Fraction part of the decimal number not included to multiplication in php - numbers

I have multiplication code for an API.
foreach($cXML->results->row as $sale)
{
$subId = $sale->subid;
$status = $sale->status;
$transId = "ad".$sale->OrderID;
$amount = $sale->total_commission;
$createdDate= $sale->date;
$subIdExplode = explode('-', $subId);
$userId = $subIdExplode[0];
$retailerId = $subIdExplode[1];
$retailerQuery = mysql_query("select * from db_retailers where retailer_id = '".$retailerId."'");
$retailer = mysql_fetch_array($retailerQuery);
if(trim($retailer['member_top']) != "")
{
$commision = $retailer['coef']*$amount;
}
}
Input example;
$retailer['coef'] has been entered as 0.6
$amount has been retrieved from XML as 2.50
$commision should be calculated as 1.50. However, it is printed as 1.20
I have found the reason of this difference when investigate from all other inputs that the fraction part of the $amount has not been taken for some reasons.
I could not figure out any possibility.

Although the values coming from XML are seen as 2.50 with dot, I was suspicious that they may be as 2,50.
So I added the code $amount = str_replace(',', '.', $amount); the problem is solved.

Related

How/When to update bias in RPROP neural network?

I am implementing this neural network for some classification problem. I initially tried back propagation but it takes longer to converge. So I though of using RPROP. In my test setup RPROP works fine for AND gate simulation but never converges for OR and XOR gate simulation.
How and when should I update bias for RPROP?
Here my weight update logic:
for(int l_index = 1; l_index < _total_layers; l_index++){
Layer* curr_layer = get_layer_at(l_index);
//iterate through each neuron
for (unsigned int n_index = 0; n_index < curr_layer->get_number_of_neurons(); n_index++) {
Neuron* jth_neuron = curr_layer->get_neuron_at(n_index);
double change = jth_neuron->get_change();
double curr_gradient = jth_neuron->get_gradient();
double last_gradient = jth_neuron->get_last_gradient();
int grad_sign = sign(curr_gradient * last_gradient);
//iterate through each weight of the neuron
for(int w_index = 0; w_index < jth_neuron->get_number_of_weights(); w_index++){
double current_weight = jth_neuron->give_weight_at(w_index);
double last_update_value = jth_neuron->give_update_value_at(w_index);
double new_update_value = last_update_value;
if(grad_sign > 0){
new_update_value = min(last_update_value*1.2, 50.0);
change = sign(curr_gradient) * new_update_value;
}else if(grad_sign < 0){
new_update_value = max(last_update_value*0.5, 1e-6);
change = -change;
curr_gradient = 0.0;
}else if(grad_sign == 0){
change = sign(curr_gradient) * new_update_value;
}
//Update neuron values
jth_neuron->set_change(change);
jth_neuron->update_weight_at((current_weight + change), w_index);
jth_neuron->set_last_gradient(curr_gradient);
jth_neuron->update_update_value_at(new_update_value, w_index);
double current_bias = jth_neuron->get_bias();
jth_neuron->set_bias(current_bias + _learning_rate * jth_neuron->get_delta());
}
}
}
In principal you don't treat the bias differently than before when you did backpropagation. It's learning_rate * delta which you seem to be doing.
One source of error may be that the sign of the weight change depends on how you calculate your error. There's different conventions and (t_i-y_i) instead of (y_i - t_i) should result in returning (new_update_value * sgn(grad)) instead of -(new_update_value * sign(grad)) so try switching the sign. I'm also unsure about how you specifically implemented everything since a lot is not shown here. But here's a snippet of mine in a Java implementation that might be of help:
// gradient didn't change sign:
if(weight.previousErrorGradient * errorGradient > 0)
weight.lastUpdateValue = Math.min(weight.lastUpdateValue * step_pos, update_max);
// changed sign:
else if(weight.previousErrorGradient * errorGradient < 0)
{
weight.lastUpdateValue = Math.max(weight.lastUpdateValue * step_neg, update_min);
}
else
weight.lastUpdateValue = weight.lastUpdateValue; // no change
// Depending on language, you should check for NaN here.
// multiply this with -1 depending on your error signal's sign:
return ( weight.lastUpdateValue * Math.signum(errorGradient) );
Also, keep in mind that 50.0, 1e-6 and especially 0.5, 1.2 are empirically gathered values so they might need to be adjusted. You should definitely print out the gradients and weight changes to see if there's something weird going on (e.g. exploding gradients->NaN although you're only testing AND/XOR). Your last_gradient value should also be initialized to 0 at the first timestep.

Looking for a more efficient way of writing my MATLAB code

I have written in MATLAB the following
for i = 1:3
alpha11(i) = b+a.*randn(1,1);
alpha22(i) = b+a.*randn(1,1);
alpha12(i) = b+a.*randn(1,1);
alpha21(i) = b+a.*randn(1,1);
AoD11(i) = randi([-180/6 +180/6],1,1);
AoA11(i) = randi([-180/6 +180/6 ],1,1);
AoD22(i) = randi([-180/6 +180/6],1,1);
AoA22(i) = randi([-180/6 +180/6 ],1,1);
AoD21(i) = randi([-180 +180],1,1);
AoA21(i) = randi([-180 +180 ],1,1);
AoD12(i) = randi([-180 +180],1,1);
AoA12(i) = randi([-180 +180 ],1,1);
ctet11(i)= ((2*pi)/lambda)*d*sin(AoD11(i));
ctet22(i)= ((2*pi)/lambda)*d*sin(AoD22(i));
ctet12(i)= ((2*pi)/lambda)*d*sin(AoD12(i));
ctet21(i)= ((2*pi)/lambda)*d*sin(AoD21(i));
f_t11_ula{i}=transpose((1/sqrt(M))*[ 1 exp(j*ctet11(i)) exp(j*2*ctet11(i)) exp(j*3*ctet11(i)) ]);
f_t22_ula{i}=transpose((1/sqrt(M))*[ 1 exp(j*ctet22(i)) exp(j*2*ctet22(i)) exp(j*3*ctet22(i)) ]);
f_t12_ula{i}=transpose((1/sqrt(M))*[ 1 exp(j*ctet12(i)) exp(j*2*ctet12(i)) exp(j*3*ctet12(i)) ]);
f_t21_ula{i}=transpose((1/sqrt(M))*[ 1 exp(j*ctet21(i)) exp(j*2*ctet21(i)) exp(j*3*ctet21(i)) ]);
cter11(i)= ((2*pi)/lambda)*d*sin(AoA11(i));
cter22(i)= ((2*pi)/lambda)*d*sin(AoA22(i));
cter12(i)= ((2*pi)/lambda)*d*sin(AoA12(i));
cter21(i)= ((2*pi)/lambda)*d*sin(AoA21(i));
f_r11_ula{i}=transpose((1/sqrt(O))*[ 1 exp(j*cter11(i)) exp(j*2*cter11(i)) exp(j*3*cter11(i)) ]);
f_r22_ula{i}=transpose((1/sqrt(O))*[ 1 exp(j*cter22(i)) exp(j*2*cter22(i)) exp(j*3*cter22(i))]);
f_r12_ula{i}=transpose((1/sqrt(O))*[ 1 exp(j*cter12(i)) exp(j*2*cter12(i)) exp(j*3*cter12(i)) ]);
f_r21_ula{i}=transpose((1/sqrt(O))*[ 1 exp(j*cter21(i)) exp(j*2*cter21(i)) exp(j*3*cter21(i))]);
channel11{i}= alpha11(i) * f_r11_ula{i}* conj(transpose(f_t11_ula{i})) ;
channel22{i}= alpha22(i) * f_r22_ula{i}* conj(transpose(f_t22_ula{i})) ;
channel12{i}= alpha12(i) * f_r12_ula{i}* conj(transpose(f_t12_ula{i})) ;
channel21{i}= alpha21(i) * f_r21_ula{i}* conj(transpose(f_t21_ula{i})) ;
end
I am writing this question here to ask how I can compress this code, as you can see its not very nicely written and I have basically many repetitions. I don't know how to write them in few commands. Every command is repeated four times and indexed by 11, 12, 21, 22..
P.S If someone wants to run the code the following variables are needed
a = 1;
b = 0;
M=4;
O = 4;
lambda=0.15;
d=lambda/2;
Looking forward for suggestions.
As #David mentioned, it can be done using 3D arrays. This removes much of the code repetition.
Here is an example of how it could be done:
sz=[2,2,3];
alpha=b+a.*randn(sz);
AoD = randi([-180/6 +180/6],sz);
AoA = randi([-180 +180],sz);
mask = logical(repmat(eye(2),1,1,3));
[AoA(mask), AoD(~mask)] = deal(AoD(~mask),AoA(mask));
ctet = 2*pi/lambda * d * sin(AoD);
f_t = reshape(arrayfun(#(x) exp(1j*(0:3)'*ctet(x))/sqrt(M),1:12,'UniformOutput',0),sz);
cter = (2*pi)/lambda*d*sin(AoA);
f_r = reshape(arrayfun(#(x) exp(1j*(0:3)'*cter(x))/sqrt(O),1:12,'UniformOutput',0),sz);
channel = reshape(arrayfun(#(x) alpha(x) * f_r{x} * conj(transpose(f_t{x})), 1:12, 'UniformOutput',0),sz);
Note that for each of the variables mentioned in the question, the same values can be accessed using the corresponding 3D index. For example, using the code above, the value that was previously in AoA11(1) is now in AoA(1,1,1). Similarly, the matrix that was stored in channel11{1} is now in channel{1,1,1}.
Hope this helps.

Extraction of data from DWT subband

I am attempting to extract data from a DWT subband. I am able to embed data correctly (I have followed it in the debugger),cal PSNR etc. PSNR rate seem very high 76.2?? however,I am having lot of trouble extracting data back!It is sometimes extracting the number 128?? Can anyone help or have any idea why this is? I would be very thankful.I have been working on this all day & having no luck!I am very curious to know??
Data Embedding:
coverImage = imread('lena.bmp');
message = importdata('minutiaTest.txt');
%message = 'Bifurcations:';
[LL,LH,HL,HH] = dwt2(coverImage,'haar');
if size(message) > size(coverImage,1) * size(coverImage,2)
error ('message too big to embed');
end
bit_count = 0;
steg_coeffs = [4, 4.75, 5.5, 6.25, 7];
for jj=1:size(message,2)+1
if jj > size(message,2)
charbits = [0,0,0,0,0,0,0,0];
else
charbits = dec2bin(message(jj),8)';
charbits = charbits(:)'-'0';
end
for ii=1:8
bit_count = bit_count + 1;
if charbits(ii) == 1
if HH(bit_count) <= 0
HH(bit_count) = steg_coeffs(randi(numel(steg_coeffs)));
end
else
if HH(bit_count) >= 0
HH(bit_count) = -1 * steg_coeffs(randi(numel(steg_coeffs)));
end
end
end
end
stego_image = idwt2(LL,LH,HL,HH,'haar');
imwrite(uint8(stego_image),'newStego.bmp');
Data Extraction:
new_Stego = imread('newStego.bmp');
[LL,LH,HL,HH] = dwt2(new_Stego,'haar');
message = '';
msgbits = '';
for ii = 1:size(HH,1)*size(HH,2)
if HH(ii) > 0
msgbits = strcat (msgbits, '1');
elseif HH(ii) < 0
msgbits = strcat (msgbits, '0');
else
return;
end
if mod(ii,8) == 0
msgChar = bin2dec(msgbits);
if msgChar == 0
break;
end
msgChar = char (msgChar);
message = [message msgChar];
msgbits = '';
end
end
The problem arises from reading your data with importdata.
This command will load the data to an array. Since you have 39 lines and 2 columns (skipping any empty lines), its size will be 39 2. However, the program assumes that your message will be a string. For example, 'i am a string' has a size 1 13. This expectation of the program compared to the data you actually give it creates all sorts of problems.
What you want is to read your data as a single string, where the number 230 is not one element, but 3 individual characters. Tabs and newlines will also be read in as well.
To read your file:
message = fileread('minutiaTest.txt');
After you extract your message, to save it to a file:
fid = fopen('myFilename.txt','w');
fprintf(fid,message);
fclose(fid);

MATLAB Execution Time Increasing

Here is my code. The intent is I have a Wireshark capture saved to a particularly formatted text file. The MATLAB code is supposed to go through the Packets, dissect them for different protocols, and then make tables based on those protocols. I currently have this programmed for ETHERNET/IP/UDP/MODBUS. In this case, it creates a column in MBTable each time it encounters a new register value, and each time it comes across a change to that register value, it updates the value in that line of the table. The first column of MBTable is time, the registers start with the second column.
MBTable is preallocated to over 100,000 Rows (nol is very large), 10 columns before this code is executed. The actual data from a file I'm pulling into the table gets to about 10,000 rows and 4 columns and the code execution is so slow I have to stop it. The tic/toc value is calculated every 1000 rows and continues to increase exponentially with every iteration. It is a large loop, but I can't see where anything is growing in such a way that it would cause it to run slower with each iteration.
All variables get initialized up top (left out to lessen amount of code.
The variables eth, eth.ip, eth.ip.udp, and eth.ip.udp.modbus are all of type struct as is eth.header and eth.ip.header. WSID is a file ID from a .txt file opened earlier.
MBTable = zeros(nol,10);
tval = tic;
while not(feof(WSID))
packline = packline + 1;
fl = fl + 1;
%Get the next line from the file
MBLine = fgetl(WSID);
%Make sure line is not blank or short
if length(MBLine) >= 3
%Split the line into 1. Line no, 2. Data, 3. ASCII
%MBAll = strsplit(MBLine,' ');
%First line of new packet, if headers included
if strcmp(MBLine(1:3),'No.')
newpack = true;
newtime = false;
newdata = false;
stoppack = false;
packline = 1;
end
%If packet has headers, 2nd line contains timestamp
if newpack
Ordered = false;
if packline == 2;
newtime = true;
%MBstrs = strsplit(MBAll{2},' ');
packno = int32(str2double(MBLine(1:8)));
t = str2double(MBLine(9:20));
et = t - lastt;
if lastt > 0 && et > 0
L = L + 1;
MBTable(L,1) = t;
end
%newpack = false;
end
if packline > 3
dataline = int16(str2double(MBLine(1:4)));
packdata = strcat(packdata,MBLine(7:53));
end
end
else
%if t >= st
if packline > 3
stoppack = true;
newpack = false;
end
if stoppack
invalid = false;
%eth = struct;
eth.pack = packdata(~isspace(packdata));
eth.length = length(eth.pack);
%Dissect the packet data
eth.stbyte = 1;
eth.ebyte = eth.length;
eth.header.stbyte = 1;
eth.header.ebyte = 28;
%Ethernet Packet Data
eth.header.pack = eth.pack(eth.stbyte:eth.stbyte+27);
eth.header.dest = eth.header.pack(eth.header.stbyte:eth.header.stbyte + 11);
eth.header.src = eth.header.pack(eth.header.stbyte + 12:eth.header.stbyte + 23);
eth.typecode = eth.header.pack(eth.header.stbyte + 24:eth.header.ebyte);
if strcmp(eth.typecode,'0800')
eth.type = 'IP';
%eth.ip = struct;
%IP Packet Data
eth.ip.stbyte = eth.header.ebyte + 1;
eth.ip.ver = eth.pack(eth.ip.stbyte);
%IP Header length
eth.ip.header.length = 4*int8(str2double(eth.pack(eth.ip.stbyte+1)));
eth.ip.header.ebyte = eth.ip.stbyte + eth.ip.header.length - 1;
%Differentiated Services Field
eth.ip.DSF = eth.pack(eth.ip.stbyte + 2:eth.ip.stbyte + 3);
%Total IP Packet Length
eth.ip.length = hex2dec(eth.pack(eth.ip.stbyte+4:eth.ip.stbyte+7));
eth.ip.ebyte = eth.ip.stbyte + max(eth.ip.length,46) - 1;
eth.ip.pack = eth.pack(eth.ip.stbyte:eth.ip.ebyte);
eth.ip.ID = eth.pack(eth.ip.stbyte+8:eth.ip.stbyte+11);
eth.ip.flags = eth.pack(eth.ip.stbyte+12:eth.ip.stbyte+13);
eth.ip.fragoff = eth.pack(eth.ip.stbyte+14:eth.ip.stbyte+15);
%Time to Live
eth.ip.ttl = hex2dec(eth.pack(eth.ip.stbyte+16:eth.ip.stbyte+17));
eth.ip.typecode = eth.pack(eth.ip.stbyte+18:eth.ip.stbyte+19);
eth.ip.checksum = eth.pack(eth.ip.stbyte+20:eth.ip.stbyte+23);
%eth.ip.src = eth.pack(eth.ip.stbyte+24:eth.ip.stbyte+31);
eth.ip.src = ...
[num2str(hex2dec(eth.pack(eth.ip.stbyte+24:eth.ip.stbyte+25))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+26:eth.ip.stbyte+27))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+28:eth.ip.stbyte+29))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+30:eth.ip.stbyte+31)))];
eth.ip.dest = ...
[num2str(hex2dec(eth.pack(eth.ip.stbyte+32:eth.ip.stbyte+33))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+34:eth.ip.stbyte+35))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+36:eth.ip.stbyte+37))),'.', ...
num2str(hex2dec(eth.pack(eth.ip.stbyte+38:eth.ip.stbyte+39)))];
if strcmp(eth.ip.typecode,'11')
eth.ip.type = 'UDP';
eth.ip.udp.stbyte = eth.ip.stbyte + 40;
eth.ip.udp.src = hex2dec(eth.pack(eth.ip.udp.stbyte:eth.ip.udp.stbyte + 3));
eth.ip.udp.dest = hex2dec(eth.pack(eth.ip.udp.stbyte+4:eth.ip.udp.stbyte+7));
eth.ip.udp.length = hex2dec(eth.pack(eth.ip.udp.stbyte+8:eth.ip.udp.stbyte+11));
eth.ip.udp.checksum = eth.pack(eth.ip.udp.stbyte+12:eth.ip.udp.stbyte+15);
eth.ip.udp.protoID = eth.pack(eth.ip.udp.stbyte+20:eth.ip.udp.stbyte+23);
if strcmp(eth.ip.udp.protoID,'0000')
eth.ip.udp.proto = 'MODBUS';
%eth.ip.udp.modbus = struct;
eth.ip.udp.modbus.stbyte = eth.ip.udp.stbyte+16;
eth.ip.udp.modbus.transID = eth.pack(eth.ip.udp.modbus.stbyte:eth.ip.udp.modbus.stbyte+3);
eth.ip.udp.modbus.protoID = eth.ip.udp.protoID;
eth.ip.udp.modbus.length = int16(str2double(eth.pack(eth.ip.udp.modbus.stbyte + 8:eth.ip.udp.modbus.stbyte + 11)));
eth.ip.udp.modbus.UID = eth.pack(eth.ip.udp.modbus.stbyte + 12:eth.ip.udp.modbus.stbyte + 13);
eth.ip.udp.modbus.func = hex2dec(eth.pack(eth.ip.udp.modbus.stbyte + 14:eth.ip.udp.modbus.stbyte+15));
eth.ip.udp.modbus.register = eth.pack(eth.ip.udp.modbus.stbyte + 16: eth.ip.udp.modbus.stbyte+19);
%Number of words to a register, or the number of registers
eth.ip.udp.modbus.words = hex2dec(eth.pack(eth.ip.udp.modbus.stbyte+20:eth.ip.udp.modbus.stbyte+23));
eth.ip.udp.modbus.bytes = hex2dec(eth.pack(eth.ip.udp.modbus.stbyte+24:eth.ip.udp.modbus.stbyte+25));
eth.ip.udp.modbus.data = eth.pack(eth.ip.udp.modbus.stbyte + 26:eth.ip.udp.modbus.stbyte + 26 + 2*eth.ip.udp.modbus.bytes - 1);
%If func 16 or 23, loop through data/registers and add to table
if eth.ip.udp.modbus.func == 16 || eth.ip.udp.modbus.func == 23
stp = eth.ip.udp.modbus.bytes*2/eth.ip.udp.modbus.words;
for n = 1:stp:eth.ip.udp.modbus.bytes*2;
%Check for existence of register as a key?
if ~isKey(MBMap,eth.ip.udp.modbus.register)
MBCol = MBCol + 1;
MBMap(eth.ip.udp.modbus.register) = MBCol;
end
MBTable(L,MBCol) = hex2dec(eth.ip.udp.modbus.data(n:n+stp-1));
eth.ip.udp.modbus.register = dec2hex(hex2dec(eth.ip.udp.modbus.register)+1);
end
lastt = t;
end
%If func 4, make sure it is the response, then put
%data into table for register column
elseif false
%need code to handle serial to UDP conversion box
else
invalid = true;
end
else
invalid = true;
end
else
invalid = true;
end
if ~invalid
end
end
%end
end
%Display Progress
if int64(fl/1000)*1000 == fl
for x = 1:length(mess);
fprintf('\b');
end
%fprintf('Lines parsed: %i',fl);
mess = sprintf('Lines parsed: %i / %i',fl,nol);
fprintf('%s',mess);
%Check execution time - getting slower:
%%{
ext = toc(tval);
mess = sprintf('\nExecution Time: %f\n',ext);
fprintf('%s',mess);
%%}
end
end
ext = toc - exst;
Update: I updated my code above to remove the overloaded operators (disp and lt were replaced with mess and lastt)
Was asked to use the profiler, so I limited to 2000 lines in the table (added && L >=2000 to the while loop) to limit the execution time, and here are the top results from the profiler:
SGAS_Wireshark_Parser_v0p7_fulleth 1 57.110 s 9.714 s
Strcat 9187 29.271 s 13.598 s
Blanks 9187 15.673 s 15.673 s
Uigetfile 1 12.226 s 0.009 s
uitools\private\uigetputfile_helper 1 12.212 s 0.031 s
FileChooser.FileChooser>FileChooser.show 1 12.085 s 0.006s
...er>FileChooser.showPeerAndBlockMATLAB 1 12.056 s 0.001s
...nChooser>FileOpenChooser.doShowDialog 1 12.049 s 12.049 s
hex2dec 44924 2.944 s 2.702 s
num2str 16336 1.139 s 0.550 s
str2double 17356 1.025 s 1.025 s
int2str 16336 0.589 s 0.589 s
fgetl 17356 0.488 s 0.488 s
dec2hex 6126 0.304 s 0.304 s
fliplr 44924 0.242 s 0.242 s
It appears to be strcat calls that are doing it. I only explicitly call strcat on one line. Are some of the other string manipulations I'm doing calling strcat indirectly?
Each loop should be calling strcat the same number of times though, so I still don't understand why it takes longer and longer the more it runs...
also, hex2dec is called a lot, but is not really affecting the time.
But anyway, are there any other methods I can use the combine the strings?
Here is the issue:
The string (an char array in MATLAB) packdata was being resized and reallocated over and over again. That's what was slowing down this code. I did the following steps:
I eliminated the redundant variable packdata and now only use eth.pack.
I preallocated eth.pack and a couple "helper variables" of known lengths by running blanks ONCE for each before the loop ever starts
eth.pack = blanks(604);
thisline = blanks(47);
smline = blanks(32);
(Note: 604 is the maximum possible size of packdata based on headers + MODBUS protocol)
Then I created a pointer variable to point to the location of the last char written to packdata.
pptr = 1;
...
dataline = int16(str2double(MBLine(1:4)));
thisline = MBLine(7:53); %Always 47 characters
smline = [thisline(~isspace(thisline)),blanks(32-sum(~isspace(thisline)))]; %Always 32 Characters
eth.pack(pptr:pptr+31) = smline;
pptr = pptr + 32;
The above was inside the 'if packline > 3' block in place of the 'packdata =' statement, then at the end of the 'if stoppack' block was the reset statement:
pptr = 1; %Reset Pointer
FYI, not surprisingly this brought out other flaws in my code which I've mostly fixed but still need to finish. Not a big issue now as this loop executes lightning fast with these changes. Thanks to Yvon for helping point me in the right direction.
I kept thinking my huge table, MBTable was the issue... but it had nothing to do with it.

Perl recursion help

I'm trying to write a program that will calculate the dividends of stocks. I did this without a subroutine. Right now, I'm trying to modify it so it can run using a recursive routine. Any help with this? Because I'm not so good at this.
Here's the original script + a pathetic attempt.
print "A stock xyz's price is now $100. It has 3.78% dividend. You have 1000 of it and reinvest the dividend into the stock.\n";
my %hash;
#stocknum = 1000;
#dividend = 6780;
while ($#dividend != 20) {
$a = $dividend[-1];
$stock = $stocknum[-1];
$div_total= $stock*100*0.0678;
$stock_total = $stock + int($a/100);
push (#stocknum, $stock_total);
push (#dividend, $div_total);
if ($#dividend == 20) {
last;
}
}
shift (#dividend);
$stock_num = $stocknum[-1];
$div = $stock_num*100*0.0678;
push (#dividend, $div);
#hash{#stocknum} = #dividend;
foreach $key(sort keys %hash) {
print "Stock number: $key\t"."Dividend: $hash{$key}\n";
}
$dividend=0.0378;
I don't think you want recursion. I think you just want to loop over the number of cycles of payouts that you're after. It looks like you're getting all mixed up with arrays for some reason.
print <<'HERE';
A stock xyz's price is now $100. It has 6.78% dividend.
You have 1000 of it and reinvest the dividend into the stock.
HERE
my $shares = 1000;
my $price = 100;
my $dividend = 6.78 / 100;
my $cycles = $ARGV[0] || 20;
foreach ( 1 .. $cycles ) {
local $cycle = $_;
local $payout = $shares * $dividend * $price;
local $new_shares = $payout / $price;
write();
$shares += $new_shares;
}
format STDOUT =
#### #####.###### ######.####### ###.###### #####.######
$cycle, $shares, $payout, $new_shares, $shares+$new_shares,
.
format STDOUT_TOP =
###.####%
$dividend
Cycle Shares Payout New Shares Total Shares
----------------------------------------------------------------
.
This gives me the output:
A stock xyz's price is now $100. It has 6.78% dividend.
You have 1000 of it and reinvest the dividend into the stock.
0.0678%
Cycle Shares Payout New Shares Total Shares
----------------------------------------------------------------
1 1000.000000 6780.0000000 67.800000 1067.800000
2 1067.800000 7239.6840000 72.396840 1140.196840
3 1140.196840 7730.5345752 77.305346 1217.502186
4 1217.502186 8254.6648194 82.546648 1300.048834
5 1300.048834 8814.3310942 88.143311 1388.192145
6 1388.192145 9411.9427423 94.119427 1482.311572
7 1482.311572 10050.0724603 100.500725 1582.812297
8 1582.812297 10731.4673731 107.314674 1690.126971
9 1690.126971 11459.0608610 114.590609 1804.717579
10 1804.717579 12235.9851873 122.359852 1927.077431
11 1927.077431 13065.5849830 130.655850 2057.733281
12 2057.733281 13951.4316449 139.514316 2197.247597
13 2197.247597 14897.3387104 148.973387 2346.220985
14 2346.220985 15907.3782750 159.073783 2505.294767
15 2505.294767 16985.8985220 169.858985 2675.153752
16 2675.153752 18137.5424418 181.375424 2856.529177
17 2856.529177 19367.2678194 193.672678 3050.201855
18 3050.201855 20680.3685775 206.803686 3257.005541
19 3257.005541 22082.4975671 220.824976 3477.830517
20 3477.830517 23579.6909021 235.796909 3713.627426
Don't worry about my use of format; I've had that on the brain this weekend since I rewrote some perlfaq stuff about it then also turned it into Use formats to create paginated, plaintext reports. You could just as easily created the output with printf:
print <<'HERE';
A stock xyz's price is now $100. It has 6.78% dividend.
You have 1000 of it and reinvest the dividend into the stock.
Cycle Shares Payout New Shares Total Shares
----------------------------------------------------------------
HERE
my $shares = 1000;
my $price = 100;
my $dividend = 6.78 / 100;
my $cycles = $ARGV[0] || 20;
foreach ( 1 .. $cycles ) {
my $payout = $shares * $dividend * $price;
my $new_shares = $payout / $price;
printf "%4d %12.6f %12.6f %10.6f %12.6f\n",
$_, $shares, $payout, $new_shares, $shares + $new_shares;
$shares += $new_shares;
}
As a side note, you really don't ever want recursion, and especially not in Perl if you can help it. Other languages get away with it because they know how to unroll your recursion to turn it into an iterative process. Perl, being a dynamic language, can't really do that because it doesn't know if the subroutine will have the same definition on the next go around. It's nice as a computer science topic because it makes the programming marginally easier and they know it all works out in the end. I think I talk about this in Mastering Perl somewhere, but Mark Jason Dominus covers it extensively in Higher-Order Perl. Basically, instead of recursion you use a queue, which is a better skill to practice anyway.