I have this code to retrieve the Localized Date:
DateTime.Now.ToString(DateTimeFormatInfo.CurrentInfo.LongDatePattern);
The thing is that it returns the year also. I don't want the year.
So I thought I could remove the year pattern from the LongDatePattern. But there are commas in some countries and it would look bad if I removed the 2013 year.
Can someone help me to be able to do it?
Windows.Globalization.DateTimeFormatting.DateTimeFormatter will allow you to supply a template that specifies exactly which components you want included in the formatted result ("month day dayofweek") for example.
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I want to convert date into a Day
I am using LibreOffice
I used some of its syntax weekday and text but it returns nothing
WEEKDAY("30-04-2019"; 1) is there any way to do that?
in google sheet i used =TEXT(C7758,"dddd") but it didn't work
how can I do that?
thanks in advance
Try the combination of functions WEEKDAY and DATE:
=WEEKDAY(DATE(2019;4;30))
The specific example will return 3 which is Tuesday (see all days and other options at https://wiki.openoffice.org/wiki/Documentation/How_Tos/Calc:_WEEKDAY_function)
Hope that helps.
So let's say I have an Infobox template in Wikipedia that retrieves a company foundation date from Wikidata. It contains the following code:
|label7 = Year founded
|text7 = {{wikidata|p571|{{{founded|}}}}}
My problem is that what's retrieved is formatted as 31 January 2010 and it looks weird next to "Year founded' since it is not a year but the whole date. Of course I could rename the label from "Year founded" to "Date founded" and voila, problem solved, right? But I do want to just get the year from Wikidata, not the whole date.
What would be the code for this? I imagine something like {{wikidata|p571[year]|{{{founded|}}}}} or {{wikidata|p571[0]|{{{founded|}}}}} or {{wikidata|p571[YYYY]|{{{founded|}}}}}.
Thanks in advance!
This doesn't sound like a programming question, but it looks like you can request a specific date format as the third parameter to wikidata
https://en.wikipedia.org/wiki/Module:Wikidata#Testing_getValue.2C_getRawValue_and_getDateValue
{{#invoke:Wikidata|getDateValue|P569|FETCH_WIKIDATA|y}}
I highly recomend you to filter the year from date using RegularExpression instead of trying to get only the year.
I am trying to bring up a date format of "Monday, February 2,2015" in meteor autoform, from this code
moment.utc("2015-02-02").format("LL")
I would like to have a list like in php.date function shows the full date format.
I believe each one of us will find few and post here so that we get the complete list. I googled and I never got the list.
I'm not sure I fully understand your question but this might help.
http://momentjs.com/
With DateJS, you'd add e.g. six months to the current date like this:
Date.today().addMonths(6);
However, I need to add 24 months not to today's date, but to a date which a user has typed into a date field. So the today() should in principle be replaced by something like this.getField('begin_date').value.
The result shall be written into another data form field.
I tried hard, but couldn't make it. Can anyone help me out?
Providing the input value is a textual representation of a date, you need to convert it into a Date object at the first place. Then you can work with it as you want.
DateJS has a pretty smart parse() function which does exactly that, so you'd achieve it like this:
Date.parse(this.getField('begin_date').value).addMonths(24)
When a specific date format is needed, like DD.MM.YYYY commonly used in Europe, you can use parseExact() and specify the format. Like this:
Date.parseExact(dateToParse, 'dd.MM.yyyy') // leading zeroes required; parses 01.04.2014 but not 1.4.2014
Date.parseExact(dateToParse, 'd.M.yyyy') // leading zeroes not required; parses both 01.04.2014 and 1.4.2014
Here is a solution that I found for my problem, using DateJS as well:
start = this.getField('begin_date').value;
var d1 = util.scand("dd.mm.yyyy", start);
var myDate = new Date(d1);
result = myDate.addMonths(24);
This works pretty fine, also spanning leap years, except for the 28th of February, 2014/2018/2022 ... ; the result then will be the 28th of February, 2016/2020/2024 ... and not the 29th of February 2016/2020/2024... In these cases it's up to the user to accept the 28th or to manually change the date to the 29th.
I have explored all the functions avialable in the trasformer, but could not found the exact function to get the last day of current month by passing date in same default format i.e. yyyy-mm-dd.Please help me in this regard.
Field("31|28|31|30|31|30|31|31|30|31|30|31", "|", MonthFromDate(InLink.dateVar))
It is more precise to establish the first day of next month then use DateFromDaysSince function to establish the day before. I created an integer(6) stage variable which contained century and month+1 from source link e.g. 201410
DateFromDaysSince(-1, StringToDate(svIHBKPR, "%yyyy%mm") : "%yyyy-%mm-%dd")
There is a transformer function called DaysInMonth.
Example: DaysInMonth(“2017-01-23”)= 31