg was in class, the teacher asked this question:
Suppose we're given a computer, with a 16-bit virtual address, and a page size of 256-bytes,the system uses one-level page tables that start at address hex 400, may be you want DMA (Direct Memory Access) on your 16-bit system. Who knows? The first pages are reserved for hardware flags, etc. Assume page-table entries have eight status bits. The eight status bits would then be ...
Mark Zuckberg answered:
One valid bit, one modified bit, one reference bit and five permission bits.
How did he get this?
http://chomaloma.blogspot.com.au/2011/02/social-network-inaccuracies-regarding.html
That does explain it a little
Intel nomenclature in parentheses. The 'valid' (present), 'modified' (dirty) and 'reference' (accessed) bits are the minimum set of bits you need for a demand paging manager and MMU.
The 'valid' (present) bit is used by the MMU to know whether the page is mapped to a valid physical address.
The 'modified' (dirty) bit is used by the demand paging manager to determine if the page being evicted needs to be written to backing media. As accessing backing media can be considered an expensive operation, you really want to keep this to a minimum--especially when writing to it as that is generally slower than reading from it.
The 'reference' (accessed) bit is useful to the demand paging manager to figure out how to age the pages it controls. You don't want to evict the most frequently used pages as that would require saving and/or loading them repeatedly from backing store (which has already been stated as SLOW).
The remaining five bits are gravy. They are free to use as permission and/or option bits. For example, can the page be accessed by supervisor and/or user threads? Is the page available for write, or is it read-only? What is the caching strategy to be used on the page?
Hope this helps.
Sparky
How did he get the answer?---That is just movie BS.
If you take the number of bits in the address and subtract the number of bits used to represent a page, you get the number of bits available for the processor to use as system status bits.
With that information, he could identify the number of system status bits
The usage of those bits is another story. The allocation of system status bits is system dependent. Maybe they exist, but I don't know of any 16-bit virtual addressing system. So he's not referring to any specific type of system.
A reference bit is not used by all systems (e.g. VMS). That's not even mandatory.
Hollywood magic.
I was going through few of the lectures conducted at UC Berkeley on Virtual Memory
# https://www.youtube.com/results?search_query=computer+science+194+-+lecture+14
"Computer Science 194 - Lecture 13_ Memory Management_ Mechanisms on various architectures, NUMA" and "Computer Science 194 - Lecture 14_ Virtual Memory Management, Swapping, Page Cache"
Its an excellent lecture. However , I am slightly confused on one point.
The lecture explains how segmentation and paging have been combined for addressing VM.
It goes on to explain that the current systems use as the structure of VM address.
It also mentioned that the virtual space visible to a process is private and the address ranges for each process remains same. Each process views its address space to start at 0 and extend till 4G. with different segment areas within this 4G space.
Questions :
Now if the address ranges for each VM space is same , How is it that two processes referring to the highest level lookup table - the PageTblPtr using "segment Number" as the index , are uniquely able to identify a row in this table ... as the segment address/number for each of the process may be same... lets say Process A's and B's have both data segment starting at address 'x' within there VM space .
Does that also mean that there could be as many as 6 entries in the PagetblPtr for a process for each - 6 possible segments - CS, DS, ...etc?
Where is the PageTblPtr maintained ?
Best Regards,
Varun
I'm not going to watch an 83-minute video lecture just to get the exact definitions of terms like PageTblPtr, but I'll try to provide some general answers:
Modern operating systems don't use segmentation. It's just a big flat address space, and all the segment selectors are set to encompass the whole thing. I don't think x86 processors even support segmentation when running in 64-bit mode.
Each process has its own page table, which defines the mappings for that process's virtual address space. Two processes can have different data at the same virtual address because their respective page tables point to different physical pages for the same virtual page.
Page tables are owned and managed by the OS kernel. When the kernel performs a task switch (changing which process it's running), one of the things it must do is activate the new process's page table instead of the old.
Is it possible to provide physical address for a given virtual address in a direct way to the TLB on x86-64 architectures in long mode?
For example, lets say, I put zeros in PML4E, so a page fault exception will be triggered because an invalid address will be found, during the exception can the CPU tell the TLB by using some instruction that this virtual address is located at X physical page frame?
I want to do this because by code I can easily tell where the physical address would be, and this way avoid expensive page walk.
No, you need to put a page to the TLB. To be precise, you need to create/update appropriate PTE (with PDE and PDPE if needed). Everything around MMU management is somehow based on page tables and TLB. Even user/supervisor protection mode is done as a special flag of mapped page.
Why do you think that "page walk" is expensive operation? It is not expensive at all. To determine the PTE that must be updated you need to dereference only 4 pointers: PML4E -> PDPE -> PDE -> PTE. These entries are just indices in related tables. To get PML4E you need to use 39-47 bits of address taken during page fault handling and use the value as an index in PML4 table. To get PDPE you need 30-39 bits of an address as an index in PDE table and so on. It's not the thing that can slow down your system. I think allocation of a physical page takes more time than that.
I'm trying to understand how does an operating system work when we want to assign some value to a particular virtual memory address.
My first question concerns whether the MMU handles everything between the CPU and the RAM. Is this true? From what one can read from Wikipedia, I'd say so:
A memory management unit (MMU), sometimes called paged memory
management unit (PMMU), is a computer
hardware component responsible for
handling accesses to memory requested
by the CPU.
If that is the case, how can one tell the MMU I want to get 8 bytes, 64 or 128bytes, for example? What about writing?
If that is not the case, I'm guessing the MMU just translates virtual addresses to physical ones?
What happens when the MMU detects there will be what we call a page-fault? I guess it has to tell it to the CPU so the CPU loads the page itself off disk, or is the MMU able to do this?
Thanks
Devoured Elysium,
I'll attempt to answer your questions one by one but note, it might be a good idea to get your hands on a textbook for an OS course or an introductory computer architecture course.
The MMU consists of some hardware logic and state whose purpose is, indeed, to produce a physical address and provide/receive data to and from the memory controller. Actually, the job of memory translation is one that is taken care of by cooperating hardware and software (OS) mechanisms (at least in modern PCs). Once the physical address is obtained, the CPU has essentially done its job and now sends the address out on a bus which is at some point connected to the actual memory chips. In many systems this bus is called the Front-Side Bus (FSB), which is in turn connected to a memory controller. This controller takes the physical address supplied by the CPU and uses it to interact with the DRAM chips, and ultimately extract the bits in the correct rows and columns of the memory array. The data is then sent back to the CPU, which can now operate on it. Note that I'm not including caching in this description.
So no, the MMU does not interact directly with RAM, which I assume you are using to mean the physical DRAM chips. And you cannot tell the MMU that you want 8 bytes, or 24 bytes, or whatever, you can only supply it with an address. How many bytes that gets you depends on the machine you're on and whether it's byte-addressable or word-addressable.
Your last question urges me to remind you: the MMU is actually a part of the CPU--it sits on the same silicon die (although this was not always the case).
Now, let's take your example with the page fault. Suppose our user-level application wants to, like you said, set someAddress = 10, I'll take it in steps. Let's assume someAddress is 0xDEADBEEF and let's ignore caches for now.
1) The application issues a store instruction to 0xsomeAddress, which, in x86 might look something like
mov %eax, 0xDEADBEEF
where 10 is the value in the eax register.
2) 0xDEADBEEF in this case is a virtual address, which must be translated. Most of the time, the virtual to physical address translation will be available in a hardware structure called the Translation Lookaside Buffer (TLB), which will provide this translation to us very fast. Typically, it can do so in one clock cycle. If the translation is in the TLB, called a TLB hit, execution can continue immediately (i.e. the physical address corresponding to 0xDEADBEEF and the value 10 are sent out to the memory controller to be written).
3) Let's suppose though, that the translation wasn't available in the TLB (called a TLB miss). Then we must find the translation in the page tables, which are structures in memory whose structure is defined by the hardware and managed by the OS. They simply contain entries that map a virtual address to a physical one (more accurately, a virtual page number to a physical page number). But these structures also reside in memory, and so must have addresses! The hardware contains a special register called cr3 which contains the physical address of the current page table. We can index into this page table using our virtual address, so the hardware takes the value in cr3, computes an address by adding an offset, and goes off to memory to fetch the page table entry (PTE). This PTE will (hopefully) contain the physical address corresponding to 0xDEADBEEF, in which case we put this mapping in the TLB (so we don't have to walk the page table again) and continue on our way.
4) But oh no! What if there is no PTE in the page tables for 0xDEADBEEF? This is a page fault, and this is where the Operating System comes into play. The PTE we got out of the page table existed, as in it was (let's assume) a valid memory address to access, but the OS had not created a VA->PA mapping for it yet, so it would have had a bit set to indicate that it is invalid. The hardware is programmed in such a way that when it sees this invalid bit upon an access, it generates an exception, in this case a page fault.
5) The exception causes the hardware to invoke the OS by jumping to a well known location--a piece of code called a handler. There can be many exception handlers, and a page fault handler is one of them. The page fault handler will know the address that caused the fault because it's stored in a register somewhere, and so will create a new mapping for our virtual address 0xDEADBEEF. It will do so by allocating a free page of physical memory and then saying "all virtual addresses between VA x and VA y will map to some address within this newly allocated page of physical memory". 0xDEADBEEF will be somewhere in that range, so the mapping is now securely in the page tables, and we can restart the instruction that caused the page fault (the mov).
6) Now, when we go through the page tables again, we will find a mapping and the PTE we pull out will have a nice physical address, the one we want to store to. We provide this with the value 10 to the memory controller and we're done!
Caches will change this game quite a bit, but I hope this serves to illustrate how paging works. Again, it would benefit you greatly to check out some OS/Computer Architecture books. I hope this was clear.
There are data structures that describe which virtual addresses correspond to which physical addresses. The OS creates and manages these data structures, and the CPU uses them to translate virtual addresses into physical addresses.
For example, the OS might use these data structures to say "virtual addresses in the range from 0x00000000 to 0x00000FFF correspond to physical addresses 0x12340000 to 0x12340FFFF"; and if software tries to read 4 bytes from the virtual address 0x00000468 then the CPU will actually read 4 bytes from the physical address 0x12340468.
Typically everything is effected by the virtual->physical translation (except for when the CPU is accessing the data structures that describe the translation). Also, usually there's some sort of translation cache build into the CPU to help reduce the overhead involved.