I know this is an often asked question, but I've tried to resolve this myself and could not.
I've got 2 tables to join and now it's returning a duplicate value from the right table.
select am.Journal
,am.EntryNumber
,am.PayInvoice
,am.PayDiscAllowed
,am.PayTaxAmtDisc
,am.PayGrossPayment
,tm.*
from CshJnlPay am right join
(select
Invoice
,SUM(NetSalesValue) as NetSalesValue
,SUM(DiscValue) as DiscValue
,SUM(TaxValue) as TaxValue
,SUM(QtyInvoiced) as QtyInvoiced
from Salesdetail
group by Invoice) tm
on am.PayInvoice = tm.Invoice
where Invoice = 'C90831'
If the query returns 2 rows with the same data from the right table then you have 2 rows in the left table with the same invoice number...
You should check the left table with this query
Select * from CshJnlPay where PayInvoice = 'C90831'
You should get two rows.
Related
Goal: Create a query to pull the closest cycle count event (Table C) for a product ID based on the inventory adjustments results sourced from another table (Table A).
All records from Table A will be used, but is not guaranteed to have a match in Table C.
The ID column will be present in both tables, but is not unique in either, so that pair of IDs and Timestamps together are needed for each table.
Current simplified SQL
SELECT
A.WHENOCCURRED,
A.LPID,
A.ITEM,
A.ADJQTY,
C.WHENOCCURRED,
C.LPID,
C.LOCATION,
C.ITEM,
C.QUANTITY,
C.ENTQUANTITY
FROM
A
LEFT JOIN
C
ON A.LPID = C.LPID
WHERE
A.facility = 'FACID'
AND A.WHENOCCURRED > '23-DEC-22'
AND A.ADJREASONABBREV = 'CYCLE COUNTS'
ORDER BY A.WHENOCCURRED DESC
;
This is currently pulling the first hit on C.WHENOCCURRED on the LPID matches. Want to see if there is a simpler JOIN solution before going in a direction that creates 2 temp tables based on WHENOCCURRED.
I have a functioning INDEX(MATCH(MIN()) solution in Excel but that requires exporting a couple system reports first and is extremely slow with X,XXX row tables.
If you are using Oracle 12 or later, you can use a LATERAL join and FETCH FIRST ROW ONLY:
SELECT A.WHENOCCURRED,
A.LPID,
A.ITEM,
A.ADJQTY,
C.WHENOCCURRED,
C.LPID,
C.LOCATION,
C.ITEM,
C.QUANTITY,
C.ENTQUANTITY
FROM A
LEFT OUTER JOIN LATERAL (
SELECT *
FROM C
WHERE A.LPID = C.LPID
AND A.whenoccurred <= c.whenoccurred
ORDER BY c.whenoccurred
FETCH FIRST ROW ONLY
) C
ON (1 = 1) -- The join condition is inside the lateral join
WHERE A.facility = 'FACID'
AND A.WHENOCCURRED > DATE '2022-12-23'
AND A.ADJREASONABBREV = 'CYCLE COUNTS'
ORDER BY A.WHENOCCURRED DESC;
I use this query to join two tables:
SELECT *
FROM horses h
RIGHT JOIN races r ON h.racedate = r.racedate
AND h.racename = r.racename
AND h.racetime = r.racetime
ORDER BY r.racedate, r.racetime
This works without a problem, but if I try:
CREATE MATERIALIZED VIEW allracesview AS
SELECT *
FROM horses h
RIGHT JOIN races r ON h.racedate = r.racedate
AND h.racename = r.racename
AND h.racetime = r.racetime
ORDER BY r.racedate, r.racetime DESC
I get the error
ERROR: FEHLER: Spalte »racetime« mehrmals angegeben
Which means "Column racetime is specified multiple times" and only 3 columns are added to the view.
How can I join these two tables in a materialized view?
Like #a_horse_with_no_name said in the comments, select * does return all columns of all tables. As you have the same columns in both tables, you have duplicated column names in the result.
How can I join these two tables in a materialized view? Without an explicit column list?
You can use a USING clause for the JOIN condition. The output of JOIN USING` suppresses redundant columns, so go with
CREATE MATERIALIZED VIEW allracesview AS
SELECT *
FROM horses
RIGHT JOIN races USING (racedate, racename, racetime)
ORDER BY racedate, racetime DESC
I have two tables, EMPL which is a historical employee table to track changes in an employee's tax rate and PAYROLL which is also a historical table filled with employee pay over a number of periods.
FROM EMPL, based upon the EMPL.effect_pd <= PAYROLL.payroll_pd, only one record should be joined from EMPL to PAYROLL.
Below are the two tables, query and result set. However, I only want 1 record for each employee per pay period, which matches the relevant employee record based upon the payroll_pd and effect_pd.
(Click image to enlarge)
first of all - welcome!
You wrote "...FROM EMPL, based upon the EMPL.effect_pd <= PAYROLL.payroll_pd ..." but you start your SQL with PAYROLL and not with EMPL.
Pls test this statement first:
SELECT
E.rec_id
,E.empl_id
,E.empl_name
,E.tax_rate
,E.effect_pd
,P.rec_id
,P.payroll_pd
,P.empl_id
,P.pd_pay
FROM
empl AS E
LEFT OUTER JOIN
payroll AS P
ON E.empl_id = P.empl_id
AND E.effect_pd < P.payroll_pd
After that you get 7 records witch are uniqe.
i think, thats it.
Best regards
After 3 days of messing around with the code, I finally arrived at the solution which is:
SELECT * FROM PAYROLL p
LEFT JOIN EMPL e on p.empl_id = e.empl_id
WHERE e.rec_id = ( SELECT TOP 1 c.rec_id
FROM EMPL c
WHERE c.empl_id = p.empl_id
AND p.payroll_pd >= c.effect_pd
ORDER BY c.effect_pd DESC );
This question already has answers here:
Nested Case statement type error (postgres)
(2 answers)
Closed 7 years ago.
I have a table with ~5,000 records. I have made three join columns in this table. The values in each column are not unique. I want to join to another table (sequentially) by each of these three columns to return values given a condition.
The join table contains multiple columns. Three of these columns are the join columns which will correspond to the first tables' join columns. The join columns in the join table are unique. I want to take the values from the join table and bring to a new column in the first table.
I have a code that I have put together from other suggestions and it runs but I am receiving over 8 million records in the return table. I want the table to only have the records from the first table.
Here is the code:
CREATE TABLE current_condition_joined AS SELECT
a.id, a.geom, a.condition_join_1, a.condition_join_2, a.condition_join_3,
coalesce(b.condition, c.condition2, d.condition3) as current_condition,
coalesce(b.ecosite, c.ecosite2, d.ecosite3) as current_ecosite,
coalesce(b.ecophase, c.ecophase2, d.ecophase3) as current_ecophase,
coalesce(b.consite, c.consite2, d.consite3) as current_consite,
coalesce(b.conphase, c.conphase2, d.conphase3) as current_conphase
FROM current_condition a
LEFT JOIN boreal_mixedwood_labeled b ON a.condition_join_1 = b.label
LEFT JOIN boreal_mixedwood_labeled c ON a.condition_join_2 = c.label2
LEFT JOIN boreal_mixedwood_labeled d ON a.condition_join_3 = d.label3
WHERE b.condition != 'ERROR' and c.condition2 != 'ERROR';
I want to get the values from the first join if condition is not ERROR, else the values from the second join if condition is not ERROR, else the values of the third join.
I've looked around, but all examples are asking slightly different things then I am so I can't piece it together.
This is not the same question as: Nested Case statement type error (postgres)
The question asked there was in regard to making a nested statement work. This question is about how the join works. Two different questions, two different posts.
Try add a DISTINCT.
CREATE TABLE current_condition_joined AS SELECT DISTINCT
a.id, a.geom, a.condition_join_1, a.condition_join_2, a.condition_join_3,
coalesce(b.condition, c.condition2, d.condition3) as current_condition,
coalesce(b.ecosite, c.ecosite2, d.ecosite3) as current_ecosite,
coalesce(b.ecophase, c.ecophase2, d.ecophase3) as current_ecophase,
coalesce(b.consite, c.consite2, d.consite3) as current_consite,
coalesce(b.conphase, c.conphase2, d.conphase3) as current_conphase
FROM current_condition a
LEFT JOIN boreal_mixedwood_labeled b ON a.condition_join_1 = b.label
LEFT JOIN boreal_mixedwood_labeled c ON a.condition_join_2 = c.label2
LEFT JOIN boreal_mixedwood_labeled d ON a.condition_join_3 = d.label3
WHERE b.condition != 'ERROR' and c.condition2 != 'ERROR';
You can try use GROUP BY too.
The code you present is what I gave you for your previous question:
Nested Case statement type error (postgres).
But you broke it by moving the conditions b.condition != 'ERROR' and c.condition2 != 'ERROR' to the WHERE clause, which is simply wrong. Consider:
Query with LEFT JOIN not returning rows for count of 0
If rows are multiplied, then your join conditions most probably identify multiple matching rows, multiplying each other. Hard to diagnose while you still refuse to provide the table definition of boreal_mixedwood_labeled like I requested repeatedly for your previous question.
I have the next query which does not work:
UPDATE item
SET popularity= (CASE
WHEN (select SUM(io.quantity) from item i NATURAL JOIN itemorder io GROUP BY io.item_id) > 3 THEN TRUE
ELSE FALSE
END);
Here I want to compare each line of inner SELECT SUM value with 3 and update popularity. But SQL gives error:
ERROR: more than one row returned by a subquery used as an expression
I understand that inner SELECT returns many values, but can smb help me in how to compare each line. In other words make loop.
When using a subquery you need to get a single row back, so you're effectively doing a query for each record in the item table.
UPDATE item i
SET popularity = (SELECT SUM(io.quantity) FROM itemorder io
WHERE io.item_id = i.item_id) > 3;
An alternative (which is a postgresql extension) is to use a derived table in a FROM clause.
UPDATE item i2
SET popularity = x.orders > 3
FROM (select i.item_id, SUM(io.quantity) as orders
from item i NATURAL JOIN itemorder io GROUP BY io.item_id)
as x(item_id,orders)
WHERE i2.item_id = x.item_id
Here you're doing a single group clause as you had, and we're joining the table to be updated with the results of the group.