$this->request->data EMPTY - When I have disabled Fields CakePHP 2 - forms

I have a form which has some disabled fields, when the form is submitted both $this->request->data and $_POST is empty, removing the disabled fields and it is fine again. I would have though it would still pass though the non-disabled fields. I've even tried to remove the disabled field attribute when the submit button is pushed but this still returns an empty array.
Is there something cake related that might be causing this?
Thanks
// SNIPPET FROM THE VIEW CODE:
$this->Form->create('Card', array('class' => 'GeneralValidate'));
$this->Form->input('Card.property_id', array('type'=>'select', 'empty'=>true , 'class' => 'required adminOnlyField', 'div' => array('class' => 'required')));
$this->Form->input('Card.building_id', array('type'=>'select', 'empty'=>true, 'id' => 'BuildingSelector', 'class' => 'adminOnlyField', 'label' => 'Building (If Applicable)'));
$this->Form->input('Prospect.waiting_list_details', array('value' => $prospect['Prospect']['waiting_list_details']));
$this->Form->input('SaleDetail.property_sold', array('class' => 'checkbox', 'checked' => $ps_checked));
$this->Form->input('SaleDetail.date_conditions_met', array('type'=>'text', 'class' => 'text date_picker adminOnlyField', 'value' => $this->Date->format($saledetail['SaleDetail']['date_conditions_met'])));
$this->Form->button('Save & Continue', array('type'=>'submit', 'label' => 'Save', 'name' => 'quicksave' , 'class' => 'submit long clear_ready_only'));
// JS FROM THE VIEW
$(function () {
var $adminOnly = $('.adminOnlyField');
$adminOnly.prop('disabled',true).prop('readonly',true);
$adminOnly.attr("onclick","return false");
$adminOnly.attr("onkeydown","return false");
$adminOnly.removeClass('required');
$adminOnly.removeClass('date_picker');
$('.clear_ready_only').click(function(e)
{
e.preventDefault();
$adminOnly.prop('disabled',false).prop('readonly',false);
$adminOnly.attr("onclick","return true");
$adminOnly.attr("onkeydown","return true");
$('#CardModifysaleForm').submit();
});
});

That's the way HTML works, disabled don't get posted. CakePHP can't change what is sent from the browser. If you still want the value you can set it as a hidden element.
Update
Some problems I see:
Missing Form::end() in view (always a good idea to insert it).
You never said your form was submitted from JS, first test with a simple form POST then JS.
Your JS code is set to submit a form by ID CardModifysaleForm. There's no such ID in your supplied view code and you're not setting your form to that ID from the snippet you supply.

I ended up removing the disabled option from this, leaving the ready only and added some addition CSS stylings so it looked disabled to the user. This is not the exact answer to the question but works as a different approach.

Related

CakePHP FormHelper multiple select does not remember settings

In my form I have a input field with multiple checkboxes.
This works as expected.
When for some reason (eg an obligated field in the form is empty upon submit) the form after submit is not posted, all other fields maintain there input except the field below, all checkboxes become unchecked.
What can I do to make this field remember it's settings?
$options = array(
'1' => 'one',
'2' => 'two',
'3' => 'three'
);
echo $this->Form->input('checkboxes',array(
'type' => 'select',
'multiple' => 'checkbox',
'options' => $options,
'default' => array(1,2,3)
));
FormHelper uses the $this->request->data to fill the fields. You need to keep (or fill) your data in request data array and the cakephp will maintain your data.

Drupal 7: Show fields on a form based on another field and a database lookup

I have a form I created in a custom module using the Form API. It is a fairly basic form with only 4 fields. It basically signs a user up for a job alert system. We are basing it only by email address with a few search parameters. We want people to be able to setup a search agent quickly and anonymously meaning they will NOT be creating a Drupal user account as we don't want them to have to deal with a password etc. They will just put in their email address, check off a few preferences and we will save the data.
Now the issue I need to deal with is allowing the user to edit their preferences later on and/or unsubscribe. Again this is not high security and it doesn't need to be. What I would like to do is initially ask ONLY for their email address in the form and allow them to submit it. I would then check the database to see if we already have an entry for that email address and if so, display the pre-filled form for them to edit or unsubsribe, other wise just show them the blank form. So I am just trying to figure out the best way to go about this. I'm thinking I just have one form with all of the fields including email address, but somehow only display the other fields besides the email address after a successful call to the database. I'm just tripping up on how to accomplish this.
EDIT:
I'm wondering if I can use Drupal's AJAX functionality to accomplish this? I tried this, but I couldn't get it to work. I put an Ajax attribute on my submit button with a wrapper ID and a callback function. I created a form element in my form with blank markup and used a prefix and suffix that created a wrapper div with the ID I used in my AJAX parameter. Then I am thinking in my callback function I can do the database lookup and then return the form elements I need either pre-filled or not into the wrapper div that was created, but when I do this, the form does submit via AJAX and I get the spinning wheel, but no matter what I return in my callback, it does not appear in my output wrapper div. Am I going about this the right way? I also made sure I have $form_state['rebuild'] = TRUE; on my original form.
Here is what I tried and it didn't work.
/**
* Implements hook_form().
*/
function _vista_form($form, &$form_state) {
$form = array();
$form_state['rebuild'] = TRUE;
$form['email'] = array(
'#type' => 'textfield',
'#title' => 'Email',
'#required' => TRUE,
);
$form['render_area'] = array(
'#type' => 'markup',
'#markup' => '',
'#prefix' => '<div id="job-agent-form">',
'#suffix' => '</div>',
);
$form['submit'] = array(
'#type' => 'submit',
'#value' => t('Submit'),
'#attributes' => array('class' => array('submit')),
'#ajax' => array(
'callback' => '_display_form',
'wrapper' => 'job-agent-form',
'method' => 'replace',
'effect' => 'fade',
),
return $form;
}
function _display_form($form, &$form_state) {
// there are other form elements that would go here also, I just added two for example
$type_options = array(
'VISTA-HealthCare-Partners-Government' => 'Vista Healthcare Partners',
'International' => 'International Locum Tenens',
'Permanent' => 'Permanent Physician',
'US-Locum-Tenens' => 'US Locum Tenens',
);
$form['job_type'] = array(
'#type' => 'checkboxes',
'#multiple' => TRUE,
'#title' => 'Type of Job',
'#options' => $type_options,
'#empty_option' => 'Choose a placement type',
'#empty_value' => 'all',
//'#default_value' => $type_selected,
);
$form['active'] = array(
'#type' => 'checkbox',
'#title' => 'Subscribe/Unsubscribe',
'#default_value' => 1,
);
return $form;
}
I would go for creating all fields in the form than use hook_form_alter() to hide the unneeded ones with ['#access'] = FALSE.

CakePHP Text as Form Submit

I've searched the web and have come up with nothing. (Multiple search engines too - I have looked!)
I'm trying to have a text link as the 'form submit' button. Any ideas if this is possible in CakePHP?
Current view code below!
<?php
echo $this->Form->create('trainees', array(
'action' => 'reassign'
));
echo $this->Form->input('emailaddress', array(
'value' => 'scott#something',
'type' => 'hidden',
));
echo $this->Form->submit('Re-Assign Mentor', array(
'class' => 'submit mid',
'before' => '<p>',
'after' => '</p>'
));
echo $this->Form->end();
?>
You need to use the HtmlHelper to output a link. In it's simplest form you use the text you want displayed with the URL that it should link to. In this case it will be JavaScript:
$this->Html->link('Submit Form', 'javascript:document.forms["myform"].submit();');
There are two additional parameters (a $options array and $confirmMessage boolean), but they along with the URL are optional.
You can also call your own JavaScript function if you need to do client side verification and call the submit function from there (also verify on the server as clients can lie).
http://book.cakephp.org/2.0/en/core-libraries/helpers/html.html#HtmlHelper::link

Zend form in a popup (fancybox, lightbox....)

I am developping a web application using Zend and I ran out of ideas for a problem I am having. In just a few words, I am trying to have a contact form in a popup (Fancybox, lightbox, colorbox or whatever...). The whole thing works fine, in the sense that it shows up the contact form in the popup and allows to send emails. However, whenever there are errors (unfilled input or filled wrong), I couldn't get those errors to be displayed on the popup (it actually redirects me back to the form in a normal display (view+layout), to show the errors.
It is perhaps possible but I now thought that perhaps I could more easily bring my error message to a new popup (the contact page, filled unproperly, would lead to a error popup page...). I think this alternative could look cool but am having real trouble doing it. Now my real question is : Can we really make a form on a popup, using Facybox (Lighbox or any other actually ... just want my popup) and Zend? Any Guru outhere??
Thanks a lot
here is the code:
the link for instance:
<a class="popLink" href=" <?php echo $this->url(array('module'=>'default', 'controller'=>'contact', 'action'=>'sendmail')).'?ProID='.$this->proProfil->getProID(); ?>">Contact</a>
the action:
public function sendmailAction()
{
$this->_helper->layout()->setLayout('blank');
$request = $this->getRequest();
$proID = $this->_getParam("ProID");
$professionalsList = new Model_DirPro();
$proName = $professionalsList->getProInfo($proID);
$translate = Zend_Registry::get('translate');
Zend_Validate_Abstract::setDefaultTranslator($translate);
Zend_Form::setDefaultTranslator($translate);
$contactform = new Form_ContactForm();
$contactform->setTranslator($translate);
$contactform->setAttrib('id', 'contact');
$this->view->contactform = $contactform;
$this->view->proName = $proName;
if ($request->isPost()){
if ($contactform->isValid($this->_getAllParams())){
$mailSubject = $contactform->getValue('mailsubject');
if ($contactform->mailattcht->isUploaded()) {
$contactform->mailattcht->receive();
//etc....
the form:
class Form_ContactForm extends Zend_Form
{
public function init ()
{
$this->setName("email");
$this->setMethod('post');
$this->addElement('text', 'mailsubject',
array('filters' => array('StringTrim'),
'validators' => array(), 'required' => true, 'label' => 'Subject:'));
$mailattcht = new Zend_Form_Element_File('mailattcht');
$mailattcht->setLabel('Attach File:')->setDestination(APPLICATION_PATH.'/../public/mails');
$mailattcht->addValidator('Count', false, 1);
$mailattcht->addValidator('Size', false, 8000000);
$mailattcht->addValidator('Extension', false,
'jpg,png,gif,ppt,pptx,doc,docx,xls,xslx,pdf');
$this->addElement($mailattcht, 'mailattcht');
$this->addElement('textarea', 'mailbody',
array('filters' => array('StringTrim'),
'validators' => array(), 'required' => true, 'label' => 'Body:'));
$this->addElement('submit', 'send',
array('required' => false, 'ignore' => true, 'label' => 'Send'));
$this->addElement('hidden', 'return', array(
'value' => Zend_Controller_Front::getInstance()->getRequest()->getRequestUri(),
));
$this->setAttrib('enctype', 'multipart/form-data');
}
}
I would suggest implementing AJAX validation. This would allow for the form to be verified before it is submitted. ZendCasts has a good tutorial on how to accomplish this: http://www.zendcasts.com/ajaxify-your-zend_form-validation-with-jquery/2010/04/
Ajax requests are handled via the contextSwitch action helper. You can to specify the various contexts an action needs to handle (xml or json) in the init method of the controller as follows:
public function init()
{
$this->_helper->contextSwitch()
->addActionContext('send-mail', 'json')
->initContext()
;
}
The request url should contain a "format=json" appended to the query string. This will execute the action and send the response in json format. The default behaviour of JSON context is to extract all the public properties of the view and encode them as JSON. Further details can be found here http://framework.zend.com/manual/en/zend.controller.actionhelpers.html
I found a "probably not the prettiest" working solution, it is to indeed use ajax as mentioned in the previous zendcast for validation to stop the real validation (preventdefault), process the data return the result and if everything's ok restart it.

Drupal: set id attribute in multi-step form

I'm building a multi-step form in Drupal 6. For some reason, the id attribute of the form element have an extra "-1" the first time the step 1 form is displayed.
For example, if the form name is "user-registration", the first time I access the step 1 form, the id is "user-registration-1". Then, if I go to step 2, the id is "user-registration". If I go back to step 1, the id remains "user-registration".
I'd like to know if there's a way for me to set the id attribute or to prevent Drupal from adding the extra "-1".
Thanks.
You can set the id yourself.
$form['#attributes'] = array('id' => 'user-registration');
Drupal 6.x has a form API property for both '#id' an '#attribute'. I had the same problem and found that the '#id' property was blank, which accounted for the blank 'id' in the form field. Then I used '#attribute' => array('id' => 'name of id'), which gave me a second 'id' in the form field. Remove the id in the '#attribute' and add another form API property for '#id'.
$form['foo'] = array(
'#type' => 'textfield',
'#title' => t('Foo'),
'#required' => FALSE,
'#id' => 'text-foo',
);
This worked for me:
$form = array( '#id' => 'myformid' );