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Some of my perl statements are executed even after commenting. I tried all the delimiter #, /*..*/, //
Does anyone face the same issue or can anyone help me how to solve this issue?
Your question appears to be "How do I create a comment in Perl?"
perlsyn says thusly:
Text from a "#" character until the end of the line is a comment, and is ignored. Exceptions include "#" inside a string or regular expression.
For example,
print "apple\n"; # Keeps the doctor away.
Keep in mind that comments can only be used where whitespace is expected. For example, the following does not contain any comments since the # is part of the string literal.
print "apple # Keeps the doctor away.
orange
";
Related
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I have a large text file of records each beginning with 22-. I want to read in the file and split it up into an array with one record per element. Looks like I will lose the 22- at the beginning of each element. Is there a way to split it without losing the 22-? I suppose after the split I could add the 22- back to the beginning of each element.
I haven't coded it yet
With split, you specify the separator. 22- is not a separator, but part of the record.
You can still use split by separating on the zero-width space that's followed by 22-.
split /(?=22-)/
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Closed 4 years ago.
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I use a bash script (konsole-name.sh) to change a terminal name, like this:
#!/usr/bin/bash
echo -en "\e]30;$1\a"
and I wanted to use the same method from a perl script that I use to check the GPU temperature, so that it updates periodically the window title.
Yet I didnt find a way.
I tried both this:
$comm='echo -en "\e]30;T=$t\a"';
`$comm`;
and this, using my bash script:
$comm="konsole-name.sh T=$t";
`$comm`;
there is some way to do it?
The console escape sequences work by printing text to the terminal. In your case, the backticks gobble up the output of the script.
Most likely you just want print "\e]30;$1\a"; from within Perl:
my $title = "Fancy terminal title";
print "\e]30;${title}\a";
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Closed 7 years ago.
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Could you please tell me what this line do of sed
the expression is on the title
Thank you
Best regards
It replaces everything on the line with the number immediately following "-svn".
eg.:
blahblabhlabhlabhalbh-svn12345blahblhablhab
is replaced by:
12345
It's matching a string of [anything]-svn[numbers][anything], and replacing the line with the [numbers].
For example:
asda-svn123123bebeb
Gets replaced with
123123
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I need to print the two previous lines before matches inside a file (for any match)
How to make it?
Thank you
The script:
sed -n "1N;2N;/XXX[^\n]*$/{h;s/\n[^\n]*$//;p;g};N;D"
works as follows:
Read the first three lines into the pattern space, 1N;2N
Search for the test string XXX in the last line, and if found: save pattern space in hold space h, delete last line s, print p, and then restore saved string g
Append the next line input to pattern space, N
Delete first line from pattern space and restart cycle, D, noting that 1N;2N is no longer applicable
See also similar SED: addressing two lines before match.
If you do not insist on using sed, use
grep -B 2
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For those that have experience in PowerShell, is this considered to be a valid variable name?
Code:
$[?#+-stuff] is a valid variable name in PowerShell.
It's a valid? Yes, if you wrap it inside curly brackets. This is required because of the special characters.
${[?#+-stuff]} = "foo"
Is it a good name? No. You should keep it simple..
If you made an effort to research it you would have figured it out yourself.
Check of the help documentation the #mjolinor suggested. Especially the part called:
VARIABLE NAMES THAT INCLUDE SPECIAL CHARACTERS
We're all here to help each other, so please show us some respect and behave like a grown-up.